Not sure what's the matter here :
file = Rails.root.join(Attachment.last.attachment.url(:original))
# => "/system/attachments/3/original/!my_awesome_pdf.pdf?1359735260"
Then I try and do this :
File.new(file, 'rb')
# => No such file or directory - /system/attachments/3/original/!my_awesome_pdf.pdf?1359735260
Why would that happen? I'm trying to be able to select the file to upload to GroupDocs.com
Ah the problem was that URI's will throw off Ruby from recognizing the name of the file. Removing the URI allows Ruby to open the file.
Related
I have a problem with my attachment system on web page. I store them on amazon S3 using paperclip. I have an option to copy attachment to new file. Everything works fine until there are polish special characters in title, like: ŁĄKA.jpg. Then I get an error:
Saving error: Appendix Paperclip::Errors::NotIdentifiedByImageMagickError
/Users/michal/.rbenv/versions/2.1.5/lib/ruby/gems/2.1.0/gems/activerecord-4.2.5/lib/active_record/validations.rb:79:in `raise_record_invalid'
/Users/michal/.rbenv/versions/2.1.5/lib/ruby/gems/2.1.0/gems/activerecord-4.2.5/lib/active_record/validations.rb:43:in `save!'
My code:
instance.appendixes.select {|a| a.temporary? && !a.appendix.exists?}.each do |a|
a.appendix = S3File.new(a.s3path)
a.process = false
a.appendix_url = nil
puts "CREATING NEW FILE from (temporary?) appendix: #{a.id}, path: #{a.s3path}, is_public: #{a.is_public}, determine_is_public: #{a.determine_is_public}"
a.is_public = a.determine_is_public
logger.debug("CREATING NEW FILE from (temporary?) appendix: #{a.id}, path: #{a.s3path}, is_public: #{a.is_public}, determine_is_public: #{a.determine_is_public}")
a.save! # bo delayed_job
end
I'm getting error on a.save! when path is like: appendixes/appendixes/242/original/%25C5%2581A%25CC%25A8KA.jpg, but works like charm when it is: appendixes/appendixes/243/original/laka.jpg or another file name without polish letters. Anybody had this kind of problem or have suggestions how to fix it?
Ok, I found what was wrong. I had to replace in a.s3path, the last part with original name (łąka.jpg) and everything works fine. So when I have:
S3File.new(appendixes/appendixes/243/original/łąka.jpg) it works good and finds the correct file on s3 server.
I am trying to upload a file to a server using the Net::SFTP gem. My code is as follows:
remote_path = "path/of/remote/file.txt"
local_path = "path/to/local/file.txt"
Net::SFTP.start("SERVER", "USER", :password => "PASSWORD") do |sftp|
sftp.upload!(local_path, remote_path)
end
When I execute this I get:
Net::SFTP::StatusException (Net::SFTP::StatusException open path/of/remote/file.txt (2, "no such file"))
I think the issue is that the entire remote_path of the directories doesn't exist yet. If I give it a path of directories that do exist, it will create the directories. I want the upload to also create the directories in the path if they don't exist yet. Is this indeed the issue, and if so, how can I create the directories with SFTP?
you will have to create the directory first
sftp.mkdir! "/path/to/directory"
Here's a little snippet to check if the dir exists and create it if not:
if !sftp.dir.entries("root").map { |entry| entry.name }.include?("new_dir")
sftp.mkdir("root/new_dir")
end
I am using Net::FTP's getbinaryfile functionality to pull in a zip file with FTP. My system is not aware of the full file name, so I would simply like to search the folder for the zip file extension. Usually I would simply input the filename as *.zip. This does not seem to work.
ftp = Net::FTP.new(domain)
path = "#{Rails.root}/public/ftp/#{self.id}.zip"
ftp.getbinaryfile("*.zip", path)
I used the following code to return the zip file name in the FTP folder. Then using the same code as above, I was able to run getbinaryfile with the correct zip file name.
files = ftp.nlst("*.zip")
I use the following to get all zip files (I'm using SFTP but hopefully this will point you in the right direction)
Net::SFTP.start(domain, user, :password => 'pass') do |sftp|
sftp.dir.glob("/yourdirectory","*.zip").each do |file|
sftp.download!(file, "/local/spot")
end
end
I'm having some problems reading a file from S3. I want to be able to load the ID3 tags remotely, but using open-URI doesn't work, it gives me the following error:
ruby-1.8.7-p302 > c=TagLib2::File.new(open(URI.parse("http://recordtemple.com.s3.amazonaws.com/music/745/original/The%20Stranger.mp3?1292096514")))
TypeError: can't convert Tempfile into String
from (irb):8:in `initialize'
from (irb):8:in `new'
from (irb):8
However, if i download the same file and put it on my desktop (ie no need for open-URI), it works just fine.
c=TagLib2::File.new("/Users/momofwombie/Desktop/blah.mp3")
is there something else I should be doing to read a remote file?
UPDATE: I just found this link, which may explain a little bit, but surely there must be some way to do this...
Read header data from files on remote server
Might want to check out AWS::S3, a Ruby Library for Amazon's Simple Storage Service
Do an AWS::S3:S3Object.find for the file and then an use about to retrieve the metadata
This solution assumes you have the AWS credentials and permission to access the S3 bucket that contains the files in question.
TagLib2::File.new doesn't take a file handle, which is what you are passing to it when you use open without a read.
Add on read and you'll get the contents of the URL, but TagLib2::File doesn't know what to do with that either, so you are forced to read the contents of the URL, and save it.
I also noticed you are unnecessarily complicating your use of OpenURI. You don't have to parse the URL using URI before passing it to open. Just pass the URL string.
require 'open-uri'
fname = File.basename($0) << '.' << $$.to_s
File.open(fname, 'wb') do |fo|
fo.print open("http://recordtemple.com.s3.amazonaws.com/music/745/original/The%20Stranger.mp3?1292096514").read
end
c = TagLib2::File.new(fname)
# do more processing...
File.delete(fname)
I don't have TagLib2 installed but I ran the rest of the code and the mp3 file downloaded to my disk and is playable. The File.delete would clean up afterwards, which should put you in the state you want to be in.
This solution isn't going to work much longer. Paperclip > 3.0.0 has removed to_file. I'm using S3 & Heroku. What I ended up doing was copying the file to a temporary location and parsing it from there. Here is my code:
dest = Tempfile.new(upload.spreadsheet_file_name)
dest.binmode
upload.spreadsheet.copy_to_local_file(:default_style, dest.path)
file_loc = dest.path
...
CSV.foreach(file_loc, :headers => true, :skip_blanks => true) do |row|}
This seems to work instead of open-URI:
Mp3Info.open(mp3.to_file.path) do |mp3info|
puts mp3info.tag.artist
end
Paperclip has a to_file method that downloads the file from S3.
I need to create a local xml file from a rails application and then copy it to a location on another server.
I have tried using the File.new option to create a new file but it gives me an error saying the file does not exist. After looking closer at the documentation it says that File.new opens a file that already exists.
I can't see any way to create a local file using Ruby, what am I missing?
Assuming you have built up your XML into a string, xml_string, you can do:
xml_file = open(filename, 'w')
xml_file.write xml_string
xml_file.close
Or using the block syntax to achieve this in one line:
File.open(local_filename, 'w') { |f| f.write(xml_string) }