Getting the value of sibling nodes in XSLT - xslt-2.0

I have the following XML
<CN>12<CN>
<CT>XYXY</CT>
I need the result AS
<DIV>12 XYXY</DIV>
I'm USING the floowing XSLT but it's not working
<xsl:variable name="x"><xsl:value-of select="CN"/></xsl:variable>
<xsl:template match="CT">
<div class="chap-title"><span><xsl:value-of select="$x"/></span></div>
</xsl:template>


Input:
<input>
<CN>12</CN>
<CT>XYXY</CT>
</input>
XSLT:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="2.0">
<xsl:output indent="yes"
method="xml"
encoding="UTF-8" />
<xsl:template match="/input">
<DIV>
<xsl:value-of select="CN"/>
<xsl:text> </xsl:text>
<xsl:value-of select="CT"/>
</DIV>
</xsl:template>
</xsl:stylesheet>

Related

How to check the sibling to output correct data after grouping?

I want to group by Reference below. XML input file
<root>
<row>
<Company>HHH</Company>
<Posting_Key>40</Posting_Key>
<Reference>12345</Reference>
<Assignment>54321</Assignment>
</row>
<row>
<Company>HHH</Company>
<Posting_Key>15</Posting_Key>
<Reference>12345</Reference>
<Assignment>321</Assignment>
</row>
<row>
<Company>HHH</Company>
<Posting_Key>15</Posting_Key>
<Reference>12345</Reference>
<Assignment>311</Assignment>
</row>
<root>
<row>
<Company>SSS</Company>
<Posting_Key>40</Posting_Key>
<Reference>67890</Reference>
<Assignment>78968</Assignment>
</row>
<row>
<Company>SSS</Company>
<Posting_Key>15</Posting_Key>
<Reference>67890</Reference>
<Assignment>98769</Assignment>
</row>
Desired Output where Posting Key 40 is inside the row, and posting key 15 are inside the details within that row.
<root>
<row>
<Company>HHH</Company>
<Posting_Key>40</Posting_Key>
<Reference>12345</Reference>
<Assignment>54321</Assignment>
<details>
<Company>HHH</Company>
<Posting_Key>15</Posting_Key>
<Reference>12345</Reference>
<Assignment>54321</Assignment>
</details>
<details>
<Company>HHH</Company>
<Posting_Key>15</Posting_Key>
<Reference>12345</Reference>
<Assignment>311</Assignment>
</details>
</row>
<row>
<Company>SSS</Company>
<Posting_Key>40</Posting_Key>
<Reference>67890</Reference>
<Assignment>78968</Assignment>
<details>
<Company>SSS</Company>
<Posting_Key>15</Posting_Key>
<Reference>67890</Reference>
<Assignment>98769</Assignment>
</details>
</row>
</root>
Current XSL code,
this only gets the data on the row where posting key is 40. How to check the sibling Posting Key 40 or 15 to output the correct value on the details section?
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema" exclude-result-prefixes="xs" version="2.0">
<xsl:template match="root">
<root>
<xsl:for-each-group select="row[Posting_Key='40']" group-by="Reference">
<row>
<xsl:value-of select="Company_Code"/>
<xsl:value-of select="Posting_Key"/>
<xsl:value-of select="Reference"/>
<xsl:value-of select="Assignment"/>
<xsl:for-each select="current-group()">
<details>
<xsl:value-of select="Company_Code"/>
<xsl:value-of select="Posting_Key"/>
<xsl:value-of select="Reference"/>
<xsl:value-of select="Assignment"/>
</details>
</xsl:for-each>
</row>
</xsl:for-each-group>
</root>
</xsl:template>
</xsl:stylesheet>
this only gets the data on the row where posting key is 40. How to check the sibling Posting Key 40 or 15 to output the correct value on the details section?

It looks like you rather want to use group-starting-with than group-by:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="#all"
version="3.0">
<xsl:mode on-no-match="shallow-copy"/>
<xsl:output indent="yes"/>
<xsl:template match="root">
<xsl:copy>
<xsl:for-each-group select="row" group-starting-with="row[Posting_Key = 40]">
<xsl:copy>
<xsl:apply-templates/>
<xsl:apply-templates select="tail(current-group())"/>
</xsl:copy>
</xsl:for-each-group>
</xsl:copy>
</xsl:template>
<xsl:template match="row">
<details>
<xsl:apply-templates/>
</details>
</xsl:template>
</xsl:stylesheet>
https://xsltfiddle.liberty-development.net/gVhDDyL

Keeping track of an iterator through a nested xsl:for-each

I want to take the following input:
<test>
<a>
<b />
<b />
</a>
<a>
<b />
<b />
</a>
</test>
And create the following output using XSLT 2.0:
<items>
<item num="1">
<item num="2"/>
<item num="3"/>
</item>
<item num="4">
<item num="5"/>
<item num="6"/>
</item>
</items>
I know this is wrong, but for a starting point, here's my current XSLT:
<xsl:template match="test">
<items>
<xsl:for-each select="a">
<item num="{position()}">
<xsl:for-each select="b">
<item num="{position()}"/>
</xsl:for-each>
</item>
</xsl:for-each>
</items>
</xsl:template>
This is clearly not the way to do it, because position() only considers elements in the same level. But how would I do this?

This transformation:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/*">
<items><xsl:apply-templates/></items>
</xsl:template>
<xsl:template match="a|b">
<xsl:variable name="vNum">
<xsl:number level="any" count="a|b"/>
</xsl:variable>
<item num="{$vNum}">
<xsl:apply-templates/>
</item>
</xsl:template>
</xsl:stylesheet>
when applied on the provided XML document:
<test>
<a>
<b />
<b />
</a>
<a>
<b />
<b />
</a>
</test>
produces the wanted, correct result:
<items>
<item num="1">
<item num="2"/>
<item num="3"/>
</item>
<item num="4">
<item num="5"/>
<item num="6"/>
</item>
</items>

In XSLT 2, using xsl:number is the right way, if your XSLT processor also supports XSLT 3, then using an accumulator https://www.w3.org/TR/xslt-30/#element-accumulator is an alternative:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="#all"
version="3.0">
<xsl:mode on-no-match="shallow-copy" use-accumulators="item-count"/>
<xsl:accumulator name="item-count" as="xs:integer" initial-value="0">
<xsl:accumulator-rule match="test" select="0"/>
<xsl:accumulator-rule match="test/a | test/a/b" select="$value + 1"/>
</xsl:accumulator>
<xsl:template match="test">
<items>
<xsl:apply-templates/>
</items>
</xsl:template>
<xsl:template match="a | b">
<item num="{accumulator-before('item-count')}">
<xsl:apply-templates/>
</item>
</xsl:template>
</xsl:stylesheet>
https://xsltfiddle.liberty-development.net/3NSSEvn
That would even work with streaming in Saxon EE where xsl:number is not supported:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="#all"
version="3.0">
<xsl:mode on-no-match="shallow-copy" use-accumulators="item-count" streamable="yes"/>
<xsl:accumulator name="item-count" as="xs:integer" initial-value="0" streamable="yes">
<xsl:accumulator-rule match="test" select="0"/>
<xsl:accumulator-rule match="test/a | test/a/b" select="$value + 1"/>
</xsl:accumulator>
<xsl:template match="test">
<items>
<xsl:apply-templates/>
</items>
</xsl:template>
<xsl:template match="a | b">
<item num="{accumulator-before('item-count')}">
<xsl:apply-templates/>
</item>
</xsl:template>
</xsl:stylesheet>

I figured out one solution: use xsl:number with any level and counting both a and b:
<xsl:template match="test">
<items>
<xsl:for-each select="a">
<item>
<xsl:attribute name="num">
<xsl:number level="any" count="a|b"/>
</xsl:attribute>
<xsl:for-each select="b">
<item>
<xsl:attribute name="num">
<xsl:number level="any" count="a|b"/>
</xsl:attribute>
</item>
</xsl:for-each>
</item>
</xsl:for-each>
</items>
</xsl:template>

update more than one result in same uri

I want to update the same result document to accumulate all the meta elements. I have tried to recreate the multiple dita-ot templates to explain the problem here. My question is, is it possible to update keyword.xml in the
<xsl:template match="html" mode="pages">
template itself? maybe using xsl:stream or xsl:accumulator? XSLT 3 and Saxon-HE-9.8.0-12
Input XML
<root>
<article>
<html name="firsthtm">
<head>Head1</head>
<meta>keyword;firsthtm</meta>
</html>
<html name="secondhtm">
<head>Head2</head>
<meta>keyword;secondhtm</meta>
</html>
<html name="thirdhtm">
<head>Head3</head>
<meta>keyword;thirdhtm</meta>
</html>
</article>
XSLT
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema" exclude-result-prefixes="xs" version="3.0">
<xsl:template match="/">
<xsl:apply-templates/>
</xsl:template>
<xsl:template match="article">
<xsl:apply-templates mode="pages"/>
</xsl:template>
<xsl:template match="html" mode="pages">
<xsl:result-document href="{#name}.html">
<html>
<title>
<xsl:value-of select="#name"/>
</title>
</html>
</xsl:result-document>
<!-- update keyword.xml for each html -->
<xsl:result-document href="keyword.xml">
<root>
<xsl:copy-of select="meta"/>
</root>
</xsl:result-document>
</xsl:template>
firsthtm.htm
<html>
<title>firsthtm</title>
</html>
secondhtm.htm
<html>
<title>secondhtm</title>
</html>
thirdhtm.htm
<html>
<title>thirdhtm</title>
</html>
keyword.xml
<root>
<meta>keyword;secondhtm</meta>
<meta>keyword;secondhtm</meta>
<meta>keyword;thridhtm</meta>
</root>

Just create the result document in the template matching article:
<xsl:template match="article">
<xsl:apply-templates mode="pages"/>
<xsl:result-document href="keyword.xml">
<root>
<xsl:copy-of select="html/meta"/>
</root>
</xsl:result-document>
</xsl:template>
If you want to use the match="html" mode="pages" then you have to decide on which match you want to construct that result e.g on the first
<xsl:template match="html" mode="pages">
<xsl:result-document href="{#name}.html">
<html>
<title>
<xsl:value-of select="#name"/>
</title>
</html>
</xsl:result-document>
<!-- update keyword.xml for first html -->
<xsl:variable name="html-index" as="xs:integer">
<xsl:number/>
</xsl:variable>
<xsl:if test="$html-index = 1">
<xsl:result-document href="keyword.xml">
<root>
<xsl:copy-of select="ancestor::article/html/meta"/>
</root>
</xsl:result-document>
</xsl:if>
</xsl:template>
In simple cases (there are only those html element children for the article and you have used xsl:strip-space) it might suffice to simply test <xsl:if test="position() = 1">.

A simple solution would be moving the xsl:result-document to the article template and copy all html/meta elements from there:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema" exclude-result-prefixes="xs" version="3.0">
<xsl:template match="/">
<xsl:apply-templates/>
</xsl:template>
<xsl:template match="article">
<xsl:apply-templates mode="pages"/>
<xsl:result-document href="keyword.xml">
<root>
<xsl:copy-of select="html/meta"/>
</root>
</xsl:result-document>
</xsl:template>
<xsl:template match="html" mode="pages">
<xsl:result-document href="{#name}.html">
<html>
<title>
<xsl:value-of select="#name"/>
</title>
</html>
</xsl:result-document>
<!-- update keyword.xml for each html -->
</xsl:template>
</xsl:stylesheet>

How to remove Soap namespace associated with attribute

I have to remove the soap name space associated with ConfigR(attribute).
Inside XSLT I am using XSL Copy and hence exclude prefix is not working.
I have tried below, but not working.Please can anyone suggest.
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" >
<xsl:output indent="yes"/>
<xsl:template match="#* | node()">
<xsl:copy>
<xsl:apply-templates select="#* | node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="soapenv:*">
<xsl:apply-templates select="#* | node()"/>
</xsl:template>
</xsl:stylesheet>
Input -
<soapenv:Envelope
xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/">
<soapenv:Body>
<ConfigR>
Inside I have some more input.
</ConfigR>
</soapenv:Body>
</soapenv:Envelope>
Now in Output I am getting:
<ConfigR xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/">

You can replace you existing template:
<xsl:template match="#* | node()">
<xsl:copy>
<xsl:apply-templates select="#* | node()" />
</xsl:copy>
</xsl:template>
with following:
<xsl:template match="*">
<xsl:element name="{local-name(.)}">
<xsl:apply-templates select="#* | node()" />
</xsl:element>
</xsl:template>
<xsl:template match="#*">
<xsl:attribute name="{local-name(.)}">
<xsl:value-of select="." />
</xsl:attribute>
</xsl:template>
You can find it here

Create a list of element from nested elements in xslt?

I have a document with nested elements.Now I want to list them one element after another element using XSLT 2.0
Here is the input:
<?xml version="1.0" encoding="UTF-8"?>
<a>
<b>
test text
<b>
this text is in b
</b>
</b>
<b>
this text is
<b>
this text is test
</b>
</b>
</a>
This is what I expect:
<a>
<b>test text</b>
<b>this text is in b</b>
<b>this text is </b>
<b>this text is test</b>
</a>
I have no any idea to do this..I tried grouping concept..but it was not succeeded.Please help me to resolve this.

try this
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:strip-space elements="*"/>
<xsl:output indent="yes" omit-xml-declaration="yes"/>
<xsl:template match="*|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="b[b]">
<xsl:copy>
<xsl:apply-templates select="text()"/>
</xsl:copy>
<xsl:apply-templates select="*"/>
</xsl:template>
<xsl:template match="text()">
<xsl:value-of select="normalize-space(.)"/>
</xsl:template>
</xsl:stylesheet>

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