I am not used to SPSS so this question will sound stupid:
I need to change fragments of a cell in spss, exemple:
'1.28'
'2.69'
'3.57'
to
'a.28'
'b.69'
'c.57'
What's the best way to do it?
Tks.
This is assuming the variable you want to recode is called 'VarA', and that it is numeric.
This creates a copy of the variable, converts it to a string, and then uses those values to create a new version that is recoded.
RECODE VarA (ELSE = COPY) INTO VarA_String.
ALTER TYPE VarA_String(A8).
EXECUTE.
COMPUTE VarA_r=REPLACE(VarA_String,'1.','a.').
COMPUTE VarA_r=REPLACE(VarA_String,'2.','b.').
COMPUTE VarA_r=REPLACE(VarA_String,'3.','c.').
EXECUTE.
The syntax is a little different in SPSS Modeler and bear with me as I can only attach one image until I have a certain reputation on SO.
After you convert VarA into a string (which I called to_str) you can use the replace command to change part of the substring, ie:
to_string(VarA)
for the first Derive node, and:
replace('1.','a.',to_str)
for the second Derive node, this command replaces all occurrences of SUBSTRING1 with SUBSTRING2 in STRING and you will get the same result but in Modeler, see the sample stream here
Assuming that these are strings, see the replace function in COMPUTE. If there are just a few, though, just edit the cells in the Data Editor.
Related
I am working with nom version 6.1.2 and I am trying to parse Strings like
A 2 1 2.
At the moment I would be happy to at least differentiate between input that fits the requirements and inputs which don't do that. (After that I would like to change the output to a tuple that has the "A" as first value and as second value a vector of the u16 numbers.)
The String always has to start with a capital A and after that there should be at least one space and after that one a number. Furthermore, there can be as much additional spaces and numbers as you want. It is just important to end with a number and not with a space. All numbers will be within the range of u16. I already wrote the following function:
extern crate nom;
use nom::sequence::{preceded, pair};
use nom::character::streaming::{char, space1};
use nom::combinator::recognize;
use nom::multi::many1;
use nom::character::complete::digit1;
pub fn parse_and(line: &str) -> IResult<&str, &str>{
preceded(
char('A'),
recognize(
many1(
pair(
space1,
digit1
)
)
)
)(line)
}
Also I want to mention that there are answers for such a problem which use CompleteStr but that isn't an option anymore because it got removed some time ago.
People explained that the reason for my behavior is that nom doesn't know when the slice of a string ends and therefore I get parse_and: Err(Incomplete(Size(1))) as answer for the provided example as input.
It seems like that one part of the use declarations created that problem. In the documentation (somewhere in some paragraph way to low that I looked at it) it says:
"
Streaming / Complete
Some of nom's modules have streaming or complete submodules. They hold different variants of the same combinators.
A streaming parser assumes that we might not have all of the input data. This can happen with some network protocol or large file parsers, where the input buffer can be full and need to be resized or refilled.
A complete parser assumes that we already have all of the input data. This will be the common case with small files that can be read entirely to memory.
"
Therefore, the solution to my problem is to swap use nom::character::complete::{char, space1}; instead of nom::character::streaming::{char, space1}; (3rd loc without counting empty lines). That worked for me :)
I have a lot of music chords that can have alternate names, rather than having to create longer lines with a lot of == and or's for each alternate name, and if chord=="Maj" or "maj" or.. don't work with Lua:
if chord=="Maj9" or chord="maj9" or chord=="M9" or chord=="Maj7(add9)" or chord=="M7(add9)" then notes="0,4,7,11,14" end
I need a simpler way to do it, maybe just reformat the lines in Notepad++ to use an array,
at the moment each of the 200+ chords on one line each:
if chord=="Maj9,maj9,M9,Maj7(add9),M7(add9)" then notes="0,4,7,11,14" end
if chord=="mMaj7,minmaj7,mmaj7,min/maj7,mM7,m(addM7),m(+7),-(M7)" then notes="0,3,7,11" end
The correct way is to normalize your input. For example, take whatever chord value comes in and use Lua’s string.lower() function to make the string all lowercase. By normalizing your input, you simplify the logic you need to write to work with that data. Consider other ways as well to normalize the data. You might, for example, write a method that converts all notes into an enumerated list (C = 1, C# = 2, etc.). That way equivalent notes get the same in-memory values.
Those are just a few ideas to get you on track. You should not try to think up and then hard-code every possible way a user may input a chord name.
Being a novel on SPSS I am struggling with finding duplicate cases based on a string-variable in a dataset containing approx 33,000 cases.
I have a variable named "nr" that is supposed to be unique id for every case. However, it turns out that some cases might have two different values in "nr" entered,the only difference being the last character. Resulting in a case being shown as two separate rows.
The structure of the var "nr" is a as follows: XX-XXXXXXX-X or X-XXXXXXX-X i.e 2-7-1 characters or 1-7-1 characters.
I would like to sort out all cases that have a "nr" equal to another case except for the last character.
To illustrate, with a succesfull syntax I would hopefully be able to sort cases like these out from the whole dataset:
20-4026988-2
20-4026988-3
5-4026992-5
5-4026992-8
20-4027281-2
20-4027281-3
Anyone have an idea on how to make a syntax for this? Would be so grateful for any input!
I suggest to create a new variable without that last character, and then look for the doubles:
* first creating some sample data to play with.
data list list/ID (a15).
begin data.
20-4026988-2
12-2345678-7
20-4026988-3
5-4026992-5
5-4026992-8
12-1234567-1
20-4027281-2
6-1234567-1
20-4027281-3
end data.
* now creating the new variable and counting the occurrences of each shortened ID.
string ShortID (a15).
compute ShortID=char.substr(ID,1,char.rindex(ID,"-")).
* also possible: compute ShortID=char.substr(ID,1,char.length(rtrim(ID))-1).
aggregate out=* mode=add /break=ShortID/occurrences=n.
* at this point you can filter based on the number or `occurrences` or sort them.
sort cases by occurrences (d) ShortID.
After removing the last character, you can use Data > Identify Duplicate Cases to find the dups. It as a number of useful options for this.
I need to calculate the percentile 85 and then save in a variable because I want to use it in many condition sentences like:
IF(variable>percentile85) a=0.
IF(variable2>percentile85) b=0.
IF(variable3>percentile85) c=0.
Is there a way to save a value into a variable and then use it?
use RANK command with Ntiles, then use the new variable created:
RANK VARIABLES=YourVar(A) /NTILES(100).
IF(NYourVar>=85) a=0.
EXECUTE.
Note that you can actually use Python in SPSS. The downloadable Programming and Data Management book has many examples. The SPSSINC TRANS extension command makes it particularly easy to do data transformations using Python code.
Hi
I want to get numbers from database, for example, if the number in database is 44.7890000000, I would like to get a string 44.789, the same 0.0010000000 -> 0.001, just keep the numbers and trim the tailing '0'.
I use this code:
qrySth.Fields[i].AsString - it does its job but I find for very small numbers like 0.0000010000 it becomes 1E-6. Is there a way I could disable the scientific notation for this AsString method?
Thanks!
As an alternative to setting the field's DisplayFormat property, you can read from AsFloat and pass the value directly to FormatFloat. It uses the same format pattern.