MVC KENDO UI GRID - dynamic columns objects - asp.net-mvc

Hi there im building a grid that have dynamic columns depending on the number of a specific object.. here's a example
public class Team
{
string name {get;set;}
List<members> memberslist {get;set;}
}
public class member{
string name {get;set;}
int goals {get;set;}
}
in the view:
#(Html.Kendo().Grid(Model.TeamList)
.Name("goalslist")
.Columns(columns =>
{
columns.Bound(team => team.name).Title("Team Name");
columns.Bound(team => team.memberslist);
}...
what i would like the result was something like this:
Team Name, John Smith Taylor Fernandez
Ajax       22      1     3
Milan      0      1      2
Any Ideia?! how its done will print object[object], i tried a lot of stufs but without sucess.. thanks

The easiest way to do this is through JSON. Convert your column list into json and pass it to the column, see below. At the very bottom you can see me pushing the columns to the grid. Below that you can see what the JSON itself looks like.
var gridJSON = {
dataSource: {
data: data,
schema: {
model: {} // the model gets filled in by the JSON coming from the database
},
pageSize: 20
},
height: 550,
groupable: false,
sortable: true,
resizable: true,
filterable: {
extra: false,
operators: {
string: {
startswith: "Starts with",
eq: "Is equal to",
neq: "Is not equal to"
}
}
},
pageable: {
refresh: true,
pageSizes: true,
buttonCount: 5
},
toolbar: kendo.template($("#template").html())
};
gridJSON.columns = currentReport.JSON.columns;
gridJSON.dataSource.schema.model.fields = currentReport.JSON.fields;
Here is the JSON for the 'currentReport.JSON.columns'
"columns" : [{
"field" : "ReceiverID",
"title" : "Receiver ID"
}, {
"field" : "ReceiverBatchID",
"title" : "Batch ID"
}, {
"field" : "PoNumber",
"title" : "PO Number"
}, {
"field" : "ReceiverTransactionDate",
"title" : "Receiver Trans Date",
"format" : "{0: yyyy-MM-dd}"
}, {
"field" : "PrintingLocation",
"title" : "Location"
}, {
"field" : "VendorID",
"title" : "Vendor ID"
}, {
"field" : "InNemo",
"title" : "InNemo"
}, {
"field" : "Path",
"title" : "Path",
"encoded" : "true",
"template": "#=Path#",
"width" : "50"
}
]

Related

How do I compare two nested documents using mongo_dart

Here is my database entry structure, it has a nested document called friends, I want to compare two different _id's friends list in dart using mongo_dart
{
"_id" : ObjectId("60ae06074e162995281b4666"),
"email" : "one#one.com",
"emailverified" : false,
"username" : "one#one.com",
"displayName" : "complete n00b",
"phonenumber" : "",
"dob" : "",
"points" : 0,
"friends" : [
{
"username" : "three#one.com",
"sent" : ISODate("2021-05-26T10:01:30.616Z")
},
{
"username" : "six#one.com",
"sent" : ISODate("2021-05-26T10:43:16.822Z")
}
]
}
Here is my code, but I am not getting any returns
Future<Map> commonFriends(store, myObjectId, theirObjectId) async {
var commonList = await store.aggregate([
{
'\$project': {
'friends': 1,
'commonToBoth': {
'\$setIntersection': [
{'_id': myObjectId, 'friends': '\$username'},
{'_id': theirObjectId, 'friends': '\$username'}
]
},
}
}
]);
return commonList;
}
I am getting an error from db.dart which is apart of mongo_dart package. The error is "Exception has occurred.
Map (4 items)"

firebase database filtering is not working. Need some assistance

I have a simple test database that I cant get to filter. I indexed the category in the rules:
"questions":{
".indexOn": ["category"]
},
My filter for the quiz app:
/questions.json?orderBy="category"&equalTo="Basics"&print=pretty
and my database:
"-MKoucSP33zm4jC43AnY" : {
"title" : {
"answers" : [ {
"score" : 30,
"text" : "Pineapple"
}, {
"score" : 5,
"text" : "Ham"
}, {
"score" : 20,
"text" : "Yogurt"
}, {
"score" : 10,
"text" : "Crab"
} ],
"category" : "Basics",
"questionId" : "101",
"questionImage" : "",
"questionLink" : "",
"questionText" : "What topping do you like the best on pizza?"
}
}
The category property is nested under the title node, so the property you need to order/filter on is title/category:
/questions.json?orderBy="title/category"&equalTo="Basics"&print=pretty
You'll also need to update your index definition for that path, so:
"questions": { ".indexOn": "title/category" }
Working example: https://stackoverflow.firebaseio.com/64596200/questions.json?orderBy="title/category"&equalTo="Basics"

Is it possible to create Salesreceipt without product/service value through QBO API?

Is it possible to create Salesreceipt without product/service value through QBO API? I have tried through API but it's not reflecting rate value and storing description value only.
If I remove ItemRef attribute(in request body) then it's reflecting rate and amount values and it's assigning some default and random product/service.
It is possible directly in QBO UI.
Request body where only description value storing:
{
"TxnDate" : "2016-05-27",
"Line" : [ {
"Amount" : 2222.00,
"Description" : "hi chk",
"DetailType" : "ItemReceiptLineDetail",
"ItemReceiptLineDetail" : {
"ItemRef" : { },
"Qty" : 1,
"UnitPrice" : 2222
} }
],
"CustomerRef" : {
"value" : "67"
},
"CustomerMemo" : {
"value" : "Thanks for your business! We appreciate referrals!"
},
"TotalAmt": 2222.00,
"PrivateNote" : "",
"CustomField" : [ {
"DefinitionId" : "1",
"Type" : "StringType",
"StringValue" : ""
} ]
}
Request body where default product/service assigning:
{
"TxnDate" : "2016-05-27",
"Line" : [ {
"Amount" : 2222.00,
"Description" : "hi chk",
"DetailType" : "ItemReceiptLineDetail",
"ItemReceiptLineDetail" : {
"Qty" : 1,
"UnitPrice" : 2222
} }
],
"CustomerRef" : {
"value" : "67"
},
"CustomerMemo" : {
"value" : "Thanks for your business! We appreciate referrals!"
},
"TotalAmt": 2222.00,
"PrivateNote" : "",
"CustomField" : [ {
"DefinitionId" : "1",
"Type" : "StringType",
"StringValue" : ""
} ]
}
No.
QuickBooks Online does not support this.

mongodb/rails "exception: can't find special index: 2d for:"

i have a rails app where i have some problems with indexes. I search locations by name.
First i thought its a problem with the addresses.coords but iam not sure about it.
The relevant parts of the search controller:
#practices = Practice.published
#practices = #practices.where(:"addresses.country" => params[:country].upcase) if params[:country].present?
if params[:location].present? && latlng = get_coordinates
#practices = #practices.near_sphere(:"addresses.coords" => latlng).max_distance(:"addresses.coords" => get_distance )
end
# now find doctors based on resulting practices
#doctors = Doctor.published.in("organization_relations.practice_id" => #practices.distinct(:_id))
The complete crash log:
Moped::Errors::OperationFailure (The operation: #<Moped::Protocol::Command
#length=255
#request_id=646
#response_to=0
#op_code=2004
#flags=[]
#full_collection_name="um-contacts.$cmd"
#skip=0
#limit=-1
#selector={:distinct=>"practices", :key=>"_id", :query=>{"deleted_at"=>nil, "published_at"=>{"$lte"=>2012-11-05 15:17:14 UTC}, "addresses.country"=>"DE", "addresses.coords"=>{"$nearSphere"=>[13.4060912, 52.519171], "$maxDistance"=>0.01569612305760477}}}
#fields=nil>
failed with error 13038: "exception: can't find special index: 2d for: { deleted_at: null, published_at: { $lte: new Date(1352128634313) }, addresses.country: \"DE\", addresses.coords: { $nearSphere: [ 13.4060912, 52.519171 ], $maxDistance: 0.01569612305760477 } }"
See https://github.com/mongodb/mongo/blob/master/docs/errors.md
for details about this error.):
app/controllers/search_controller.rb:16:in `index'
Thats the result of the indexes, not sure how to query them from the addresses which are embedded via has_many.
> db.practices.getIndexes()
[
{
"v" : 1,
"key" : {
"_id" : 1
},
"ns" : "um-contacts.practices",
"name" : "_id_"
}
]
Help would be really appreciated!
Edit: Looks like the indexes for adresses.coords arent created,
db.system.indexes.find()
{ "v" : 1, "key" : { "_id" : 1 }, "ns" : "um-contacts.users", "name" : "_id_" }
{ "v" : 1, "key" : { "_id" : 1 }, "ns" : "um-contacts.doctors", "name" : "_id_" }
{ "v" : 1, "key" : { "_id" : 1 }, "ns" : "um-contacts.collaborations", "name" : "_i
{ "v" : 1, "key" : { "_id" : 1 }, "ns" : "um-contacts.practices", "name" : "_id_" }
but should be created within the practice class:
class Practice
...
embeds_many :addresses, cascade_callbacks: true, as: :addressable
...
field :name, type: String
field :kind, type: String
field :slug, type: String
index({"addresses.coords" => '2d'}, { min: -180, max: 180, background: true })
index({name: 1})
index({slug: 1}, { unique: true })
...
Anyone have an idea why its failing?
try to re-create your indexes. for mongoid:
rake db:mongoid:create_indexes

How to join query in mongodb?

I have user document collection like this:
User {
id:"001"
name:"John",
age:30,
friends:["userId1","userId2","userId3"....]
}
A user has many friends, I have the following query in SQL:
select * from user where in (select friends from user where id=?) order by age
I would like to have something similar in MongoDB.
To have everything with just one query using the $lookup feature of the aggregation framework, try this :
db.User.aggregate(
[
// First step is to extract the "friends" field to work with the values
{
$unwind: "$friends"
},
// Lookup all the linked friends from the User collection
{
$lookup:
{
from: "User",
localField: "friends",
foreignField: "_id",
as: "friendsData"
}
},
// Sort the results by age
{
$sort: { 'friendsData.age': 1 }
},
// Get the results into a single array
{
$unwind: "$friendsData"
},
// Group the friends by user id
{
$group:
{
_id: "$_id",
friends: { $push: "$friends" },
friendsData: { $push: "$friendsData" }
}
}
]
)
Let's say the content of your User collection is the following:
{
"_id" : ObjectId("573b09e6322304d5e7c6256e"),
"name" : "John",
"age" : 30,
"friends" : [
"userId1",
"userId2",
"userId3"
]
}
{ "_id" : "userId1", "name" : "Derek", "age" : 34 }
{ "_id" : "userId2", "name" : "Homer", "age" : 44 }
{ "_id" : "userId3", "name" : "Bobby", "age" : 12 }
The result of the query will be:
{
"_id" : ObjectId("573b09e6322304d5e7c6256e"),
"friends" : [
"userId3",
"userId1",
"userId2"
],
"friendsData" : [
{
"_id" : "userId3",
"name" : "Bobby",
"age" : 12
},
{
"_id" : "userId1",
"name" : "Derek",
"age" : 34
},
{
"_id" : "userId2",
"name" : "Homer",
"age" : 44
}
]
}
Edit: this answer only applies to versions of MongoDb prior to v3.2.
You can't do what you want in just one query. You would have to first retrieve the list of friend user ids, then pass those ids to the second query to retrieve the documents and sort them by age.
var user = db.user.findOne({"id" : "001"}, {"friends": 1})
db.user.find( {"id" : {$in : user.friends }}).sort("age" : 1);
https://docs.mongodb.org/manual/reference/operator/aggregation/lookup/
This is the doc for join query in mongodb , this is new feature from version 3.2.
So this will be helpful.
You can use in Moongoose JS .populate() and { populate : { path : 'field' } }.
Example:
Models:
mongoose.model('users', new Schema({
name:String,
status: true,
friends: [{type: Schema.Types.ObjectId, ref:'users'}],
posts: [{type: Schema.Types.ObjectId, ref:'posts'}],
}));
mongoose.model('posts', new Schema({
description: String,
comments: [{type: Schema.Types.ObjectId, ref:'comments'}],
}));
mongoose.model('comments', new Schema({
comment:String,
status: true
}));
If you want to see your friends' posts, you can use this.
Users.find(). //Collection 1
populate({path:'friends', //Collection 2
populate:{path:'posts' //Collection 3
}})
.exec();
If you want to see your friends' posts and also bring all the comments, you can use this and too, you can indentify the collection if this not find and the query is wrong.
Users.find(). //Collection 1
populate({path:'friends', //Collection 2
populate:{path:'posts', //Collection 3
populate:{path:'commets, model:Collection'//Collection 4 and more
}}})
.exec();
And to finish, if you want get only some fields of some Collection, you can use the propiertie select Example:
Users.find().
populate({path:'friends', select:'name status friends'
populate:{path:'comments'
}})
.exec();
MongoDB doesn't have joins, but in your case you can do:
db.coll.find({friends: userId}).sort({age: -1})
one kind of join a query in mongoDB, is ask at one collection for id that match , put ids in a list (idlist) , and do find using on other (or same) collection with $in : idlist
u = db.friends.find({"friends": ? }).toArray()
idlist= []
u.forEach(function(myDoc) { idlist.push(myDoc.id ); } )
db.friends.find({"id": {$in : idlist} } )
Only populate array friends.
User.findOne({ _id: "userId"})
.populate('friends')
.exec((err, user) => {
//do something
});
Result is same like this:
{
"_id" : "userId",
"name" : "John",
"age" : 30,
"friends" : [
{ "_id" : "userId1", "name" : "Derek", "age" : 34 }
{ "_id" : "userId2", "name" : "Homer", "age" : 44 }
{ "_id" : "userId3", "name" : "Bobby", "age" : 12 }
]
}
Same this: Mongoose - using Populate on an array of ObjectId
You can use playOrm to do what you want in one Query(with S-SQL Scalable SQL).
var p = db.sample1.find().limit(2) ,
h = [];
for (var i = 0; i < p.length(); i++)
{
h.push(p[i]['name']);
}
db.sample2.find( { 'doc_name': { $in : h } } );
it works for me.
You can do it in one go using mongo-join-query. Here is how it would look like:
const joinQuery = require("mongo-join-query");
joinQuery(
mongoose.models.User,
{
find: {},
populate: ["friends"],
sort: { age: 1 },
},
(err, res) => (err ? console.log("Error:", err) : console.log("Success:", res.results))
);
The result will have your users ordered by age and all of the friends objects embedded.
How does it work?
Behind the scenes mongo-join-query will use your Mongoose schema to determine which models to join and will create an aggregation pipeline that will perform the join and the query.

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