Confusion about ARC , AutoRelease - ios

I am new to IOS development and I have started to learn objective c to program towards IOS 7. and as I know, it is way easier to code now than it has been before because of the Automatic reference counting.
there are a couple of things I do not understand . in MAIN method we have the autoreleasepool block, so my first question is that in order to enable ARC , the code has to be inside this block? if no, then what is the difference between the code that is inside autoreleasepool and the rest those aren't?
my second question is that when I am writing my IPHONE programs , I have bunch of classes and non of those codes are inside "autoreleasepool" , only the code inside the MAIN method.
int main(int argc, char * argv[])
{
#autoreleasepool {
return UIApplicationMain(argc, argv, nil,
NSStringFromClass([HomepwnerAppDelegate class]));
}
}
so , does this mean that this block somehow magically gets applied to all lines of code inside any other classes of the same program?
My last question is that whether with ARC or without it, if we had a declared pointer variable inside a method, does the object gets released/destroyed when the method returns/exit?
assume we have a method like this :
- (void)doSomething {
NSMutableArray *allItems = [[NSMutableArray alloc] init];
NSString *myString = #"sample string";
[allItems addObject:myString]
}
then when we call this method and it exits, what would happen to those local variables defined inside the method ? is there any difference in the outcome if we are using ARC or not ? (Object are still in the memory or not)

Autorelease pools predate ARC by about 15 years. Cocoa uses a reference-counting memory management scheme, where (conceptually, at least) objects are created with a reference count of 1, retain increases it by 1 and release decreases the count by 1, and the object is destroyed when the count gets to 0.
A problem with this scheme is that it makes returning an object kind of awkward, because you can't release the object before you return it — if you did, it might be destroyed before the other method got to use it — but you don't want to require the other method to release the object either. This is where autorelease pools come in. An autorelease pool lets you hand an object to it, and it promises to release the object for you later. Under manual retain/release (the way we used to do things before ARC), you did this by sending autorelease to an object.
OK, so then ARC comes into the picture. The only thing that really changes with ARC is that you aren't the one writing retain, release and autorelease anymore — the compiler inserts them for you. But you still need an autorelease pool for autoreleased object to go into.
As for your second question:
My last question is that whether with ARC or without it, if we had a declared pointer variable inside a method, does the object gets released/destroyed when the method returns/exit?
assume we have a method like this :
- (void)doSomething {
NSMutableArray *allItems = [[NSMutableArray alloc] init];
NSString *myString = #"sample string";
[allItems addObject:myString]
}
then when we call this method and it exits, what would happen to those local variables defined inside the method ? is there any difference in the outcome if we are using ARC or not ?
If you're using ARC, the compiler will release any objects referenced by local variables. If you're not using ARC, you'd need write [allItems release] yourself, because the variable going out of scope does not magically cause the object it references to be released.

new to IOS development
Best not to worry, Automatic means that you mostly concentrate on other things ^)
does this mean that this block somehow magically gets applied to all lines of code inside any other classes of the same program
Yes. You're in main function, so all the code that is executed has to be inside this function - your app will terminate once it ends. Unless you create a separate thread, but it's hard to do that by accident.
the code has to be inside this block
As said above, all of your code on main thread will execute within this block.
what would happen to those local variables defined inside the method
You're guaranteed that they will be destroyed before returning.

in MAIN method we have the autoreleasepool block, so my first question is that in order to enable ARC, the code has to be inside this block? if no, then what is the difference between the code that is inside autoreleasepool and the rest those aren't?
ARC is enabled by corresponding Objective-C compiler setting. If you create a new project in the latest version of Xcode it will be enabled by default.
The #autorelease keyword places code inside the curly brackets into autorelease pool scope. Autorelease pools are used both with ARC and manual memory management.
my second question is that when I am writing my IPHONE programs , I have bunch of classes and non of those codes are inside "autoreleasepool" , only the code inside the MAIN method.
iOS applications are event based. Main thread starts event loop when you call UIApplicationMain function processing touch events, notifications etc. This event loop has its own autorelease pool that autoreleases objects at the end of the loop iteration. This autorelease pool has nothing to do with the autorelease pool you see in main function.
My last question is that whether with ARC or without it, if we had a declared pointer variable inside a method, does the object gets released/destroyed when the method returns/exit?
If you use ARC the objects will be released (unless you return a reference to an object from the method). In MMR you would need to manually send release message to destroy the objects.

Related

Can an object be deallocated during method execution?

Let's assume that we create an instance of class var foo: Foo? = Foo() on the main thread and we call some time consuming instance method bar of Foo on another thread, after a short time we set foo to nil on main thread. What happens with the execution of bar, in my understanding bar should still continue its execution since invoking instance method implicitly passes self as the first argument, so even those the last explicit ref to foo was broken we still have a ref inside of a method and it should be good. But then I found this stackoverflow post which completely breaks my understanding. So, can somebody confirm/deny the fact that object cannot be deallocated during its method execution
Short answer is that your belief is correct, and you're looking at a question that's not relevant to Swift.
Your link is to non-ARC Objective-C. Swift always uses ARC, and ARC is very conservative about retains. Consider the following Objective-C call:
[target runMethod: parameter];
Under ARC, this is (conceptually) transformed into:
[target retain];
[parameter retain];
[target runMethod: parameter];
[parameter release];
[target release];
retain and release are atomic, thread-safe calls.
A similar behavior exists in Swift. Because of this, as a general rule (in the absence of Unsafe), a variable cannot "disappear" while you'll holding onto it.
This is the implementation detail. The better way to think about it is that by default variables and parameters are strong, and an object cannot be destroyed while there is a strong reference. This matches your understanding.
Prior to ARC, though, you needed to insert extra retains and releases yourself to protect against this kind of situation, and it was very common not to. (Prior to 10.6, most ObjC was single-threaded.)
Even without threads, there are ways this can go astray without ARC. Since callers often didn't immediately retain returned values if they only needed them temporarily, it was possible to get dangling pointers even without multiple threads. For example, with a trivial accessor with no memory management, this can crash:
NSString *name = [person name];
[person release];
[self doSomethingWithName: name];
This is why you often see old ObjC getters written in the form:
- (NSString*) title {
return [[title retain] autorelease];
}
This made sure that the returned value would survive until the end of the event loop even if self released it or self was deallocated.
Swift does similar things via ARC, but as the name suggests, it's all automatic.

Mark an object un-AutoRelease in ARC

As we all know, object will not dealloc immediately in ARC when no variable refer it. eg,
NSObject* obj = [[NSObject alloc] init];
obj = nil;
obj will dealloc after a time.(auto release pool drain).
Now, I want the obj dealloc right after it's been set to nil, which means the obj is not in auto-release-pool. But all other obj should work well as before, which means the program is still in ARC mode.
Is there a way, maybe macro or compiler flag, to do this?
First of all: You should not care about early deallocation. This is a strong code smell.
Second: Are you really, really sure, because -init does not put an object into ARP. Maybe the expression causes a retain autorelease combination, but compiling in release mode should optimize that away.
However, if it is in ARP you can close the ARP as mentioned by Hermann Klecker or – I think this is better – find the reason for being that object in ARP. There is no need for that.
Amin is right: the object is not in an autorelease pool. alloc, which created the object, does not engage a pool. On the other hand, you're right: ARC may not release the object immediately.
There is indeed an annotation you can use to force the release: objc_precise_lifetime. Adding that to the variable declaration will cause ARC to send release as soon as the object is no longer valid in the current scope.
However, Amin is also right that this is not very likely to be what you want. ARC knows what it's doing -- there are optimizations it can't make when you use this annotation -- and unless you know what it's doing too, you should strongly consider just letting it do its job.

Are objects immediately released when a property is allocated a second time?

I am working on an app where I am presenting 100 sentences using AVAudioplayer. Rather than have 100 AVAudioplayer objects I wanted to just have one property and change the object associated with it on the fly. My code boils down to the following (though the lines arent immediately following each other in the actual code):
self.thePlayer = [[AVAudioPlayer alloc] initWithContentsOfURL:url1 error:&error];
self.thePlayer = [[AVAudioPlayer alloc] initWithContentsOfURL:url2 error:&error];
Does the object initialized with url1 get released when thePlayer is allocated and initialized a second time with url2, or are both objects only released when the view is dismissed? As I am dealing with 100 sound files I don't want them all hanging around in memory. I'm using ARC
Thanks in advance
In your specific case, guessing at what your code likely includes, the objects will probably be deallocated when you want them to be. That's a lot of "guessing," "likely," and "probably." You really need to understand how the memory management works in order to reason about it.
If the AVAudioPlayer is strongly referenced by anything else, then it won't be released until those strong references are gone. In other words, setting thePlayer won't deallocate the player if something else has a strong reference to it. (That "something" may be some part of the system frameworks, or even itself in some rare cases. It doesn't have to be your code.)
If the AVAudioPlayer has pending autorelease calls on it, then it won't be released until the autorelease pool drains (usually at the end of event loop, which basically means "when your method that UIKit called returns.") For example, if you create a large number of objects in a loop and immediately throw them away, they may or may not be deallocated until the autorelease pool drains. Again, autoreleases may be injected by system frameworks. In practice, this means that the object will usually be deallocated "soon" (in a small fraction of a second), but not necessarily immediately. You can clean up autoreleased objects sooner by using #autoreleasepool blocks, which is sometimes necessary if you create many temporary objects in a loop. This is not needed very often.
But to a first-order approximation, in many of the most common cases, yes, replacing the property will automatically and immediately deallocate the previous object.
It would be useful to show how you declared thePlayer. If they are synthesized properly the memory management would be handled automatically. It appears that you are using "self" to access thePlayer and if so you'd be setting the value through a setter/getter and that would handle the memory management for you. But I also notice that "Self" is capitalized and should not be in order to properly use the setter/getter. For more info on synthesized variables check out: What exactly does #synthesize do?. Note there are some places where you should NOT use self and this link discusses that: How does an underscore in front of a variable in a cocoa objective-c class work?.

Asynchronous methods called inside `-dealloc` could generate unwanted zombie objects

As I was walking through some line of codes I stumbled upon this problem a couple of days ago,
- (void)dealloc {
...
[self.postOfficeService deregister:self];
...
}
Where the de-registration from the Post Office Service is an asynchronous operation, even if it's not self evident from the interface as there's no block or function passed to the postOfficeService.
The internal implementation of postOfficeService's -deregister method is something like that
// -deregister:(id)formerSubscriber implementation
//some trivial checks here
// deregister former subscriber
dispatch_asynch(_serialQueue, ^{
[self.subcribers removeObject:formerSubscriber];
});
...
The container, self.subscribers, does perfectly its job and contains only weak references. I.e. it is a NSHashTable.
As long as the deregistration method got called within the dealloc method, I keep on getting a crash while postOfficeService is trying to remove the former subscribers from its list inside that asynch block, which is used for thread safety purposes I guess.
Adding a breakpoint on [self.subscribers removeObject:formerSubscriber], it's possible to notice that the formerSubscriber object is always a NSZombieObject. That's the reason for crashes.
I know that it's possible to get thread safety for deregister method without incurring in this problem - I figure it should be enough use the dispatch_synch in lieu of the dispatch_asynch version
I think this is one of the reason why asynchronous methods shouldn't be called within dealloc methods.
But the question is how's possible to constantly get NSZombie objects even if we are in an ARC environment and the container objects is a NSHashTable (so it should be working I guess)?
The rule is: When dealloc is called, the object will be gone once dealloc returns to its caller (whoever called release when the reference count was 0), and nothing is going to prevent this.
Before ARC, you might have tried to retain an object inside dealloc - doesn't help; once dealloc is called the object will go (and dealloc will be called only once for it, in case you do a retain / release inside dealloc). ARC does the same, just automatically.
Using ARC doesn't means all your memory problem magically disappeared.
What happened is
[obj release] called by ARC
[obj dealloc]
[obj.postOfficeService deregister:obj]
[obj retain] - sorry you can't cancel the deallocation process
dispatch_async
free(obj) - from this point, obj is a zombie
GCD scheduling tasks
dispatch_async execute task
use obj - crash
The correct solution is use dispatch_sync to make sure you not trying to use object after it is deallocated. (be careful about dead lock)
Don't call asynchronous cleanup methods from dealloc. It's just not a good idea. Your -deregister should be synchronous.
NSHashTable stores pointers - it's the equivalent of __unsafe_unretained or assign - UNLESS it was created using +weakObjectsHashTable or the equivalent set of options (NSHashTableZeroingWeakMemory and NSPointerFunctionsObjectPersonality). If it was not created that way, it is quite likely you will have values pointing to zombie objects.
The question of "why am I getting zombies" is best answered by profiling your application with the Zombies template in Instruments and stimulating the required behavior.
I agree with the others that you should probably avoid asynchronous cleanup in your -dealloc method. However, it may be possible to fix this by making the parameter to -deregister: __unsafe_unretained. That method would then have to treat the pointer purely as a opaque value. It must not dereference it or message it. Unfortunately, you don't control the implementation of NSHashTable and can't guarantee that. Even if NSHashTable could be relied upon, the interface of -removeObject: takes an implicitly strong object pointer, so ARC might retain the pointer when it's copied from the unsafe unretained pointer.
You might use the C function API for hash tables (e.g. NSHashRemove()) as suggested in the overview for the NSHashTable class.

Object lifecycle with a method receiving a block, under ARC

Right now I have something like this:
- (void)viewDidLoad
{
MyObject *myObject = nil;
#autoreleasepool
{
myObject = [[MyObject alloc] init];
[myObject doSomethingWithBlock:^{
NSLog(#"Something Happened");
}];
}
NSLog(#"End of method");
}
And the doSomethingWithBlock: has the following:
- (void)doSomethingWithBlock:(void(^)())aBlock
{
[self performSelector:#selector(something:) withObject:aBlock afterDelay:4.0f];
}
And the something:
- (void)something:(void(^)())aBlock {
aBlock();
}
I understand that the block is being passed between stacks frames, so it's kept alive until it actually is executed and it is disposed. But why when the "End of method" is called does myObjct still exists? I know that I am not referencing the object from within the block, so shouldn't it be released within the autorelease pool? Or is this a compiler detail (if it should actually release it there, or after the method returns), and I shouldn't care about it?
Someone pointed out that performSelector will retain the target so I used this instead:
dispatch_after(dispatch_time(DISPATCH_TIME_NOW, 4 * NSEC_PER_SEC), dispatch_get_main_queue(), ^{
aBlock();
});
It is not clear to me whether the question is about the lifetime of the block, as per the title, or the lifetime of the object referenced by myObject, so we'll cover both.
First, the stack allocation of blocks in an optimisation and something programmers should not really need to be aware of. Unfortunately when blocks were first introduced the compiler was not smart enough to handle this optimisation completely automatically, hence the need to know about Block_copy() etc. But the compiler is now much smarter and the programmer can pretty much forget about stack allocation of blocks.
This answer applies to Xcode 5.0.2/Clang 4.2. Use a different (earlier) version and YMMV.
Second, the block:
^{ NSLog(#"Something Happened"); }
is not actually stack allocated at all. As it references no values from the environment it is statically allocated and never needs to be placed on the stack or moved to the heap - another optimisation. To get a stack allocated block just change it to:
^{ NSLog(#"Something Happened: %p", self); }
which will be stack allocated (and don't worry about possible retain cycles, that's another topic...)
With that out of the way, let's look at the lifetimes:
The object:
The variable myObject has a lifetime of at most the call to viewDidLoad, the variable is created on entry to the method and destroyed on exit, if precise lifetime semantics are in force, or earlier if not needed and precise lifetime semantics are not in force - the latter is the default allowing the compiler to optimise storage use (independent of ARC). By default local variables have a strong ownership qualifier, so an ownership interest is asserted for any reference stored in one. ARC will release that ownership interest when another reference is stored in the variable or when the variable itself is destroyed. The latter will happen in this case and the variable is destroyed at some time after the last use of it and the end of the method - depending on how the compiler does its optimisations.
All this means that the object referenced by myObject may or may not be still around at your call to NSLog(). In the case of using performSelector:withObject:afterDelay: that call will assert ownership over the object until after the selector has been executed -= so the object will live. In the case of using dispatch_after the object is not required and so will not stay alive.
The block:
As mentioned above as written the block is statically allocated so lifetime is easy - it always exists. More interesting is modifying it as above to make it stack allocated.
If the block is stack allocated it will exist in the stack frame of the viewDidLoad call and unless moved or copied to the heap it will disappear when that call returns.
The call to doSomethingWithBlock: will be passed a reference to this stack allocated block. This is possible as doSomethingWithBlock: expects a block and code within it can move it to the heap if needed as it knows it is a block.
Now it gets interesting. Within doSomethingWithBlock: in the performSelector:withObject:afterDelay: case the block is passed as the withObject: parameter which is of type id - which means the called code expects a standard Objective-C object and those live on the heap. This is a case of type information loss, the caller has a block, the callee only sees an id. So at this point the compiler inserts code to copy the block to the heap and passes that new heap block to performSelector:withObject:afterDelay: - which treats it as it would any other object. [Older compilers did not always do this, the programmer had to know that type information loss was about to occur and manually insert code to move the block to the heap.]
In the case of dispatch_after, the function argument is block typed so the compiler just passes a stack allocated block on. However the dispatch_after function copies the block to the heap, as per its documentation, and there is no problem.
So in either case a stack allocated block is copied to the heap before viewDidLoad finishes and its stack frame is destroyed taking with it the stack allocated block.
HTH.
It is declared outside of the autorelease pool, so it should exist after it. It's all about scope where the object is declared, not allocated. By your logic class variables allocated inside an autorelease pool should be nil'd at the end of the pool and not usable elsewhere.
Example
-(void)function
{
MyObject *object; //MyObject declared here
if(someBoolean)
{
object = [[MyObject alloc] init]; //MyObject allocated here
}
//This is outside the scope of allocation,
//but it's still inside the scope of declaration.
//If ARC referenced the scope of allocation your
//object would not be valid here, as ARC would
//release it as out of scope.
}

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