How to efficiently merge two overlapping contours into one big contour? - opencv

I have a huge image ( about 63000 x 63000 pixels = 3969 Megapixels )
what i have done so far is i decided to make "tiles" of (1024 x 1024) and do my calculations based on these tiles, resulting in an 62 x 62 image tile grid!
(this works out very well and has the advantage of making the image viewable with zoom-in and zoom out, only viewn tiles are downsized for example)
But what i need now are the contours from the huge image!
i use the OpenCV function "findContours" to detect contours on each
one of the tiles.
i have added some overlap in the tiles so i get
overlapping contours ( 1 pixel overlap )
i used the offset parameter
of "findContours" to shift the contours to the right position
into the "virtual total image"
Here are some screenshot's i made from a demo application
What I want is this:
Now my questions:
is it possible to stitch the contours, my worst case is a contour which covers the total image... is there some library that can do this?
is there a library which works on a compressed version of the total image ( like rle for example )
is there a way to make opencv findcontours work on 1 bit binary images ?
Here's the code used by findcontours:
// Surf2DTiledData ...a gobject based class used for 2d tile management and viewing..
Surf2DTiledData* td = (Surf2DTiledData*)in_td;
int nr_hor_tiles = surf2_d_tiled_data_get_nr_hor_tiles(td);
int nr_ver_tiles = surf2_d_tiled_data_get_nr_ver_tiles(td);
int tile_size_x = surf2_d_tiled_data_get_tile_width(td);
int tile_size_y = surf2_d_tiled_data_get_tile_height(td);
contouring_data_obj = surf2_d_tiled_data_get_ContouringData(td);
p_contours = contouring_data_obj->p_contours;
p_border_contours = contouring_data_obj->p_border_contours;
g_return_if_fail(p_border_contours != NULL);
g_return_if_fail(p_contours != NULL);
for (y = 0; y < nr_ver_tiles; y++){
int x;
for (x = 0; x < nr_hor_tiles; x++){
int idx = x + y*nr_hor_tiles;
CvMemStorage *mem = contouring_data_obj->contour_storage[idx];
CvMat _src;
CvSeq *contours = NULL;
uchar* dataBuffer = (uchar*)p_data[x][y];
// the idea is to have some extra space available for the overlap
// detection of contours!
// the extra space is needed for the algorithm to check for
// overlaps of contours later on!
#define VIRT_BORDER_EXTEND 2
int virtual_x = x * tile_size_x - VIRT_BORDER_EXTEND;
int virtual_y = y * tile_size_y - VIRT_BORDER_EXTEND;
int virtual_width = tile_size_x + VIRT_BORDER_EXTEND * 2;
int virtual_height = tile_size_y + VIRT_BORDER_EXTEND * 2;
int x_off = -VIRT_BORDER_EXTEND;
int y_off = -VIRT_BORDER_EXTEND;
if (virtual_x < 0) {
virtual_width += virtual_x;
virtual_x = 0;
x_off = 0;
}
if (virtual_y < 0) {
virtual_height += virtual_y;
virtual_y = 0;
y_off = 0;
}
if ((virtual_x + virtual_width) > (nr_hor_tiles*tile_size_x)) {
virtual_width = nr_hor_tiles*tile_size_x - virtual_x;
}
if ((virtual_y + virtual_height) > (nr_ver_tiles*tile_size_y)) {
virtual_height = nr_ver_tiles*tile_size_y - virtual_y;
}
CvMat* _roi_mat = get_roi_mat(td,
virtual_x, virtual_y,
virtual_width, virtual_height);
// Use either this:
//mem = cvCreateMemStorage(0);
if (_roi_mat){
// CV_LINK_RUNS => different algorithm!!!!
int tile_off_x = tile_size_x * x;
int tile_off_y = tile_size_y * y;
CvPoint contour_shift = cvPoint(x_off + tile_off_x, y_off + tile_off_y);
int n = cvFindContours(_roi_mat, mem, &contours, sizeof(CvContour), CV_RETR_LIST, CV_CHAIN_APPROX_SIMPLE, contour_shift);
cvReleaseMat(&_roi_mat);
p_contours[x][y] = contours;
}
//cvReleaseMemStorage(&mem);
}
}
later i used opengl to make textures out of the tiles and for every tile there is a quad !
the opencv contours are not drawn as this could be too slow for now, but i draw their bounding boxes... which are drawn in opengl too..

Related

Converting a pointcloud to a depth/multi channel image

I have a pointcloud generated by scanning a planar surface using stereo cameras. I have generated features such as normals, fpfh etc and using this information I want to classify areas in the pointcloud. To enable the use of more traditional CNN approaches I want to convert this pointcloud to a multi-channel image in opencv. I have the pointcloud collapsed to the XY plane, and aligned to the X and Y axes so that I can create a bounding box for the image.
I am looking for ideas on how to proceed further with the mapping from points to pixels. Specifically, I am confused about the image size, and how to go about filling in each pixel with the appropriate data. (Overlapping points would be averaged out, empty ones will be labelled accordingly). Since this is an unorganized pointcloud, I do not have camera parameters to use, and I guess PCL's RangImage class would not work in my case.
Any help is appreciated!
Try creating an empty cv::Mat of predetermined size first. Then iterate through every pixel of that Mat to determine what value it should take.
Here is some code which does something similar to what you were describing:
cv::Mat makeImageFromPointCloud(pcl::PointCloud<pcl::PointXYZI>::Ptr cloud, std::string dimensionToRemove, float stepSize1, float stepSize2)
{
pcl::PointXYZI cloudMin, cloudMax;
pcl::getMinMax3D(*cloud, cloudMin, cloudMax);
std::string dimen1, dimen2;
float dimen1Max, dimen1Min, dimen2Min, dimen2Max;
if (dimensionToRemove == "x")
{
dimen1 = "y";
dimen2 = "z";
dimen1Min = cloudMin.y;
dimen1Max = cloudMax.y;
dimen2Min = cloudMin.z;
dimen2Max = cloudMax.z;
}
else if (dimensionToRemove == "y")
{
dimen1 = "x";
dimen2 = "z";
dimen1Min = cloudMin.x;
dimen1Max = cloudMax.x;
dimen2Min = cloudMin.z;
dimen2Max = cloudMax.z;
}
else if (dimensionToRemove == "z")
{
dimen1 = "x";
dimen2 = "y";
dimen1Min = cloudMin.x;
dimen1Max = cloudMax.x;
dimen2Min = cloudMin.y;
dimen2Max = cloudMax.y;
}
std::vector<std::vector<int>> pointCountGrid;
int maxPoints = 0;
std::vector<pcl::PointCloud<pcl::PointXYZI>::Ptr> grid;
for (float i = dimen1Min; i < dimen1Max; i += stepSize1)
{
pcl::PointCloud<pcl::PointXYZI>::Ptr slice = passThroughFilter1D(cloud, dimen1, i, i + stepSize1);
grid.push_back(slice);
std::vector<int> slicePointCount;
for (float j = dimen2Min; j < dimen2Max; j += stepSize2)
{
pcl::PointCloud<pcl::PointXYZI>::Ptr grid_cell = passThroughFilter1D(slice, dimen2, j, j + stepSize2);
int gridSize = grid_cell->size();
slicePointCount.push_back(gridSize);
if (gridSize > maxPoints)
{
maxPoints = gridSize;
}
}
pointCountGrid.push_back(slicePointCount);
}
cv::Mat mat(static_cast<int>(pointCountGrid.size()), static_cast<int>(pointCountGrid.at(0).size()), CV_8UC1);
mat = cv::Scalar(0);
for (int i = 0; i < mat.rows; ++i)
{
for (int j = 0; j < mat.cols; ++j)
{
int pointCount = pointCountGrid.at(i).at(j);
float percentOfMax = (pointCount + 0.0) / (maxPoints + 0.0);
int intensity = percentOfMax * 255;
mat.at<uchar>(i, j) = intensity;
}
}
return mat;
}

How tu put B, G and R component value straight into a pixel of cv::Mat? [duplicate]

I have searched internet and stackoverflow thoroughly, but I haven't found answer to my question:
How can I get/set (both) RGB value of certain (given by x,y coordinates) pixel in OpenCV? What's important-I'm writing in C++, the image is stored in cv::Mat variable. I know there is an IplImage() operator, but IplImage is not very comfortable in use-as far as I know it comes from C API.
Yes, I'm aware that there was already this Pixel access in OpenCV 2.2 thread, but it was only about black and white bitmaps.
EDIT:
Thank you very much for all your answers. I see there are many ways to get/set RGB value of pixel. I got one more idea from my close friend-thanks Benny! It's very simple and effective. I think it's a matter of taste which one you choose.
Mat image;
(...)
Point3_<uchar>* p = image.ptr<Point3_<uchar> >(y,x);
And then you can read/write RGB values with:
p->x //B
p->y //G
p->z //R
Try the following:
cv::Mat image = ...do some stuff...;
image.at<cv::Vec3b>(y,x); gives you the RGB (it might be ordered as BGR) vector of type cv::Vec3b
image.at<cv::Vec3b>(y,x)[0] = newval[0];
image.at<cv::Vec3b>(y,x)[1] = newval[1];
image.at<cv::Vec3b>(y,x)[2] = newval[2];
The low-level way would be to access the matrix data directly. In an RGB image (which I believe OpenCV typically stores as BGR), and assuming your cv::Mat variable is called frame, you could get the blue value at location (x, y) (from the top left) this way:
frame.data[frame.channels()*(frame.cols*y + x)];
Likewise, to get B, G, and R:
uchar b = frame.data[frame.channels()*(frame.cols*y + x) + 0];
uchar g = frame.data[frame.channels()*(frame.cols*y + x) + 1];
uchar r = frame.data[frame.channels()*(frame.cols*y + x) + 2];
Note that this code assumes the stride is equal to the width of the image.
A piece of code is easier for people who have such problem. I share my code and you can use it directly. Please note that OpenCV store pixels as BGR.
cv::Mat vImage_;
if(src_)
{
cv::Vec3f vec_;
for(int i = 0; i < vHeight_; i++)
for(int j = 0; j < vWidth_; j++)
{
vec_ = cv::Vec3f((*src_)[0]/255.0, (*src_)[1]/255.0, (*src_)[2]/255.0);//Please note that OpenCV store pixels as BGR.
vImage_.at<cv::Vec3f>(vHeight_-1-i, j) = vec_;
++src_;
}
}
if(! vImage_.data ) // Check for invalid input
printf("failed to read image by OpenCV.");
else
{
cv::namedWindow( windowName_, CV_WINDOW_AUTOSIZE);
cv::imshow( windowName_, vImage_); // Show the image.
}
The current version allows the cv::Mat::at function to handle 3 dimensions. So for a Mat object m, m.at<uchar>(0,0,0) should work.
uchar * value = img2.data; //Pointer to the first pixel data ,it's return array in all values
int r = 2;
for (size_t i = 0; i < img2.cols* (img2.rows * img2.channels()); i++)
{
if (r > 2) r = 0;
if (r == 0) value[i] = 0;
if (r == 1)value[i] = 0;
if (r == 2)value[i] = 255;
r++;
}
const double pi = boost::math::constants::pi<double>();
cv::Mat distance2ellipse(cv::Mat image, cv::RotatedRect ellipse){
float distance = 2.0f;
float angle = ellipse.angle;
cv::Point ellipse_center = ellipse.center;
float major_axis = ellipse.size.width/2;
float minor_axis = ellipse.size.height/2;
cv::Point pixel;
float a,b,c,d;
for(int x = 0; x < image.cols; x++)
{
for(int y = 0; y < image.rows; y++)
{
auto u = cos(angle*pi/180)*(x-ellipse_center.x) + sin(angle*pi/180)*(y-ellipse_center.y);
auto v = -sin(angle*pi/180)*(x-ellipse_center.x) + cos(angle*pi/180)*(y-ellipse_center.y);
distance = (u/major_axis)*(u/major_axis) + (v/minor_axis)*(v/minor_axis);
if(distance<=1)
{
image.at<cv::Vec3b>(y,x)[1] = 255;
}
}
}
return image;
}

Un-Distort raw images received from the Leap motion cameras

I've been working with the leap for a long time now. 2.1.+ SDK version allows us to access the cameras and get raw images. I want to use those images with OpenCV for square/circle detection and stuff... the problem is i can't get those images undistorted. i read the docs, but don't quite get what they mean. here's one thing i need to understand properly before going forward
distortion_data_ = image.distortion();
for (int d = 0; d < image.distortionWidth() * image.distortionHeight(); d += 2)
{
float dX = distortion_data_[d];
float dY = distortion_data_[d + 1];
if(!((dX < 0) || (dX > 1)) && !((dY < 0) || (dY > 1)))
{
//what do i do now to undistort the image?
}
}
data = image.data();
mat.put(0, 0, data);
//Imgproc.Canny(mat, mat, 100, 200);
//mat = findSquare(mat);
ok.showImage(mat);
in the docs it says something like this "
The calibration map can be used to correct image distortion due to lens curvature and other imperfections. The map is a 64x64 grid of points. Each point consists of two 32-bit values....(the rest on the dev website)"
can someone explain this in detail please, OR OR, just post the java code to undistort the images give me an output MAT image so i may continue processing that (i'd still prefer a good explanation if possible)
Ok, I have no leap camera to test all this, but this is how I understand the documentation:
The calibration map does not hold offsets but full point positions. An entry says where the pixel has to be placed instead. Those values are mapped between 0 and 1, which means that you have to mutiply them by your real image width and height.
What isnt explained explicitly is, how you pixel positions are mapped to 64 x 64 positions of your calibration map. I assume that it's the same way: 640 pixels width are mapped to 64 pixels width and 240 pixels height are mapped to 64 pixels height.
So in general, to move from one of your 640 x 240 pixel positions (pX, pY) to the undistorted position you will:
compute corresponding pixel position in the calibration map: float cX = pX/640.0f * 64.0f; float cY = pY/240.0f * 64.0f;
(cX, cY) is now the locaion of that pixel in the calibration map. You will have to interpolate between two pixel locaions, but I will now only explain how to go on for a discrete location in the calibration map (cX', cY') = rounded locations of (cX, cY).
read the x and y values out of the calibration map: dX, dY as in the documentation. You have to compute the location in the array by: d = dY*calibrationMapWidth*2 + dX*2;
dX and dY are values between 0 and 1 (if not: dont undistort this point because there is no undistortion available. To find out the pixel location in your real image, multiply by the image size: uX = dX*640; uY = dY*240;
set your pixel to the undistorted value: undistortedImage(pX,pY) = distortedImage(uX,uY);
but you dont have discrete point positions in your calibration map, so you have to interpolate. I'll give you an example:
let be (cX,cY) = (13.7, 10.4)
so you read from your calibration map four values:
calibMap(13,10) = (dX1, dY1)
calibMap(14,10) = (dX2, dY2)
calibMap(13,11) = (dX3, dY3)
calibMap(14,11) = (dX4, dY4)
now your undistorted pixel position for (13.7, 10.4) is (multiply each with 640 or 240 to get uX1, uY1, uX2, etc):
// interpolate in x direction first:
float tmpUX1 = uX1*0.3 + uX2*0.7
float tmpUY1 = uY1*0.3 + uY2*0.7
float tmpUX2 = uX3*0.3 + uX4*0.7
float tmpUY2 = uY3*0.3 + uY4*0.7
// now interpolate in y direction
float combinedX = tmpUX1*0.6 + tmpUX2*0.4
float combinedY = tmpUY1*0.6 + tmpUY2*0.4
and your undistorted point is:
undistortedImage(pX,pY) = distortedImage(floor(combinedX+0.5),floor(combinedY+0.5)); or interpolate pixel values there too.
Hope this helps for a basic understanding. I'll try to add openCV remap code soon! The only point thats unclear for me is, whether the mapping between pX/Y and cX/Y is correct, cause thats not explicitly explained in the documentation.
Here is some code. You can skip the first part, where I am faking a distortion and creating the map, which is your initial state.
With openCV it is simple, just resize the calibration map to your image size and multiply all the values with your resolution. The nice thing is, that openCV performs the interpolation "automatically" while resizing.
int main()
{
cv::Mat input = cv::imread("../Data/Lenna.png");
cv::Mat distortedImage = input.clone();
// now i fake some distortion:
cv::Mat transformation = cv::Mat::eye(3,3,CV_64FC1);
transformation.at<double>(0,0) = 2.0;
cv::warpPerspective(input,distortedImage,transformation,input.size());
cv::imshow("distortedImage", distortedImage);
//cv::imwrite("../Data/LenaFakeDistorted.png", distortedImage);
// now fake a calibration map corresponding to my faked distortion:
const unsigned int cmWidth = 64;
const unsigned int cmHeight = 64;
// compute the calibration map by transforming image locations to values between 0 and 1 for legal positions.
float calibMap[cmWidth*cmHeight*2];
for(unsigned int y = 0; y < cmHeight; ++y)
for(unsigned int x = 0; x < cmWidth; ++x)
{
float xx = (float)x/(float)cmWidth;
xx = xx*2.0f; // this if from my fake distortion... this gives some values bigger than 1
float yy = (float)y/(float)cmHeight;
calibMap[y*cmWidth*2+ 2*x] = xx;
calibMap[y*cmWidth*2+ 2*x+1] = yy;
}
// NOW you have the initial situation of your scenario: calibration map and distorted image...
// compute the image locations of calibration map values:
cv::Mat cMapMatX = cv::Mat(cmHeight, cmWidth, CV_32FC1);
cv::Mat cMapMatY = cv::Mat(cmHeight, cmWidth, CV_32FC1);
for(int j=0; j<cmHeight; ++j)
for(int i=0; i<cmWidth; ++i)
{
cMapMatX.at<float>(j,i) = calibMap[j*cmWidth*2 +2*i];
cMapMatY.at<float>(j,i) = calibMap[j*cmWidth*2 +2*i+1];
}
//cv::imshow("mapX",cMapMatX);
//cv::imshow("mapY",cMapMatY);
// interpolate those values for each of your original images pixel:
// here I use linear interpolation, you could use cubic or other interpolation too.
cv::resize(cMapMatX, cMapMatX, distortedImage.size(), 0,0, CV_INTER_LINEAR);
cv::resize(cMapMatY, cMapMatY, distortedImage.size(), 0,0, CV_INTER_LINEAR);
// now the calibration map has the size of your original image, but its values are still between 0 and 1 (for legal positions)
// so scale to image size:
cMapMatX = distortedImage.cols * cMapMatX;
cMapMatY = distortedImage.rows * cMapMatY;
// now create undistorted image:
cv::Mat undistortedImage = cv::Mat(distortedImage.rows, distortedImage.cols, CV_8UC3);
undistortedImage.setTo(cv::Vec3b(0,0,0)); // initialize black
//cv::imshow("undistorted", undistortedImage);
for(int j=0; j<undistortedImage.rows; ++j)
for(int i=0; i<undistortedImage.cols; ++i)
{
cv::Point undistPosition;
undistPosition.x =(cMapMatX.at<float>(j,i)); // this will round the position, maybe you want interpolation instead
undistPosition.y =(cMapMatY.at<float>(j,i));
if(undistPosition.x >= 0 && undistPosition.x < distortedImage.cols
&& undistPosition.y >= 0 && undistPosition.y < distortedImage.rows)
{
undistortedImage.at<cv::Vec3b>(j,i) = distortedImage.at<cv::Vec3b>(undistPosition);
}
}
cv::imshow("undistorted", undistortedImage);
cv::waitKey(0);
//cv::imwrite("../Data/LenaFakeUndistorted.png", undistortedImage);
}
cv::Mat SelfDescriptorDistances(cv::Mat descr)
{
cv::Mat selfDistances = cv::Mat::zeros(descr.rows,descr.rows, CV_64FC1);
for(int keyptNr = 0; keyptNr < descr.rows; ++keyptNr)
{
for(int keyptNr2 = 0; keyptNr2 < descr.rows; ++keyptNr2)
{
double euclideanDistance = 0;
for(int descrDim = 0; descrDim < descr.cols; ++descrDim)
{
double tmp = descr.at<float>(keyptNr,descrDim) - descr.at<float>(keyptNr2, descrDim);
euclideanDistance += tmp*tmp;
}
euclideanDistance = sqrt(euclideanDistance);
selfDistances.at<double>(keyptNr, keyptNr2) = euclideanDistance;
}
}
return selfDistances;
}
I use this as input and fake a remap/distortion from which I compute my calib mat:
input:
faked distortion:
used the map to undistort the image:
TODO: after those computatons use a opencv map with those values to perform faster remapping.
Here's an example on how to do it without using OpenCV. The following seems to be faster than using the Leap::Image::warp() method (probably due to the additional function call overhead when using warp()):
float destinationWidth = 320;
float destinationHeight = 120;
unsigned char destination[(int)destinationWidth][(int)destinationHeight];
//define needed variables outside the inner loop
float calX, calY, weightX, weightY, dX1, dX2, dX3, dX4, dY1, dY2, dY3, dY4, dX, dY;
int x1, x2, y1, y2, denormalizedX, denormalizedY;
int x, y;
const unsigned char* raw = image.data();
const float* distortion_buffer = image.distortion();
//Local variables for values needed in loop
const int distortionWidth = image.distortionWidth();
const int width = image.width();
const int height = image.height();
for (x = 0; x < destinationWidth; x++) {
for (y = 0; y < destinationHeight; y++) {
//Calculate the position in the calibration map (still with a fractional part)
calX = 63 * x/destinationWidth;
calY = 63 * y/destinationHeight;
//Save the fractional part to use as the weight for interpolation
weightX = calX - truncf(calX);
weightY = calY - truncf(calY);
//Get the x,y coordinates of the closest calibration map points to the target pixel
x1 = calX; //Note truncation to int
y1 = calY;
x2 = x1 + 1;
y2 = y1 + 1;
//Look up the x and y values for the 4 calibration map points around the target
// (x1, y1) .. .. .. (x2, y1)
// .. ..
// .. (x, y) ..
// .. ..
// (x1, y2) .. .. .. (x2, y2)
dX1 = distortion_buffer[x1 * 2 + y1 * distortionWidth];
dX2 = distortion_buffer[x2 * 2 + y1 * distortionWidth];
dX3 = distortion_buffer[x1 * 2 + y2 * distortionWidth];
dX4 = distortion_buffer[x2 * 2 + y2 * distortionWidth];
dY1 = distortion_buffer[x1 * 2 + y1 * distortionWidth + 1];
dY2 = distortion_buffer[x2 * 2 + y1 * distortionWidth + 1];
dY3 = distortion_buffer[x1 * 2 + y2 * distortionWidth + 1];
dY4 = distortion_buffer[x2 * 2 + y2 * distortionWidth + 1];
//Bilinear interpolation of the looked-up values:
// X value
dX = dX1 * (1 - weightX) * (1- weightY) + dX2 * weightX * (1 - weightY) + dX3 * (1 - weightX) * weightY + dX4 * weightX * weightY;
// Y value
dY = dY1 * (1 - weightX) * (1- weightY) + dY2 * weightX * (1 - weightY) + dY3 * (1 - weightX) * weightY + dY4 * weightX * weightY;
// Reject points outside the range [0..1]
if((dX >= 0) && (dX <= 1) && (dY >= 0) && (dY <= 1)) {
//Denormalize from [0..1] to [0..width] or [0..height]
denormalizedX = dX * width;
denormalizedY = dY * height;
//look up the brightness value for the target pixel
destination[x][y] = raw[denormalizedX + denormalizedY * width];
} else {
destination[x][y] = -1;
}
}
}

HSV values using openCV or javaCV

I want to track a color within an image. I use the following code (javaCV):
//Load initial image.
iplRGB = cvLoadImage(imageFile, CV_LOAD_IMAGE_UNCHANGED);
//Prepare for HSV
iplHSV = cvCreateImage(iplRGB.cvSize(), iplRGB.depth(), iplRGB.nChannels());
//Transform RGB to HSV
cvCvtColor(iplRGB, iplHSV, CV_BGR2HSV);
//Define a region of interest.
//minRow = 0; maxRow = iplHSV.height();
//minCol = 0; maxCol = iplHSV.width();
minRow = 197; minCol = 0; maxRow = 210; maxCol = 70;
//Print each HSV for each pixel of the region.
for (int y = minRow; y < maxRow; y++){
for (int x = minCol; x < maxCol; x++) {
CvScalar pixelHsv = cvGet2D(iplHSV, y, x);
double h = pixelHsv.val(0);
double s = pixelHsv.val(1);
double v = pixelHsv.val(2);
String line = y + "," + x + "," + h + "," + s + "," + v;
System.out.println(line);
}
}
I can easily find out the minimum and maximum for HUE and SAT from the output. Let's call then minHue, minSat, maxHue and maxSat (not fancy hey !). Then I execute this code:
iplMask = cvCreateImage(iplHSV.cvSize(), iplHSV.depth(), 1);
CvScalar min = cvScalar(minHue, minSat, 0, 0);
CvScalar max = cvScalar(maxHue, maxSat, 255 ,0);
cvInRangeS(iplHSV, min, max, iplMask);
When I show the iplMask, should not I see the region of interest entirely white ? I don't, I see the contour being white but the inside of the rectangle is black. I must mess with something but I do not understand what.
I know that Hue is in [0..179] with OpenCV and Sat and Val are in [0..255] but since I use the values displayed by openCV I would think I do not have to rescale...
Anyway, I am lost. Can somebody explain ? Thanks.

Search for lines with a small range of angles in OpenCV

I'm using the Hough transform in OpenCV to detect lines. However, I know in advance that I only need lines within a very limited range of angles (about 10 degrees or so). I'm doing this in a very performance sensitive setting, so I'd like to avoid the extra work spent detecting lines at other angles, lines I know in advance I don't care about.
I could extract the Hough source from OpenCV and just hack it to take min_rho and max_rho parameters, but I'd like a less fragile approach (have to manually update my code w/ each OpenCV update, etc.).
What's the best approach here?
Well, i've modified the icvHoughlines function to go for a certain range of angles. I'm sure there's cleaner ways that plays with memory allocation as well, but I got a speed gain going from 100ms to 33ms for a range of angle going from 180deg to 60deg, so i'm happy with that.
Note that this code also outputs the accumulator value. Also, I only output 1 line because that fit my purposes but there was no gain really there.
static void
icvHoughLinesStandard2( const CvMat* img, float rho, float theta,
int threshold, CvSeq *lines, int linesMax )
{
cv::AutoBuffer<int> _accum, _sort_buf;
cv::AutoBuffer<float> _tabSin, _tabCos;
const uchar* image;
int step, width, height;
int numangle, numrho;
int total = 0;
float ang;
int r, n;
int i, j;
float irho = 1 / rho;
double scale;
CV_Assert( CV_IS_MAT(img) && CV_MAT_TYPE(img->type) == CV_8UC1 );
image = img->data.ptr;
step = img->step;
width = img->cols;
height = img->rows;
numangle = cvRound(CV_PI / theta);
numrho = cvRound(((width + height) * 2 + 1) / rho);
_accum.allocate((numangle+2) * (numrho+2));
_sort_buf.allocate(numangle * numrho);
_tabSin.allocate(numangle);
_tabCos.allocate(numangle);
int *accum = _accum, *sort_buf = _sort_buf;
float *tabSin = _tabSin, *tabCos = _tabCos;
memset( accum, 0, sizeof(accum[0]) * (numangle+2) * (numrho+2) );
// find n and ang limits (in our case we want 60 to 120
float limit_min = 60.0/180.0*PI;
float limit_max = 120.0/180.0*PI;
//num_steps = (limit_max - limit_min)/theta;
int start_n = floor(limit_min/theta);
int stop_n = floor(limit_max/theta);
for( ang = limit_min, n = start_n; n < stop_n; ang += theta, n++ )
{
tabSin[n] = (float)(sin(ang) * irho);
tabCos[n] = (float)(cos(ang) * irho);
}
// stage 1. fill accumulator
for( i = 0; i < height; i++ )
for( j = 0; j < width; j++ )
{
if( image[i * step + j] != 0 )
//
for( n = start_n; n < stop_n; n++ )
{
r = cvRound( j * tabCos[n] + i * tabSin[n] );
r += (numrho - 1) / 2;
accum[(n+1) * (numrho+2) + r+1]++;
}
}
int max_accum = 0;
int max_ind = 0;
for( r = 0; r < numrho; r++ )
{
for( n = start_n; n < stop_n; n++ )
{
int base = (n+1) * (numrho+2) + r+1;
if (accum[base] > max_accum)
{
max_accum = accum[base];
max_ind = base;
}
}
}
CvLinePolar2 line;
scale = 1./(numrho+2);
int idx = max_ind;
n = cvFloor(idx*scale) - 1;
r = idx - (n+1)*(numrho+2) - 1;
line.rho = (r - (numrho - 1)*0.5f) * rho;
line.angle = n * theta;
line.votes = accum[idx];
cvSeqPush( lines, &line );
}
If you use the Probabilistic Hough transform then the output is in the form of a cvPoint each for lines[0] and lines[1] parameters. We can get x and y co-ordinated for each of the two points by pt1.x, pt1.y and pt2.x and pt2.y.
Then use the simple formula for finding slope of a line - (y2-y1)/(x2-x1). Taking arctan (tan inverse) of that will yield that angle in radians. Then simply filter out desired angles from the values for each hough line obtained.
I think it's more natural to use standart HoughLines(...) function, which gives collection of lines directly in rho and theta terms and select nessessary angle range from it, rather than recalculate angle from segment end points.

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