Fetching contacts based on tag - ios

Question

I'm trying to modify a simple Core Data fetch request for contacts to only look for contacts with a relationship with a certain tag. Contact and Tag are both entities with a many-to-many relationship.
I understand with Core Data I can do this by first fetching the Tag object, and then calling tag.contact, but I don't want to do it this way as the rest of the code is dependent on the fact that the fetchResultsController returns Contact objects, not Tag objects.
If I were to do relational databasing, I could do a simple cross-table query and find all contacts with a certain tag. Is there a simple way I can replicate this via Core Data?
-(NSFetchedResultsController *) fetchedResultsController {
//if fetch controller already exists
if(_fetchedResultsController != nil) {
return _fetchedResultsController;
}
//create a new fetch request
NSFetchRequest *fetchRequest = [[NSFetchRequest alloc] init];
NSEntityDescription *entity = [NSEntityDescription entityForName:#"Contact"
inManagedObjectContext:[self managedObjectContext]];
[fetchRequest setEntity:entity];
NSSortDescriptor *sortDescriptor = [[NSSortDescriptor alloc] initWithKey:#"lastName"
ascending:YES];
NSArray *sortDescriptors = [[NSArray alloc] initWithObjects:sortDescriptor, nil];
[fetchRequest setSortDescriptors:sortDescriptors];
//instantiate the fetch controller with the fetch request and sort by last name into sections
_fetchedResultsController = [[NSFetchedResultsController alloc] initWithFetchRequest:fetchRequest managedObjectContext:[self managedObjectContext] sectionNameKeyPath:nil cacheName:nil];
//declare delegate of fetch controller as self
_fetchedResultsController.delegate = self;
NSLog(#"fetchResultsController Created");
return _fetchedResultsController;
}

Answer 1

Use NSPredicate.
Lets say you have related Contacts with Tag by name tags and tag entity has property name.
NSPredicate *predicate = [NSPredicate predicateWithFormat:#"ANY tags.name = [cd] %#", #"sales"];
[fetchRequest setPredicate:predicate];