How To Write - If Item Does Not Match Multiple Numbers - In Swift? - ios

Question

I have a grid of buttons 11 buttons x 7 buttons. I need to check the tags of the buttons that are not on the outside edge of the grid. My current solution is to exclude the tags that are on the outside edge. The buttons are in an outlet collection. So the tags I need to exclude are 0-10, 21, 32, 43, 54, 65, 76, 0, 11, 22, 33, 44, 55, 66-76.
How do you check if an item in an if-statement, that's inside of a for-loop, matches multiple numbers? You can see the code below will become a mess if I play it out with 28 different || conditions. The numbers I'm trying to match are not in sequence.
for item in buttonOutlets {
if item.tag != 0 || item.tag != 1 || item.tag != 2 {
var tag = item.tag
var tagMinusOne: Int? = Int(item.tag) - 1
var tagMinusTen: Int? = Int(item.tag) - 10
var tagMinusEleven: Int? = Int(item.tag) - 11
var tagMinusTwelve: Int? = Int(item.tag) - 12
var titleLabel = item.titleLabel?.text
var minusTwelve: String? = buttonOutlets[tagMinusTwelve!].titleLabel?.text!
var minusOne: String? = buttonOutlets[tagMinusOne!].titleLabel?.text!
}
}
Here is what works but is a mess. Note that the tags are not in a perfect range. Updated code:
func checkForMatchingCells() {
for item in buttonOutlets {
var tag = item.tag as Int
if tag != 0
&& tag != 1
&& tag != 2
&& tag != 3
&& tag != 4
&& tag != 5
&& tag != 6
&& tag != 7
&& tag != 8
&& tag != 9
&& tag != 10
&& tag != 11
&& tag != 12
&& tag != 33
&& tag != 44
&& tag != 55
&& tag != 21
&& tag != 32
&& tag != 43
&& tag != 54
&& tag != 65
&& tag != 66
&& tag != 67
&& tag != 68
&& tag != 69
&& tag != 70
&& tag != 71
&& tag != 72
&& tag != 73
&& tag != 74
&& tag != 75
&& tag != 76 {
println(tag)
var tagMinusOne: Int? = Int(item.tag) - 1
var tagMinusTen: Int? = Int(item.tag) - 10
var tagMinusEleven: Int? = Int(item.tag) - 11
var tagMinusTwelve: Int? = Int(item.tag) - 12
var titleLabel = item.titleLabel?.text
var minusTwelve: String? = buttonOutlets[tagMinusTwelve!].titleLabel?.text
var minusOne: String? = buttonOutlets[tagMinusOne!].titleLabel?.text
println(minusOne)
}
}

Answer 1

I can think of two ways. First is with ClosedIntervals:
(0...10).contains(3) // true
Or if you have more complex numbers, you can use contains methods on other CollectionTypes:
Set([2, 5, 8]).contains(5) // true
Although I'm not sure what you're trying to do. (The statement x != 0 || x != 1 || x != 2 will return true for every number, for example. Maybe you meant x != 0 && x != 1 && x != 2?)
With your edit, the most effecient solution is to create a Set of things you want to exclude:
var toExclude: Set = [21, 32, 43, 54, 65, 76, 0, 11, 22, 33, 44, 55]
toExclude.unionInPlace(0...10)
toExclude.unionInPlace(66...76)
And then the condition in your if statement would be:
if !toExclude.contains(item.tag) {...