I made a simple calculator and Everytime I hit calculate it'll give a an answer but gives six unnecessary zeros, my question, how can I remove those zeros?
NSString *firstString = textfieldone.text;
NSString *secondString = textfieldtwo.text;
NSString *LEGAL = #"0123456789";
NSCharacterSet *characterSet = [[NSCharacterSet characterSetWithCharactersInString:LEGAL] invertedSet];
NSString *filteredOne = [[firstString componentsSeparatedByCharactersInSet:characterSet]
componentsJoinedByString:#""];
NSString *filteredTwo = [[secondString componentsSeparatedByCharactersInSet:characterSet]
componentsJoinedByString:#""];
firstString = filteredOne;
secondString = filteredTwo;
//Here we are creating three doubles
double num1;
double num2;
double output;
//Here we are assigning the values
num1 = [firstString doubleValue];
num2 = [secondString doubleValue];
output = num1 + num2;
label.text = [NSString stringWithFormat:#"%f",output];
Example:
15 + 15 = 30.000000
I want to add that none of that is necessary if you use the %g specifier.
If you're displaying this by using a string, check the following approaches.
NSString
NSString * display = [NSString stringWithFormat:#"%f", number];
//This approach will return 30.0000000
NSString * display = [NSString stringWithFormat:#"%.2f", number];
//While this approach will return 30.00
Note: You can specify the number of decimals you want to return by adding a point and a number before the 'f'
-Edited-
In your case use the following approach:
label.text = [NSString stringWithFormat:#"%.0f", output];
//This will display your result with 0 decimal places, thus giving you '30'
Please try this out. This should suit your requirements completely.
NSString * String1 = [NSString stringWithFormat:#"%f",output];
NSArray *arrayString = [String1 componentsSeperatedByString:#"."];
float decimalpart = 0.0f;
if([arrayString count]>1)
{
decimalpart = [[arrayString objectAtIndex:1] floatValue];
}
//This will check if the decimal part is 00 like in case of 30.0000, only in that case it would strip values after decimal point. So output will be 30
if(decimalpart == 0.0f)
{
label.text = [NSString stringWithFormat:#"%.0f", output];
}
else if(decimalpart > 0.0f) //This will check if the decimal part is 00 like in case of 30.123456, only in that case it would shows values upto 2 digits after decimal point. So output will be 30.12
{
label.text = [NSString stringWithFormat:#"%.02f",output];
}
Let me know if you need more help.
Hope this helps you.
Related
I am getting this from webservice
"rateavg": "2.6111"
now i am getting this in a string.
How to do this that if it is coming 2.6 it will show 3 and if it will come 2.4 or 2.5 it will show 2 ?
How to get this i am not getting. please help me
Try This
float f=2.6;
NSLog(#"%.f",f);
Hope this helps.
I come up with this, a replica of your query:
NSString* str = #"2.611";
double duble = [str floatValue];
NSInteger final = 0;
if (duble > 2.5) {
final = ceil(duble);
}else{
final = floor(duble);
}
NSLog(#"%ld",(long)final);
So it a case of using either ceil or floor methods.
Edit: Since you want it for all doubles:
NSString* str = #"4.6";
double duble = [str floatValue];
NSInteger final = 0;
NSInteger temp = floor(duble);
double remainder = duble - temp;
if (remainder > 0.5) {
final = ceil(duble);
}else{
final = floor(duble);
}
NSLog(#"%ld",(long)final);
check this
float floatVal = 2.6111;
long roundedVal = lroundf(floatVal);
NSLog(#"%ld",roundedVal);
plz use this
lblHours.text =[NSString stringWithFormat:#"%.02f", [yourstrvalue doubleValue]];
update
NSString *a =#"2.67899";
NSString *b =[NSString stringWithFormat:#"%.01f", [a doubleValue]];
// b will contane only one vlue after decimal
NSArray *array = [b componentsSeparatedByString:#"."];
int yourRating;
if ([[array lastObject] integerValue] > 5) {
yourRating = [[array firstObject] intValue]+1;
}
else
{
yourRating = [[array firstObject] intValue];
}
NSLog(#"%d",yourRating);
Try below code I have tested it and work for every digits,
NSString *str = #"2.7";
NSArray *arr = [str componentsSeparatedByString:#"."];
NSString *firstDigit = [arr objectAtIndex:0];
NSString *secondDigit = [arr objectAtIndex:1];
if (secondDigit.length > 1) {
secondDigit = [secondDigit substringFromIndex:1];
}
int secondDigitIntValue = [secondDigit intValue];
int firstDigitIntValue = [firstDigit intValue];
if (secondDigitIntValue > 5) {
firstDigitIntValue = firstDigitIntValue + 1;
}
NSLog(#"final result : %d",firstDigitIntValue);
Or another solution - little bit short
NSString *str1 = #"2.444";
float my = [str1 floatValue];
NSString *resultString = [NSString stringWithFormat:#"%.f",my]; // if want result in string
NSLog(#"%#",resultString);
int resultInInt = [resultString intValue]; //if want result in integer
To round value to the nearest integer use roundf() function of math.
import math.h first:
#import "math.h"
Example,
float ValueToRoundPositive;
ValueToRoundPositive = 8.4;
int RoundedValue = (int)roundf(ValueToRoundPositive); //Output: 8
NSLog(#"roundf(%f) = %d", ValueToRoundPositive, RoundedValue);
float ValueToRoundNegative;
ValueToRoundNegative = -6.49;
int RoundedValueNegative = (int)roundf(ValueToRoundNegative); //Output: -6
NSLog(#"roundf(%f) = %d", ValueToRoundNegative, RoundedValueNegative);
Read doc here for more information:
http://developer.apple.com/library/mac/#documentation/Darwin/Reference/ManPages/man3/roundf.3.html
NSString *value = #"1.23456";
float floatvalue = value.floatValue;
int rounded = roundf(floatvalue);
NSLog(#"%d",rounded);
if you what the round with greater value please use ceil(floatvalue)
if you what the round with lesser value please use floor(floatvalue)
You can round off decimal values by using NSNumberFormatter
There are some examples you can go through:
NSNumberFormatter *format = [[NSNumberFormatter alloc] init];
[format setPositiveFormat:#"0.##"];
NSLog(#"%#", [format stringFromNumber:[NSNumber numberWithFloat:25.342]]);
NSLog(#"%#", [format stringFromNumber:[NSNumber numberWithFloat:25.3]]);
NSLog(#"%#", [format stringFromNumber:[NSNumber numberWithFloat:25.0]]);
Corresponding results:
2010-08-22 15:04:10.614 a.out[6954:903] 25.34
2010-08-22 15:04:10.616 a.out[6954:903] 25.3
2010-08-22 15:04:10.617 a.out[6954:903] 25
NSString* str = #"2.61111111";
double value = [str doubleValue];
2.5 -> 3: int num = value+0.5;
2.6 -> 3: int num = value+0.4;
Set as your need:
double factor = 0.4
if (value < 0) value *= -1;
int num = value+factor;
NSLog(#"%d",num);
I have float like 3500,435232123. All I want to know if exists (in Objective C) a function that let me keep just the last 4 digits in my case is 2123.
You can use NSNumberFormatter
NSNumberFormatter *format = [[NSNumberFormatter alloc]init];
[format setNumberStyle:NSNumberFormatterDecimalStyle];
[format setRoundingMode:NSNumberFormatterRoundHalfUp];
[format setMaximumFractionDigits:4];
[format setMinimumFractionDigits:4];
string = [NSString stringWithFormat:#"%#",[format stringFromNumber:[NSNumber numberWithFloat:65.50055]] ;
Or simply
NSString *string = [NSString stringWithFormat:#"%.04f", floatValue];
If you want only last four digits, convert the float to a string
NSString *string = [NSString stringWithFormat:#"%f", floatValue];
and get the last four characters
NSString *lastFour = [string substringFromIndex: [string length] - 4];
It you want to get the decimal part, you can do x - floor(x). For instance:
float x = 3500,435232123;
NSString *string = [NSString stringWithFormat:#"%.04f", x - floor(x)];
And to get 4 decimal digits do what Fawad Masud says.
No there is no such function, as far as i know. But here is a way to achieve exactly what you want.
First you have to round it to four digits after point:
NSString *exampleString = [NSString stringWithFormat:#"%.04f", valueToRound];
Then you get the location for the comma inside the exampleString:
NSRange commaRange = [valueString rangeOfString:#","];
Finally you create the finalString with the values from that NSRange. The substring starts at commaRange.location+commaRange.lengthbecause thats the index directly after the comma.
NSString *finalString = [valueString substringWithRange:NSMakeRange(commaRange.location+commaRange.length,valueString.length-commaRange.location-commaRange.length)];
Hope that helps you.
I think is no predefined function for that.
and the solution i thought of is:
float floatNum = 3500.435232123;
converting float number to string and trim/substring the string, like for example:
NSString *stringFloat = [NSString stringWithFormat:#"%f", floatNum];
NSString *newString = [stringFloat substringWithRange:NSMakeRange(stringFloat.length - 4, stringFloat.length)];
NSLog(#"%#", newString);
another is something like:
NSString *stringFloat = [NSString stringWithFormat:#"%f", floatNum];
//separates the floating number to
arr[0] = whole number
arr[1] = decimals
NSArray *arr=[str componentsSeparatedByString:#"."];
since you just want to work on the decimal, i think arr[1] is what you need..
NSString *stringDecimals = (NSString *)arr[1];
if ( stringDecimals.length > 4) //check the length of the decimals then cut if exceeds 4 character..
{
stringDecimals = [stringDecimals substringWithRange:NSMakeRange(stringDecimals.length - 4, stringDecimals.length)];
}
NSLog(#"stringDecimals: %#", stringDecimals);
I want the concatenated NSString I have to be output in the format "00:00", the 0s being the digits in the concatenated string. And if there are not enough characters in the NSString, the other digits are made to be 0.
And if there are more than 4 digits than I want to only have the furthest right digits.
I have done this in Java before, I am assuming it's possible in Objective-C as well.
UIButton *button = sender;
NSString *concatenated = [self.input stringByAppendingString: button.titleLabel.text];
self.input = concatenated;
self.userOutput.text = self.input;
For example, I might get "89" as my concatenated string. I then want, self.input = 00:89.
OR
if I get 89374374 from my concatenated string, I then want self.input = 43:74.
I hope I am being clear
The following method should give the desired output:
- (NSString *)getFormattedTimeStringFromString:(NSString *)string
{
int input = [string intValue];
int mins = input % 100;
input /= 100;
int hours = input % 100;
return [NSString stringWithFormat:#"%02d:%02d", hours, mins];
}
You can use this by calling
self.input = [self getFormattedTimeStringFromString:concatenated];
Like this:
NSDateFormatter * df = [[NSDateFormatter alloc] init];
[df setDateFormat:#"HH:mm"];
NSString *dateTimeStr = [df stringFromDate:[NSDate date]];
if ([concatenated length] == 2) {
self.input = [NSString stringWithFormat:#"00:%#",concatenated];
}
else
{
NSString *test = [concatenated substringFromIndex:[concatenated length] -4];
self.input = [NSString stringWithFormat:#"%#:%#",[test substringToIndex:2],[test substringFromIndex:[test length]-2]];
}
Please try above code it will fail if [concatenated length] is 3 or 1 , modify it accordingly
I have an app I'm developing and one of my features is giving answers in float or double values when needed and an integer when the answer is a whole number
so for example if the answer comes out to 8.52 the answer becomes 8.52 but when the answer is 8 the answer is 8 instead of 8.0000, i don't want it to show all the extra 0s.
- (IBAction) equalsbutton {
NSString *val = display.text;
switch(operation) {
case Plus :
display.text= [NSString stringWithFormat:#"%qi",[val longLongValue]+[storage longLongValue]];
case Plus2 :
display.text= [NSString stringWithFormat:#"%f",[val doubleValue]+[storage doubleValue]];
this code doesn't seem to work
These specifiers are standard IEEE format specifiers, which means that you can do things like %.2f to only show 2 decimal places on a float variable.
You could also convert it into an int, and then use the %d format specifier if you wanted to do it that way.
Here's also Apple's documentation on the subject.
EDIT: Based on your comment on the other post, it looks like you're looking for %g, which will essentially remove the extraneous 0's from floats.
display.text= [NSString stringWithFormat:#"%g",[val doubleValue]+[storage doubleValue]];
I found the answer here: Use printf to format floats without decimal places if only trailing 0s
EDIT Formatting
Here is a way that I did this when I needed to display currency (but whole numbers if the currency was a round number.
First we get the money amount as a string
NSString *earnString = _money.payout.displayableAmount;
NSMutableString *strippedString = [NSMutableString
stringWithCapacity:earnString.length];
//scan the string to remove anything but the numbers (including decimals points)
NSScanner *scanner = [NSScanner scannerWithString:earnString];
NSCharacterSet *numbers = [NSCharacterSet
characterSetWithCharactersInString:#"0123456789"];
while ([scanner isAtEnd] == NO) {
NSString *buffer;
if ([scanner scanCharactersFromSet:numbers intoString:&buffer]) {
[strippedString appendString:buffer];
} else {
[scanner setScanLocation:([scanner scanLocation] + 1)];
}
}
//create an int with this new string
int earnInt = [strippedString intValue];
//if the string is less than 100 then we only had "change" so display that amount
if(earnInt < 100){
//Dollar amount is less then dollar display just the cents and the cent symbol
NSString *centString = [NSString stringWithFormat:#"%i¢", earnInt];
earnAmount.text = centString;
//if we have a number evenly divisible by 100 then we have whole dollar amount, display that properly
}else if(earnInt % 100 == 0){
//The amount is exactly a dollar, display the whole number
NSString *wholeDollar = [NSString stringWithFormat:#"$%i", (earnInt/100)];
earnAmount.text = wholeDollar;
//finally if we have a mixed number then put them back together with the decimal in-between.
}else{
//Dollar amount is not exactly a dollar display the entire amount
NSString *dollarString = [NSString stringWithFormat: #"$%0d.%02d", (earnInt / 100), (earnInt % 100)];
earnAmount.text = dollarString;
}
Hopefully this helps you out...
You can try this method call:
[NSString stringWithFormat:#"%.0f", [val doubleValue] + [storage doubleValue]];
Easiest way, is NSNumberFormatter. It will only display the decimal if needed. Example (Swift):
let num1: Double = 5
let num2: Double = 5.52
let numberFormatter = NSNumberFormatter()
numberFormatter.numberStyle = .DecimalStyle
print(numberFormatter.stringFromNumber(NSNumber(double: num1)))
print(numberFormatter.stringFromNumber(NSNumber(double: num2)))
This will print 5 and then 5.52.
I have a UILabel that shows the outside temperature, the problem is, sometimes it shows it as a XX.XXº format instead of the normal XXº or XXXº format used to show temperature, is there anyway to force the label to only show the temperature without the decimals or at least force it to only be able to use 2 characters?
You can use this to eliminate the decimals:
NSString* numberString = [NSString stringWithFormat:#"%.0f", d]; // 0 means no decimals
Otherwise I believe this will work to limit the number of chars to 2:
NSNumberFormatter *formatter = [[NSNumberFormatter alloc] init];
formatter.usesSignificantDigits = YES;
formatter.maximumSignificantDigits = 2;
I have not really used NSNumberFormatter very much though.
NSString *temp = [galleryEntryTree objectForKey:#"description"];
if ([temp length] > 500) {
NSRange range = [temp rangeOfComposedCharacterSequencesForRange:(NSRange){0, 500}];
temp = [temp substringWithRange:range];
temp = [temp stringByAppendingString:#" …"];
}
coverView.label2.text = temp;
You may also use substring method
NSString *newformat = [NSString stringWithFormat:#"%#",[temperature substringWithRange:NSMakeRange(0,2)]];
In this case temperature is a string that you set for your label and you are only retrieving the 1st 2 digits only