I have a Cisco ASA 8.4 VPN Concentrator. I am trying to use Lua to extract digits from a certificate string coming in and use them in a LDAP lookup with AD for authorization. I found a string that works...sometimes.
The string comes in with the format:
LAST_NAME.FIRST_NAME.MIDDLE_NAME.1234567890
My LDAP only wants to see the digits and #domainname. The script I am currently us is: return string.gsub(cert.subject.cn, "^(%w+)%.(%w+)%.(%w+)%.(%w+)$", "%4#domain")
This script works fine in most cases (80-90% of the time). When it doesn't work is when people have no middle name, 4 names instead of 3, etc.
My question is how can I get it to output only the 10 digits, regardless of what comes before it. Seems too easy with a return string.match, but so far I can't get it to work. Any ideas?
You can use the pattern .*(%d%d%d%d%d%d%d%d%d%d)$:
local str = 'LAST_NAME.FIRST_NAME.MIDDLE_NAME.1234567890'
print(str:match('.*(' .. ('%d'):rep(10) .. ')$'))
or .*(%d+)$ if the number of digits is always 10.
If the 10 digits is always the last 10 characters, this works:
print(str:sub(-10, -1))
Related
I've been looking for a good way to see if a string of items are all numbers, and thought there might be a way of specifying a range from 0 to 9 and seeing if they're included in the string, but all that I've looked up online has really confused me.
def validate_pin(pin)
(pin.length == 4 || pin.length == 6) && pin.count("0-9") == pin.length
end
The code above is someone else's work and I've been trying to identify how it works. It's a pin checker - takes in a set of characters and ensures the string is either 4 or 6 digits and all numbers - but how does the range work?
When I did this problem I tried to use to_a? Integer and a bunch of other things including ranges such as (0..9) and ("0..9) and ("0".."9") to validate a character is an integer. When I saw ("0-9) it confused the heck out of me, and half an hour of googling and youtube has only left me with regex tutorials (which I'm interested in, but currently just trying to get the basics down)
So to sum this up, my goal is to understand a more semantic/concise way to identify if a character is an integer. Whatever is the simplest way. All and any feedback is welcome. I am a new rubyist and trying to get down my fundamentals. Thank You.
Regex really is the right way to do this. It's specifically for testing patterns in strings. This is how you'd test "do all characters in this string fall in the range of characters 0-9?":
pin.match(/\A[0-9]+\z/)
This regex says "Does this string start and end with at least one of the characters 0-9, with nothing else in between?" - the \A and \z are start-of-string and end-of-string matchers, and the [0-9]+ matches any one or more of any character in that range.
You could even do your entire check in one line of regex:
pin.match(/\A([0-9]{4}|[0-9]{6})\z/)
Which says "Does this string consist of the characters 0-9 repeated exactly 4 times, or the characters 0-9, repeated exactly 6 times?"
Ruby's String#count method does something similar to this, though it just counts the number of occurrences of the characters passed, and it uses something similar to regex ranges to allow you to specify character ranges.
The sequence c1-c2 means all characters between c1 and c2.
Thus, it expands the parameter "0-9" into the list of characters "0123456789", and then it tests how many of the characters in the string match that list of characters.
This will work to verify that a certain number of numbers exist in the string, and the length checks let you implicitly test that no other characters exist in the string. However, regexes let you assert that directly, by ensuring that the whole string matches a given pattern, including length constraints.
Count everything non-digit in pin and check if this count is zero:
pin.count("^0-9").zero?
Since you seem to be looking for answers outside regex and since Chris already spelled out how the count method was being implemented in the example above, I'll try to add one more idea for testing whether a string is an Integer or not:
pin.to_i.to_s == pin
What we're doing is converting the string to an integer, converting that result back to a string, and then testing to see if anything changed during the process. If the result is =>true, then you know nothing changed during the conversion to an integer and therefore the string is only an Integer.
EDIT:
The example above only works if the entire string is an Integer and won’t properly deal with leading zeros. If you want to check to make sure each and every character is an Integer then do something like this instead:
pin.prepend(“1”).to_i.to_s(1..-1) == pin
Part of the question seems to be exactly HOW the following portion of code is doing its job:
pin.count("0-9")
This piece of the code is simply returning a count of how many instances of the numbers 0 through 9 exist in the string. That's only one piece of the relevant section of code though. You need to look at the rest of the line to make sense of it:
pin.count("0-9") == pin.length
The first part counts how many instances then the second part compares that to the length of the string. If they are equal (==) then that means every character in the string is an Integer.
Sometimes negation can be used to advantage:
!pin.match?(/\D/) && [4,6].include?(pin.length)
pin.match?(/\D/) returns true if the string contains a character other than a digit (matching /\D/), in which case it it would be negated to false.
One advantage of using negation here is that if the string contains a character other than a digit pin.match?(/\D/) would return true as soon as a non-digit is found, as opposed to methods that examine all the characters in the string.
I have been looking around and have read a lot of different answers but none seems to answer my specific request.
I make watchfaces for Wear OS 2 with an app called ''WATCHMAKER'' witch uses LUA as language. I want to make a watch face with a special clock pointing to a number depending on a blood sugar value sent by an transmitter connected to the body.
The string values I want to parse follows this syntax:
<DECIMAL NUMBER> <ARROW> (<TIME>)
One example would be
5,6 -> (1m)
I want to extract the <DECIMAL NUMBER> part of the reading. In the above example, I want the value 5,6.
Every 5 minutes, the transmitter sends another reading, all of those informations change:
5,8 - (30 secondes)
Thank you so much
Say you have a string, in LUA, s="14,11 -> (something)" and you want this first number of the string to be parsed to a float so you can do maths on it.
s='9,6 -> (24m)'
-- Now we use so called regular expressions
-- to parse the string
new_s=string.match(s, '[0-9]+,[0-9]+')
-- news now has the number 9,6. Which is now parsed
-- however it's still a string and to be able to treat
-- it like a number, we have to do more:
-- But we have to switch the comma for a period
new_s=new_s:gsub(",",".")
-- Now s has "9.6" as string
-- now we convert it to a number
number = string.format('%.10g', tonumber(new_s))
print(number)
Now number contains the number 9.6.
I need to be able to print Hebrew characters on my Epson TM-T20ii. I am trying to get my printer to switch to character code page 36(PC862) using
ESC t36
for some reason the printer is switching to code page 3 and then printing the number 6.
Is there a way to let the printer know that the 6 is part of my command?
If you know of a different workaround please comment below.
Thanks
You are making a mistake, you aren't meant to replace n with an actual number.
The proper syntax in your case would be ←t$
Explanation: the manual says "ESC t n", n referring to the page sheet, however you don't replace n with a number rather with the ASCII character n, so in your example 36 = $ because $ is the 36th character on the ASCII table.
If i have a string like "123123123" - Here 123 is repeated 3 times.
1. So how can i get only "123" in ruby?
2. So if the string is "12312312" - Here 123 is repeated 2 times and then just 12, so here still i need to get "123".
3. Even if string is 99123123123, still i need to get 123.
Is this possible in Ruby Regex?
EDIT: I want this to solve Project Euler Problem 26 . So here 123 can be anything. All i want is to extract 1 number of at-least 2 repeated numbers.
This regex will detect all repeating groups.
(\d+)(?=.*\1)
Demo
Works great with ruby too.
result = '9912341234123'.scan(/(\d+)(?=.*\1)/)
#gets group with largest length
longestRepeatingGroup = result.max_by{|arr| arr[0].length}
puts longestRepeatingGroup
puts longestRepeatingGroup[0].length
Try this
99123123123.scan(/123/).count
12312312.scan(/123/).count
I am using Yahoo Pipes to rewrite a URL. Everything is fine but the last 6 characters of the URL need to be removed from all the links.
Ex.
http://www.mysite.com/blahblah/34567
needs to be rewritten to
http://www.mysite.com/blahblah
The number at the end is always changing, so I am hoping to just chop the last 6 characters off of each url.
You'll want the Sub string module. Presuming it functions in a similar way to other languages, you'll want an undefined From value, and a Length value of -6, which should cut 6 characters off the end of the URL.
Seems that a regex in (.*)(.....) and takinq only the first match should do the trick