I need to create a local xml file from a rails application and then copy it to a location on another server.
I have tried using the File.new option to create a new file but it gives me an error saying the file does not exist. After looking closer at the documentation it says that File.new opens a file that already exists.
I can't see any way to create a local file using Ruby, what am I missing?
Assuming you have built up your XML into a string, xml_string, you can do:
xml_file = open(filename, 'w')
xml_file.write xml_string
xml_file.close
Or using the block syntax to achieve this in one line:
File.open(local_filename, 'w') { |f| f.write(xml_string) }
Related
I am trying to create a new file and then write some content to it just to create a basic backup of a template.
When I log out the values of filename and file_content they are correct, but when I send the data all I get is a file named after the method (download_include) and a fixnum inside the file, the last one made was 15.
# POST /download_include/:id
def download_include
#include = Include.find(params[:id])
version_to_download = #include.latest_version_record
filename = "#{version_to_download.name}"
file_content = "#{version_to_download.liquid_code.to_s}"
file = File.open(filename, "w") { |f| f.write (file_content) }
send_data file
end
I also tried send_file but that produces the error
no implicit conversion of Fixnum into String
I also tried to just write dummy values like below, and it still produced a file named after the method with a fixnum inside it.
file = File.open("DOES THIS CHANGE THE FILENAME?", "w") { |f| f.write ("FILE CONTENT?") }
I feel I am missing something obvious but I cannot figure it out after looking at many examples here and in blogs.
If you don't end along the filename as an option for send_data, it defaults to the method name.
Secondly, the download wants to read the data from a buffer. My guess is your syntax is just sending a file handle.
Try this...
send_data(file.read, filename: filename)
Or skip the intermediate file and try...
send_data(version_to_download.liquid_code.to_s, filename: filename)
I have the following code to connect my rails app to my FTP. This works great. However, I want to use open-uri to open the csv file so I can parse it. Any ideas how to do this? I think it's an easy thing to do but I'm missing something.
require 'net/ftp'
ftp = Net::FTP.new
ftp.connect("xxx.xxx.xx.xxx",21)
ftp.login("xxxxx","xxxx")
ftp.chdir("/")
ftp.passive = true
puts ftp.list("TEST.csv")
You'll need to use #gettextfile.
A) Get the file to a local temporary file and read its content
# Creating a tmp file can be done differently as well.
# It may also be omitted, in which case `gettextfile`
# will create a file in the current directory.
Dir::Tmpname.create(['TEST', ['.csv']) do |file_name|
ftp.gettextfile('TEST.csv', file_name)
content = File.read(file_name)
end
B) Pass a block to gettextfile and get the content one line at a time
content = ''
ftp.gettextfile('TEST.csv') do |line|
content << line
end
I am having some trouble writing a file to a specific path taking the file name from excel. Here is the code which I am using
out_file = File.new (#temp_path/ "#{obj_info[3].to_s}","w")
"#{obj_info[3].to_s}" = sample.txt
The value sample.txt comes from Excel during run time
#temp_path = "C:/Users/Somefolder/"
The error displayed is:
NoMethodError: undefined method `[]' for nil:NilClass
However, if the code is:
out_file = File.new ("#{obj_info[3].to_s}","w")
it successfully creates a file called sample.txt in the default directory. However, I want it to be stored in a specific directory and the file name needs to be passed from Excel.
Any help is much appreciated.
I believe your problem is because there a space between / and "
#temp_path/ "#{obj_info[3].to_s}
and I guess you want to build a path.
My advice is that you use File.join
f_path = File.join(#temp_path,obj_info[3].to_s)
out_file = File.new (f_path,"w")
Let me know if that solved the problem
You have 2 problems:
obj_info is nil so you make an error reading the value from excel, the error you get indicates it is on an array, in the code you published the only thing that's an array is what you read from excel.
Print the contents with p obj_info right before your code to check.
#temp_path and {obj_info[3].to_s} need to be concatenated to make a path.
You can do that with File.join like Mauricio suggests or like this
out_file = File.new ("#{#temp_path}/#{obj_info[3]}","w")
You can drop the to_s in this case.
It would be better if you publish the whole of your script that is meaningful.
I want to create a temporary .zip in rails. For creating zip file I am using rubyzip gem.
Currently I am doing this:
zfname = Tempfile.new(['somename','.zip'], Rails.root.to_s + '/tmp/')
Zip::ZipFile.open(zfname.path, Zip::ZipFile::CREATE) do |zipfile|
zipfile.add(file, basepath + file)
end
This generates following error:
Zip::ZipError: Zip end of central directory signature not found
Is it possible to use Tempfile for zip? If yes, what is wrong here?
In my rails app when I needed to send zip files to user, I just stored them in a buffer and used 'send data' method in controller.
I was trying to use 'Tempfile' initially but it had an added task of removing zip files after sending it to user which is a pain.
Is this something you are looking for?
Zip::OutputStream.write_buffer do |stream|
file_paths.each_with_index do |file_path, index|
# rename the pdf
stream.put_next_entry("#{name}-#{index + 1}.pdf")
# add pdf to zip
stream.write IO.read(file_path)
end
end
So it doesn't actually look like you need or want a Tempfile. You really want a random path in the Rails.root/tmp directory. Try something like this:
zfpath = Rails.root.join('tmp', "somename-#{SecureRandom.hex(8)}.zip"
Zip::ZipFile.open(zfpath, Zip::ZipFile::CREATE) do |zipfile|
zipfile.add(file, basepath + file)
end
Update:
While it's far more complex, you can find a discussion of how to do this with a Tempfile here - http://thinkingeek.com/2013/11/15/create-temporary-zip-file-send-response-rails/ .
Not sure what's the matter here :
file = Rails.root.join(Attachment.last.attachment.url(:original))
# => "/system/attachments/3/original/!my_awesome_pdf.pdf?1359735260"
Then I try and do this :
File.new(file, 'rb')
# => No such file or directory - /system/attachments/3/original/!my_awesome_pdf.pdf?1359735260
Why would that happen? I'm trying to be able to select the file to upload to GroupDocs.com
Ah the problem was that URI's will throw off Ruby from recognizing the name of the file. Removing the URI allows Ruby to open the file.