I want to read file from "res" folder on blackberry. The file that i used is a file javascript.
I used this code InputStream in = classs.getResourceAsStream("file.js");. But i get "could not find this path" and I use also
String srcFile = "/res/ressourcesWeb/file.js";
FileConnection srcConn = (FileConnection) Connector.open(srcFile, Connector.READ);
InputStream in = srcConn.openInputStream();
but i got an exception.
Can any one help me to read the file and give me the right path that should I use?
Your res folder has to be inside src folder to be accessed from your code.
src folder is the root folder of your project package. And all folders outside of src folder are invisible for the code at runtime.
Check this post for more details: Blackberry runtime error: FRIDG: could not find img/logo.png
There's file location principle described.
You actually do not need to put your resources under the src folder for them to be accessible from your code.
That is one way to do it, but I don't think it's the best way. Files under the src folder should really be source code, not images, or other resources. For JavaScript resources, it's debatable whether those should be under src or not. Most projects I've seen have used the src folder for only Java source code.
In any case, if you would like to keep your file (or other resources, like images) outside the src folder, you can do so. The BlackBerry plugin for Eclipse actually sets it up like this by default, when you create a new project. There is a res folder at the top level, next to (not under) src.
If you have
src\
src\com\mycompany\myapp\
res\
res\resourcesWeb\
res\resourcesWeb\file.js
Then, you can open the file like this:
String jsPath = "/resourcesWeb/file.js";
InputStream input = getClass().getResourceAsStream(jsPath);
byte [] content = IOUtilities.streamToBytes(input);
String contentAsString = new String(content);
P.S. You also can probably do this:
String jsPath = "/file.js";
InputStream input = getClass().getResourceAsStream(jsPath);
and not specify the path to the resource. Obviously, this will only work if there are no naming conflicts in your resource folders (e.g. you don't have /res/resourcesWeb/file.js and also /res/otherPath/file.js)
Related
I want to load the bytes of a file into a variable while testing my flutter application.
I can't use the assets directory as those are bundled with the app and require WidgetsFlutterBinding.ensureInitialized();
I tried searching the file manually with the path package, but this did not seem to work and was rather hacky. That is why i'm searching for a more official approach.
I was thinking way to complicated ...
As Chuck Batson commented, you can just use the path from the projects root for passing it into the (dart:io) File:
File loadResource(String relativePath) {
final filePath = path.join("test", "resources", relativePath);
return File(filePath);
}
(Notice: The above code makes use of the path package for constructing a file path.)
I'm trying to create link for the file upload. I'm calling file upload function from .cfc file. The file should be uploaded in a different folder. Here is what I get if after this code is executed in component.cfc page:
<cfset thisPath = ExpandPath( "./" ) />
C:\\wwwroot\\myapp\\components\\
I need to go level back in myapp and open bug folder. Then in a bug folder I need to direct the path either to folder1/ documents or folder2/documents. That will depend on the form field, here is example:
<cfset folder = trim(form.type) EQ 1 "folder1" : "folder2">
The path should either point to:
C:\\wwwroot\\myapp\\bug\\folder1\\documents\\
or
C:\\wwwroot\\myapp\\bug\\folder2\\documents\\
I'm looking for a solution that will work even if I roll this code to a different server with the same directory structure. Is there a good way to achieve this in ColdFusion?
I have an .il file which I can compile without any problems. I can strong name it and so without any issues. But I am not able to set the file version via the attribute as I would expect it. How can I set the FileVersion for an assembly when using ilasm?
If I do a round trip I get always a .res file which does contain only binary data which is not readable. What is inside this res file and can I edit it?
The code does not work
.assembly myAssembly
{
.custom instance void [mscorlib]System.Reflection.AssemblyFileVersionAttribute::.ctor(string) = { string('1.2.3.4') }
The issue can be solved by using the .res file. It is not sufficient to do a round trip with ildasm and ilasm. The IL file does not reference the .res file. I had to add it to the ilasm call manually. The data in the res file seemed to contain the infos which are written into the PE header which is ok for me.
The final command line needed was
ilasm test.il /dll /res:test.res
I still do not know what exactly is inside the res file but I can exhange it with the meta data information of any other assemlby that I create manually and then decompile it to replace the metadata of the original assembly as I need.
It seems not many people are doing such stuff.
I have multimodule project
Project
|--src
|-JavaFile.java
Web-Project
|-Web-Content
|-images
| |-logo.PNG
|-pages
|-WEB-INF
regular java module - contains src with all java files
dynamic web project module - contains all web related stuff
eventually regular java module goes as a jar file in dynamic web module in lib folder
Problem
java file after compilation looks for an image file in c:\ibm\sdp\server completepath\logo.png rather in context. File is defined in java file as below for iText:
Image logo = Image.getInstance("/images/logo.PNG");
Please suggest how can I change my java file to refer to image. I am not allowed to change my project structure.
You need to use ServletContext#getResource() or, better, getResourceAsStream() for that. It returns an URL respectively an InputStream of the resource in the web content.
InputStream input = getServletContext().getResourceAsStream("/images/logo.PNG");
// ...
This way you're not dependent on where (and how!) the webapp is been deployed. Relying on absolute disk file system paths would only end up in portability headache.
See also:
getResourceAsStream() vs FileInputStream
Update: as per the comments, you seem to be using iText (you should have clarified that a bit more in the question, I edited it). You can then use the Image#getInstance() method which takes an URL:
URL url = getServletContext().getResource("/images/logo.PNG");
Image image = Image.getInstance(url);
// ...
Update 2: as per the comments, you turn out to be sitting in the JSF context (you should have clarified that as well in the question). You should use ExternalContext#getResource() instead to get the URL:
URL url = FacesContext.getCurrentInstance().getExternalContext().getResource("/images/logo.PNG");
Image image = Image.getInstance(url);
// ...
i want to embed a xml file to a resource file in my project,whenever i need the file i must get it from resource and use it,how to do this and i want to modify the contents of the xml file depending upon my requirements.how to do this
If you add the XML file to a Visual Studio project and, in the Property window for it, select Build Action: Embedded resource, the file will be embedded into the build output artifact for that project.
To access it from code, use something like:
string resourceName = "Namespace.Prefix.FileName.xml";
Assembly someAssembly = LoadYourAssemblyContainingTheResource();
XmlDocument xml = new XmlDocument();
using (Stream resourceStream = someAssembly.GetManifestResourceStream(resourceName))
{
xml.Load(resourceStream);
}
// The embedded XML resource is now available in: xml
If the resource you're loading is embedded in your own assembly, you can do something like Assembly.GetExecutingAssembly() to achieve what I listed as LoadYourAssemblyContainingTheResource() above, or possibly typeof(SomeTypeInYourResourceAssembly).Assembly
It's unclear what you mean by "want to modify the contents" - you cannot modify the resource inside the assembly at run-time, but whenever you change the XML file and recompile, the new version will be embedded.