Can anyone guide me in finding the three largest values, and sum them up in the column "I"?
And also need to highlight the top three values in each row.
For example, in this image, I want to find the largest three from D,E,F,G columns in each row and SUM of largest three should be filled in column "I".
You can use the large formula,
I'm sure there is a better way, but if there is an error you can use the iferror() so if there is an error the value will show up as 0.
=IFERROR(LARGE(D2:G2,1),0)+IFERROR(LARGE(D2:G2,2),0+IFERROR(LARGE(D2:G2,3),0))
Related
I’m trying to emulate Minesweeper in Google Sheets, and for this I want to create a second map adjacent to the first with all of the correct values already in it. To randomize bomb position, I need a list of random numbers or cells(cells would be preferable). However, I cannot figure out how to do this without ending up repeating numbers. The result would ideally be a vertical array of cell coordinates. Thank you!
Answer
The following formula should produce the result you desire:
=SORTN(FLATTEN(MAKEARRAY(10,10,LAMBDA(row,col,ADDRESS(row,col)))),20,,RANDARRAY(100),)
In =MAKEARRAY, change the first 10 to adjust how many rows to randomly choose from, or the second 10 to adjust how many columns to choose from. The value in =RANDARRAY must be equal to the product of the number of rows and the number of columns. (e.g. in the above example, 10*10=100).
Change the 20 to adjust how many randomly chosen values to return.
Explanation
=MAKEARRAY is used to generate an array of every possible row and column combination. It accepts a =LAMBDA, which in this case is just the =ADDRESS function. The first two arguments of =MAKEARRAY determine how large the array should be, which is why changing them adjusts how many rows/columns to randomly pick from.
Then, the result of =MAKEARRAY is squashed into a single column using the =FLATTEN formula.
Finally, the entire thing is sorted randomly using =SORTN combined with =RANDARRAY. =SORTN also limits the number of results that are returned dependent on its second argument, which is why changing it adjusts how many results are returned.
If you want information on how to "freeze" the value of =RANDARRAY so it doesn't recalculate each time you change something, check out this question by player0.
Functions used:
=MAKEARRAY
=LAMBDA
=ADDRESS
=FLATTEN
=SORTN
=RANDARRAY
SECOND IMAGE CLICK NUMBER 1 I Want To Transpose Row Value Range A2:A50 To Column CZ2 To BC2. Formula Should Be Given IN CZ2. AND VALUE SHOULD GET IN REVERSE OR LEFT COLUMNS.[First IMAGE Click Number 2] 2. If I Give Transpose (AO2:AO50) In CZ2 it Will go range from CZ2 To EW2. I Want Transpose in Reverse Columns. If I Increase Row Value AO2:AO60 It Should Flow Towards Left From CZ2 To AS2. I Mean Transpose Should work towards Left Side Columns. Its Ok with any other formula If Not Transpose. Hope My Question is Understandable. Someone Help Me Out. Thank You In Advance.
It's not clear why you would want to do this. However, the end goal can be achieved by placing the following formula in cell B2 (not CZ2):
=ArrayFormula(IFERROR(VLOOKUP(COLUMNS(B1:1)-COLUMN(B1:1)+ROW(A2)+1,{ROW(A2:A),A2:A},2,FALSE)))
Try it and you'll see what I mean.
The formula is written to be flexible. So if you add or subtract data from A2:A, the value in A2 will always be in Row 2 of the last column to the right in the sheet; and all other values will work backward from there.
If you always want to start to backward progression in Column CZ and Column CZ is not (or may not always be) your rightmost column, you can use this version:
=ArrayFormula(IFERROR(VLOOKUP(COLUMN(CZ1)-COLUMN(B1:CZ1)+ROW(A2)+1,{ROW(A2:A),A2:A},2,FALSE)))
Just understand that, if you don't have columns at least through Column CZ, this formula will fail to work as expected.
I recommend using the first formula I supplied above, since it will always work, no matter how many columns there are, filling backward as far as to the formula column (B2) as needed.
Understand also that if you have more than 103 rows of data in A2:A, that would be more than could fit between B2 and CZ2; so only the first 103 would be displayed.
ADDENDUM (after reading first two comments below):
The principle is the same if you want to run results from "CZ to BC"; only in this case, you want to limit the results to no more than 50.
Place the following formula in BC2:
=ArrayFormula(IFERROR(VLOOKUP(SEQUENCE(1,50,ROW(A2)+50-1,-1),{ROW(A2:A),A2:A},2,FALSE)))
To reiterate, you cannot run formulas that will fill or columns backward. (Even if the sheet is set to right-to-left font with Column A appearing at the far right, the formula is still filling A-Z according to that setup.) However, if you know that you want a 50-column range reserved and you want the answers to go backward, this can still be achieved by placing the formula in the first of the 50 columns rather than the last, as I have proposed above.
I have a sheet like this how can make a cell in front of x under the sum column get the sum of the x count column and y get the sum y count column
of course, I use sum function on both but the issue I face is how to make the z ,x1,y1,z1 the same I try to fill it down but as you see in the picture it is wrong
how can I do it for 100 row ?
This formula seems to give the result you want:
={"Header","Sum";
ARRAY_CONSTRAIN(TRANSPOSE(D1:1),COUNTA(D1:1),1),
ARRAYFORMULA(MMULT(TRANSPOSE(N(D2:AJ10)),{SEQUENCE(ROWS(D2:AJ10),1,1,0)}))}
It places the two column labels in the first row, then transposes all of the header values into a vertical column in A2:A, but prevents any blank rows by using ARRAY_CONSTRAIN, and a check for the number of header values to transpose.
The main result is the Sums, calculated using MMULT. You need to enter the range of the cells you are going to sum over - I've used D2:AJ10, entered twice in the formula. MMULT can slow down performance the more cells it has to review, but this seemed fine for 33 columns by 9 rows. Test it out in your actual sheet, and report back if any issues.
REFERENCES:
ARRAY_CONSTRAIN To limit size of an array result, by # rows and # columns
MMULT The matrix product of two matrices. Can be used for summing, if one matrix is one dimensional (eg. a row or a column) with values of just 1.
I'm trying to count the number of empty cells that exist in a column between each non-empty cell but haven't been able to work out how.
Using this, I'm also trying to find the largest "empty distances" and locate the cell in the center of these distances.
The sheet I'm working with lists a set of marker colors and denotes the ones that are owned out of the full set of colors. I'm trying to find the largest ranges of missing colors and then find the colors in the middle of those ranges in order to find a handful of markers that would best help to fill out the spectrum.
Columns 1-6 are information- Column 7 marks whether the color is owned:
I may have an answer that helps you.
I could only get it to work using a helper column, but someone may know how to eliminate that requirement.
The helper column creates an array, basically listing the row numbers of the rows that have an "x" in your column B.
The main formula then measures the gap between each of these listed row numbers. It also checks the gap before the first "x", and after the last "x". Note that I have the data starting on row 2, which complicates the formula, but makes the sample sheet clearer - this can easily be changed to row 1 if you prefer.
={F2-1;
query(ArrayFormula(if(isnumber(F3:F),F3:F-F2:F-1,"")),
"select Col1 where Col1 > 0",0);
counta(A2:A)-indirect("F"&COUNTA(F$2:F))}
See a sample sheet here:
https://docs.google.com/spreadsheets/d/19QUFGRqTT6BqOsBrEBpTIxQCeNdRa5mzXhxQpCZ8sV4/edit?usp=sharing
Then I used a second formula to calculate the max gap between "x"s, (or before the first or after the last x).
Note that calculating the midpoint of the gaps, and doing a lookup of the corresponding mid-point colour, is something that can be added to this answer, if you share a sample copy of your sheet and share it for editing.
Let me know if this helps. I'll add more explanation to describe what the formula is doing tomorrow.
And I'll provide a second tab with the formulas adjusted to work with data beginning on row 1.
You can also get the lengths of the gaps using Frequency:
=ArrayFormula(frequency(if((B1:B20<>"X")*(A1:A20<>""),row(B1:B20)),if((B1:B20="X")*(A1:A20<>""),row(B1:B20))))
but finding the centres of the gaps and allowing for equal-sized gaps is more difficult.
This should find the position of the "X" at the end of the longest gap:
=ArrayFormula(
sum(frequency(if((B1:B20<>"X")*(A1:A20<>""),row(B1:B20)),
if((B1:B20="X")*(A1:A20<>""),row(B1:B20)))*(sequence(countif(B1:B20,"X")+1,1)<=
match(max(frequency(if((B1:B20<>"X")*(A1:A20<>""),row(B1:B20)),
if((B1:B20="X")*(A1:A20<>""),row(B1:B20)))),frequency(if((B1:B20<>"X")*(A1:A20<>""),row(B1:B20)),
if((B1:B20="X")*(A1:A20<>""),row(B1:B20))),0)))+
countif(sequence(countif(B1:B20,"X")+1,1),"<="&
match(max(frequency(if((B1:B20<>"X")*(A1:A20<>""),row(B1:B20)),
if((B1:B20="X")*(A1:A20<>""),row(B1:B20)))),frequency(if((B1:B20<>"X")*(A1:A20<>""),row(B1:B20)),
if((B1:B20="X")*(A1:A20<>""),row(B1:B20))),0))
)
and then it should just be a case of working backwards from there to the centre of the longest gap. However the formula needs further refinement to deal with the cases
(1) Where the longest gap is after the last "X"
(2) Where there is a tie for the longest gap
(3) Where there is a need to list the longest, second longest, third longest gap etc.
Is there a way to delete empty cells in a given range and shift the column up to the desired display as shown below? Closest I came was
=ARRAYFORMULA({A1:C1; TRANSPOSE(SPLIT(TRANSPOSE(QUERY(A2:C,,999^99)), " "))})
which removes empty cells, but splits the first names and surnames into separate cells, which I have not figured out how to avoid. Pfa a made-up sample of current and desired displays:
Current Display
Desired Display
I'm new at this, but I came up with a bit of a brute force method, which may help you.
={
{(A1:C1)};
{FILTER(A2:A100,A2:A100<>"");indirect("N1:N" & 100-counta(A2:A100))},
{FILTER(B2:B100,B2:B100<>"");indirect("N1:N" & 100-counta(B2:B100))},
{FILTER(C2:C100,C2:C100<>"");indirect("N1:N" & 100-counta(C2:C100))}}
Assuming your data block is in columns A1:C100, this formula filters blank cells from each individual column, and then pads each column with blank cells at the bottom, to make the three arrays equal in length/dimension.
Note that in "100-counta(...", the 100 is the expected maximum length of your data column.
This could be calculated, and must be the same for all three columns.
Note also that the first array is horizontal (ends with a semi-colon), followed by the three columns, stacked beside each other (ends with a comma).
Here is a working example.
https://docs.google.com/spreadsheets/d/1MGaqqGrkmIliuAzEqxPtdEVZXWPN2K5W7jFFM-ZnwgE/edit?usp=sharing
If I missed something you were trying to achieve, let me know.
Also, I'm sure that there is a more elegant way to do this, or one not requiring the use of a block of "reserved" blank cells, but I couldn't think of that at the moment.
Edit: The formula as follows also works. But you need to remember to set the "100" value to be equal to the number of rows in your data block, since we pad the columns with the necessary number of blanks rows, after removing the blank cells in each column.
={
{(A1:C1)};
{FILTER(A2:A,A2:A<>"");indirect("N1:N" & 100-counta(A2:A))},
{FILTER(B2:B,B2:B<>"");indirect("N1:N" & 100-counta(B2:B))},
{FILTER(C2:C,C2:C<>"");indirect("N1:N" & 100-counta(C2:C))}}