How to arrange this pixel address one by one? - image-processing

Question

I am doing map processing. I solved the maze and got the address of the turnings. Below is my result.
(28,136)
(122,136)
(344,391)
(548,493)
(548,191)
(344,191)
(122,391)
But the addresses are not in correct order. My expected output is:
28 136
122 136
122 391
344 391
344 191
548 191
549 493
MY program is below. I programmed to get direction also
for(i=1:tblob)
if (shape(i).order==1)
map(i).cen=shape(i).cen;
end
end
White=[255 255 255];
i=1;
order=1;
left=0;
right=0;
up=0;
down=0;
left(1)=0;
right(1)=0;
up(1)=0;
down(1)=0;
left(2)=0;
right(2)=0;
up(2)=0;
down(2)=0;
left(3)=0;
right(3)=0;
up(3)=0;
down(3)=0;
left(4)=0;
right(4)=0;
up(4)=0;
down(4)=0;
left(5)=0;
right(5)=0;
up(5)=0;
down(5)=0;
left(6)=0;
right(6)=0;
up(6)=0;
down(6)=0;
left(7)=0;
right(7)=0;
up(7)=0;
down(7)=0;
left(8)=0;
right(8)=0;
up(8)=0;
down(8)=0;
x=map(i).cen(1,:);
y=map(i).cen(2,:);
for(z=1:100)
xi=x+1;
xj=x-1;
yi=y+1;
yj=y-1;
colorvalxi=color(y,xi,RGB);
colorvalxi
colorvalxj=color(y,xj,RGB);
colorvalxj
colorvalyi=color(yi,x,RGB);
colorvalyi
colorvalyj=color(yj,x,RGB);
colorvalyj
if(i>1)
s=i-1;
else
s=1;
end
if (left(s)==0)
if(colorvalxi==White)
n=1;
end
else
if (right(s)==0)
if(colorvalxj==White)
n=2;
end
else
if(up(s)==0)
if (colorvalyi==White)
n=3;
end
else
if(down(s)==0)
if(colorvalyj==White)
n=4;
end
else
break;
end
end
end
end
switch(n)
case 1 %RIGHT
for(ks=1:1000)
color_val=color(y,x,RGB);
if(color_val==White)
x=x+1;
else
right(i)=1;
instruction(i)=1;
i=i+1;
x=x-1;
map(i).cen(1,1)=x;
map(i).cen(2,1)=y;
break;
end
end
case 2 %LEFT
for(ks=1:1000)
color_val==color(y,x,RGB)
if(color_val==White)
x=x-1;
else
left(i)=1;
instruction(i)=2;
i=i+1;
x=x+1;
map(i).cen(1,1)=x;
map(i).cen(2,1)=y;
break;
end
end
case 3 %DOWN
for(ks=1:1000)
color_val=color(y,x,RGB);
if(color_val==White)
y=y+1;
else
down(i)=1;
instruction(i)=3;
i=i+1;
y=y-1;
map(i).cen(1,1)=x;
map(i).cen(2,1)=y;
break;
end
end
case 4 %UPWARD
for(ks=1:1000)
color_val=color(y,x,RGB);
if(color_val==White)
y=y-1;
else
up(i)=1;
instruction(i)=4;
i=i+1;
y=y-1;
map(i).cen(1,1)=x;
map(i).cen(2,1)=y;
break;
end
end
end
end