I want to convert the 8 bytes I have in an NSData instance to a uint32_t array that has 2 items. I did the following, but it's not correct.
NSLog(#"Challenge data %#",dataChallenge);
uint32_t *data = (uint32_t *)dataChallenge.bytes;
NSLog(#"data0: %08x, data1: %08x", data[0], data[1]);
And this is the result:
Challenge data <3ce3e664 dafda14b>
data0: 64e6e33c, data1: 4ba1fdda
The order of data is not correct.
The values should be:
Challenge data <3ce3e664 dafda14b>
data0: 3ce3e664, data1: dafda14b
uint32_t *data = (uint32_t *)dataChallenge.bytes;
Example:
NSData *dataChallenge = [#"12345678" dataUsingEncoding:NSUTF8StringEncoding];
NSLog(#"dataChallenge: %#", dataChallenge);
uint32_t *data = (uint32_t *)dataChallenge.bytes;
NSLog(#"data0: %08x, data1: %08x", data[0], data[1]);
NSLog output:
dataChallenge: <31323334 35363738>
data0: 34333231, data1: 38373635
Note: The bytes are reversed because this is a lithe-endian machine
With memcpy:
NSData *dataChallenge = [#"12345678" dataUsingEncoding:NSUTF8StringEncoding];
NSLog(#"dataChallenge: %#", dataChallenge);
uint32_t data[2];
memcpy(data, (uint32_t *)dataChallenge.bytes, dataChallenge.length);
NSLog(#"data0: %08x, data1: %08x", data[0], data[1]);
NSLog output:
dataChallenge: <31323334 35363738>
data0: 34333231, data1: 38373635
Swapping the byte order:
NSLog(#"data0: %08x, data1: %08x", CFSwapInt32BigToHost(data[0]), CFSwapInt32BigToHost(data[1]));
NSLog output:
data0: 31323334, data1: 35363738
Note: See CFByteOrder.h for more combinations of byte swapping.
Below logic converts NSData to integer perfectly. Length of bytes does not matter. It just works.
NSData *data;
NSString *stringData = [data description];
stringData = [stringData substringWithRange:NSMakeRange(1, [stringData length]-2)];
unsigned dataAsInt = 0;
NSScanner *scanner = [NSScanner scannerWithString: stringData];
[scanner scanHexInt:& dataAsInt];
Related
I am using the following code to write the 0xDE value for a Bluetooth Caracteristic (Reset Device) using the IOS Core Bluetooth :
...
NSData *bytes = [#"0xDE" dataUsingEncoding:NSUTF8StringEncoding];
[peripheral writeValue:bytes
forCharacteristic:characteristic
type:CBCharacteristicWriteWithResponse];
...
is there any mistake in my code because the value is not written properly?
Swift 3.0: In case anyone is wondering the format for Swift is slightly different as writeValue can get the count from the array.
let value: UInt8 = 0xDE
let data = Data(bytes: [value])
peripheral.writeValue(data, for: characteristic, type: .withResponse)
Try creating your data with an array of single byte values.
const uint8_t bytes[] = {0xDE};
NSData *data = [NSData dataWithBytes:bytes length:sizeof(bytes)];
This is a useful approach for creating arbitrary constant data. For more bytes,
const uint8_t bytes[] = {0x01,0x02,0x03,0x04,0x05};
NSData *data = [NSData dataWithBytes:bytes length:sizeof(bytes)];
If you want to create data to send using variables, I would recommend using NSMutableData and appending the bytes that you need. It isn't very pretty, but it is easy to read / understand, especially when you are matching a packed struct on the embedded side. Example below is from a BLE project where we were making a simple communication protocol.
NSMutableData *data = [[NSMutableData alloc] init];
//pull out each of the fields in order to correctly
//serialize into a correctly ordered byte stream
const uint8_t start = PKT_START_BYTE;
const uint8_t bitfield = (uint8_t)self.bitfield;
const uint8_t frame = (uint8_t)self.frameNumber;
const uint8_t size = (uint8_t)self.size;
//append the individual bytes to the data chunk
[data appendBytes:&start length:1];
[data appendBytes:&bitfield length:1];
[data appendBytes:&frame length:1];
[data appendBytes:&size length:1];
The answer by bensarz is almost correct. Except one thing: you shouldn't use sizeof(int) as the length for NSData. The size of int is 4 or 8 bytes (depending on the architecture). As you want to send 1 byte, use uint8_t or Byte instead:
uint8_t byteToWrite = 0xDE;
NSData *data = [[NSData alloc] initWithBytes:&byteToWrite length:sizeof(&byteToWrite)];
[peripheral writeValue:data
forCharacteristic:characteristic
type:CBCharacteristicWriteWithResponse];
Of courser you could also use int as the variable's type, but you have to initialize NSData with the length of 1.
This code will fix the problem :
NSData * data = [self dataWithHexString: #"DE"];
[peripheral writeValue:data forCharacteristic:characteristic
type:CBCharacteristicWriteWithResponse];
dataWithHexString implementation :
- (NSData *)dataWithHexString:(NSString *)hexstring
{
NSMutableData* data = [NSMutableData data];
int idx;
for (idx = 0; idx+2 <= hexstring.length; idx+=2) {
NSRange range = NSMakeRange(idx, 2);
NSString* hexStr = [hexstring substringWithRange:range];
NSScanner* scanner = [NSScanner scannerWithString:hexStr];
unsigned int intValue;
[scanner scanHexInt:&intValue];
[data appendBytes:&intValue length:1];
}
return data;
}
What you are, in fact, doing here is writing the string "0xDE" to the characteristic. If you want to use binary/octal notation, you need to stay away from strings.
int integer = 0xDE;
NSData *data = [[NSData alloc] initWithBytes:&integer length:sizeof(integer)];
[peripheral writeValue:data
forCharacteristic:characteristic
type:CBCharacteristicWriteWithResponse];
I have an NSData object that contains just <64> which is supposed to represent the int 100
How can I convert this NSData to an int?
I can convert it to it's Chr equivalent d using
NSString *string = [[NSString alloc] initWithData:characteristic.value encoding:NSUTF8StringEncoding];
but I need the Dec equivalent of 100
Thanks
<64> means that the NSData object contains a single byte with the value 0x64 = 100,
so the following should work;
const uint8_t *bytes = [data bytes]; // pointer to the bytes in data
int value = bytes[0]; // first byte
int *b = (int *)data.bytes;
printf("%d",*b); //prints 100
Below logic converts NSData to integer perefctly. Length of bytes does not matter. It just works.
NSData *data;
NSString *stringData = [data description];
stringData = [stringData substringWithRange:NSMakeRange(1, [stringData length]-2)];
unsigned dataAsInt = 0;
NSScanner *scanner = [NSScanner scannerWithString: stringData];
[scanner scanHexInt:& dataAsInt];
I need to represent a NSInteger and NSString into array of bytes. below are the sample of what I am looking for.
For how, this harcodings are working fine. I want to do this through code. Any clue.
First, NSInteger into bytes of Hex:
NSInteger test = 1;
unsigned char byte[] = { 0x00, 0x01 };
NSInteger test = 16;
unsigned char byte[] = { 0x00, 0x10 };
NSData *data = [NSData dataWithBytes:byte length:sizeof(byte)];
Second, NSString into bytes of Hex:
NSString *test = #"31C5B562-BD07-4616-BCBD-130BA6822790";
unsigned char byte[] = {0x31, 0xC5, 0xB5, 0x62, 0xBD, 0x07, 0x46, 0x16, 0xBC, 0xBD, 0x13, 0x0B, 0xA6, 0x82, 0x27, 0x90};
NSData *data = [NSData dataWithBytes:byte length:sizeof(byte)];
I tried with below code and it works well for my UUID but for NSInteger to to be working I need to send "0010" instead of 16 and "0001" instead of 1. So any clue on how to do this conversion.
- (NSData *)hexData {
NSMutableData *hexData = [NSMutableData data];
int idx = 0;
for (idx = 0; idx+2 <= self.length; idx+=2) {
NSRange range = NSMakeRange(idx, 2);
NSString* hexStr = [self substringWithRange:range];
NSScanner* scanner = [NSScanner scannerWithString:hexStr];
unsigned int intValue;
[scanner scanHexInt:&intValue];
[hexData appendBytes:&intValue length:1];
}
return hexData;
}
EDIT:
int8_t test = -59;
int8_t bytes = CFSwapInt16HostToBig(test);
NSData *data1 = [NSData dataWithBytes:&bytes length:sizeof(bytes)];
Reaching as 0xFF instead of 0xC4
Since your string is a UUID string you can do something like this:
NSString *test = #"";
uuid_t uuid;
uuid_parse([test UTF8String], uuid)
NSData *data = [NSData dataWithBytes:uuid length:16];
For the number you can do:
NSInteger test = 1;
NSData *data = [NSData dataWithBytes:&test length:sizeof(test)];
Keep in mind that NSInteger is probably more than two bytes and you may also need to worry about byte order.
Update: Since it seems you need the integer value to be two bytes, you should do:
uint16_t test = 1;
NSData *data = [NSData dataWithBytes:&test length:sizeof(test)];
This will ensure 2 bytes. You also need to worry about byte ordering so you really need:
uint16_t test = 1;
uint16_t bytes = CFSwapInt16HostToBig(test);
NSData *data = [NSData dataWithBytes:&bytes length:sizeof(bytes)];
Change CFSwapInt16HostToBig to CFSwapInt16HostToLitte if appropriate.
How do I convert a series of 32 bits (representing 4 bytes) stored in an NSString, into an NSData object of 4 bytes in objective-c?
For example, how can I convert the following string:
NSString *bitSeries = #"00000000000000000000000111101100";
into NSData object with length precisely 4?
You can use strtoul() with base 2 to convert the string to an unsigned integer:
NSString *bitSeries = #"00000000000000000000000111101100";
uint32_t value = strtoul([bitSeries UTF8String], NULL, 2);
and then create an NSData object:
NSData *data = [NSData dataWithBytes:&value length:sizeof(value)];
NSLog(#"%#", data);
// Output: <ec010000>
Or, if you prefer big-endian byte order:
value = OSSwapHostToBigInt32(value);
NSData *data = [NSData dataWithBytes:&value length:sizeof(value)];
NSLog(#"%#", data);
// Output: <000001ec>
According to my requirement:
The input string has to be converted into Byte Values.
Each character of string , which are 16 bit values , has to be converted to low 8 bits.
The Sha1 is then computed over the byte Array.
The resulting SHA-1 is converted into a 40 character string.
I know how to convert a string into SHA1 , but the rest of part is a bit gloomy to me.
I have been able to do the last two steps.
unsigned char digest[CC_SHA1_DIGEST_LENGTH];
NSData *dataString = [yourString dataUsingEncoding: NSUTF8StringEncoding];
if (CC_SHA1([dataString bytes], [dataString length], digest)) {
//Sha1 is calculated & stored in digest.
}
Any help will be appreciated.
I have created this function , which works fine according to your requirement . You just have to input a string.
#import <CommonCrypto/CommonDigest.h>
- (NSString *)calculateSHA:(NSString *)yourString
{
const char *ptr = [yourString UTF8String];
int i =0;
int len = strlen(ptr);
Byte byteArray[len];
while (i!=len)
{
unsigned eachChar = *(ptr + i);
unsigned low8Bits = eachChar & 0xFF;
byteArray[i] = low8Bits;
i++;
}
unsigned char digest[CC_SHA1_DIGEST_LENGTH];
CC_SHA1(byteArray, len, digest);
NSMutableString *hex = [NSMutableString string];
for (int i=0; i<20; i++)
[hex appendFormat:#"%02x", digest[i]];
NSString *immutableHex = [NSString stringWithString:hex];
return immutableHex;
}
Then you just have to call the above method.
[self calculateSHA:yourString];
NSData *dataString = [yourString dataUsingEncoding: NSUTF8StringEncoding];
converts the string to UTF-8 bytes, e.g. "é" = Unicode 00E9 is converted to the two bytes C3 A9, and "€" = Unicode 20AC is converted to three bytes E2 82 AC.
If your requirement is to "truncate" the Unicode characters to the lower 8 bits, you have to do this "manually", I do not know a built-in encoding that could be used for that:
NSMutableData *dataString = [NSMutableData dataWithLength:[yourString length]];
uint8_t *dataBytes = [dataString mutableBytes];
for (NSUInteger i = 0; i < [yourString length]; i++) {
// assigning the character to a uint_8 truncates to the lower 8 bit:
dataBytes[i] = [yourString characterAtIndex:i];
}
Based on your code snippet, you want to do something like:
unsigned char digest[CC_SHA1_DIGEST_LENGTH];
NSData *dataString = [yourString dataUsingEncoding: NSUTF8StringEncoding];
NSMutableString *outString;
if (CC_SHA1([dataString bytes], [dataString length], digest)) {
for (int i=0;i<CC_SHA1_DIGEST_LENGTH;i++) {
[outString appendFormat:#"%02x", digest[i]];
}
}
Where outString will be your 40-char string.
Here's an NSString category for creating a SHA1 hash of an NSString.
Creating SHA1 Hash from NSString