Working with a UITableViewController. You can see my prototype cell in the screenshot; It's made up by 2 labels (1 on the left containing quantity X item name, and 1 on the right with the price).
When the left label is too long (or when testing on a 3.5" device), there's no space left between the 2 labels and they enter each other's space. How can I make sure that when they get really close to each other, I show something like "1 X item n..." instead of "1 X item name" so that there's always some space between the 2?
I am using auto-layout by the way (with a spacing constraint between them but it doesn't seem to respect it).
Hope I am making sense!
Ah, just got it. Had to decrease content hugging.
Related
I'm trying to make constraints via Snapkit in a table view cell but my problem is I need to find out which element has max y position (The lowest one).
I have an UIImageView and next to image view UILabel elements. The label text is dynamic and could be very long or very short. Below these 2 elements, I have another one that should be aligned based on the label height, either taking image view or label.
My question is how to find which element (UIIMageView, UILabel) has a bigger Y position.
To be more clear I attached a draw with simple two cases.
Set a greaterThanOrEqualTo constraint on both elements.
In "plain language":
AnotherElement.top >= ImageView.Bottom (with constant of 12, or however much space you want)
AnotherElement.top >= Label.Bottom (with constant of 12, or however much space you want)
I'm having trouble setting up constraints.
This is the thing I am trying to achieve:
I have 2 objects A and B. I want there there to be a maximum of 100 points between A and B if its a larger screen, or less if its a smaller screen.
Also, I want there to be a minimum of a 20 point margin from the main view controller. So on a smaller screen the minimum spacing will be 20 points, and on a larger screen the margin can be as wide as needs in order to satisfy the space between A and B at 100 points.
To illustrate how I want it to look on various screens:
4 inch screen
I want there to be a 20 point margin on either side and the middle (space between A and B) can be variable, i.e. 100 or less.
5.5 inch screen
The margins can be variable and expand as large as they need to, but the middle section (space between A and B) can be a maximum of 100.
Any help how to achieve this would be greatly appreciated.
This can be achieved with help from three dummy views and two width constrains with different priorities. I set up a test project to test my thought. check it out to see whether it's what you needed
https://github.com/dopcn/testSeg
Good afternoon,
I'm trying to put an image in the middle of two inputs, that means that I would like to have the same margin to the first input as the second input. I'm going to explain better with an example:
[input a]---- 20px-----[image]---- 20px-----[input b]
I want to have the image always at the middle between them, because when I rotate the screen I have to make it large.
I have to use constraints? Which one? Is it possible?
Thanks in advance.
There are a number of ways to approach this. (There are a number of ways to approach everything, lol).
I'm only going to show AutoLayout solutions because it will make things easer when things are moving. Also, your description is pretty much already using AutoLayout Visual Format Language.
The first would be to place inputA, inputB and image into a third view which I'll call interfaceView.
Now you can lay it out like this...
|[inputA] // i.e. up against the left edge
[inputB]| // i.e. up against the right edge
[image] is different. You then align the centre of image with the centerX of interfaceView
The second option is to use "spacer" views.
Create two more views called spacer1 and spacer2 and layout the screen like this...
[inputA][spacer1][image][spacer2(==spacer1)][inputB]
Make spacer 1 and 2 hidden. They are just there for layout purposes. Now, because I have given them equal widths they will align the image view exactly in the middle of A and B.
I have now been bashing my head against this problem for a couple of hours and figured it was time to ask somebody else.
I have 2 views that must be the same size, within these two views there are 2 boxes (green and blue in the pictures below), which are of variable sizes, and a box (pink'ish) that is fixed size.
Here is a sample image:
The green and pink boxes are set to be at the top, and the blue box floats underneath them. The blue box should never be further down than 15pt from the lowest of the other two boxes. This means that if the green box becomes smaller (as seen in the next image), then the blue box should stay 15pt from the pink box.
Lastly, since the cells are fixed height then if the blue box becomes smaller, then it should stay at the other boxes, but leave space below itself to fill out the rest of the view (since it must be as big as the view next to it), as I tried picturing here:
The key point here is that we are working on the smaller view of the two.
(The green and blue boxes are both labels with text that must be at the top of the box.)
The best solution I've come up with is to add:
green.bottom >=15 blue.top
pink.bottom >=15 blue.top
blue.bottom >=15 superview.bottom
But I get an "Inequality Constraint Ambiguity" between them, because inequality is not "good enough".
You need to add two more constraints between the blue view and the green and pink views. The should be,
green.bottom == 15 blue.top priority 900
pink.bottom == 15 blue.top priority 900
Your >= constraints have the default priority of 1000, meaning that they are required. This will ensure that neither view is ever closer than 15 points to the blue view. Adding these new equal constraints with a lower priority, means that the system will try to satisfy them, but it doesn't have to. This will result in the system satisfying which ever of those two equal constraints that it can, without violating the >= constraints.
I'm not exactly sure what constraint you need to the bottom of the view (from the blue view) since I'm unsure what size you want it to be.
Suppose I have a view that contains two columns of objects. The first column contains labels, and the second column contains, say, sliders. I want the sliders all to align left with each other. I want the labels all to align left with each other. The trick is, how can I set the spacing between the labels and sliders so that the default spacing is used between the left sliders and the longest label, thus:
label 1 slider 1
label 2 slider 2
longer label 3 slider 3
very long label 4[]slider 4
label 5 slider 5
I've placed square brackets, [], where the default spacing should be. Is it possible to add this sort of constraint in the storyboard (iOS 7)? If so, how? The trick is that I don't know which label is the longest, especially with localization.
Ideally, I could specify a bounding box around the labels and align the sliders with the right side of the bounding box.
Yes, you can do this in IB. All the labels should have their left edges aligned, and one of them should have a fixed space to the left edge of their superview (all the elements should be enclosed in a UIView). Similarly, the sliders would have their right edges aligned and one of them would have a fixed space to the right edge of the box. Give one of the labels a horizontal spacing constraint to a slider -- make that a short one, say ==8 with a priority of 900 (that's the important thing). Now, give all the labels a >= constraint with whatever value you want for the minimum spacing (and leave the priority at 1000).