I want to make irregular shaped UIScrollView(using CGPath or UIBezierPath).
The contents will be scrollable and zoomable. And scroll actions will be accepted only in these areas, not rectangular area. Any ideas?
Your could use a CAShapedLayer with a path to create a clipping path and apply this to the Scrollview's layer's mask. Use the same path in the view's hitTest:withEvent: to decide, if the UIView should response to a touch or not.
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I have a UIView which contains a stack of subviews. I want to draw bezier path on the super view. The angle of subviews is dynamic. Can somebody tell me how to achieve this?
I need to create an animated chevron effect using the bitmap tile below. I am hoping that a UIView with a pattern fill will be sufficient, but I need to be able to animate the origin of the pattern over time, and I can't see that this is possible.
I think this is possible with Quartz, or CoreGraphics at the low level. What would be the best way to do this, and can you provide some example code in Swift that demonstrates the solution?
I would add the image as contents of multiple sublayers (CALayer instances) aligned one below the other and animate those sublayers y position.
The main layer would clip its sublayers on the border and sublayers that go offscreen would move to the bottom to be reused, similarly to how UITableView reuses its cells.
You might also want to look at CADisplayLink to have better control of the rendering.
I've used the CGContext based routine to fill a rectangle, but this time I actually want to fill all of a rectangle EXCEPT one part of it. I know this is possible in other drawing systems for other platofrm but can it be done with core graphics on iOS?
Both borderWidth and cornerRadius are animatable properties. So you could just animate them directly (using CABasicAnimation). In that rendering, you'd go from no border and no corners to having a border and corners in an animated way.
If you want to animate the rectangular tracing of the border, you'd need to use a CAShapeLayer (because the end of its path is animatable) and provide the illusion that way.
I'm trying to draw a complex border around a UIView in it's drawRect method using core graphics. The border is being clipped because it's outside of the view's bounds. Is there any way to prevent this clipping? Setting clipsToBounds to NO doesn't work.
drawRect: gives you a CGRect. This defines the area in which you can draw. As it stands, you cannot draw outside this area.
You'd have to look into a different solution to your problem. I'd suggest CALayers, or a subview/superview hierarchy, perhaps a border view and a content view. But don't try doing that in drawRect:, unless you can get the desired results while keeping within the area specified by drawRect:.
I have a UIView. I am drawing a line inside the UIView programmativally. But when the line goes outside the UIView, the part of the line which goes out, is invisible. How can I resize the UIView so that whatever I draw inside the drawRect method is visible?
you can change the frame of view. If your line is horizontal then give width to view else increase height of view.
view.frame = CGRectMake(view.frame.origine.x, view.frame.origine.y,view.frame.size.width,lengthOfLine );
If the curve you are drawing is a subview, then you can make use of sizeToFit method. This will make the view's frame enclose the curve(and all subviews, for that matter). Then you can reposition and scale the view's frame to make it fit in the window.
You have mentioned in a comment that you are actually drawing a curve. From what I can tell, you will need to calculate the curve's bounding box yourself.
Based on the bounding box, update the UIView's bounds property (as Durgaprasad suggested). This also resizes the underlying CALayer, which also gives its underlying Core Graphics rendering context a larger bitmap.
Without knowing more about your curve, it's hard to help, apart from linking to some very generic discussion on quadratic Beziers.
You may want to update your question with a minimal implementation of -drawRect: that will allow someone to reproduce your issue.