Hello
I would like to get the current url of the page after a click on link. When I click on the link (of the 1rst page), the link open a new page (2nd page), and I want get the url of the 2nd page but when I call GetCurrentUrl(), the method return the url of the first page.
This is my code :
String att = driver.findElement(By.linkText("Lien 2")).getAttribute("href");
driver.findElement(By.linkText("Lien 2")).click(); // Open a the 2nd page
driver.manage().timeouts().pageLoadTimeout(30, TimeUnit.SECONDS);
String act = driver.getCurrentUrl(); // Return the url of the 1rst page; but I want the 2nd
System.out.println("act "+act+" att "+att);
assertEquals(act, att);
Thanks very much for the help !
Instead of the change to pageloadTimeout(), try manually waiting for the Url to change (this is what I'm doing in my code so thought I'd answer).
Insert the function definition below into your code.
The function prints the current URL in a loop so its helpful to debug any problems.
Change the value "30" in WebDriverWait(driver, 30)) if you want a longer timeout.
Make sure to call the function as follows:
try {
waitForUrl(the-url-you-want-to-wait-for);
} catch (Exception ex) {
//handle exception
}
Function:
/**
* Wait until the current page's URL changes to whatever you specify.
* #param Url The URL you want to wait for.
*/
protected static void waitForUrl(WebDriver driver, final String Url) throws Exception {
try {
(new WebDriverWait(driver, 30)).until(new ExpectedCondition<Boolean>() {
public Boolean apply(WebDriver d) {
System.out.println(d.getCurrentUrl());
return d.getCurrentUrl().toLowerCase().endsWith(Url);
}
});
}
catch (TimeoutException e) {
throw new Exception("Timeout Exception encountered while waiting for URL " + Url + ": \n" + e.getMessage());
}
}
Related
I am using the url_launcher plugin for call, but the dialer is not showing the # character:
String url = 'tel:*123#';
if (await canLaunch(url)) {
await launch(url);
} else {
throw 'Could not launch $url';
}
You need to use URL encoding for special character in a URL.
So # equals %23
This will work launch('tel:\*123\%23');
Other Way is to encode the number typed by user and pass it through Uri.encodeFull(urlString) or Uri.encodeComponent(urlString)
Like this.
launch("tel:" + Uri.encodeComponent('*123#'));
Disclaimer: plugin author here.
Do you want the phone call user interface to open or would you rather make the request silently? If you prefer to do it without popping the phone call UI, Android introduced in API level 26 the method sendUssdRequest.
I made a Flutter plugin called ussd_service to be able to easily access it from dart in a Flutter application. It can be used in the following manner:
import 'package:ussd_service/ussd_service.dart';
makeMyRequest() async {
int subscriptionId = 1; // sim card subscription Id
String code = "*21#"; // ussd code payload
try {
String ussdSuccessMessage = await UssdService.makeRequest(subscriptionId, code);
print("succes! message: $ussdSuccessMessage");
} on PlatformException catch (e) {
print("error! code: ${e.code} - message: ${e.message}");
}
};
makeMyRequest();
Hope this helps! Let me know on the Github repo's issues if you have any issue with it.
I created a custom attribute, inheriting from HandleErrorAttribute:
public class CustomHandleErrorAttribute : HandleErrorAttribute
{
public override void OnException(ExceptionContext filterContext)
{
try
{
Utility.LogAndNotifyOfError(filterContext.Exception, null, true);
}
catch(Exception ex)
{
filterContext.Exception = ex;
}
}
}
, and then registered with:
filters.Add(new CustomHandleErrorAttribute());
This has always worked as intended. However a common problem with my log method is that it uses a custom event log source when writing to the event log, which the app pool account typically doesn't have the permissions to create. Creating the event log source is a simple powershell script, however I wanted to actually include that tidbit in the error:
try
{
log.WriteEntry(error, EventLogEntryType.Error);
}
catch(SecurityException ex1)
{
throw new ErrorHandlerException($"The event log could not be written to due to a SecurityExcption. The likely issue is that the '{eventLogSource}' does not already exist. Please run the following powershell command:\r\n"
+ $"New - EventLog - LogName Application - Source {eventLogSource}", ex1);
}
The problem is that the catch in the OnException is never hit. When debugging, the custom error I throw from LogAndNotifyOfError instead triggers a second call to OnException, and the detail of my ErrorHandlerException is never seen. I want the asp.net error page that comes up to be with my custom error detail rather than the SecurityException that was originally raised.
You can even see the surrounding try in the displayed error:
Edit: Entire log method listed:
public static void LogAndNotifyOfError(Exception ex, String extraInfo, Boolean sendEmail)
{
//if the error handler itself faulted...
if (ex is ErrorHandlerException)
return;
string eventLogName = "Application";
string eventLogSource = "MySourceName";
String error = ex.ToString();
if (error.Length > 28000)
error.Substring(0, 28000);//event log is limited to 32k
error += "\r\n\r\nAdditional Information: \r\n"
+ "Machine Name: " + Environment.MachineName + "\r\n"
+ "Logged in user:" + App.CurrentSecurityContext.CurrentUser?.UserId + "\r\n"
+ extraInfo + "\r\n";
EventLog log = new EventLog(eventLogName);
log.Source = eventLogSource;
try
{
log.WriteEntry(error, EventLogEntryType.Error);
}
catch(SecurityException ex1)
{//this doesn't work - for some reason, OnError still reports the original error.
throw new ErrorHandlerException($"The event log could not be written to due to a SecurityExcption. The likely issue is that the '{eventLogSource}' does not already exist. Please run the following powershell command:\r\n"
+ $"New - EventLog - LogName Application - Source {eventLogSource}", ex1);
}
//if the email-to field has been set...
if (!String.IsNullOrEmpty(App.Config.General.ErrorHandlerSendToAddresses) && sendEmail)
{
//...then send the email
MailMessage email = new MailMessage();
email.To.Add(App.Config.General.ErrorHandlerSendToAddresses);
email.IsBodyHtml = false;
email.Subject = String.Format("Error in {0}", eventLogSource);
email.Body = email.Subject + "\r\n\r\n"
//+ "Note: This error may be occuring continuously, but this email is only sent once per hour, per url, in order to avoid filling your mailbox. Please check the event log for reoccurances and variations of this error.\r\n\r\n"
+ "The error description is as follows: \r\n\r\n"
+ error + "\r\n\r\n";
SmtpClient smtp = new SmtpClient();
smtp.Send(email);
}
}
I figured it out (sort of). It would appear that when the newly throw exception has an inner exception, it is only displaying that inner exception. It does not matter what the type is on the outer or inner exception.
I am currenttly developing a Chrome extension and i would like to store the url of a popup window into a string variable.
I am able to get the url via the "document.createElement and variable.appendChild methods, but I can't store it in a string.
This works :
function getLinks(){
var url = document.createElement("p");
chrome.tabs.query({windowType:"popup"}, function (tab){
for(x in tab){
var adresse= document.createTextNode(tab[x].url);
url.appendChild(adresse);
}
});
document.body.appendChild(url);
}
This does not work :
function getLinksbis(){
var url = "1 - ";
chrome.tabs.query({windowType:"popup"}, function (tab){
for(x in tab){
var adresse= tab[x].url;
url = url + adresse;
}
});
document.write(url);
}
Can you help me ? Is it possible to do what i want ?
I want it in a string because I want to add parameters to this url and then shoot it back to the user.
Please excuse my english, I'm french. ;-)
Thanks.
Your code does work, just ensure you have
{
..
"permissions":["tabs"]
..
}
tabs permission in your manifest file.
Output taken after testing
EDIT 1
function getLinksbis() {
var url = "1 - ";
chrome.tabs.query({
windowType: "popup"
}, function (tab) {
for (x in tab) {
var adresse = tab[x].url;
url = url + adresse;
}
document.write(url);
});
}
Move your document.write(url); inside async call back, it is an asynchronous function and final call should be taken after call back is successful.
I am running Eclipse Java EE and tomcat for running my webapp. I used the following code to store an image file to the upload/images/profilepics directory:
public String uploadPhoto() {
try {
//get path to upload photo
String filePath = servletRequest.getSession().
getServletContext().getRealPath("/uploads/profilepics");
System.out.println("Server path:" + filePath);
//creating unique picture name
Map sess = (Map) ActionContext.getContext().get("session");
Integer uid = (Integer) sess.get("uid");
String profilePictureName = uid + "-" +
MyUtilityFunctions.createVerificationUrl() + this.userImageFileName;
//update user record
//tobe done
String imgUrl = filePath + profilePictureName;
ViewProfileModel pofilePictureUpdate = new ViewProfileModel();
pofilePictureUpdate.updateUserPhotoUrl(imgUrl, uid);
//create new File with new path and name
File fileToCreate = new File(filePath, profilePictureName);
//copy file to given location and with given name
FileUtils.copyFile(this.userImage, fileToCreate);
} catch (Exception e) {
e.printStackTrace();
addActionError(e.getMessage());
return INPUT;
}
return SUCCESS;
}
after printing filePath I got the following result:
Server Path: /home/bril/webspace/.metadata/.plugins/org.eclipse.wst.server.core/tmp0/wtpwebapps/picvik/uploads/profilepics
Now the problem is, I am not able to get the image or if I give the same url to <img src=""> nothing is getting displayed.
Please correct where I am doing wrong.
There are suggestions:
there are lots of reason, that you shouldn't save user images in this way, just like #DaveNewton mentioned in another question. There
are some post to help you make your decision:
Post1
Post2
My personal opinion is to save them into DB, because you don't want
to let your user lost their images.
If you need access session, you can check out SessionAware. This should be a better way to access session.
You are using tomcat as application container, you can configure the server to use its local installation, which makes you easier to track the problem in this case. check out this picture below
Back to your question, There are different ways to do this:
if you cannot find the image user just uploaded, you can check it
manual, see 3.
Otherwise, you could try <img src="/uploads/profilepics/<s:property
value='profilePictureName'/>"
Or you can get this picture using stream, here is the snippet:
JSP:
<img src="
<s:url var="profilePic" action="customer-image-action">
<s:param name="uid" value="%{uid}"/>
</s:url>
" alt="kunden logo" />
Action:
public String execute() throws Exception {
// filename = somehow(uid);
HttpServletRequest request = (HttpServletRequest) ActionContext.getContext().get(ServletActionContext.HTTP_REQUEST);
imgPath = request.getSession().getServletContext().getRealPath("/uploads/profilepics/")+filename;
log.debug("context-path: " + imgPath);
try {
inputStream = FileUtils.openInputStream(new File(imgPath));
} catch (IOException e) {
log.error(e.getCause(), e);
}
return SUCCESS;
}
I want to store position coords (latitude, longitude) in a table in my MySQL DB querying a url in a way similar to this one: http://locationstore.com/postlocation.php?latitude=var1&longitude=var2 every ten seconds. PHP script works like a charm. Getting the coords in the device ain't no problem either. But making the request to the server is being a hard one. My code goes like this:
public class LocationHTTPSender extends Thread {
for (;;) {
try {
//fetch latest coordinates
coords = this.coords();
//reset url
this.url="http://locationstore.com/postlocation.php";
// create uri
uri = URI.create(this.url);
FireAndForgetDestination ffd = null;
ffd = (FireAndForgetDestination) DestinationFactory.getSenderDestination
("MyContext", uri);
if(ffd == null)
{
ffd = DestinationFactory.createFireAndForgetDestination
(new Context("MyContext"), uri);
}
ByteMessage myMsg = ffd.createByteMessage();
myMsg.setStringPayload("doesnt matter");
((HttpMessage) myMsg).setMethod(HttpMessage.POST);
((HttpMessage) myMsg).setQueryParam("latitude", coords[0]);
((HttpMessage) myMsg).setQueryParam("longitude", coords[1]);
((HttpMessage) myMsg).setQueryParam("user", "1");
int i = ffd.sendNoResponse(myMsg);
ffd.destroy();
System.out.println("Lets sleep for a while..");
Thread.sleep(10000);
System.out.println("woke up");
} catch (Exception e) {
// TODO Auto-generated catch block
System.out.println("Exception message: " + e.toString());
e.printStackTrace();
}
}
I haven't run this code to test it, but I would be suspicious of this call:
ffd.destroy();
According to the API docs:
Closes the destination. This method cancels all outstanding messages,
discards all responses to those messages (if any), suspends delivery
of all incoming messages, and blocks any future receipt of messages
for this Destination. This method also destroys any persistable
outbound and inbound queues. If Destination uses the Push API, this
method will unregister associated push subscriptions. This method
should be called only during the removal of an application.
So, if you're seeing the first request succeed (at least sometimes), and subsequent requests fail, I would try removing that call to destroy().
See the BlackBerry docs example for this here
Ok so I finally got it running cheerfully. The problem was with the transport selection; even though this example delivered WAP2 (among others) as an available transport in my device, running the network diagnostics tool showed only BIS as available. It also gave me the connection parameters that I needed to append at the end of the URL (;deviceside=false;ConnectionUID=GPMDSEU01;ConnectionType=mds-public). The code ended up like this:
for (;;) {
try {
coords.refreshCoordinates();
this.defaultUrl();
this.setUrl(stringFuncs.replaceAll(this.getUrl(), "%latitude%", coords.getLatitude() + ""));
this.setUrl(stringFuncs.replaceAll(this.getUrl(), "%longitude%", coords.getLongitude() + ""));
cd = cf.getConnection(this.getUrl());
if (cd != null) {
try {
HttpConnection hc = (HttpConnection)cd.getConnection();
final int i = hc.getResponseCode();
hc.close();
} catch (Exception e) {
}
}
//dormir
Thread.sleep(15000);
} catch (Exception e) {
} finally {
//cerrar conexiones
//poner objetos a null
}
Thanks for your help #Nate, it's been very much appreciated.