How to delete the number from non repeating number array? - ios

Question

I am trying this code for generating a random number and saving the list of numbers in an array, then i am trying to delete those numbers from the list one by one which appeared once, e.g
1, 5, 9 , 4, 3, 7 ,6 ,10, 11, 8, 2 are the list of integers now 9 is appeared once and now i do not need 9 again.. this is my code of random non repeating numbers array.
NSMutableArray *storeArray = [[NSMutableArray alloc] init];
BOOL record = NO;
int x;
for (int i=0; [storeArray count] < 10; i++) //Loop for generate different random values
{
x = arc4random() % 10;//generating random number
if(i==0)//for first time
{
[storeArray addObject:[NSNumber numberWithInt:x]];
}
else
{
for (int j=0; j<= [storeArray count]-1; j++)
{
if (x ==[[storeArray objectAtIndex:j] intValue])
record = YES;
}
if (record == YES)
{
record = NO;
}
else
{
[storeArray addObject:[NSNumber numberWithInt:x]];
}
}
}

Answer 1

Try this,
NSArray *arrRandoms = [[NSArray alloc]initWithObjects:1,5,8,7,36,17,96,32,5,7,8,13,36,nil] ; // This contains your random numbers
NSMutableArray *arrFresh = [[NSMutableArray alloc]init];
// Now removing the duplicate numbers
BOOL checkRepeat = NO;
int _Current;
for (int i=0; i<[arrRandoms count]; i++)
{
_Current = [arrRandoms objectAtIndex:i];
if (i == 0)
[arrFresh addObjects:_Current];
else
{
checkRepeat = NO;
for(int j=0; j< [arrFresh count]; j++)
{
if ( _Current == [arrFresh objectAtIndex:j])
checkRepeat = YES;
}
if (checkRepeat == NO)
[arrFresh addObjects:_Current];
}
}
I think this code will work. Check It.

Answer 2

try it
//**************remove repeat objects from array***************************//
NSArray *noDuplicates = [[NSSet setWithArray: yourArray] allObjects];

Answer 3

you add
.h file
BOOL isSame;
NSMutableArray *countArray;
NSInteger randomNumber;
.m file
countArray=[[NSMutableArray alloc]init];
//get randon no
-(NSInteger)getRandomNo:(NSInteger)range
{
isSame=TRUE;
while (isSame){
isSame = FALSE;
randomNumber = arc4random() % range;
for (NSNumber *number in countArray){
if([number intValue] ==randomNumber){
isSame = TRUE;
break;
}
}
}
[countArray addObject:[NSNumber numberWithInt:randomNumber]];
return randomNumber;
}

Answer 4

Tested Please try this,
NSMutableArray *storeArray = [[NSMutableArray alloc] init];
NSMutableSet * setUnique = [[NSMutableSet alloc] init];
for (int i=0; [setUnique count] < 10; i++) //Loop for generate different random values
{
[setUnique addObject:[NSNumber numberWithInt:arc4random() % 10]];
}
storeArray = [[setUnique allObjects] mutableCopy];

Answer 5

// check this how to get random number in array (i.e.. this array(below arr_numbers) contain non repeated number)
// for general purpose i am posting this.. so people cannot check for another answer
int num_count = 10;
int RandomNumber;
NSMutableArray *arr_numbers = [[NSMutableArray alloc] init];
for (int j =0; j < num_count; j++)
{
RandomNumber = 0 + arc4random() % num_count;
NSLog(#"%d",RandomNumber);
if ([arr_numbers count]>0)
{
if (![arr_numbers containsObject:[NSNumber numberWithInt:RandomNumber]])//
{
[arr_numbers addObject:[NSNumber numberWithInt:RandomNumber]];
}
if (j == num_count-1)
{
if ([arr_numbers count] != num_count)
{
j = 0;
}
}
}
else
{
[arr_numbers addObject:[NSNumber numberWithInt:RandomNumber]];
}
}
NSLog(#"%#",arr_numbers);