I want to make an app that won't be released on the App Store. I want this app to open siri through private API's, basically inject a home button press and hold into the events queue. I have tried using GSEvent(GSSendEvent - Inject Touch Event iOS), but it no longer works(it silently fails) after iOS 7. I believe it is possible through SBUIController but I can't figure how to use SBUIController in iOS 8. To be clear, I want to do this on a non-jailbroken phone.
How can I go about doing this in iOS 8?
Thanks
You should check out the runtime headers of all the private/public apis here.
I found a method hidden in accessibility, which could possibly work in your case. Have a look at it here: http://git.io/frK6Sw . The method is named -(void)openSiri, which suggest that it might open Siri, I haven't tried though.
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I’m trying to get a voice shortcut for a custom Siri Intent working as part of an Apple Watch app, but I’m not sure whether that’s possible. Has anyone had success with this or know if it’s supported?
There isn't much code to share in this case, since most of the code is auto-generated by Xcode, but here’s a quick overview of how I have everything set up.
I created a custom Intent with a .intentdefiniton file and separate Intents Extension targets for my iOS app and watchOS app to handle the Intent.
I set up and donate the shortcuts at the appropriate time. I included an INUIAddVoiceShortcutButton in my app so a user can easily add or edit a phrase for the shortcut.
Everything works fine on an iPhone: the shortcut shows up at relevant times throughout iOS, and the Intents Extension in my iOS app handles the shortcut when I say the invocation phrase to Siri.
Since 20% of my app’s users use the Apple Watch app, I want to provide a congruent experience on watchOS. The donated shortcut shows up on the Siri watch face, as expected. I trigger the shortcut from the Siri watch face, and is handled by the Intents Extension that's part of my watchOS app.
When I say the intent’s invocation phrase to my Apple Watch (Series 3 GPS-only), however, it doesn’t work. Siri says:
Checking with the app...
Then a few seconds later:
I do not recognize that command.
I’ve tried this with a separate Intents Extension for my watchOS app, and without. I get the same results in both situations. It works on the simulator, but not on a real device.
I’ve also made sure I have my Watch Extension and Watch App selected under Target Membership for the .intentdefinition file.
I’ve also tried going into Settings > Developer and enabling Display Recent Shortcuts then tapping Force Sync Shortcuts to Watch, but that doesn’t change the behavior.
Are voice shortcuts for these custom intents even supported on Apple Watch? I haven’t been able to tell one way or another with Apple’s documentation. The SoupChef sample project is set up with an Intents Extension for the watchOS app, which makes me think it should be supported. And, since it works on the simulator, that makes me think it should be supported.
However, this page doesn’t list custom intents as being supported on watchOS, so that makes me think they may not be supported: https://developer.apple.com/design/human-interface-guidelines/watchos/user-interaction/siri/
If anyone can help me figure out whether this is supported I’d really appreciate it. I’m not sure if I’m doing something wrong or if this just isn’t supported.
The problem was on my Apple Watch.
I was able to get it working by erasing the watch (Settings > General > Reset > Erase All Content and Settings) then restoring it from a backup.
I want to know is there any way to turn on or off the iPhone wifi or switch the device to offline mode in codes in swift 4 or not
I know that apple may not allow the app can do such things to be distributed in App Store But it's Not important I just want to know is there any codes to do that or not (Just in swift 4)
5 Solutions Collect From Internet About “How to turn off internet connection, bluetooth and WIFI programmatically?”
Ans
You can’t. Apple does not allow 3rd party apps to change global system settings like that.
There is no API available to control cellular data,wi-fi,bluetooth within in an app , User have to go to settings to enable or disable cellular data,wi-fi and bluetooth.
This is not possible in iOS unless you jailbroke your device. Apple is not allowing any apps developer to access wifi/bluetooth. You can only check wifi/tooth is connected or not.
You can’t do that using the iOS application. Apple not allowing it.
Legally there is no way to do it. Even somehow if you are manage to do it, Apple will reject your app while submitting to AppStore.
update
I am not sure the following code will work or not, try once, initially add the header file to your project folder and create the bridging header to your code ,then use the below code where you need , for ref purpose I taken the answer from here
var tempSBWifiManager: SBWiFiManager = objc_getClass("SBWiFiManager")
// Steal a class from SpringBoard
tempSBWifiManager.sharedInstance().isWiFiEnabled = false
I have been working on a project wherein i made a framework where i automatically test the SDK my company is developing.
I have created my dummy sample application for all the platforms(iOS, Android, OSX, Windows) which makes use of this SDK and i thereby test this SDK, call the SDK API's do my work.
Now my question is for iOS i get permission alerts for Contacts, Camera and Microphone first time whenever i use the API's of my SDK which internally is invoking something in iOS framework. Is there a way i can automatically give this permission to my application ?? i know it's iOS own Security concern and it's correct. But how do i bypass it.
I see there is Apple's XCUITest framework but i don't want to open my application via it.
Right now i handle this alert manually but i need to implement Continuous Integration(using ios-deploy), i have done everything but i can't handle these alerts automatically.
Can someone please help me.. Thanks!!
I would like to know if it is possible to launch an app on iOS that is currently in the back group using three taps for example ? Think of it as a short cut on a desktop app.
Thanks
No!
That is not possible. There is no way to open one specific app on some combination of touches.
You can however open other apps from your app using url schemes, but something like that is not supported across the entire OS and of course not supported on the springboard. (see the apple docs)
I wanted to know how I can open an external app from a custom keyboard in iOS 8?
is it by example possible to open Facebook, or post a Facebook message from a custom keyboard, if yes, how can I achieve this?
Thank you,
joe
I was trying to work with the UIApplication sharedApplication openURL: method in order to open the AppStore to link to the app so user's could rate it, Xcode kept telling me that the openURL method would not work in the extension. So I am sure you are able to refer back to the app itself but not open other app's which hopefully they will be able to change fairly soon.