Make a phone call programmatically using Libgdx - ios

I'm creating an app using libgdx.
In the contact page I would like, as for the email
(
Gdx.net.openURI("mailto:cippa#lippa.com");
), give the chance to made a phone call by clicking on the phone number.
Is this possible using libgdx?
Or I have to do this twice, using first Android and then iOS?
(Like in this question:
How to make a phone call programmatically?)
EDIT
How is possible to make a phone call programmatically in JAVA for iOS?
Because for Android is clear, simple and done, but for iOS, without using Objective-C?

As for the edited question (IOs phone call in Java), I haven't tested this code, but I think it should work:
UIApplication.getSharedApplication().openURL(new NSURL("telprompt://" + number));

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This question is for iOS 10 and Xcode 8. I know how to get user local address book contacts using ABAddressbook and show them in my app. What I was trying to do next are two things
Show the user what contacts he/she has blocked himself
Try see if I can block or unblock those contacts programmatically
The reason I am doing this is that as of now the only way to "block" a contact using native iOS app is to click on a contact, scroll down and click on block/unblock button. I was just trying to figure out if I can help the user quickly see all the contacts in their addresbook they have blocked and perhaps unblock/block one with one less tap using my app.
I have looked into callkit and that is not what I need. I am not creating a VOIP app nor do I need to create my own block list.
I have googled quite a bit and didn't find an answer for blocking / unblocking contacts using ABAddressbook which must mean its not possible. Suggestions?
In some way it is not possible till your device is jailbroken as this says and also it is possible if we use CallKit framework as Possible to programmatically block phone number in iOS source.
Apple document Says
The CallKit framework provides programmatic access to VoIP functionality, as well as call blocking and identification.

Customize phone call (using sim) UI on iPhone

Normally if we want to make a phone call from our application, we need open NSURL from app with prefix: tel://
However, I want to customize phone call UI that using sim card on phone from app. Do u have any idea about that.
If you know Viber app, you can see that app already done it.
You can choose to call by using Viber api or using sim card. When you use sim card call, you can see customized phone call UI.

How to read call duration and phone status on iOS 7?

I understand we cannot extract phone number/ call log from iOS 7. However, how do I give the user a pop-up every time an incoming or outgoing call ends. This pop up will open a form from the App that will already have call duration pre-filled and the user will fill the rest of the call.
I know similar topics exist, but nothing precisely on iOS 7.
That's not possible with current versions of iOS (or iOS 8). I wouldn't expect such a facility becoming available any time soon because it doesn't feel like something Apple would allow.

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How to add a hyperlink in an HTML5 application, so I can call a specific number with 3cx application for iPhone?
Try this it should work
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Actually html link is same for all calls, how You call to it is depends on phone settings.

iOS Programing, making phone calls

Is it possible to make a call from my app without accessing the standart phone application?
The problem is that if I make a call, my app goes to the background, and I really do not need that. I need it to be always active even if I am calling.
No there is no way to do that, you can only make calls via de tel URL sheme.
You can use tel://123456789, but this will display a confirmation before opening the phone app.
There are a few apps, however, that open the phone app and make a call directly without displaying a confirmation (like Dialvetica).
To answer your question, no, you can not make calls directly from your app, unless you create your own version of Skype (the whole network, not just the app), and you probably don't have the time, money and resources to do that.

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