I have tried the string(contain special character) to original String. The string received from service. I tried many codes. But i cant get the original String.
i tried the following code
// \U00e0\U00ae\U0089\U00e0\U00ae\U00b2\U00e0\U00ae\U0095\U00e0\U00ae\U00ae\U00e0\U00af\U008d
NSString *name2escaped = #"\\U00e0\\U00ae\\U0089\\U00e0\\U00ae\\U00b2\\U00e0\\U00ae\\U0095\\U00e0\\U00ae\\U00ae\\U00e0\\U00af\\U008d";
NSString *name2 = [NSString stringWithCString:[name2escaped cStringUsingEncoding:NSUTF8StringEncoding] encoding:NSNonLossyASCIIStringEncoding];
NSLog(#"name2 = %#", name2);
inputvalue.stringValue = name2;
NSLog (#"%#",name2);
Output prints: à®à®²à®à®®à¯
I worked in Mac OS X development 10.9 Mavericks
Service sometimes send chinese character also. Can anybody help me
As according to your requirement output should be Tamil or Chinese or English Language
Change NSNonLossyASCIIStringEncoding to NSUTF16StringEncoding :
NSString *name2escaped = #"\\U00e0\\U00ae\\U0089\\U00e0\\U00ae\\U00b2\\U00e0\\U00ae\\U0095\\U00e0\\U00ae\\U00ae\\U00e0\\U00af\\U008d";
NSString *name2 = [NSString stringWithCString:[name2escaped cStringUsingEncoding:NSUTF8StringEncoding] encoding:NSUTF16StringEncoding];
NSLog(#"name2 = %#", name2);
Output is : name2 = 屵〰攰屵〰慥屵〰㠹屵〰攰屵〰慥屵〰戲屵〰攰屵〰慥屵〰㤵屵〰攰屵〰慥屵〰慥屵〰攰屵〰慦屵〰㡤 –
I did it
My code is
- (NSString *) OrigninalString:(NSString *)getfilername
{
const char *c;
NSString *name2escaped = [NSString stringWithFormat:#"%#",getfilername];
NSString *string = [NSString
stringWithCString:[name2escaped cStringUsingEncoding:NSUTF8StringEncoding]
encoding:NSNonLossyASCIIStringEncoding];
c = [string cStringUsingEncoding:NSISOLatin1StringEncoding];
if (!c) {
c = [name2escaped cStringUsingEncoding:NSISOLatin1StringEncoding];
}
NSString *newString = [NSString stringWithCString:c encoding:NSUTF8StringEncoding];
c = nil;
string = nil;
return newString;
}
Related
I have NSString with input Value from keyboard.
Eg.
NSString *myText = #"Apple";
In my case , i want to get a word before last letter.
For above eg , i want to get only l letter before e letter.
How can i get it?
NSString *text = #"Apple";
unichar c = [text characterAtIndex:text.length - 2];
If you need a NSString
NSString *character = [NSString stringWithCharacters:&c length:1];
that may be a useful implenentaion as well:
NSString *_string = #"string";
NSString *_letter = nil;
if (_string.length > 1) {
[_string substringWithRange:NSMakeRange(_string.length - 2, 1)];
}
it does not crash either, when the string is not long enough.
I am trying to replace some characters with unknown index like this(i need to replace this Ă,Ŏ,Ĭ,ă,ŏ,ĭ and my input nsstring can be anything):
(void)repairText:(NSString *)textToRepair{`
NSString *pom = textToRepair;`
int pomNum = [pom length];
NSLog(#"Input nsstring: %#",pom);
for (int a = 0; a<pomNum; a++) {
NSString *pomChar, *pomChar2;
pomChar = [pom substringFromIndex:a];
pomChar2 = [pomChar substringToIndex:(1)];
NSLog(#"Char to repair: %#",pomChar2);
if ([pomChar2 isEqual: #"Ă"] || [pomChar2 isEqual:#"Ŏ"] || [pomChar2 isEqual:#"Ĭ"] || [pomChar2 isEqual:#"ă"] || [pomChar2 isEqual:#"ŏ"] || [pomChar2 isEqual:#"ĭ"]) {
if ([pomChar2 isEqual:#"Ă"]) {
NSLog(#"Wrong big a");
}
if ([pomChar2 isEqual:#"Ŏ"]) {
NSLog(#"Wrong big o");
}
if ([pomChar2 isEqual:#"Ĭ"]) {
NSLog(#"Wrong big i");
}
if ([pomChar2 isEqual:#"ă"]) {
NSLog(#"Wrong small a");
}
if ([pomChar2 isEqual:#"ŏ"]) {
NSLog(#"Wrong small o");
}
if ([pomChar2 isEqual:#"ĭ"]) {
NSLog(#"Wrong small i");
}
} else {
NSLog(#"Good");
}
}
pom = [textToRepair stringByReplacingOccurrencesOfString:#"•" withString:#" kulka "];
pom = [textToRepair stringByReplacingOccurrencesOfString:#"¥" withString:#" jen "];
pom = [textToRepair stringByReplacingOccurrencesOfString:#"£" withString:#" libra "];
pom = [textToRepair stringByReplacingOccurrencesOfString:#"€" withString:#" euro "];
[self synthesize:pom];
}
But I am having trouble with 'if'. If anyone know about this, please help in this regard.
NSString *str=#"ĂdsdaĬsd";
str=[str stringByReplacingOccurrencesOfString:#"Ă" withString:#""];
str=[str stringByReplacingOccurrencesOfString:#"Ĭ" withString:#""];
NSLog(#"%#",str);
O/p :dsdasd
NSString has functions to do that for you. dataUsingEncoding:allowLossyConversion: is the method you need.
From the documentation:
- (NSData *)dataUsingEncoding:(NSStringEncoding)encoding allowLossyConversion:(BOOL)flag
If flag is YES and the receiver can’t be converted without losing some information, some characters may be removed or altered in conversion. For example, in converting a character from NSUnicodeStringEncoding to NSASCIIStringEncoding, the character ‘Á’ becomes ‘A’, losing the accent.
Sample code:
NSString *str = #"á, é, í, ó, ú, ü, ñ";
NSData *asciiStringData = [str dataUsingEncoding:NSASCIIStringEncoding
allowLossyConversion:YES];
NSString *finalString = [[NSString alloc] initWithData:asciiStringData
encoding:NSASCIIStringEncoding];
The final string will be : a, e, i, o, u, u, n
NSString * textToRepair = #"Your String";
textToRepair =[textToRepair stringByReplacingOccurrencesOfString:#"•" withString:#"kulka"];
textToRepair =[textToRepair stringByReplacingOccurrencesOfString:#"¥" withString:#"jen"]
textToRepair =[textToRepair stringByReplacingOccurrencesOfString:#"£" withString:#"libra"];
textToRepair =[textToRepair stringByReplacingOccurrencesOfString:#"€" withString:#"euro"];;
and now textToRepair is your output string with changes.
You can used this:
NSString * myString = #"Hello,";
NSString * newString = [myString stringByReplacingOccurrencesOfString:#"," withString:#""];
NSLog(#"%#xx",newString);
I hope this is used full to you.
I call api and get the string which include the android java unicode in NSDictionary :
\ud83d\ude25\ud83d\ude1e\U2764\ud83d\ude2d
When get the the value above and assign to string, I just will get the string as:
\ud83d\ude25\ud83d\ude1e❤\ud83d\ude2d
I totally can not get the value \U2764 but get the value ❤
So I can not replace the code \U2764 to IOS unicode.
How can I get it \U2764? I convert into UTF-8.
Thanks
Edit:
This is get the directory from api (dic):
{
message = "\ud83d\ude25\ud83d\ude1e\U2764\ud83d\ude2d";
mesgid = "213133";
Thumbnail = "";
}
Then i get the message, but the dic2 string is still get \ud83d\ude25\ud83d\ude1e❤\ud83d\ude2d:
const char *cString = [[dic6 objectForKey:#"Message"] UTF8String];
NSString *dic2 = [[NSString alloc] initWithUTF8String:cString];
if ([dic2 rangeOfString:#"\\U"].location==NSNotFound && [dic2 rangeOfString:#"\\u"].location==NSNotFound)
{
NSLog(#"Substring Not Found");
}
else
{
NSLog(#"Substring Found");
}
I totally can not get the unicode.
Why?
try this
NSString *uniString = [NSString stringWithUTF8String:#"\ud83d\ude25\ud83d\ude1e❤\ud83d\ude2d
"];
Hopefully this will resolve your problem
char cString[] = "\ud83d\ude25\ud83d\ude1e\U2764\ud83d\ude2d";
NSData *data = [NSData dataWithBytes:cString length:strlen(cString)];
NSString *string = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];
I want to replace some "ilegal" characters from a string to another "legal" characters, I have this code:
- (NSString *) quitarTildes:(NSString *)aStr
{
NSString *aux = aStr;
NSString *invalid = #"áéíóúÁÉÍÓÚñÑ";
NSString *valid = #"aeiouAEIOUnN";
for (int i = 0; i < [invalid length]; i++)
[aux stringByReplacingOccurrencesOfString: [NSString stringWithFormat:#"%c",[invalid characterAtIndex:i]]
withString: [NSString stringWithFormat:#"%c",[valid characterAtIndex:i]]];
NSLog(#"%#",aux);
return aux;
}
And all ilegal character still there...
NSString *test = #"Hólá, Ésto es una prueba.";
test = [self quitarTildes: test];
NSLog, response:
2013-04-04 08:58:52.896 GeoRuta_v1[1960:907] Hólá, Ésto es una prueba.
From the documentation:
stringByReplacingOccurrencesOfString:withString: Returns a new string
in which all occurrences of a target string in the receiver are
replaced by another given string.
-(NSString *)stringByReplacingOccurrencesOfString:(NSString *)target withString:(NSString *)replacement
So:
aux = [aux stringByReplacingOccurrencesOfString: [NSString stringWithFormat:#"%c",[invalid characterAtIndex:i]]
withString: [NSString stringWithFormat:#"%c",[valid characterAtIndex:i]]];
A perhaps simpler solution to achieve your goal:
NSString *test = #"Hólá, Ésto es una prueba. - áéíóúÁÉÍÓÚñÑ";
test = [test stringByFoldingWithOptions:NSDiacriticInsensitiveSearch locale:NULL];
NSLog(#"%#", test);
Output:
Hola, Esto es una prueba. - aeiouAEIOUnN
One. You're using the wrong format specifier for characterAtIndex:. That method returns unichar and not char (for obvious reasons). You have to use %C (capital C).
Two. You're returning the original string, and not replacing its characters.
NSMutableString *tmp = [aStr mutableCopy];
// ...
[tmp replaceOccurrencesOfString:[NSString stringWithFormat:#"%C", [invalid characterAtIndex:i]]
withString:[NSString stringWithFormat:#"%C", [valid characterAtIndex:i]]];
I would like to be able to right align a string using spaces. I have to be able to use the stringWithFormat: method.
So far I have tried the recommended format and it does not seem to work: [NSString stringWithFormat:#"%10#",#"test"].
I would expect this to return a string that has six spaces followed by "test" but all I am getting is "test" with no spaces.
It appears that stringWithFormat ignores the sizing requests of the %# format specifier. However, %s specifier works correctly:
NSString *test = #"test";
NSString *str = [NSString stringWithFormat:#"%10s", [test cStringUsingEncoding:NSASCIIStringEncoding]];
NSLog(#"'%#'", str);
This prints ' test'.
It's C style formatting. %nd means the width is n.
check following code.
NSLog(#"%10#",[NSString stringWithFormat:#"%10#",#"test"]);
NSLog(#"%#",[NSString stringWithFormat:#" %#",#"test"]);
NSLog(#"%10#", #"test");
NSLog(#"%10s", [#"test" cStringUsingEncoding:[NSString defaultCStringEncoding]]);
NSLog(#"%10d", 1);
NSString *str = #"test";
int padding = 10-[str length]; //6
if (padding > 0)
{
NSString *pad = [[NSString string] stringByPaddingToLength:padding withString:#" " startingAtIndex:0];
str = [pad stringByAppendingString:str];
}
NSLog(#"%#", str);