Find record with LIKE on partial attribute - ruby-on-rails

In my app I have invoice numbers like this:
2014.DEV.0001
2014.DEV.0002
2014.TSZ.0003
The three character code is a company code. When a new invoice number needs to be assigned it should look for the last used invoice number for that specific company code and add one to it.
I know the company code, I use a LIKE to search on a partial invoice number like this:
last = Invoice.where("invoice_nr LIKE ?", "#{DateTime.now.year}.#{company_short}.").last
This results in this SQL query:
SELECT "invoices".* FROM "invoices" WHERE "invoices"."account_id" = 1 AND (invoice_nr LIKE '2014.TSZ.') ORDER BY "invoices"."id" DESC LIMIT 1
But unfortunately it doesn't return any results. Any idea to improve this, as searching with LIKE doesn't seem to be correct?

Try wrapping string with % and use lower to convert the query string and result into downcase to avoid any wrong results due to case, try this
last = Invoice.where("lower(invoice_nr) LIKE lower(?)", "%#{DateTime.now.year}.#{company_short}.%").last

You want % for partial match
last = Invoice.where("invoice_nr LIKE ?", "%#{DateTime.now.year}.#{company_short}.%").last

Since you want to match only the left part you need to add one % at the right part of your string
Invoice.where("invoice_nr LIKE ?", "#{DateTime.now.year}.#{company_short}.%").last

Related

How to use ilike for phone number filter

Hi im fetching the user input and displaying the records that matches the condition, my query will look like
customers = customers.where('customers.contact_num ilike :search', {search: "%#{options[:search_contact]}%"})
here in db the contact number is stored in string with the format (091)-234-5678 like that
on while searching the user on basis of contact number if i search like this
091 it filters the number correctly, but while searching like 0912, it doesn't display record due to the braces, so how to modify the query to neglect the ) and - while searching..
As im new to the domain please help me out
thanks in advance
What about using REGEXP_REPLACE to remove all non-digit chars from the search - something like below?
customers = customers.where("REGEXP_REPLACE(customers.contact_num,'[^[:digit:]]','','g') ilike :search", {search: "%#{options[:search_contact]}%"})
Changing the query is hard. Let's not do that.
Instead right a quick script to transforms your numbers into
1112223333 form. No formatting at all. Something like:
require 'set';
phone = "(234)-333-2323"
numbers = Set.new(["1","2","3","4","5","6","7","8","9","0"])
output = phone.chars().select{|n| numbers.include?(n)}.join("")
puts output
=> "2343332323"
Then write a little function to transform them into display form for use in the views.
This will make your query work as is.

Multi term Ransack search in same field not working

I have implemented Ransack for my site's search function and want to be able to search in one database column for multiple terms entered in the same input field.
Here is the code in my controller:
if params[:q]
params[:q][:groupings] = []
split_genres = params[:q][:genres_name_cont].split(' ')
params[:q][:genres_name_cont].clear
split_genres.each_with_index do |word, index|
params[:q][:groupings][index] = {genres_name_cont: word}
end
end
#q = Band.ransack(params[:q])
#bands = #q.result(distinct: true).includes(:genres).sort_by{|band| band.name}
And here is the query which is returned when I enter multiple genres in the search:
SELECT "bands".* FROM "bands" LEFT OUTER JOIN "bands_genres"
ON "bands_genres"."band_id" = "bands"."id" LEFT OUTER JOIN "genres"
ON "genres"."id" = "bands_genres"."genre_id"
WHERE ("genres"."name" ILIKE '%rock%' AND "genres"."name" ILIKE '%blues%')
The query looks right to me, especially with it being more or less identical to the query generated when only one term is entered, which works fine.
Can anybody shed any light on what I may need to change to get this search working when multiple terms are entered within the field?
Welcome to Stack Overflow 👋.
The query doesn't work for multiple genres because it's only picking rows from the genres table where the name of a genre contains both "rock" and "blues", so it would only match genres like "rock/blues" or "bluesy rock ballads".
It sounds like what you're after is WHERE ("genres"."name" ILIKE '%rock%' OR "genres"."name" ILIKE '%blues%'), where OR means it will match either, so both the "rock" and "blues" genres will be matched.
In terms of getting this to work in Ransack, this comment on the GitHub project looks similar to yours, but includes the following line before you set your groupings:
params[:q][:combinator] = 'or'
I haven't tested this locally, but it appears that adding that line will convert the group combination from AND to OR, which should get you the right search results.
Let me know how it goes and I'll remove the tentative "should" and "appears" if it works 😉.

Activerecord query against array column using wildcard

So let's say i have a Customer model with array column phones.
It's pretty easy to find all customers with given phone
Customer.where('? = ANY(phones)', '+79851234567')
But i can't figure out how to use LIKE with wildcard when i want to find customers with phones similar to given one, something like:
Customer.where('ANY(phones) LIKE ?', '+7985%')
I'm using PostgreSQL 9.5 and Rais 4.2
Any ideas?
I think, first of all, its better to use second table phones with fields customer_id, phone_number. I think it's more rails way ). In this way you can use this query
Phone.where("phone_number LIKE ?", '%PART%').first.customer
If you serialize your array in some text field, by example JSON, you should use % on both sides of your pattern:
Customer.where('phones LIKE ?', '%+7985%')
If you have an array in your database, you should use unnest() function to expand an array to a set of rows.
Can you try this
Customer.where("array_to_string(phones, ', ') like ?", '+7985%')
I believe this will work.

Active Record - Chain Queries with OR

Rails: 4.1.2
Database: PostgreSQL
For one of my queries, I am using methods from both the textacular gem and Active Record. How can I chain some of the following queries with an "OR" instead of an "AND":
people = People.where(status: status_approved).fuzzy_search(first_name: "Test").where("last_name LIKE ?", "Test")
I want to chain the last two scopes (fuzzy_search and the where after it) together with an "OR" instead of an "AND." So I want to retrieve all People who are approved AND (whose first name is similar to "Test" OR whose last name contains "Test"). I've been struggling with this for quite a while, so any help would be greatly appreciated!
I digged into fuzzy_search and saw that it will be translated to something like:
SELECT "people".*, COALESCE(similarity("people"."first_name", 'test'), 0) AS "rankxxx"
FROM "people"
WHERE (("people"."first_name" % 'abc'))
ORDER BY "rankxxx" DESC
That says if you don't care about preserving order, it will just filter the result by WHERE (("people"."first_name" % 'abc'))
Knowing that and now you can simply write the query with similar functionality:
People.where(status: status_approved)
.where('(first_name % :key) OR (last_name LIKE :key)', key: 'Test')
In case you want order, please specify what would you like the order will be after joining 2 conditions.
After a few days, I came up with the solution! Here's what I did:
This is the query I wanted to chain together with an OR:
people = People.where(status: status_approved).fuzzy_search(first_name: "Test").where("last_name LIKE ?", "Test")
As Hoang Phan suggested, when you look in the console, this produces the following SQL:
SELECT "people".*, COALESCE(similarity("people"."first_name", 'test'), 0) AS "rank69146689305952314"
FROM "people"
WHERE "people"."status" = 1 AND (("people"."first_name" % 'Test')) AND (last_name LIKE 'Test') ORDER BY "rank69146689305952314" DESC
I then dug into the textacular gem and found out how the rank is generated. I found it in the textacular.rb file and then crafted the SQL query using it. I also replaced the "AND" that connected the last two conditions with an "OR":
# Generate a random number for the ordering
rank = rand(100000000000000000).to_s
# Create the SQL query
sql_query = "SELECT people.*, COALESCE(similarity(people.first_name, :query), 0)" +
" AS rank#{rank} FROM people" +
" WHERE (people.status = :status AND" +
" ((people.first_name % :query) OR (last_name LIKE :query_like)))" +
" ORDER BY rank#{rank} DESC"
I took out all of quotation marks in the SQL query when referring to tables and fields because it was giving me error messages when I kept them there and even if I used single quotes.
Then, I used the find_by_sql method to retrieve the People object IDs in an array. The symbols (:status, :query, :query_like) are used to protect against SQL injections, so I set their values accordingly:
# Retrieve all the IDs of People who are approved and whose first name and last name match the search query.
# The IDs are sorted in order of most relevant to the search query.
people_ids = People.find_by_sql([sql_query, query: "Test", query_like: "%Test%", status: 1]).map(&:id)
I get the IDs and not the People objects in an array because find_by_sql returns an Array object and not a CollectionProxy object, as would normally be returned, so I cannot use ActiveRecord query methods such as where on this array. Using the IDs, we can execute another query to get a CollectionProxy object. However, there's one problem: If we were to simply run People.where(id: people_ids), the order of the IDs would not be preserved, so all the relevance ranking we did was for nothing.
Fortunately, there's a nice gem called order_as_specified that will allow us to retrieve all People objects in the specific order of the IDs. Although the gem would work, I didn't use it and instead wrote a short line of code to craft conditions that would preserve the order.
order_by = people_ids.map { |id| "people.id='#{id}' DESC" }.join(", ")
If our people_ids array is [1, 12, 3], it would create the following ORDER statement:
"people.id='1' DESC, people.id='12' DESC, people.id='3' DESC"
I learned from this comment that writing an ORDER statement in this way would preserve the order.
Now, all that's left is to retrieve the People objects from ActiveRecord, making sure to specify the order.
people = People.where(id: people_ids).order(order_by)
And that did it! I didn't worry about removing any duplicate IDs because ActiveRecord does that automatically when you run the where command.
I understand that this code is not very portable and would require some changes if any of the people table's columns are modified, but it works perfectly and seems to execute only one query according to the console.

Returning a semi-unique set of most recent records

In my application a User has Highlights.
Each Highlight has a HighlightType. So if I run user.highlights I might see an output like this:
Notice that there are many highlights of type_id 47. This marks milestones of the number of times the user has gone running.
What I would like to do is return this full list of records, but only include one highlight for each highlight_type, and I want that one record to be the most recent record (in this case the "50th run" highlight). So in the example above I would get the same results but with IDs 195-199 removed.
Is there an efficient way to accomplish this?
I don't think there is an easy or clean way to achieve that, nor a "Rails way". Look at e.g. this link
According to one suggestion in that link you would do this SQL request:
SELECT h1.*
FROM highlights h1
LEFT JOIN highlights h2
ON (h1.user_id = h2.user_id
AND h1.highlight_type_id = h2.highlight_type_id
AND h1.created_at < h2.created_at)
WHERE h2.id IS NULL AND h1.user_id = <the user id you are interested in>
group by h1.highlight_type_id
I think it will be some performance problem if you have big tables maybe, an it not so very clean I think.
Otherwise, if there isn't so much highlights for a user I would have done something like this:
rows = {}
user.highlights.order('highlight_type_id, created_at DESC').each do |hi|
rows[hi.highlight_type_id] ||= hi
end
# then use rows which will have one object for each highlight_type_id
The DESC on created_at is important
EDIT:
I also saw some suggestions based on this
user.highlights.group('highlight_type_id').order('created_at DESC')
And that was also how I first thought it should be solved, but I tested it and it doesn't seems to get a correct result - at least on my test data.

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