Split string by a constant number, only on a space - ios

I am using the answer from this question (https://stackoverflow.com/a/13854813) to split a large string into an array based on a specific length.
- (NSArray *) componentSaparetedByLength:(NSUInteger) length{
NSMutableArray *array = [NSMutableArray new];
NSRange range = NSMakeRange(0, length);
NSString *subString = nil;
while (range.location + range.length <= self.length) {
subString = [self substringWithRange:range];
[array addObject:subString];
//Edit
range.location = range.length + range.location;
//Edit
range.length = length;
}
if(range.location<self.length){
subString = [self substringFromIndex:range.location];
[array addObject:subString];
}
return array;
}
I would like to make this only split the string on a space. So, if the last character of the substring is not a space, I would like it it shorten that substring until the last character is a space (hopefully that makes sense). Basically I want this to split the string, but not split words in the process.
Any suggestions?

May be you can separate with componentsSeparatedByCharactersInSet: and re-construct lines.
But in your case, I think you'd better to iterate unichars.
NSMutableArray *result = [NSMutableArray array];
NSUInteger charCount = string.length;
unichar *chars = malloc(charCount*sizeof(unichar));
if(chars == NULL) {
return nil;
}
[string getCharacters:chars];
unichar *cursor = chars;
unichar *lineStart = chars;
unichar *wordStart = chars;
NSCharacterSet *whitespaces = [NSCharacterSet whitespaceCharacterSet];
while(cursor < chars+charCount) {
if([whitespaces characterIsMember:*cursor]) {
if(cursor - lineStart >= length) {
NSString *line = [NSString stringWithCharacters:lineStart length:wordStart - lineStart];
[result addObject:line];
lineStart = wordStart;
}
wordStart = cursor + 1;
}
cursor ++;
}
if(lineStart < cursor) {
[result addObject:[NSString stringWithCharacters:lineStart length: cursor - lineStart]];
}
free(chars);
return result;
Input:
#"I would like to make this only split the string on a space. So, if the last character of the substring is not a space, I would like it it shorten that substring until the last character is a space (hopefully that makes sense). Basically I want this to split the string, but not split words in the process."
Output(length == 30):
(
"I would like to make this ",
"only split the string on a ",
"space. So, if the last ",
"character of the substring is ",
"not a space, I would like it ",
"it shorten that substring ",
"until the last character is a ",
"space (hopefully that makes ",
"sense). Basically I want this ",
"to split the string, but not ",
"split words in the process."
)

Related

Get string between strings with multiple occurrences

I found a lot of examples how to find string between 2 strings, but none of which shows how to handle multiple occurrences of that string. I have for example string like this
"Hi, I am <id>User</id>. I am 20 <id>years old</id>, and live in <id>some country</id>."
The idea behind is that I want to hyperlink each occurrence of that string within UITextField, and remove tags from the string. I also have 2 types of the tag, one should display hyperlink, the other should popup alert view with some text description of the word or phrase clicked.
EDIT:
Found a perfectly good working solution to extend this logic with changing content of the text with attributed string between tags provided in the text. Link here.
#Aleksandar Try this.. it works for me..
NSString *serverOutput = #"Hi, I am <id>User</id>. I am 20 <id>years old</id>, and live in <id>some country</id>.";
if([serverOutput containsString:#"</id>"])
{
NSArray *arrSeparate = [serverOutput componentsSeparatedByString:#"</id>"];
NSString *output = #"";
for(int i=0; i<arrSeparate.count; i++)
{
if([[arrSeparate objectAtIndex:i] containsString:#"<id>"])
{
NSArray *arrTest = [[arrSeparate objectAtIndex:i] componentsSeparatedByString:#"<id>"];
if(output.length < 1)
output = [arrTest objectAtIndex:1];
else
output = [NSString stringWithFormat:#"%#\n%#",output,[arrTest objectAtIndex:1]];
}
}
serverOutput = output;
}
NSLog(#"%#", serverOutput);
Please look into this, and i hope this gets you all the range where the keyword exists
NSString *serverOutput = #"Hi, I am <id>User</id>. I am 20 <id>years old</id>, and live in <id>some country</id>";
NSUInteger count = 0, length = [serverOutput length];
NSRange startRange = NSMakeRange(0, length);
NSRange endRange = NSMakeRange(0, length);
while(startRange.location != NSNotFound)
{
startRange = [serverOutput rangeOfString: #"<id>" options:0 range:startRange];
if(startRange.location != NSNotFound)
{
endRange = [serverOutput rangeOfString: #"</id>" options:0 range:endRange];
startRange = NSMakeRange(startRange.location + startRange.length, length - (startRange.location + startRange.length));
endRange = NSMakeRange(endRange.location + endRange.length, length - (endRange.location + endRange.length));
count++;
}
}
startRange will be the range from where the tag starts and endRange is where starts
You can change the range, location, create attributed string and add hyperlink as the range of string is available to you.

How to get the first alphabet character of a string in iOS

I have an example NSString in iOS
NSString* str = #"-- This is an example string";
I want to get the first alphabet letter. The result of above situation is letter "T" from word "This". Some characters before letter "T" is not alphabet letter so it returns the first alphabet letter is "T".
How can I retrieve it? If the string not contain any alphabet letter, it can return nil.
Besides, the result can be a NSRange
NSRange range = [string rangeOfCharacterFromSet:[NSCharacterSet letterCharacterSet]];
First create a NSCharecterSet as a global variable and write this code
-(void)viewDidLoad{
NSCharacterSet *s = [NSCharacterSet characterSetWithCharactersInString:#"abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"]
s = [s invertedSet];
NSString *myString = #"--- This is a string";
NSArray *arrayOfStrings = [myString componentsSeparatedByString:#" "];
for(int i=0;i<arrayOfStrings.count){
NSString *current = [arrayOfStrings objectAtIndex:i];
char c = [self returnCharacter:current];
if(c == nil){
//that means first word is not with alphabets;
}
else {
NSLog(#"%c",c);
//your output.
}
}
}
And here is the method
-(char)returnChracter:(NSString*)string{
NSRange r = [string rangeOfCharacterFromSet:s];
if (r.location != NSNotFound) {
NSLog(#"the string contains illegal characters");
return nil;
}
else {
//string contains all alphabets
char firstLetter = [string charAtIndex:0];
return firstLetter;
}
}
You can use the following function. Pass a string and get first character as a string.
-(NSString*)getFirstCharacter:(NSString*)string
{
for(int i=0;i<string.length;i++)
{
unichar firstChar = [string characterAtIndex:i];
NSCharacterSet *letters = [NSCharacterSet letterCharacterSet];
if ([letters characterIsMember:firstChar]) {
return [NSString:stringWithFormat:#"%c",firstChar];
}
}
return nil;
}

Find substring range of NSString with unicode characters

If I have a string like this.
NSString *string = #"😀1😀3😀5😀7😀"
To get a substring like #"3😀5" you have to account for the fact the smiley face character take two bytes.
NSString *substring = [string substringWithRange:NSMakeRange(5, 4)];
Is there a way to get the same substring by using the actual character index so NSMakeRange(3, 3) in this case?
Thanks to #Joe's link I was able to create a solution that works.
This still seems like a lot of work for just trying to create a substring at unicode character ranges for an NSString. Please post if you have a simpler solution.
#implementation NSString (UTF)
- (NSString *)substringWithRangeOfComposedCharacterSequences:(NSRange)range
{
NSUInteger codeUnit = 0;
NSRange result;
NSUInteger start = range.location;
NSUInteger i = 0;
while(i <= start)
{
result = [self rangeOfComposedCharacterSequenceAtIndex:codeUnit];
codeUnit += result.length;
i++;
}
NSRange substringRange;
substringRange.location = result.location;
NSUInteger end = range.location + range.length;
while(i <= end)
{
result = [self rangeOfComposedCharacterSequenceAtIndex:codeUnit];
codeUnit += result.length;
i++;
}
substringRange.length = result.location - substringRange.location;
return [self substringWithRange:substringRange];
}
#end
Example:
NSString *string = #"😀1😀3😀5😀7😀";
NSString *result = [string substringWithRangeOfComposedCharacterSequences:NSMakeRange(3, 3)];
NSLog(#"%#", result); // 3😀5
Make a swift extension of NSString and use new swift String struct. Has a beautifull String.Index that uses glyphs for counting characters and range selecting. Very usefull is cases like yours with emojis envolved

How to Split NSString to multiple Strings after certain number of characters

I am developing an iOS app using Xcode 4.6.2.
My app receives from the server lets say for example 1000 characters which is then stored in NSString.
What I want to do is: split the 1000 characters to multiple strings. Each string must be MAX 100 characters only.
The next question is how to check when the last word finished before the 100 characters so I don't perform the split in the middle of the word?
A regex-based solution:
NSString *string = // ... your 1000-character input
NSString *pattern = #"(?ws).{1,100}\\b";
NSError *error = NULL;
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern: pattern options: 0 error: &error];
NSArray *matches = [regex matchesInString:string options:0 range:NSMakeRange(0, [string length])];
NSMutableArray *result = [NSMutableArray array];
for (NSTextCheckingResult *match in matches) {
[result addObject: [string substringWithRange: match.range]];
}
The code for the regex and the matches part is taken directly from the docs, so the only difference is the pattern.
The pattern basically matches anything from 1 to 100 characters up to a word boundary. Being a greedy pattern, it will give the longest string possible while still ending with a whole word. This ensures that it won't split any words in the middle.
The (?ws) makes the word recognition work with Unicode's definition of word breaks (the w flag) and treat a line end as any other character (the s flag).
Notice that the algorithm doesn't handle "words" with more than 100 characters well - it will give you the last 100 characters and drop the first part, but that should be a corner case.
(assuming your words are separated by a single space, otherwise use rangeOfCharacterFromSet:options:range:)
Use NSString -- (NSRange)rangeOfString:(NSString *)aString options:(NSStringCompareOptions)mask range:(NSRange)aRange with:
aString as #" "
mask as NSBackwardsSearch
Then you need a loop, where you check that you haven't already got to the end of the string, then create a range (for use as aRange) so that you start 100 characters along the string and search backwards looking for the space. Once you find the space, the returned range will allow you to get the string with substringWithRange:.
(written freehand)
NSRange testRange = NSMakeRange(0, MIN(100, sourceString.length));
BOOL complete = NO;
NSMutableArray *lines = [NSMutableArray array];
while (!complete && (testRange.location + testRange.length) < sourceString.length) {
NSRange hitRange = [sourceString rangeOfString:#"" options:NSBackwardsSearch range:testRange];
if (hitRange.location != NSNotFound) {
[lines addObject:[sourceString substringWithRange:hitRange];
} else {
complete = YES;
}
NSInteger index = hitRange.location + hitRange.length;
testRange = NSMakeRange(index, MIN(100, sourceString.length - index));
}
This can help
- (NSArray *)chunksForString(NSString *)str {
NSMutableArray *chunks = [[NSMutableArray alloc] init];
double sizeChunk = 100.0; // or whatever you want
int length = 0;
int loopSize = ceil([str length]/sizeChunk);
for (int index = 0; index < loopSize; index++) {
NSInteger newRangeEndLimit = ([str length] - length) > sizeChunk ? sizeChunk : ([str length] - length);
[chunks addObject:[str substringWithRange:NSMakeRange(length, newRangeEndLimit)];
length += 99; // Minus 1 from the sizeChunk as indexing starts from 0
}
return chunks;
}
use NSArray *words = [stringFromServer componentsSeparatedBy:#" "];
this will give you words.
if you really need to make it nearest to 100 characters, start appending strings maintaining the total length of the appended strings and check that it should stay < 100.

How to split string into substrings on iOS?

I received an NSString from the server. Now I want to split it into the substring which I need.
How to split the string?
For example:
substring1:read from the second character to 5th character
substring2:read 10 characters from the 6th character.
You can also split a string by a substring, using NString's componentsSeparatedByString method.
Example from documentation:
NSString *list = #"Norman, Stanley, Fletcher";
NSArray *listItems = [list componentsSeparatedByString:#", "];
NSString has a few methods for this:
[myString substringToIndex:index];
[myString substringFromIndex:index];
[myString substringWithRange:range];
Check the documentation for NSString for more information.
I wrote a little method to split strings in a specified amount of parts.
Note that it only supports single separator characters. But I think it is an efficient way to split a NSString.
//split string into given number of parts
-(NSArray*)splitString:(NSString*)string withDelimiter:(NSString*)delimiter inParts:(int)parts{
NSMutableArray* array = [NSMutableArray array];
NSUInteger len = [string length];
unichar buffer[len+1];
//put separator in buffer
unichar separator[1];
[delimiter getCharacters:separator range:NSMakeRange(0, 1)];
[string getCharacters:buffer range:NSMakeRange(0, len)];
int startPosition = 0;
int length = 0;
for(int i = 0; i < len; i++) {
//if array is parts-1 and the character was found add it to array
if (buffer[i]==separator[0] && array.count < parts-1) {
if (length>0) {
[array addObject:[string substringWithRange:NSMakeRange(startPosition, length)]];
}
startPosition += length+1;
length = 0;
if (array.count >= parts-1) {
break;
}
}else{
length++;
}
}
//add the last part of the string to the array
[array addObject:[string substringFromIndex:startPosition]];
return array;
}

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