I am trying to create a new Property File with the below snippet of Ant script.
<propertyfile file="${path}/sample.properties">
<entry key="k1" value="v1"/>
</propertyfile>
It tries create the property file and I get the below error
(The system cannot find the path specified). Here the path includes the file name as well. I confirmed the parent folder where the property files needs to be created exists.
I created a build file with your snippet and couldn't see an issue. If the directory specified by the path property doesn't exist an exception is thrown but this seems like the correct behaviour.
I suggest you add some tests to confirm the actual value of the path property. Maybe it doesn't hold the value you expect.
build.xml
<project>
<property name="path" value="./test"/>
<propertyfile file="${path}/sample.properties">
<entry key="k1" value="v1"/>
</propertyfile>
</project>
Test Case 1 - 'test' directory not present - expected result FAIL
$ ls test
ls: cannot access test: No such file or directory
$ ant build.xml
Buildfile: /home/owen/stackoverflow/build.xml
[propertyfile] Creating new property file: /home/owen/stackoverflow/test/sample.properties
BUILD FAILED
/home/owen/stackoverflow/build.xml:3: java.io.FileNotFoundException: /home/owen/stackoverflow/test/sample.properties (No such file or directory)
Total time: 0 seconds
Test Case 2 - 'test' directory now available - expected result SUCCESS
$ mkdir test
$ ant
Buildfile: /home/owen/stackoverflow/build.xml
[propertyfile] Creating new property file: /home/owen/stackoverflow/test/sample.properties
BUILD SUCCESSFUL
Total time: 0 seconds
EDIT: Sorry didn't read the section mentioning that the parent folder exists. For me the given snippet works (in Eclipse). What does your path variable contains and which environment you use exactly ?
All folders specified by your path variable must exist before Ant can create the property file, even before any target is executed.
Related
I've looked at both these posts.. they don't help:
PHP build for Jenkins failing with 'Cannot run program "phploc"'
Cannot run phploc installed through composer
If I run phploc at a shell prompt, it works just fine. So it must be something with my build.xml file... but I don't know what.
<target name="phploc" description="Measure project size using PHPLOC">
<exec executable="phploc">
<arg path="${basedir}/../src" />
<arg value="--log-csv" />
<arg value="${basedir}/build/logs/phploc.csv" />
</exec>
</target>
This works fine:
C:\projects\project1\build>phploc ../src
phploc 2.0.6 by Sebastian Bergmann.
My folder structure is
c:\projects\project1
build
...
vendor
bin
...
src
tests
c:\projects\project1\build>ant
phploc:
BUILD FAILED
C:\projects\project1\build\build.xml:55: Execute failed: java.io.IOException:
Cannot run program "phploc": CreateProcess error=2, The system cannot find the
file specified
at java.lang.ProcessBuilder.start(ProcessBuilder.java:1048)
at java.lang.Runtime.exec(Runtime.java:620)
at org.apache.tools.ant.taskdefs.launcher.Java13CommandLauncher.exec(Jav
UPDATE
C:\>where phploc
INFO: Could not find files for the given pattern(s).
What am I missing?
From chat discussion, it came out to be a PATH related issue. That's exactly what I was thinking it to be.
Setting absolute path of phploc in <exec executable="phploc"> did the trick. It was working on command line from C:\projects\project1\build directory because phploc was in one of its sub-directory (vendor\bin) and this sub-directory was already in the PATH variable.
PATH=C:\Windows;C:\Windows\System32\Wbem;C:\Windows\System32\WindowsPowerShell\v1.0\;C:\Program Files (x86)\Calibre2\;C:\xampp\php;C:\ProgramData\ComposerSetup\bin;C:\Program Files (x86)\IDM Computer Solutions\UltraEdit\;C:\Program Files (x86)\Java;c:\ant\bin;.\vendor\bin
Note: Although providing absolute path worked here but it's a good practice to use relative path so that your project is portable. In this case, you could use basedir as the reference point for all relative paths.
I'd like to create a temporary directory in ant (version 1.6.5) and assign it to a property.
The command "mktemp -d" would be ideal for this, but I cannot find similar functionality from inside ant
I can't find any official function in the docs apart from the tempfile task which apparently only creates files, not directories.
I'm considering using exec to call tempfile and get the result, however this will make my build.xml dependent on UNIX/linux, which I'd like to avoid.
Background: I'm trying to speed up an existing build process which builds inside networked filesystem. The build already copies all the source to a temporary directory, however this is on the same filesystem. I've tested changing this to /tmp/foo and it gives a worthwhile speed increase: 3mins vs 4mins.
You could combine the tempfile task with the java.io.tmpdir system property to get a file path to use to create a temporary dir:
<project default="test">
<target name="test">
<echo>${java.io.tmpdir}</echo>
<tempfile property="temp.file" destDir="${java.io.tmpdir}" prefix="build"/>
<echo>${temp.file}</echo>
</target>
</project>
Note that the tempfile task does not create the file (unless you ask it to). It just sets a property which you can use to create a file or dir.
This task sets a property to the name of a temporary file. Unlike
java.io.File.createTempFile, this task does not actually create the
temporary file, but it does guarantee that the file did not exist when
the task was executed.
Output in my environment:
test:
[echo] C:\Users\sudocode\AppData\Local\Temp\
[echo] C:\Users\sudocode\AppData\Local\Temp\build1749402932
The answer above only hints at how to create a temporary directory. The point is that merely returns a string. A more complete answer is
<target name="temptest" description="test making tempdir">
<tempfile property="mytempdir" destdir="${java.io.tmpdir}"/>
<tempfile property="mytempfile" destdir="${mytempdir}"/>
<tstamp>
<format property="now" pattern="MMMM dd yyyy"/>
</tstamp>
<copy tofile="${mytempfile}">
<string value="today=${now}"/>
</copy>
<property file="${mytempfile}"/>
<echo message="It it now ${today}"/>
</target>
I am trying to create a rpm package using ant task for that I need to create specfile which will have all the file names in the following format
%attr(0755, root, root) %dir dir1
%attr(0755, root, root) %dir dir1/dir2
%attr(0755, root, root) %dir dir1/dir2/dir3
%attr(0500, root, root) dir1/file1
%attr(0500, root, root) dir1/dir2/file1
I have such directory structure created during my build process but using ant I am not able to list all the files and directories which I can then write into my specfile
following is what I have tried to list the files but it does not differentiate between files and directory , moreover I need some way to iterate over the list.
<fileset id="dist.contents" dir="${nativePackageDir}" includes="**"/> |
<property name="prop.dist.contents" refid="dist.contents"/> | <target name="javaobject-library" depends="props">
<echo>${prop.dist.contents}</echo>
<dirset id="dist.contents" dir="${nativePackageDir}" includes="*"/>
<property name="prop.dist.contents" refid="dist.contents"/>
<echo>${prop.dist.contents}</echo>
Using dirset instead of fileset should fix your problem.
You simply have to write in java an ant task implementation, to which you'll provide as parameters the input directory and the path of the specfile you want to be written.
I find it better and more manageable to have reusable ant tasks in java, instead of having gigantic ant xml files.
I don't want to get the basedir -- that appears to contain the build.xml script -- I want the CWD of the call to ant itself.
Basically, I want to do this:
$ cd /home/chrisr/projects/some_project
$ ant -f ../../tools/ant-build-rules/library.xml build-library
At this point, I need two things:
The path to ant-build-rules in absolute form; this is currently found in the basedir property, so I'm set there.
The path of some_project, in absolute form. This is what I don't know how to get.
Which property contains this information?
The java property user.dir contains the current directory
<project name="demo" default="printCWD">
<target name="printCWD">
<echo message="${user.dir}"/>
</target>
</project>
There is no such property, but you can run a script to get it.
${bsh:WorkDirPath.getPath()}
See urbancode.com.
I am trying to invoke an ANT target from Windows (right-click) file context menu.
I have setup the registry entries to invoke a batch script which invokes my ANT EXEC target.
I need to pass the path of the file (on which user right-clicked) to my ANT target. So I am using %~dp1 to set an ANT properties in my bat script:
Set tobeusedfilepath=%~dp1
Set tobeusedfile=%~n1
resulting in:
tobeusedfilepath=D:\Project\Rel L\
tobeusedfile=file
The problem is %~dp1 returns a string with "\" as file separator. But ANT EXEC task wants "/"
[exec] '-source'
[exec] 'D:ProjectRel L/file'
[exec] ......
[exec] The file, 'D:ProjectRel L/file', does not exist.
Any suggestions how to get around this path separators?
set AntPath="D:\Project\Rel L\"
set AntPath=%AntPath:\=/%
set AntPath=%AntPath::/=:%
gives
set AntPath="D:\Project\Rel L\"
set AntPath="D:/Project/Rel L/"
set AntPath="D:Project/Rel L/"
If you are running on Windows Ant will happily accept OS directory separator which is \.
Upon examination of the output of your program I see that the path separators are missing: you have D:ProjectRel not D:\Project\Rel. I may only guess that you are trying to exec a Cygwin program. Cygwin programs will use \ as an escape character. Therefore you need to use a <pathconvert> property to adjust the directory separators.
Code snippet below illustrates how to do this
<property name="tobeusedfilepath" location="D:\Project\Rel L\"/>
<property name="tobeusedfile" value="file"/>
<property name="system-path-filename"
location="${tobeusedfilepath}/${tobeusedfile}"
/>
<pathconvert property="unixized-filename" targetos="unix">
<path location="${system-path-filename}"/>
</pathconvert>
<echo message="system-path-filename=${system-path-filename}"/>
<echo message="unixized-filename=${unixized-filename}"/>
And here is the output of this run:
[echo] system-path-filename=D:\Project\Rel L\file
[echo] unixized-filename=D:/Project/Rel L/file