So i'm trying to make a table but it doesn't look to good since the lines break inside the table in a way I don't like.
\begin{tabular}{|p{8cm}|p{1cm}|}
\hline
! (4 < 5) & \\
! false & \\
(2 > 2) ││ ((4 == 4) && (1 < 0)) & \\
(2 > 2) ││ (4 == 4) && (1 < 0) & \\
(34 != 33) && ! false & \\
\hline
end{tabular}
What happens is that it breaks into new lines after every "&&", how do I stop this from happening? How do I make latex type "&&" instead of it thinking "& something empty &"?
Use an escape character: \
(I added a package here for clarity)
\begin{tabular}{|p{8cm}|p{1cm}|}
\hline
! (4 < 5) & \\
! false & \\
(2 > 2) ││ ((4 == 4) \&\& (1 < 0)) & \\
(2 > 2) ││ (4 == 4) \&\& (1 < 0) & \\
(34 != 33) \&\& ! false & \\
\hline
\end{tabular}
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I am trying to include both a decimal point and comma separator in a table. Even though the table input includes both the commas and the decimal separators, the latex table converts all the comma separating the thousands digits to decimal points. Is there a way to have both at the same time and align the numbers at the decimal and comma separators?
Thank you!
\documentclass{wptemp}
\usepackage{adjustbox}
\usepackage{setspace}\doublespacing
\usepackage{booktabs}
\usepackage{siunitx}
\newcolumntype{d}{S[input-symbols = ()]}
\usepackage{lscape}
\newcommand{\source}[1]{\caption*{Source: {#1}} }
% *****************************************************************
% Estout LaTeX wrapper
% *****************************************************************
%%Original code developed by Jörg Weber: see
%% https://www.jwe.cc/2012/03/stata-latex-tables-estout/
%% and
%% https://www.jwe.cc/blog/
\let\estinput=\input % define a new input command so that we can still flatten the document
\newcommand{\estwide}[3]{
\vspace{.75ex}{
%\textsymbols% Note the added command here
\begin{tabular*}
{\textwidth}{#{\hskip\tabcolsep\extracolsep\fill}l*{#2}{#3}}
\toprule
\estinput{#1}
\bottomrule
\addlinespace[.75ex]
\end{tabular*}
}
}
\newcommand{\estauto}[3]{
\vspace{.75ex}{
%\textsymbols% Note the added command here
\begin{tabular}{l*{#2}{#3}}
\toprule
\estinput{#1}
\bottomrule
\addlinespace[.75ex]
\end{tabular}
}
}
% Allow line breaks with \ in specialcells
\newcommand{\specialcell}[2][c]{%
\begin{tabular}[#1]{#{}c#{}}#2\end{tabular}
}
\newcommand{\sym}[1]{\rlap{#1}}% Thanks David Carlisle
%%%%%%%%%%% End of wrapper %%%%%%%%%%%%%%%%%%%%%
%%%%%%%%%%% TiKz %%%%%%%%%%%%%%%%%%%%%
\usepackage{tikz}
\usetikzlibrary{shapes.geometric, arrows}
\tikzstyle{startstop} = [rectangle, rounded corners, minimum width=3cm, minimum height=1cm,text centered, draw=black, fill=red!30]
\tikzstyle{io} = [trapezium, trapezium left angle=70, trapezium right angle=110, minimum width=3cm, minimum height=1cm, text centered, text width =5cm, draw=black, fill=blue!30]
\tikzstyle{process} = [rectangle, minimum width=3cm, minimum height=1cm, text centered, text width =5cm, draw=black, fill=orange!30]
\tikzstyle{decision} = [diamond, minimum width=3cm, minimum height=1cm, text centered, draw=black, fill=green!30]
\tikzstyle{arrow} = [thick,->,>=stealth]
\begin{document}
\linespread{1}{\title{{\fontfamily{ptm}\selectfont{\Large{\MakeUppercase{}}}}
% \thanks{}
}}
\author{}
\date{\fontfamily{pbk}\selectfont\normalsize{\textsc{\today}}}
\maketitle
% \begin{abstract}
% % \keywords{Keyword1; Keyword2; Keyword3.}
% % \JEL{}
% \end{abstract}
\thispagestyle{empty}
\pagenumbering{arabic}
\begin{table}[H]
\caption{Spill Over Effect of depression on GPA \label{tab:reggpa}}
\centering
\resizebox{\linewidth}{!}{
\begin{tabular}[t]{ldddddd}
\toprule
\multicolumn{1}{c}{Dependent Variable} & \multicolumn{1}{c}{Own Depression} & \multicolumn{1}{c}{GPA} & \multicolumn{1}{c}{Skip School} & \multicolumn{1}{c}{Miss School} & \multicolumn{1}{c}{Smoke Cigarettes} & \multicolumn{1}{c}{Get Drunk} \\
\cmidrule(l{3pt}r{3pt}){1-1} \cmidrule(l{3pt}r{3pt}){2-2} \cmidrule(l{3pt}r{3pt}){3-3} \cmidrule(l{3pt}r{3pt}){4-4} \cmidrule(l{3pt}r{3pt}){5-5} \cmidrule(l{3pt}r{3pt}){6-6} \cmidrule(l{3pt}r{3pt}){7-7}
& {\specialcell{(1)}} & {\specialcell{(2)}} & {\specialcell{(3)}} & {\specialcell{(4)}} & {\specialcell{(5)}} & {\specialcell{(6)}}\\
\midrule
\addlinespace[0.5em]
\multicolumn{7}{l}{\textit{Panel A: Full Sample}}\\
\midrule \hspace{1em}\specialcell{Average Depression \\ Index: friends} & 0.74*** & -0.33*** & 0.24*** & 0.15*** & 0.40*** & 0.30***\\
\hspace{1em} & (0.05) & (0.09) & (0.04) & (0.04) & (0.05) & (0.05)\\
\hspace{1em}Observations & 53,912 & 36,065 & 51,813 & 50,816 & 51,941 & 51,579\\
\addlinespace[0.5em]
\multicolumn{7}{l}{\textit{Panel B: Women}}\\
\midrule \hspace{1em}\specialcell{Average Depression \\ Index: friends} & 0.84*** & -0.41*** & 0.25*** & 0.24*** & 0.44*** & 0.28***\\
\hspace{1em} & (0.09) & (0.10) & (0.05) & (0.07) & (0.06) & (0.06)\\
\hspace{1em}Observations & 28,703 & 19,272 & 27,797 & 27,339 & 27,856 & 27,659\\
\addlinespace[0.5em]
\multicolumn{7}{l}{\textit{Panel C: Men}}\\
\midrule \hspace{1em}\specialcell{Average Depression \\ Index: friends} & 0.69*** & -0.23* & 0.25*** & 0.06 & 0.37*** & 0.34***\\
\hspace{1em} & (0.08) & (0.13) & (0.05) & (0.06) & (0.06) & (0.07)\\
\hspace{1em}Observations & 25,195 & 16,784 & 24,003 & 23,465 & 24,071 & 23,906\\
\addlinespace[0.5em]
\multicolumn{7}{l}{\textit{Panel D: Above median \# friends}}\\
\midrule \hspace{1em}\specialcell{Average Depression \\ Index: friends} & 0.89*** & -0.57*** & 0.31*** & 0.17*** & 0.42*** & 0.33***\\
\hspace{1em} & (0.08) & (0.10) & (0.05) & (0.05) & (0.05) & (0.06)\\
\hspace{1em}Observations & 34,654 & 23,653 & 33,558 & 32,948 & 33,640 & 33,400\\
\addlinespace[0.5em]
\multicolumn{7}{l}{\textit{Panel E: Below median \# friends}}\\
\midrule \hspace{1em}\specialcell{Average Depression \\ Index: friends} & 0.60*** & -0.04 & 0.16*** & 0.14** & 0.37*** & 0.27***\\
\hspace{1em} & (0.09) & (0.11) & (0.05) & (0.06) & (0.07) & (0.07)\\
\hspace{1em}Observations & 19,258 & 12,412 & 18,255 & 17,868 & 18,301 & 18,179\\
\midrule
\hspace{1em}School FE & {X} & {X} & {X} & {X} & {X} & {X}\\
\hspace{1em}Clustered Standard Errors & {by: SchoolID} & {by: SchoolID} & {by: SchoolID} & {by: SchoolID} & {by: SchoolID} & {by: SchoolID}\\
Mean Full Sample & 0.00 & 2.86 & 0.30 & 0.45 & 0.36 & 0.31\\
Mean Women Sample & 0.26 & 2.94 & 0.29 & 0.48 & 0.35 & 0.29\\
Mean Men Sample & -0.24 & 2.78 & 0.32 & 0.42 & 0.36 & 0.33\\
Mean Friends > Median & 0.11 & 2.91 & 0.30 & 0.44 & 0.38 & 0.34\\
Mean Friends $\leq$ Median & -0.11 & 2.80 & 0.30 & 0.46 & 0.32 & 0.27\\
\bottomrule
\multicolumn{7}{l}{\rule{0pt}{1em}\textit{Note: }}\\
\multicolumn{7}{l}{\rule{0pt}{1em}I include controls for sex, age, race, parental education, parental work status, parental job, and school fixed effects. }\\
\multicolumn{7}{l}{\rule{0pt}{1em}* p $<$ 0.1, ** p $<$ 0.05, *** p $<$ 0.01}\\
\end{tabular}}
\end{table}
\end{document}
I want the variables and signs aligned in a set of equations.
Desired output:
What I am trying in Mathjax:
\[
\begin{align}
2&x_1 - x_2 &+ 1.5&x_3 &= 8 \\
&x_1 &- 4&x_3 &= -1
\end{align}
\]
What I got:
So, what do I have to do to have the same alignment as in the "desired output" image?
There are a number of ways to achieve this. Below I use an array (with appropriate stretch and spacing), alignat and align coupled with eqparbox for measuring similarly-tagged boxes (this latter approach requires two compilations with every change in the largest element associated with every <tag>):
\documentclass{article}
\usepackage{amsmath,eqparbox}
%\usepackage{xparse}% If you have LaTeX2e < 2020-10-01
% https://tex.stackexchange.com/a/34412/5764
\makeatletter
% \eqmathbox[<tag>][<align>]{<math>}
\NewDocumentCommand{\eqmathbox}{o O{c} m}{%
\IfValueTF{#1}
{\def\eqmathbox###1##2{\eqmakebox[#1][#2]{$##1##2$}}}
{\def\eqmathbox###1##2{\eqmakebox{$##1##2$}}}
\mathpalette\eqmathbox#{#3}
}
\makeatother
\begin{document}
\[
\renewcommand{\arraystretch}{1.2}
\setlength{\arraycolsep}{0pt}
\begin{array}{ r c r c r c r }
2 x_1 & {}-{} & x_2 & {}+{} & 1.5 x_3 & {}={} & 8 \\
x_1 & & & {}-{} & 4 x_3 & {}={} & -7
\end{array}
\]
\begin{alignat*}{4}
2 x_1 & {}-{} & x_2 & {}+{} & 1.5 x_3 = {} && 8 \\
x_1 & & & {}-{} & 4 x_3 = {} && -7
\end{alignat*}
\begin{align*}
\eqmathbox[x1][r]{2 x_1} - \eqmathbox[x2][r]{x_2} + \eqmathbox[x3][r]{1.5 x_3} &= \eqmathbox[c][r]{8} \\
\eqmathbox[x1][r]{ x_1} \phantom{{}-{}} \eqmathbox[x2][r]{} - \eqmathbox[x3][r]{4 x_3} &= \eqmathbox[c][r]{-7}
\end{align*}
\end{document}
All yield similar output:
I have one flalign environment, so columns are aligned same way whole page. I need \subsections inside this flalign, so I used \intertext. And I need \label these \subsections. And thats where I failed. It \label first equation after \subsection but not \subsection itself or error occurs.
Image:
When I tried to use more flalign environments and place subsections between them they were not aligned same way and it looked terible.
Thanks for help.
\begin{flalign}
&\text{Značení: } &&X\sim \text{Exp($\lambda$)} &&
\\
&\text{Parametry: } &&\lambda > 0 &&
\\
&\text{Nosič: } &&X \in (0,\infty) &&
\\
&\text{Hustota: } &&f(x)=
\begin{cases}
\lambda e^{-\lambda x} & x>0
\\
0 & x\leq 0
\end{cases}
\\
&\text{Distribuční funkce: } &&F(x)=
\begin{cases}
1-e^{-\lambda x} & x>0
\\
0 & x\leq 0
\end{cases} &&
\\
&\text{Střední hodnota: } && \E X = \frac{1}{\lambda} &&
\\
&\text{Rozptyl: } && \var X = \frac{1}{\lambda^2} &&
\\
\intertext{\subsection{Weibullovo rozdělení}}\label{priloha:weibdist}
&\text{Značení: } &&X\sim \text{Weib($\alpha$, $\beta$)}&&
\\
&\text{Parametry: } &&\text{$\alpha$, $\beta>0$}&&
\\
&\text{Nosič: } &&X \in \langle 0,\infty)&&
\\
&\text{Hustota: } &&f(x)=
\begin{cases}
\alpha \beta^\alpha x^{\alpha-1} e^{-(\beta x)^\alpha} & x\geq 0
\\
0 & x< 0
\end{cases}&&
\\
&\text{Distribuční funkce: } &&F(x)=
\begin{cases}
1-e^{-(\beta x)^\alpha} & x\geq 0
\\
0 & x< 0
\end{cases}
\\
&\text{Střední hodnota: } &&\E X = \frac{1}{\beta} \Gamma\left(1+\frac{1}{\alpha}\right)
\\
&\text{Rozptyl: } &&\var X = \frac{1}{\beta^2} \left\lbrace\Gamma \left(1+\frac{2}{\alpha}\right)-\left[\Gamma\left(1+\frac{1}{\alpha}\right)\right]^2\right\rbrace
\\
\intertext{\subsection{Gama rozdělení}}\label{priloha:gammadist}
&\text{Značení: } &&X\sim \Gamma(\alpha,\;\beta)&&
\\
&\text{Parametry: } &&\alpha,\; \beta > 0
\\
&\text{Nosič: } &&X \in (0,\infty)
\\
&\text{Hustota: } &&f(x)=
\begin{cases}
\frac{\alpha^\beta}{\Gamma(\beta)}x^{\beta-1}e^{-\alpha x} & x>0
\\
0 & x\leq 0
\end{cases}
\\
&\text{Střední hodnota: } && \E X = \frac{\beta}{\alpha}
\\
&\text{Rozptyl: } && \var X = \frac{\beta}{\alpha^2}
\end{flalign}
From the images you show, I would suggest to use a tabular with a fixed width instead. This will allow you to break for things like subsections:
\documentclass[12pt,fleqn]{article}
\usepackage{amsmath}
\usepackage{array}
\begin{document}
\subsection{First part}
\noindent%
{%
\abovedisplayskip=-\baselineskip
\belowdisplayskip=-.5\baselineskip
\begin{tabular}{#{}p{.3\textwidth}#{}p{.7\textwidth}#{}}
First equation: & \begin{equation} a+b+c=d \end{equation}\\
Second equation: & \begin{equation} a+b+c=d \end{equation}\\
\end{tabular}
}
\subsection{Second part}
\label{sub:1}
\noindent%
{%
\abovedisplayskip=-\baselineskip
\belowdisplayskip=-.5\baselineskip
\begin{tabular}{#{}m{.3\textwidth}#{}m{.7\textwidth}#{}}
Next equation: & \begin{equation} a+b+c+45867+ddlk=d \end{equation}\\
Another equation: & \begin{equation} a+b+c+sdfsdf+565=d \end{equation}\\
\end{tabular}
}
Here alignment is working, but labeling not. Second part is \ref{sub:1}. It referes to 3th equation instead of subsection.
\end{document}
I would like to call a single value from a table inside a textbody.
% latex table generated in R 3.5.1 by xtable 1.8-3 package
% Wed Dec 12 13:56:07 2018
\begin{table}[ht]
\centering
\begin{tabular}{rrrrr}
\hline
& Estimate & Std. Error & z value & Pr($>$$|$z$|$) \\
\hline
(Intercept) & -1.819 & 0.926 & -1.964 & 0.050 \\
hiveH2 & 2.418 & 0.951 & 2.542 & 0.011 \\
nectar+ & 0.827 & 0.947 & 0.873 & 0.383 \\
\hline
\end{tabular}
\label{tab:x}
\end{table}
I would like to be able to write something along the line:
The z value of Hive~2 is \call{tab:x{z value}{hiveH2}}.
That should compile as:
The z value of Hive 2 is 2.542.
the LaTeX table was generated with a R script (neither R markdown nor R sweave):
library(lme4)
library(xtable)
data <- matrix(c("H1","H1","H2","H2","H1","H1","H2","H2","H1","H1","H2","H2","H1","H1","H2","H2","H1","H1","H2","H2","H1","H1","H2","H2","H1","H1","H2","H2",
"+","+","-","-","+","+","-","-","+","+","-","-","+","+","-","-","-","-","+","+","-","-","+","+","-","-","+","+",
0.00000000,0.00000000,0.25000000,0.00000000,0.00000000,0.00000000,0.00000000,0.10000000,0.20000000,0.00000000,0.10000000,0.00000000,0.00000000,0.00000000,0.00000000,0.09090909,0.09090909,0.00000000,0.41666667,0.08333333,0.00000000,0.14285714,0.85714286,0.61538462,0.00000000,0.00000000,0.25000000,1.10000000),
nrow=28, ncol=3)
data <- as.data.frame(data)
colnames(data) <- c("hive", "nectar", "severity")
glm <- glm(severity ~ hive + nectar, data = data, family = binomial)
summary.glm <- summary(glm)
summary.glm
print(xtable(summary.glm, type = "latex", caption.placement = getOption("xtable.caption.placement", "bottom"),
digits = 3,
label = "tab:x",
table.placement = getOption("xtable.table.placement", "h")),
file = "test.tex")
Does anyone know how to modify the following string in order to display the two-lines bracket?
str = '$$c_i =\{\begin{array}{l l} 1 \quad L\left(Q_i\right) < 0 \\ 0 \quad L\left(Q_i\right) \geq 0 \\ \end{array}$$';
The current output is the following:
The sign '{' has to embrace both rows (1 and 0).
$$c_i =\begin{cases} 1 & L\left(Q_i\right) < 0 \\
0 & L\left(Q_i\right) \geq 0
\end{cases}$$
The tex file should have \usepackage{amsmath} in the preamble.
This is derived from Niall Murphy's answer, "tidied up" a bit:
\[
c_i =
\begin{cases}
1 & L (Q_i) < 0 \\
0 & L (Q_i) \geq 0
\end{cases}
\]
Note that the "\" becomes "\\", and I've removed the \left and \right parenthesis modifiers, which introduce unwanted (I think) space between L and (.
Try add \left before \{ and \rigth. at the end.
It should look like
$$\alpha_t = \left \{ {{\sqrt{\frac1N},\; t = 0 } \atop {\sqrt{\frac2N},\; t \ne 0 } } \right.$$
or
$$
\left\{\begin{tabular}{l} \textbf{Y} = 0,299\textbf{R} + 0,587\textbf{G} + 0,114\textbf{B} \\ \textbf{Cb} = 128 + 0,5\textbf{R} - 0,418688\textbf{G} - 0,081312\textbf{B} \\ \textbf{Cr} = 128 - 0,168736\textbf{R} - 0,331264\textbf{G} - 0,53\textbf{B} \end{tabular} \right.
$$