Creepify text - Combining characters - ios

I want to create creepify text in my app with js code (creepify())
https://github.com/combatwombat/Lunicode.js/blob/master/lunicode.js
website using this js code: http://lunicode.com/creepify
My problem is when i try to combine characters, the result is'nt like in website.
I try to create 3 NSMutableArray
NSMutableArray *diacriticsTop;
NSMutableArray *diacriticsMiddle;
NSMutableArray *diacriticsBottom;
and store value like this
for (int i = 768; i <= 789; i++) {
[diacriticsTop addObject:[NSNumber numberWithInt:i]];
}
for (int i = 790; i <= 819; i++) {
if (i != 794 && i != 795) {
[diacriticsBottom addObject:[NSNumber numberWithInt:i]];
}
}
...
then i convert creepify() in js code to
- (NSString *)creepifyString:(NSString *)inputString
{
BOOL isTop = YES;
BOOL isMiddle = YES;
BOOL isBottom = YES;
NSInteger maxHeight = 15;
NSInteger randomization = 100;
NSMutableString *outputString = [[NSMutableString alloc] init];
unichar output = 0;
for (int i = 0; i < inputString.length; i++) {
unichar c = [inputString characterAtIndex:i];
if (isMiddle) {
NSNumber *temp = diacriticsMiddle[lroundf(drand48()*diacriticsMiddle.count)];
c = c + (unichar) temp;
}
// Top
if (isTop) {
// Put up to this.options.maxHeight random diacritics on top.
// optionally fluctuate the number via the randomization value (0-100%)
// randomization 100%: 0 to maxHeight
// 30%: 70% of maxHeight to maxHeight
// x%: 100-x% of maxHeight to maxHeight
int diacriticsTopLength = diacriticsTop.count - 1;
for (int count = 0,
len = maxHeight - drand48()*((randomization/100)*maxHeight); count < len; count++) {
NSNumber *temp = diacriticsTop[lroundf(drand48()*diacriticsTopLength)];
c = c + (unichar) temp;
}
}
// Bottom
if (isBottom) {
int diacriticsBottomLength = diacriticsBottom.count - 1;
for (int count = 0,
len = maxHeight - drand48()*((randomization/100)*maxHeight); count < len; count++) {
NSNumber *temp =diacriticsBottom[lroundf(drand48()*diacriticsBottomLength)];
c = c + (unichar) temp;
}
}
output = output + c;
}
[outputString appendFormat:#"%C", output];
NSLog(#"%#", outputString);
return outputString;
}

Related

Create array of negative numbers in Objective C

I have created an array of positive, negative and zero numbers but it treats all the elements in the array as positive numbers. Here in code, the positiveCount is 6. How to put negative numbers in an array in Objective-C?
NSInteger positiveCount = 0;
NSInteger zeroCount = 0;
NSInteger negativeCount = 0;
NSArray *arr = [NSArray arrayWithObjects:#-4,#-3,#-9,#0,#4,#1, nil];
for (NSInteger i = 0; i < arr.count; i++){
NSLog(#"%d",arr[i]);
if (arr[i] > 0)
{
positiveCount += 1;
} else if (arr[i] < 0){
negativeCount += 1;
} else {
zeroCount += 1;
}
}
NSLog(#"%d",positiveCount);
The elements in your array are not numbers, they are NSNumber instances, that is, pointers. Pointers are always positive:
for (NSNumber* number in arr) {
NSInteger intValue = number.integerValue;
NSLog(#"%d", intValue);
if (intValue > 0) {
positiveCount += 1;
} else if (intValue < 0) {
negativeCount += 1;
} else {
zeroCount += 1;
}
}
One more way for the solution using enumerateObjectsUsingBlock,
__block NSInteger positiveCount = 0;
__block NSInteger zeroCount = 0;
__block NSInteger negativeCount = 0;
NSArray *arr = [NSArray arrayWithObjects:#-4,#-3,#-9,#0,#4,#1, nil];
[arr enumerateObjectsUsingBlock:^(id _Nonnull obj, NSUInteger idx, BOOL * _Nonnull stop) {
NSInteger value = ((NSNumber *)obj).integerValue;
if (value > 0) {
positiveCount += 1;
} else if (value < 0) {
negativeCount += 1;
} else {
zeroCount += 1;
}
}];
NSLog(#"%ld",(long)positiveCount);

How to compare two numbers and pick the smallest to proceed with execution?

Let say number = 0 and otherNumber = 10. The loop will execute. But what if number = 10 and otherNumber = 0. I want the compiler to pick the smallest number and use it to proceed.
The code I have so far is here:
- (NSString *) stringWithNumbersBetweenNumber:(NSInteger)number andOtherNumber: (NSInteger)otherNumber {
if (number <= otherNumber) {
NSMutableString *indices = [NSMutableString stringWithCapacity:1];
for (NSInteger i= number; i <= otherNumber; i++) {
[indices appendFormat:#"%d", i];
}
} else {
NSMutableString *indices = [NSMutableString stringWithCapacity:1];
for (NSInteger i= otherNumber; i <= number; i++) {
[indices appendFormat:#"%d", i];
}
}
return #"%#", indices;
}
A simple fix is to move the declaration of indices outside the conditional:
- (NSString *) stringWithNumbersBetweenNumber:(NSInteger)number andOtherNumber: (NSInteger)otherNumber {
NSMutableString *indices = [NSMutableString stringWithCapacity:1];
if (number <= otherNumber) {
for (NSInteger i= number; i <= otherNumber; i++) {
[indices appendFormat:#"%d", i];
}
} else {
for (NSInteger i= otherNumber; i <= number; i++) {
[indices appendFormat:#"%d", i];
}
}
return indices;
}
You could further unify your like this:
- (NSString *) stringWithNumbersBetweenNumber:(NSInteger)number andOtherNumber: (NSInteger)otherNumber {
NSInteger from, to;
if (number <= otherNumber) {
from = number;
to = otherNumber;
} else {
from = otherNumber;
to = number;
}
NSMutableString *indices = [NSMutableString stringWithCapacity:1];
for (NSInteger i= from; i <= tp; i++) {
[indices appendFormat:#"%d", i];
}
return indices;
}
One option would be:
- (NSString *) stringWithNumbersBetweenNumber:(NSInteger)number andOtherNumber: (NSInteger)otherNumber {
NSInteger minNum = MIN(number, otherNumber);
NSInteger maxNum = MAX(number, otherNumber);
NSMutableString *indices = [NSMutableString stringWithCapacity:maxNum - minNum + 1];
for (NSInteger i = minNum; i <= maxNum; i++) {
[indices appendFormat:#"%d", i];
}
return indices; // or [indices copy];
}
Pick one of the variables to always be considered the larger variable, and then do a simple swap-test before the function body proper.
- (NSString *) stringWithNumbersBetweenNumber:(NSInteger)number andOtherNumber: (NSInteger)otherNumber {
if (number < otherNumber) {
NSInteger temp = number;
number = otherNumber;
otherNumber = temp;
}
NSMutableString *indices = [NSMutableString stringWithCapacity:1];
for (NSInteger i= otherNumber; i <= number; i++) {
[indices appendFormat:#"%d", i];
}
return #"%#", indices;
}
(Apologies for any code errors, Objective-C isn't my primary language)

Find the highest repeated character in string and the count of the repeated character

I need to get the highest repeated character in string and the count of the repeated character.
For that i stored the each character of the string in the array and using the for loops i got each character and the count. is there any other delegate methods to find it to reduce the code?
for example
NSRange theRange = {0, 1}; //{location, length}
NSMutableArray * array = [NSMutableArray array];
for ( NSInteger i = 0; i < [myFormattedString length]; i++) {
theRange.location = i;
[array addObject:[myFormattedString substringWithRange:theRange]];
}
int countForChar = 0;
for (int i=0; i<[array count]; i++) {
NSString *firstCharacter = [array objectAtIndex:i];
for (int j=1; j< [array count]; j++) {
if ([firstCharacter isEqualToString:[array objectAtIndex:j]]) {
countForChar = countForChar + 1;
}
}
NSLog(#"The Charcter is %# The count is %d", firstCharacter, countForChar);
countForChar = 0;
}
Thanks in advance...
Because the string may have more than a char have same most repeat count, so here is my solution:
- (NSArray *)mostCharInString:(NSString *)string count:(int *)count{
NSMutableDictionary *dict = [NSMutableDictionary dictionary];
int len = string.length;
NSRange theRange = {0, 1};
for (NSInteger i = 0; i < len; i++) {
theRange.location = i;
NSString *charStr = [string substringWithRange:theRange];
int preCount = 0;
if ([dict objectForKey:charStr]) {
preCount = [[dict objectForKey:charStr] unsignedIntegerValue];
}
[dict setObject:#(preCount+1) forKey:charStr];
}
NSArray *sortValues = [[dict allValues] sortedArrayUsingSelector:#selector(compare:)];
*count = [[sortValues lastObject] unsignedIntegerValue];
return [dict allKeysForObject:#(*count)];
}
How to use and test:
int mostRepeatCount = 0;
NSArray *mostChars = nil;
mostChars = [self mostCharInString:#"aaabbbcccc" count:&mostRepeatCount];
NSLog(#"count:%d char:%#", mostRepeatCount, mostChars);
the result is:
count:4 char:(
c
)
try:
mostChars = [self mostCharInString:#"aaabbbccccdddd" count:&mostRepeatCount];
the result is:
count:4 char:(
d,
c
)
Hope to help you.
Here is my code might be not good enough but I think its the fastest
NSString *myFormattedString = #"oksdflajdsfd";
NSMutableDictionary *lettersCount = [[NSMutableDictionary alloc] init];
for (NSInteger i = 0; i < [myFormattedString length]; i++) {
unichar charAtIndex = [myFormattedString characterAtIndex:i];
NSNumber *countForThisChar = [lettersCount objectForKey:[NSString stringWithFormat:#"%c",charAtIndex]];
int count = 1;
if(countForThisChar) {
count = [countForThisChar integerValue] + 1;
[lettersCount setObject:#(count) forKey:[NSString stringWithFormat:#"%c",charAtIndex]];
} else {
// not added yet, add it with 1 count
[lettersCount setObject:#(count) forKey:[NSString stringWithFormat:#"%c",charAtIndex]];
}
}
// for now the work is O(n)
// ignoring the work of this cycle or consider it as O(1)
NSString *mostFrequentChar = nil;
NSInteger maxCount = 0;
for(NSString *oneChar in lettersCount.keyEnumerator) {
NSNumber *count = [lettersCount objectForKey:oneChar];
if([count integerValue] > maxCount) {
mostFrequentChar = oneChar;
maxCount = [count integerValue];
}
}
NSLog(#"the char %# met for %d times", mostFrequentChar, maxCount);
Remember the search for an object in NsDictionary is O(1) for the average case scenario.
Here is an example that would work correctly with any string and has linear time complexity. This uses the NSCountedSet which can be pretty useful.
NSString* string = #"This is a very wonderful string. Ølsen & ジェイソン";
NSCountedSet* characterCounts = [[NSCountedSet alloc] init];
// This ensures that we deal with all unicode code points correctly
[string enumerateSubstringsInRange:NSMakeRange(0, [string length]) options:NSStringEnumerationByComposedCharacterSequences usingBlock:^(NSString *substring, NSRange substringRange, NSRange enclosingRange, BOOL *stop) {
[characterCounts addObject:substring];
}];
NSString* highestCountCharacterSequence = nil;
NSUInteger highestCharacterCount = 0;
for (NSString* characterSequence in characterCounts) {
NSUInteger currentCount = [characterCounts countForObject:characterSequence];
if (currentCount > highestCharacterCount) {
highestCountCharacterSequence = characterSequence;
highestCharacterCount = currentCount;
}
}
NSLog(#"Highest Character Count is %# with count of %lu", highestCountCharacterSequence, (unsigned long)highestCharacterCount);
Sadly, my silly example string ends up having space characters as the most repeated :)
Every character can be presented by its int value. Make an instance of NSArray with n size (n number of unique characters string can have). Loop through string and add +1 on (int)character index in array at every cycle. When you finish the character with greatest value in array is the highest repeated character.

I want the loop of numbers in pyramid pattern by edit form code below

I want to change the following code
NSString* loop = #"";
for (int i = 1; i <= 5; i++)
{
loop = [loop stringByAppendingString:#"0"];
NSLog(#" %#", loop);
}
for (int i = 10; i >= 1; i--)
{
loop = [loop substringFromIndex:1];
NSLog(#" &#", loop);
}
to be result in the pattern of pyramid below. What should I do?
1
101
21012
3210123
432101234
and
0
01
012
0123
01234
012345
01234
0123
012
01
0
For second pattern you can use code:
NSString *loop=#"";
for (int i = 0; i <= 10; i++) {
if (i > 5) {
loop = [loop substringToIndex:[loop length] - 1];
}
else {
loop = [loop stringByAppendingString:[NSString stringWithFormat:#"%i", i]];
}
NSLog (#" %#" , loop);
}
For first
NSString *loop = #"";
NSString *spaces = #" ";
for (int i = 1; i <= 5; i++)
{
if (i==1) {
loop = [loop stringByAppendingString:[NSString stringWithFormat:#"%#%i", [spaces substringFromIndex:i], i - 1]];
} else {
loop = [loop substringFromIndex:6 - i];
loop = [[NSString stringWithFormat:#"%#%i",[spaces substringFromIndex:i], i - 1] stringByAppendingString:[loop stringByAppendingString:[NSString stringWithFormat:#"%i", i - 1]]];
}
NSLog(#" %#", loop);
}

How to delete the number from non repeating number array?

I am trying this code for generating a random number and saving the list of numbers in an array, then i am trying to delete those numbers from the list one by one which appeared once, e.g
1, 5, 9 , 4, 3, 7 ,6 ,10, 11, 8, 2 are the list of integers now 9 is appeared once and now i do not need 9 again.. this is my code of random non repeating numbers array.
NSMutableArray *storeArray = [[NSMutableArray alloc] init];
BOOL record = NO;
int x;
for (int i=0; [storeArray count] < 10; i++) //Loop for generate different random values
{
x = arc4random() % 10;//generating random number
if(i==0)//for first time
{
[storeArray addObject:[NSNumber numberWithInt:x]];
}
else
{
for (int j=0; j<= [storeArray count]-1; j++)
{
if (x ==[[storeArray objectAtIndex:j] intValue])
record = YES;
}
if (record == YES)
{
record = NO;
}
else
{
[storeArray addObject:[NSNumber numberWithInt:x]];
}
}
}
Try this,
NSArray *arrRandoms = [[NSArray alloc]initWithObjects:1,5,8,7,36,17,96,32,5,7,8,13,36,nil] ; // This contains your random numbers
NSMutableArray *arrFresh = [[NSMutableArray alloc]init];
// Now removing the duplicate numbers
BOOL checkRepeat = NO;
int _Current;
for (int i=0; i<[arrRandoms count]; i++)
{
_Current = [arrRandoms objectAtIndex:i];
if (i == 0)
[arrFresh addObjects:_Current];
else
{
checkRepeat = NO;
for(int j=0; j< [arrFresh count]; j++)
{
if ( _Current == [arrFresh objectAtIndex:j])
checkRepeat = YES;
}
if (checkRepeat == NO)
[arrFresh addObjects:_Current];
}
}
I think this code will work. Check It.
try it
//**************remove repeat objects from array***************************//
NSArray *noDuplicates = [[NSSet setWithArray: yourArray] allObjects];
you add
.h file
BOOL isSame;
NSMutableArray *countArray;
NSInteger randomNumber;
.m file
countArray=[[NSMutableArray alloc]init];
//get randon no
-(NSInteger)getRandomNo:(NSInteger)range
{
isSame=TRUE;
while (isSame){
isSame = FALSE;
randomNumber = arc4random() % range;
for (NSNumber *number in countArray){
if([number intValue] ==randomNumber){
isSame = TRUE;
break;
}
}
}
[countArray addObject:[NSNumber numberWithInt:randomNumber]];
return randomNumber;
}
Tested Please try this,
NSMutableArray *storeArray = [[NSMutableArray alloc] init];
NSMutableSet * setUnique = [[NSMutableSet alloc] init];
for (int i=0; [setUnique count] < 10; i++) //Loop for generate different random values
{
[setUnique addObject:[NSNumber numberWithInt:arc4random() % 10]];
}
storeArray = [[setUnique allObjects] mutableCopy];
// check this how to get random number in array (i.e.. this array(below arr_numbers) contain non repeated number)
// for general purpose i am posting this.. so people cannot check for another answer
int num_count = 10;
int RandomNumber;
NSMutableArray *arr_numbers = [[NSMutableArray alloc] init];
for (int j =0; j < num_count; j++)
{
RandomNumber = 0 + arc4random() % num_count;
NSLog(#"%d",RandomNumber);
if ([arr_numbers count]>0)
{
if (![arr_numbers containsObject:[NSNumber numberWithInt:RandomNumber]])//
{
[arr_numbers addObject:[NSNumber numberWithInt:RandomNumber]];
}
if (j == num_count-1)
{
if ([arr_numbers count] != num_count)
{
j = 0;
}
}
}
else
{
[arr_numbers addObject:[NSNumber numberWithInt:RandomNumber]];
}
}
NSLog(#"%#",arr_numbers);

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