Can anyone help me to achieve this kind of animated transformation through Core Graphics. Look at the rough sketch:
This is a simple chart graphic, and I need to transform a histogramm-style bar (left shape) to a pie chart (right shape).
Literally the task is to roll a rectangle to a ring with a smooth animation. I almost found the way to do this with a tricky queue of drawings, mask clippings and affine transformations but this won't look exactly how I want it to look.
This is an interesting challenge, especially as you want to maintain the different segments. I won't give you a full answer (i.e full example code to achieving this), but I will explain what I think needs to be done to achieve the effect that you want.
Paths
First, I see both of these diagrams as a single line that is stroked (let's ignore the segments for a moment), so the challenge is going from a straight line to an enclosed circle.
I propose the following two paths, that you can animate between to achieve a nice wrapping effect.
// As we render a circle as a chain of straight line segments
// changing the count of said segments makes the circle more or less smooth
// Try this with other values, such as 8 or 32
let segments = 72
// With this segment count, the angle of each segment in the circle is
let angle = (2 * CGFloat(M_PI)) / CGFloat(segments)
// First path (straight)
let length = CGFloat(300.0)
let segmentLength = length / CGFloat(segments)
let straightPath = CGPathCreateMutable()
CGPathMoveToPoint(straightPath, nil, 0.0, 0.0)
for i in 0...segments {
CGPathAddLineToPoint(straightPath, nil, 0.0, CGFloat(i) * segmentLength)
}
// Second path (circle)
let radius = CGFloat(100.0)
let center = CGPoint(x: 104.0, y: 104.0)
let space = (x: 2.0, y: 2.0)
var circlePath = CGPathCreateMutable()
CGPathMoveToPoint(circlePath, nil, center.x + radius, center.y)
for i in 0...segments {
let x = cos(-CGFloat(i) * angle)
let y = sin(-CGFloat(i) * angle)
CGPathAddLineToPoint(circlePath, nil, center.x + radius * x, center.y + radius * y)
}
I have also uploaded a Swift plaground for you to experiment with, which you can find here
Segments
Now, handling the segments can be a bit tricky, however I propose a relatively naive implementation that might work. Mainly, CAShapeLayer has the following two properties - strokeStart and strokeEnd, which allow controlling the part of the path that is actually stroked.
With this in mind, you could create as many layers as there are segments, assign them all the same path(s) and tweak their respective strokeStart and strokeEnd properties to make it look the way you expect. Somewhat similar to what they do in this post.
Animation
Assuming you have conquered the previous two aspects, the animation aspect should be relatively straight forward, using the two types of paths you have, you can create a simple CABasicAnimation that goes from one to another. I will assume you are familiar with CoreAnimation and its usage (i.e how to properly change model values to match those that are presented etc.).
I will end my answer with a quick animation showing what the end result could look like (minus the segments), I have frozen the animation and am manipulating the timeOffset property of the layer to manually scrub through it.
I hope my answer helps you get closer to the solution you want. It is also important to emphasise that my code examples are just a beginning, you will likely need to tweak the values quite a bit to achieve a satisfying animation (for example, the length of the line should be similar to that of the circumference of the circle).
Skewing, twisting and bending are none trivial transformations on bodies.
These can't be done Core Graphics.
Better draw the chart yourself with CGContextAddArcToPoint in core graphic and mask out the inner circle.
The other (hardcore) way would be using a 3d engine - i.e. scene kit - and apply your chart as texture to it.
Related
Objective: There is a SCNCylinder object in my scene. I want to be able to drag one end of the cylinder and rotate the cylinder in any direction, while keeping the other end in the same position.
Currently, I am calling localRotate(by: SCNQuaternion) to first rotate the node, then calculate the position offset needed to move the cylinder so that the other end can go back to its original position.
How can I achieve the objective in one step instead of what I am doing now?
The pivot property is what you're looking for. Or, since modern SceneKit often works better / makes nicer Swift / interoperates easier with ARKit when you use SIMD types, the simdPivot property.
Note this bit in the docs:
Changing the pivot transform alters these behaviors in many useful ways. You can:
Offset the node’s contents relative to its position. For example, by setting the pivot to a translation transform you can position a node containing a sphere geometry relative to where the sphere would rest on a floor instead of relative to its center.
Move the node’s axis of rotation. For example, with a translation transform you can cause a node to revolve around a faraway point instead of rotating around its center, and with a rotation transform you can tilt the axis of rotation.
Similarly, for a cylinder, you can make its pivot a transform matrix that translates the origin by half its height, giving it an "anchor point" (for position and rotation changes) at one end instead of in the center. Something like this (untested):
let cylinder = SCNCylinder(radius: /*...*/, height: /*...*/)
let cylinderNode = SCNNode(geometry: cylinder)
cylinderNode.simdPivot = float4x4(translation: cylinder.height / 2)
extension float4x4 {
init(translation vector: float3) {
self.init(float4(1, 0, 0, 0),
float4(0, 1, 0, 0),
float4(0, 0, 1, 0),
float4(vector.x, vector.y, vector.z, 1))
}
}
More generally, whenever you're using a scene-graph / transform-hierarchy based graphics framework, any time you find yourself doing math depending on one transform (rotation, translation, etc) to affect another, it's always good to check for API that can do that math for you — because doing that kind of math is what transform hierarchy is all about.
And if there's not an API fairly specific to what you need, remember that the hierarchy itself is good for making dependent transforms. For example, if you want one node to follow a circular orbit around another, you don't need to set its position using sines and cosines... just make it the child of another node, and rotate that other node.
In this case, pivot is a convenience equivalent to using the node hierarchy. You could just as well create an intermediate node and move the cylinder within it (something like this):
let cylinder = SCNCylinder(radius: /*...*/, height: /*...*/)
let cylinderNode = SCNNode(geometry: cylinder)
let offsetNode = SCNNode()
offsetNode.addChildNode(cylinderNode)
cylinderNode.simdPosition.y = cylinder.height / 2
offsetNode.position = /*...*/ // set world-space position of end of cylinder
offsetNode.eulerAngles.x = /*...*/ // rotate cylinder around its end
I experienced that for some NSBezierPaths SCNShape seems to be unable to draw a shape.
The path is created only using line(to:).
//...set up scene...
//Create path (working)
let path = NSBezierPath()
path.move(to: CGPoint.zero)
path.line(to: NSMakePoint(0.000000, 0.000000))
path.line(to: NSMakePoint(0.011681, 0.029526))
// more points ...
path.close()
// Make a 3D shape (not working)
let shape = SCNShape(path: path, extrusionDepth: 10)
shape.firstMaterial?.diffuse.contents = NSColor.green
let node = SCNNode(geometry: shape)
root.addChildNode(node)
For verifying that the general process of creating a SCNShape is correct, I also drew a blue shape that only differs by having different points. The blue shape gets drawn, the green shape doesn't.
You can find a playground containing the full example here. In the example you should be able to see a green and a blue shape in assistant editor. But only the blue shape gets drawn.
Do you have any idea why the green shape is not shown?
The short story: your path has way more points than it needs to, leading you to unexpected, hard to find geometric problems.
Note this bit in the documentation:
The result of extruding a self-intersecting path is undefined.
As it turns out, somewhere in the first 8 or so points, your "curve" makes enough of a turn the wrong way that the line closing the path (between the first point in the path 0,0, and the last point 32.366829, 29.713470) intersects the rest of the path. Here's an attempt at making it visible by excluding all but the first few points and the last point from a playground render (see that tiny little zigzag in the bottom left corner):
And at least on some SceneKit versions/renderers, when it tries to make a mesh out of a self-intersecting path it just gives up and makes nothing.
However, you really don't need that many points to make your path look good. Here it is if you use 1x, 1/5x, and 1/10x as many points:
If you exclude enough points overall, and/or skip the few at the beginning that make your curve zag where it should zig, SceneKit renders the shape just fine:
Some tips from diagnosing the problem:
When working with lots of coordinate data like this, I like to use ExpressibleByArrayLiteral so I can easily build an array of lots of points/vectors/etc:
extension CGPoint: ExpressibleByArrayLiteral {
public init(arrayLiteral elements: CGFloat...) {
precondition(elements.count == 2)
self.init(x: elements.first!, y: elements.last!)
}
}
var points: [CGPoint] = [
[0.000000, 0.000000],
[0.011681, 0.029526],
// ...
]
That gets me an array (and a lot less typing out things like NSPointMake over and over), so I can slice and dice the data to figure out what's wrong with it. (For example, one of my early theories was that there might be something about negative coordinates, so I did some map and min() to find the most-negative X and Y values, then some more map to make an array where all points are offset by a constant amount.)
Now, to make paths using arrays of points, I make an extension on NSBezierPath:
extension NSBezierPath {
convenience init(linesBetween points: [CGPoint], stride: Int = 1) {
precondition(points.count > 1)
self.init()
move(to: points.first! )
for i in Swift.stride(from: 1, to: points.count, by: stride) {
line(to: points[i])
}
}
}
With this, I can easily create paths from not just entire arrays of points, but also...
paths that skip parts of the original array (with the stride parameter)
let path5 = NSBezierPath(linesBetween: points, stride: 5)
let path10 = NSBezierPath(linesBetween: points, stride: 10)
(This is handy for generating playground previews a bit more quickly, too.)
paths that use some chunk or slice of the original array
let zigzag = NSBezierPath(linesBetween: Array(points.prefix(to:10)) + [points.last!])
let lopOffBothEnds = NSBezierPath(linesBetween: Array(points[1 ..< points.count < 1]))
Or both... the winning entry (in the screenshot above) is:
let path = NSBezierPath(linesBetween: Array(points.suffix(from: 10)), stride: 5)
You can get a (marginally) better render out of having more points in your path, but an even better way to do it would be to make a path out of curves instead of lines. For extra credit, try extending the NSBezierPath(linesBetween:) initializer above to add curves by keeping every nth point as part of the path while using a couple of the intermediary points as control handles. (It's no general purpose auto trace algorithm, but might be good enough for cases like this.)
In no way does this compare to Rikster's answer, but there is another way to prevent this kind of problem. It's a commercial way, and there's probably freeware apps that do similar, but this is one I'm used to using, that does this quite well.
What is 'this' that I'm talking about?
The conversion of drawings to code, by an app called PaintCode. This will allow you to see your paths and be sure they have none of the conflicts that Rickster pointed out are your issue.
Check it out here: https://www.paintcodeapp.com/
Other options are listed in answers here: How to import/parse SVG into UIBezierpaths, NSBezierpaths, CGPaths?
I have built a circular graph very similar to this example in paintcode:
http://www.paintcodeapp.com/news/animating-apple-watch-activity-rings-in-paintcode
I have successfully drawn out the control on my iOS view with ease, but now I would like to animate the graph so that it begins at 0 and eases towards the specified angle. Basically the animation should look like the first two seconds of the video in the URL above.
What is the best way to go about this type of animation?
FYI: I am working in C#/Xamarin but I am not fussy on syntax at all, so an Objective C or Swift example will do just fine.
I wrote a UIView subclass which does exactly what you're asking for. You just provide an array of rings along with a few other parameters, and it handles all of the setup and management for you.
https://github.com/lionheart/ConcentricProgressRingView
At the top of your UIViewController, import the module:
import ConcentricProgressRingView
Then, in your viewDidLoad:
let rings = [
ProgressRing(color: UIColor.redColor()),
ProgressRing(color: UIColor.blueColor()),
]
let margin: CGFloat = 2
let radius: CGFloat = 80
let progressRingView = ConcentricProgressRingView(center: view.center, radius: radius, margin: margin, rings: rings, defaultWidth: 20)
view.addSubview(progressRingView)
Once you've instantiated your ConcentricProgressRingView instance, animate a specific ring to a percentage with setProgress.
ring.arcs[1].setProgress(0.5, duration: 2)
Under the hood, this just uses CABasicAnimation and sets a few parameters which make it look "right". I know you're not using Swift, but if you want specific pointers, just check out the source code to see how I've solved it. Hope this helps!
You want to use CAShapeLayers, one for each arc, with a full-circle arc installed in each one, and the line cap style set to rounded.
Then you want to set the strokeEnd property to a small value (try .05). That will cause the shape to only draw 5% of it's arc.
Finally you want to submit CAAnimations to each shape layer that animate the strokeEnd value from the starting value to 1.0. That will animate the arcs drawing the full circle.
I don't have any ready-made sample code for you. I do have a sample project written in Objective-C that uses a very similar technique to create a "clock wipe" animation using a CAShapeLayer as a mask layer.
Take a look at the clock wipe animation in the project "iOS CAAnimationGroup demo" project on Github.
I would like draw a curved line and attach an object to it. Is it possible to create fraction (from 0.0 to 1.0) which makes move my object on the path? When fraction is 0 then object is on the beginning, when 0.5 is on half way and finally when is on 1.0 it is at the end. Of course i want a curved path, not a straight line :) Is it possible to do in PaintCode?
If you need it only as a progress bar, it is possible in PaintCode. The trick is to use dashed stroke with very large Gap and then just change the Dash.
Then just attach a Variable and you are done.
Edit: Regarding the discussion under the original post, this solution uses points as the unit, so it will be distributed equally along the curve, no matter how curved the bezier is.
Based on the fact that you're going to walk along the curve using linear distance, a thing Bezier curves are terrible for, you need to build the linear mapping yourself. That's fairly simple though:
When you draw the curve, also build a look-up table that samples the curve once, at say 100 points (t=0, t=0.01, t=0.02, etc). In pseudocode:
lut = [];
lut[0] = 0;
tlen = curve.length();
for(v=0; v<=100; v++) {
t = v/100;
clen = curve.split(0,t).length();
percent = 100*clen/tlen;
lut[percent] = t;
}
This may leave gaps in your LUT - you can either fix those as a secondary step, or just leave them in and do a binary scan on your array to find the nearest "does have a value" percentage.
Then, when you need to show your progress as some percentage value, you just look up the corresponding t value: say you need to show 83%, you look up lut[83] and draw your object at the value that gives you.
The picture shows a simple UIView after applying the following transform:
- (CATransform3D) transformForOpenedMenu
{
CATransform3D transform = CATransform3DIdentity;
transform.m34 = -1.0 /450;
transform = CATransform3DRotate(transform, D2R(40), 0, 1, 0);
transform = CATransform3DTranslate(transform, 210, 150, -500);
return transform;
}
I'm trying to make the distances highlighted with black to have equal length. Could you please help me understand the logic behind the values and calculations?
Cheers
UPD Sept 13
Looks like removing 3DTranslate keeps distances equal. I see I can use layer's frame property to reposition rotated view to the bottom left of the screen. Not yet sure, but this might actually work.
The .m34 value you are setting is best set on the sublayerTransform of the containing view rather than the view you are transforming.
I don't fully understand the maths behind affine transforms so I made this project which allows me to play around with the transform values to achieve the effect I want. You can plug in the values from your code above and see what it looks like, though note that there is already a perspective value applied using the sublayerTransform property mentioned above.
For your specific case, I think you want to adjust the anchor point of the layer to (0.0,0.5) and apply the rotation transform only. This assumes you want the menu to swing back like a door, with the hinges on the left edge.
The problem you're seeing is caused by your CATransform3DTranslate call. You're essentially setting the Y Axis off center, and hence seeing a different perspective view of the frame.
Think of it this way;
You're standing in the center of a long narrow field stretching off into the horizon. The edge of the field appears as if it is converges to a center point somewhere off in the distance. The angle of each edge to the converging point will appear equal if you are at the center of the field. If, on the other hand, you move either to the left or the right, the angles change and one will seem greater than the other (inversely opposite of course).
This is essentially what is happening with your view; As your converging points are to the right, changing the Y axis away from 0 will have the same effect as moving to the left or right in my example above. You're no longer looking at the parallel lines from the center.
so in your code above Setting the ty in CATransform3DTranslate to 0 Should fix your problem I.E.
transform = CATransform3DTranslate(transform, 210, 0, -500);
You may also need to alter the tz and tx Value to make it fit.
OK, so what eventually solved my question is this:
3D transform on Y axis to swing the view like a door transform = CATransform3DRotate(transform, D2R(40), 0, 1, 0);
set Z anchor point on a layer, to move it back targetView.layer.anchorPointZ = 850;
adjust layer position so that the view is located slightly to the bottom left of the parent view:
newPosition.x += 135 * positionDirection;
newPosition.y += 70 * positionDirection;
This sequence adjusts position without CATransform3DTranslate and keeps the 'swinged' effect not distorted.
Thanks everybody!