I am trying to find out how can I read from a file, for example test environment.
The file contains:
test_env1 = "http://test.com"
test_env2 = "http://test2.com"1
Is possible to read from this file for test_env1 to visit the assigned URL.
Related
I wants to read a excel file existing on Live URL of another website.
When I hit that URL in browser file is downloading. While in my rails app it is giving below error
No such file or directory # rb_sysopen - http://www.carsa.jp/admin/data.xlsx (Errno::ENOENT)
My Rails app code is as below
data = Roo::Excelx.new('http://www.carsa.jp/admin/data.xlsx')
header = data.row(1)
puts header
Note: If I download file and place it within my application it is working fine but the requirement is to read it from the third-party website in a scheduled job as per the above script.
data = Roo::Excelx.new('lib/data.xlsx')
header = data.row(1)
puts header
Try using Roo::Spreadsheet.open instead of Roo::Excelx.new. According to the Roo Readme:
Roo::Spreadsheet.open can accept both paths and File instances.
This should do the trick:
Roo::Spreadsheet.open('http://www.carsa.jp/admin/data.xlsx')
How do I replace the new File method with a secure one? Is it possible to create a python script and connect it?
Part of the code where I have a problem:
def template Name = new File(file: "${template}").normalize.name.replace(".html", "").replace(".yaml", "")
But when I run my pipeline, I get the error
java.lang.SecurityException: Unable to find constructor: new java.io .File java.util.LinkedHashMap
This method is prohibited and is blacklisted. How do I replace it and with what?
If you're reading the contents of the file, you can replace that "new File" with "readFile".
See https://www.jenkins.io/doc/pipeline/steps/workflow-basic-steps/#readfile-read-file-from-workspace
readFile: Read file from workspace
Reads a file from a relative path (with root in current directory, usually > workspace) and returns its content as a plain string.
file : String
Relative (/-separated) path to file within a workspace to read.
encoding : String (optional)
The encoding to use when reading the file. If left blank, the platform default encoding will be used. Binary files can be read into a Base64-encoded string by specifying "Base64" as the encoding.
I'd like to create a file object from an image located at a specific url. I'm downloading the file with Net Http:
img = Net::HTTP.get_response(URI.parse('https://prium-solutions.com/wp-content/uploads/2016/11/rails-1.png'))
file = File.read(img.body)
However, I get ArgumentError: string contains null byte when trying to read the file and store in into the file variable.
How can I do this without having to store it locally ?
Since File deals with reading from storage, it's really not applicable here. The read method is expecting you to hand it a location to read from, and you're passing in binary data.
If you have a situation where you need to interface with a library that expects an object that is streaming, you can wrap the string body in a StringIO object:
file = StringIO.new(img)
# you can now call file.read, file.seek, file.rewind, etc.
I am having some trouble writing a file to a specific path taking the file name from excel. Here is the code which I am using
out_file = File.new (#temp_path/ "#{obj_info[3].to_s}","w")
"#{obj_info[3].to_s}" = sample.txt
The value sample.txt comes from Excel during run time
#temp_path = "C:/Users/Somefolder/"
The error displayed is:
NoMethodError: undefined method `[]' for nil:NilClass
However, if the code is:
out_file = File.new ("#{obj_info[3].to_s}","w")
it successfully creates a file called sample.txt in the default directory. However, I want it to be stored in a specific directory and the file name needs to be passed from Excel.
Any help is much appreciated.
I believe your problem is because there a space between / and "
#temp_path/ "#{obj_info[3].to_s}
and I guess you want to build a path.
My advice is that you use File.join
f_path = File.join(#temp_path,obj_info[3].to_s)
out_file = File.new (f_path,"w")
Let me know if that solved the problem
You have 2 problems:
obj_info is nil so you make an error reading the value from excel, the error you get indicates it is on an array, in the code you published the only thing that's an array is what you read from excel.
Print the contents with p obj_info right before your code to check.
#temp_path and {obj_info[3].to_s} need to be concatenated to make a path.
You can do that with File.join like Mauricio suggests or like this
out_file = File.new ("#{#temp_path}/#{obj_info[3]}","w")
You can drop the to_s in this case.
It would be better if you publish the whole of your script that is meaningful.
In my Hadoop Map Reduce application I have one input file.I want that when I execute the jar of my application, then the input file will automatically be called.To do this I code one class to specify the input,output and file itself but from where I am calling the file, there I want to specify the file path. To do that I have used this code:
QueriesTest.class.getResourceAsStream("/src/main/resources/test")
but it is not working (cannot read the input file from the generated jar)
so I have used this one
URL url = this.getClass().getResource("/src/main/resources/test") here I am getting the problem of URL. So please help me out. I am using Hadoop 0.21.
I'm not sure what you want to tell us with your resource loading, but the usual way to add an input file is this:
Configuration conf = new Configuration();
Job job = new Job(conf);
Path in = new Path("YOUR_PATH_IN_HDFS");
FileInputFormat.addInputPath(job, in);
job.setInputFormatClass(TextInputFormat.class); // could be a sequencefile also
// set the other stuff
job.waitForCompletion(true);
Make sure your file resides in HDFS then.