I have the following string:
R$1.234.567,89
I need it to look like: 1.234.567.89
How can i do this?
This is what i tried:
NSString* cleanedString = [myString stringByReplacingOccurrencesOfString:#"." withString:#""];
cleanedString = [[cleanedString stringByReplacingOccurrencesOfString:#"," withString:#"."]
stringByTrimmingCharactersInSet: [NSCharacterSet symbolCharacterSet]];
It works, but I think there must be a better way. Suggestions?
If your number always after $, but you got more characters before it, you can make it like this:
NSString* test = #"R$1.234.567,89";
NSString* test2 = #"TESTERR$1.234.567,89";
NSString* test3 = #"HEllo123344R$1.234.567,89";
NSLog(#"%#",[self makeCleanedText:test]);
NSLog(#"%#",[self makeCleanedText:test2]);
NSLog(#"%#",[self makeCleanedText:test3]);
method is:
- (NSString*) makeCleanedText:(NSString*) text{
int indexFrom = 0;
for (NSInteger charIdx=0; charIdx<[text length]; charIdx++)
if ( '$' == [text characterAtIndex:charIdx])
indexFrom = charIdx + 1;
text = [text stringByReplacingOccurrencesOfString:#"," withString:#"."];
return [text substringFromIndex:indexFrom];
}
result is:
2013-10-20 22:35:39.726 test[40546:60b] 1.234.567.89
2013-10-20 22:35:39.728 test[40546:60b] 1.234.567.89
2013-10-20 22:35:39.731 test[40546:60b] 1.234.567.89
If you just want to remove the first two characters from your string you can do this
NSString *cleanedString = [myString substringFromIndex:2];
Related
i have string value
NSString *str = #"12:15"
now how to convert it in to integer value??
i tryNSInteger i =[str integerValue];
but it's return only 12 and i want 1215.
Please suggest.
Thank you
A more generic approach would be to replace everything but the numeric values with an empty string like below:
NSString *str = #"12: a15xx";
str = [str stringByReplacingOccurrencesOfString:#"[^0-9]"
withString:#""
options:NSRegularExpressionSearch
range:NSMakeRange(0, str.length)];
NSLog(#"%d", str.integerValue); // prints 1215
a simple answer would be
NSString *str=#"12:15";
str = [str stringByReplacingOccurrencesOfString:#":" withString:#""];
NSInteger i =[str integerValue];
NSArray* arr = [#"12:15" componentsSeparatedByString: #":"];
NSString* strValue = [NSString stringWithFormat:#"%#%#",[arr objectAtIndex:0],[arr objectAtIndex:1]];
int value=(int)strValue;
I have a long string, and I would like to remove a specific hexadecimal character from it.
NSString * myString = #"longlongstringwithcharacters\"ofallsorts\"";
Any suggestions?
The hex character I am after is 08, that corresponds to backspace. How can I use code like the following to substitute it? I have no idea on how to represent 08 in a string:
NSString *stringWithoutSpaces = [myString
stringByReplacingOccurrencesOfString:#" " withString:#""];
EDIT:
I will try to clarify a bit more what I am trying to do..
I am trying to remove all occurrences of a character that corresponds to 08 hex from the string that I receive as payload.
The payload is in a string format and I found out the character by using Xcode debugger and view the hex codes of the string as there was an invalid character when trying to covert the NSData corresponding to the string to a NSDictionary.
I am not sure how to phrase the problem correctly..
- (NSString *)stringFromHexString:(NSString *)hexString {
// The hex codes should all be two characters.
if (([hexString length] % 2) != 0)
return nil;
NSMutableString *string = [NSMutableString string];
for (NSInteger i = 0; i < [hexString length]; i += 2) {
NSString *hex = [hexString substringWithRange:NSMakeRange(i, 2)];
NSInteger decimalValue = 0;
sscanf([hex UTF8String], "%x", &decimalValue);
[string appendFormat:#"%c", decimalValue];
}
return string;
}
Try this code...This will help you to convert Hex to string
NSString * str = #"68656C6C6F";
NSMutableString * newString = [[[NSMutableString alloc] init] autorelease];
int i = 0;
while (i < [str length])
{
NSString * hexChar = [str substringWithRange: NSMakeRange(i, 2)];
int value = 0;
sscanf([hexChar cStringUsingEncoding:NSASCIIStringEncoding], "%x", &value);
[newString appendFormat:#"%c", (char)value];
i+=2;
}
this will help u to convert Hex to NSString
This code worked for me:
NSString * dataString = message.payloadString;
NSString * wrongCharacter = [[NSString alloc] initWithFormat:#"%c", (char)0x08];
dataString = [dataString stringByReplacingOccurrencesOfString:wrongCharacter withString:#""];
I have a number which will be represented as string. It is longer than 4 chars. I need to create new string from 5th till the end for that number.
For example if I have 56789623, I need to have 9623 as a result (5678 | 9623).
How to do that?
P.S. I suppose that this is very simple question, but I don't know how properly ask Google about that.
NSString *str = #"56789623";
NSString *first, *second;
if ([str length] > 4) {
first = [str substringWithRange:NSMakeRange(0, 4)];
second = [str substringWithRange:NSMakeRange(4, [str length] - 4)];
} else {
first = str;
second = nil;
}
Use this Simple functions
- (NSString *)substringFromIndex:(NSUInteger)from;
- (NSString *)substringToIndex:(NSUInteger)to;
- (NSString *)substringWithRange:(NSRange)range;
You can use:
- (NSString *)substringFromIndex:(NSUInteger)anIndex
NSString *number = #"56789623";
NSString *result = [number substringFromIndex:4];
NSLog(#"%#", result);
result contains the string: #"9623"
The keywords you were looking for are: substring and range. There are several ways to use them. Example code split string into 2 equal (if number of characters is even almost equal) substrings:
NSString *str = #"56789623";
NSInteger middleIndex = (NSInteger)(str.length/2);
NSString *strFirstPart = [str substringToIndex:middleIndex];
NSString *strSecondPart = [str substringFromIndex:middleIndex];
NSString *strFirstPart2 = [str substringWithRange:NSMakeRange(0, middleIndex)];
NSString *strSecondPart2 = [str substringWithRange:NSMakeRange(middleIndex, [str length]-middleIndex)];
for example i have string like this:
NSString *one = B3#This is the first string
NSString *two = 1#This is the second string
How can i get the "B3" and "1" Character only (using objective C)
Thanks..
Turns out this is one way to do it:
NSRange range = [one rangeOfString:#"#" options:NSBackwardsSearch];
NSString *newString = [one substringToIndex:range.location];
Thanks for all the answers.
NSString* one = #"B3#";
NSString* two = #"1#";
NSString* result = [one stringByReplacingOccurrencesOfString:#"#" withString:#""];
NSString* result_2 = [two stringByReplacingOccurrencesOfString:#"#" withString:#""];
//if you need to marge
NSString* tot = [NSString stringWithFormat:#"%#%#",result,result_2];
I'w working with a server and I have to download text to my iOS application. Only problem : all characters like "é à ç" are replaced by "\U008" for example. Is there a way to fix this problem, to replace this code by the right character ?
Try to parse the received text (textToParse variable) with this one:
NSString *encodedString = textToParse;
NSString *decodedString = [NSString stringWithUTF8String:[encodedString cStringUsingEncoding:[NSString defaultCStringEncoding]]];
I tested some encodings and NSMacOSRomanStringEncoding fit well.
My test was:
NSString *encodedString = [NSString stringWithCString:"Você realmente deseja sair da área restrita" encoding:NSMacOSRomanStringEncoding];
Remember that the message has to be a C-string ("string") and not an NSString(#"string")
You can get character buffer and validate each character like so:
- (NSString *) removeUnicode:(NSString *) unicodeString {
NSUInteger len = [unicodeString length];
unichar buffer[len+1];
[unicodeString getCharacters:buffer range:NSMakeRange(0, len)];
unichar okBuffer[len+1];
int index = 0;
for(int i = 0; i < len; i++) {
if(buffer[i] < 128) {
okBuffer[index] = buffer[i];
index = index + 1;
}
}
NSString *removedUnicode = [[NSString alloc] initWithCharacters:okBuffer length:index];
return removedUnicode;
}
or you can use this sample:
NSCharacterSet *notAllowedChars = [[NSCharacterSet characterSetWithCharactersInString:[NSCharacterSet alphanumericCharacterSet]] invertedSet];
stringWithOutUnicode = [[stringWithUnicode componentsSeparatedByCharactersInSet:notAllowedChars] componentsJoinedByString:#""];
and you can create your own valid character set and get not allowed characters
NSString *allowedCharacters = #"abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ";
NSCharacterSet *notAllowedChars = [[NSCharacterSet characterSetWithCharactersInString: allowedCharacters] invertedSet];