RxJava Observable to smooth out bursts of events - twitter

Question

I'm writing a streaming Twitter client that simply throws the stream up onto a tv. I'm observing the stream with RxJava.
When the stream comes in a burst, I want to buffer it and slow it down so that each tweet is displayed for at least 6 seconds. Then during the quiet times, any buffer that's been built up will gradually empty itself out by pulling the head of the queue, one tweet every 6 seconds. If a new tweet comes in and faces an empty queue (but >6s after the last was displayed), I want it to be displayed immediately.
I imagine the stream looking like that described here:
Raw: --oooo--------------ooooo-----oo----------------ooo|
Buffered: --o--o--o--o--------o--o--o--o--o--o--o---------o--o--o|
And I understand that the question posed there has a solution. But I just can't wrap my head around its answer. Here is my solution:
myObservable
.concatMap(new Func1<Long, Observable<Long>>() {
#Override
public Observable<Long> call(Long l) {
return Observable.concat(
Observable.just(l),
Observable.<Long>empty().delay(6, TimeUnit.SECONDS)
);
}
})
.subscribe(...);
So, my question is: Is this too naïve of an approach? Where is the buffering/backpressure happening? Is there a better solution?

Answer 1

Looks like you want to delay a message if it came too soon relative to the previous message. You have to track the last target emission time and schedule a new emission after it:
public class SpanOutV2 {
public static void main(String[] args) {
Observable<Integer> source = Observable.just(0, 5, 13)
.concatMapEager(v -> Observable.just(v).delay(v, TimeUnit.SECONDS));
long minSpan = 6;
TimeUnit unit = TimeUnit.SECONDS;
Scheduler scheduler = Schedulers.computation();
long minSpanMillis = TimeUnit.MILLISECONDS.convert(minSpan, unit);
Observable.defer(() -> {
AtomicLong lastEmission = new AtomicLong();
return source
.concatMapEager(v -> {
long now = scheduler.now();
long emission = lastEmission.get();
if (emission + minSpanMillis > now) {
lastEmission.set(emission + minSpanMillis);
return Observable.just(v).delay(emission + minSpanMillis - now, TimeUnit.MILLISECONDS);
}
lastEmission.set(now);
return Observable.just(v);
});
})
.timeInterval()
.toBlocking()
.subscribe(System.out::println);
}
}
Here, the source is delayed by the number of seconds relative to the start of the problem. 0 should arrive immediately, 5 should arrive # T = 6 seconds and 13 should arrive # T = 13. concatMapEager makes sure the order and timing is kept. Since only standard operators are in use, backpressure and unsubscription composes naturally.