error: database is locked in sqlite - ios

Question

//create database here
-(void) createDataBase
{
docPath = [NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES)objectAtIndex:0];
fullPath = [docPath stringByAppendingPathComponent:#"Recording.sqlite"];
sqlite3_open([fullPath UTF8String], &dbForEmf);
}
// create table
-(void) createTable
{
if (sqlite3_open([fullPath UTF8String], &dbForE) == SQLITE_OK)
{
const char* createQuery = "CREATE TABLE IF NOT EXISTS EEE(E_ID INTEGER PRIMARY KEY AUTOINCREMENT NOT NULL, E_NAME TEXT,E_READING TEXT,E_DATE TEXT,E_SIZE TEXT,E_LABLE TEXT)";
int errorCode = sqlite3_prepare(dbForE, createQuery, -1, &prepareStmt, NULL);
if (errorCode == 0) {
sqlite3_step(prepareStmt);
}
else
{
}
sqlite3_finalize(prepareStmt);
sqlite3_close(dbForE);
}
else
{
NSLog(#"data base not Open");
}
}
// insert data here
-(void) insertData
{
if (sqlite3_open([fullPath UTF8String], &dbForE)==SQLITE_OK)
{
NSString *insertSql = [NSString stringWithFormat:#"INSERT INTO EEE(E_NAME,E_READING,E_DATE,E_SIZE,E_LABLE) VALUES('%#','%#','%#','%#','%#')",_referenceObject.lastFilePath,_referenceObject.fileString,_referenceObject.dateString,_referenceObject.fileSizeString,_referenceObject.titleOfButtonString];
const char *insert_stmt=[insertSql UTF8String];
sqlite3_prepare_v2(dbForE,insert_stmt,-1,&prepareStmt,NULL);
sqlite3_reset(prepareStmt);
if (sqlite3_step(prepareStmt)==SQLITE_DONE)
{
NSLog(#"inserted the values in table");
}
else
{
NSLog(#" not inserted the values in table");
NSLog(#"error: %s", sqlite3_errmsg(dbForE));
}
sqlite3_finalize(prepareStmt);
sqlite3_close(dbForE);
}
}
hai data is insert on first viewController when ever i goto second viewController and come back to first viewController the data is not inserted error displays database is locked...

Answer 1

check if you have leave the database open in second ViewController or anywhere else.

Answer 2

in createDataBase you have opened your database and it was not closed and you again tried to open this hence your database get locked first you should close database in createdatabase function.