I have a question regarding a volume calculation formula. We use Lua formulae embedded in pharmacy labels. One enables us to calculate the volume of drug from the entered dose where we use either %0, %1, or %2, depending on the drug, to calc to the required number of decimal places, . However even if we have defined %2 for a particular label design/drug, for some doses if the result obtained ends up as .00, for best practice it is best not to show the trailing zeroes, is there a line we can add to the formula so that the trailing zeroes are not shown
lua
Dose = Label.TextFromTag("Dose")
Concentration = Label.TextFromTag("CONC")
volume = string.format("%.2f", Dose / Concentration)
return volume
Remove the trailing zeros explicitly with
return (volume:gsub("0+$",""))
Use this only if the format is not %.0f.
Related
I'm making a list for buying groceries in Google Sheets and have the following value in cell B4.
0.95 - Lemon Juice
2.49 - Pringle Chips
1.29 - Baby Carrots
9.50 - Chicken Kebab
What I'm trying to do is split using the dash character and combine the costs (0.95+2.49+1.29+9.50).
I've tried to use Index(SPLIT(B22,"-"), 7) and SPLIT(B22,"-") but I don't know how to use only numbers from the split string.
Does someone know how to do this? Here's a sample sheet.
Answer
The following formula should produce the result you desire:
=SUM(ARRAYFORMULA(VALUE(REGEXEXTRACT(SPLIT(B4,CHAR(10)),"(.*)-"))))
Explanation
The first thing to do is to split the entry in B4 into its component parts. This is done by using the =SPLIT function, which takes the text in B4 and returns a separate result every time it encounters a specific delimiter. In this case, that is =CHAR(10), the newline character.
Next, all non-number information needs to be removed. This is relatively easy in your sample data because the numbers always appear to the left of a dash. =REGEXEXTRACT uses a regular expression to only return the text to the left of the dash.
Before the numbers can be added together, however, they must be converted to be in a number format. The =VALUE function is used to convert each result from a text string containing a number to an actual number.
All of this is wrapped in an =ARRAYFORMULA so that =VALUE and =REGEXEXTRACT parse each returned value from =SPLIT, rather than just the first.
Finally, all results are added together using =SUM.
Functions used:
=CHAR
=SPLIT
=REGEXEXTRACT
=VALUE
=ARRAYFORMULA
=SUM
Firstly you can add , symbols start and ends of numbers with below code:
REGEXREPLACE(B4,"([0-9\.]+)",",$1,")
Then split it based of , sign.
SPLIT(A8, ",")
Try below formula (see your sheet)-
=SUM(ArrayFormula(--REGEXEXTRACT(SPLIT(B4,CHAR(10)),"-*\d*\.?\d+")))
I need a print function that writes Loop i / round, where both values i and round have to have at least four digits (12 -> 0012). It must have the format-method too.
I found the paste formatC and other ways to add leading zeroes but I can't make them work for this case..
It needs to be like this:
print('Loop {} / {}'.format('i', 'round'))
But with four digit numbers as I said.
number_str = str(a_number)
zero_filled_number = number_str.zfill(4)
a_number is 12.
zero_filled_number will give you 0012
Use print("{:02d}".format(1)) as found in this answer.
I have a model which has a column named code, which is a combination of the model's name column and its ID with leading zeros.
name = 'Rocky'
id = 16
I have an after_create callback which runs and generates the code:
update(code: "#{self.name[0..2].upcase}%.4d" % self.id)
The generated code will be:
"ROC0016"
The code is working.
I found (%.4d" % self.id) from another project, but I don't know how it works.
How does it determine the number of zeros to be preceded based on the passed integer.
You’re using a "format specifier". There are many specifiers, but the one you’re using, "%d", is the decimal specifier:
% starts it. 4 means it should always use at least four numbers, so if the number is only two digits, it gets padded with 0s to fill in the rest of the numbers. The second % means replace 4d with whatever comes after it. So in your case, 4d is getting replaced with "0016".
sprintf has more information about format specifiers.
You can read more about String#% in the documentation also.
After the percentage sign ("%") is a decimal (".") and a number. That number is the number of total digits in the result. If the result is less than this value, additional zeros will be added.
Thus, in this first example, the result is "34" but length was set to "4". The result will have two leading zeros to fill it into four digits.
"This is test string %.4d" % 34
result => "This is test string 0034"
"I want more zeroes in my code %.7d" % 34
result => "I want more zeroes in my code 0000034"
Im converting binary to decimal and Im converting Decimal to binary. My problem is Length of the binary integer. For example:
Convertx("001110",2,10) = 14
Convertx("14",10,2) = 1110
But length of the binary is NOT constant, So How can I get exact original binary with zeros front of it? How can I get "001110" instead of "1110" ?
I m using this function in Delphi 7. -> How can I convert base of decimal string to another base?
The function you are using returns a string that is the shortest length required to express the value you have converted.
Any zeroes in front of that string are simply padding - they do not alter the binary value represented. If you need a string of a minimum length then you need to add this "padding" yourself. e.g. if you want a binary representation of a "byte" (i.e. 8 binary digits) then the minimum length you would need is 8:
binStr := Convertx("14",10,2);
while Length(binStr) < 8 do
binStr := '0' + binStr;
If you need the exact number of zeroes that were included in the "padding" of some original binary value when converting from binary to decimal and then back to "original" binary again, then this is impossible unless you separately record how many padding zeroes there were or the length of the original string, including those zeroes.
i.e. in your example, the ConvertX function has no idea (and now way to figure out) that the number "14" it is asked to convert to binary was originally converted from a 6 digit binary string with 2 leading zeroes, rather than an 8 digit binary with 4 leading zeroes (or a 16 digit binary with 12 leading zeroes, etc etc).
What you are hoping for is impossible. Consider
Convertx('001110', 2, 10)
and
Convertx('1110', 2, 10)
These both return the same output, 14. At that point there is no way to recover the length of the original input.
The way forward is therefore clear. You must remember the length of the original binary, as well as the equivalent decimal. However, once you have reached that conclusion then you might wonder whether there is an even simpler approach. Just remember the original binary value and save yourself having to convert back from decimal.
I have the following code in an attempt to align things in latex using amsmath package:
\begin{alignat}{3}
\text{max} && c^Tx &=\\
\text{s.t.} && Ax &\leq b \\
&& x &\geq 0
\end{alignat}
Basically, i would like for max and s.t. to be in one column, c^Tx, Ax, x to be in second column, and lastly b and 0 to be in the last column. I'm not sure why it doesn't work (it clumps max and c^Tx together for some reason.
if anyone can help me out with this it would be much appreciated!
With math-mode \text{} you should put in some explicit whitespace such as \quad. But max smells like a log-like symbol so you should be using pre-defined \max or self-defined \operatorname{max} instead of \text{max}.
Additionally, the parameter for the alignat environment should be 2 in this case. The param is the number of alignment structures and can be calculated by solving n from a=2n-1 where a is the number of ampersands on a row. However, it doesn't seem to have a difference in this case.
I believe what's happening here is that max and s.t. are being right-aligned, which is running them right up next to c^Tx and Ax. If you just add some whitespace to the right-hand-side of max and s.t., you should be in business.
(Also, laalto is right, you should definitely use \operatorname{max} if max is some sort of operator or function. Though I'm not really sure what you're doing, so maybe it isn't.)