Best way to create a url method in objective c - ios

Question

I have two labels in my app which purely contain URLs:
-(void)openURLA{
NSString *url = #"http://urla.com";
[[UIApplication sharedApplication] openURL: [NSURL URLWithString:url]];
}
-(void)openURLB{
NSString *url = #"http://urlb.com";
[[UIApplication sharedApplication] openURL: [NSURL URLWithString:url]];
}
And this code inside an existing method:
UITapGestureRecognizer *gra = [[UITapGestureRecognizer alloc] initWithTarget:self action:#selector(openURLA)];
UITapGestureRecognizer *grb = [[UITapGestureRecognizer alloc] initWithTarget:self action:#selector(openURLB)];
When a user taps on one of these labels, the openURL methods run fine and the URL opens in safari.
I was wondering how I could create just one method that will open the URL and pass an argument containing label1.text or label2.text values?
I am not 100% sure where to begin doing this so I will appreciate some help.

Answer 1

EDITED:
Follow this whole code:
UILabel * label1 = [[UILabel alloc] initWithFrame:CGRectMake(40, 70, 300, 50)];
label1.backgroundColor = [UIColor redColor];
label1.userInteractionEnabled = YES;
label1.textColor=[UIColor whiteColor];
label1.text = #"http://urla.com";
[self.view addSubview:label1];
UILabel * label2 = [[UILabel alloc] initWithFrame:CGRectMake(40, 130, 300, 50)];
label2.backgroundColor = [UIColor redColor];
label2.userInteractionEnabled = YES;
label2.textColor=[UIColor whiteColor];
label2.text = #"http://urlb.com";
[self.view addSubview:label2];
UITapGestureRecognizer *gsture1 = [[UITapGestureRecognizer alloc] initWithTarget:self action:#selector(openURLS:)];
[label1 addGestureRecognizer:gsture1];
UITapGestureRecognizer *gesture2 = [[UITapGestureRecognizer alloc] initWithTarget:self action:#selector(openURLS:)];
[label2 addGestureRecognizer:gesture2];
And call method of UITapGestureRecognizer
- (void)openURLS:(UITapGestureRecognizer*)gesture
{
UILabel *lblUrl=(UILabel *)[gesture view];
NSLog(#"%#", lblUrl.text); // here you get your selected label text.
[[UIApplication sharedApplication] openURL: [NSURL URLWithString:lblUrl.text]];
}

Answer 2

On creating a label set tag like:
label1.tag = 1000;
label2.tag = 1001;
UITapGestureRecognizer *gsture1 = [[UITapGestureRecognizer alloc] initWithTarget:self action:#selector(openURLS:)];
[label1 addGestureRecognizer:gsture1];
UITapGestureRecognizer *gesture2 = [[UITapGestureRecognizer alloc] initWithTarget:self action:#selector(openURLS:)];
[label2 addGestureRecognizer:gesture2];
and use the following code to find the view it was tapped
- (void)openURLS:(UITapGestureRecognizer*)sender
{
UIView *view = sender.view;
int tag = view.tag;
if (tag == 1000) {
...
}
}