How to get a part of a current content in umbraco - umbraco

My question is: How can I get a part of a current content in Umbraco CMS in backend file (*.master.cs)? About 350 characters, but i'm sure, that a large does not matter. Is there any useful method to do it?
Umbraco version: 4.6.2.
Regards

I found solution myself:
string part = currentNode.GetProperty("bodyText").Value.Substring(0, 450) + "...";

Related

Angular 2 - upload of file

I need to create upload of images to my webserver in my Angular 2 app. Can anybody provide me some guidance how to achive this?
These are the prerequisities:
ASMX web service communicating in JSON.
post method used for communication.
JPEG / PNG up to 1MB of size.
Concept I wanted to follow (but failed)
Load the content of JPEG to variable, encode it using the Base64 coding and post it to ASMX service that will accept two parameters (token for authentication and encoded data.
What exactly is my problem
Web service was the easy part, it is done and working, but I can't manage to get the file content for enconding. I used this:
component.html
...
<input type="file" (change)="fileChangeEvent($event)" />
...
component.ts
private fileChangeEvent(fileInput: any) {
let image = fileInput.target.files[0] as File;
...
}
As you have probably guessed, the problem is in the File class, because it provides me only basic info about the file (name, size, last modif, ...) but I can't get the content of the file. Or at least I don't know how to get it. I also checked other questions here on SO, but all of the answers had something special that did not met my requirements. And maybe I'm just blind, but I can't see where the content is get.
So, is there anybody, who is able to provide me some guidelines to follow?
Thank you very much in advance.
I have left this question open for experienced guys, who could be able to answer it. There is no answer though and I found out the answer yesterday. So, after some research and modification of search phrase, I found out the answer. There is a FileReader type which can be used for reading the content of the file. Here is the source of the answer:
Getting byte array through input type = file
Thanks to original answer now I know how to do it.

Localized URLs in Play 2.0?

Yesterday we had a Play 2.0 presentation at our local JUG but we couldn't figure out whether it is possible to have localized URLs (for SEO purposes).
For example /help, /hilfe etc should point to the same controller but the template should be rendered with different language content.
Is there any way to do this in Play 2.0?
I like your question, because it was creative at least for me :) Check this approach it works for me:
conf/routes:
GET /help controllers.Application.helpIndex(lang = "en")
GET /hilfe controllers.Application.helpIndex(lang = "de")
GET /help/:id controllers.Application.helpTopic(lang = "en", id: Long)
GET /hilfe/:id controllers.Application.helpTopic(lang = "de", id: Long)
controllers/Application.java:
public static Result helpIndex(String lang) {
return ok("Display help's index in " + lang.toUpperCase());
}
public static Result helpTopic(String lang, Long id) {
return ok("Display details of help topic no " + id + " in " + lang.toUpperCase());
}
views/someView.scala.html:
Help index<br/>
Hilfe index<br/>
Help topic no 12<br/>
Hilfe topic no 12
(This is different approach than in previous answer, therefore added as separate one)
You can also create some kind of mapping table in DB where you can store full paths to records with different params:
urlpath record_id lang
/help/some-topic 12 en
/hilfe/ein-topic 12 de
than in conf/routes file you need to use rule allowing you to use Dynamic parts spanning several / (see routing doc) ie:
GET /:topic controller.Application.customDbRouter(topic:String)
You can also mix both - standard routing mechanismus with custom one by placing above rule at the end of your conf/routes file if no 'static' rule will be available, then it will try to find it in mapping table or will return notFound() Result.
You use from GlobalSettings.onHandlerNotFound() and check if the is a translated version of the url. Then you can make a redirect. However this ends with urls in default language.
More cleaner would be to use the GlobalSettings.onRouteRequest where you can implement your own logic to get the handler.
Furthermore you can create your own router. There was a discussion about it at google-groups with a scala solution.
It was possible in Play 1.2.x, not in 2.x as far as I know. I mean, it's not possible without duplicating the mappings in your file, adding one for EN, one for DE, etc.
A simpler alternative for SEO may be to "fake" the urls in your Sitemaps file.
So your Routes file has
GET /action/:param/:seo-string Controller.methodAction(param)
so seo-string will be ignored in processing, and you generate several links on your Sitemaps file:
/action/1/english-text
/action/1/german-text
This would set the search engines. For users, so they see the url in the right language, you could change the URL using HTML 5 history.
It's extra work, but if you really want it...

Custom URL format for news in Expression Engine

Our site is migrating from MovableType to ExpressionEngine, and there is one small issue we are having. MT uses a date based URL structure, e.g. www.site.com/2012/03/post-title.html, while EE uses a category based structure, e.g. www.site.com/index.php/news/comments/post-title. The issue is that our MT page used Disqus for comments, and as such comments are tied to a specific URL, meaning that we'd lose all of our comments if we were to migrate. I am wondering if there's a way to change the URL structure in EE to match MT's, thus allowing us to keep the comments. Thanks in advance.
Correction: EE uses a Template Group/Template based structure for URLs, not categories - just to clarify.
You've got a couple of options here.
One is to create an .htaccess rule which internally redirects all requests matching YYYY/MM/ to your EE template which displays your posts (say, /news/entry/). I don't know exactly what those rewrite rules would look like off the top of my head, my mod_rewrite-fu is pretty shallow. But it could definitely work.
Another is to export all of your comments from Disqus via their XML export tool, then do a grep-based find and replace using something like BBEdit, replacing all /YYYY/MM/ strings in that file with /news/entry/; delete all of your existing comments on Disqus; then import your newly-modifed XML file.

How do you handle line breaks in HTML Encoded MVC view?

I am unsure of the best way to handle this. In my index view I display a message that is contained in TempData["message"]. This allows me to display certain error or informational messages to the user when coming from another action (for example, if a user tries to enter the Edit action when they don't have access, it kicks them back to the Index with a message of "You are not authorized to edit this data").
Prior to displaying the message, I run Html.Encode(TempData["message"]). However, I have recently come into the issue where for longer messages I want to be able to separate the lines out via line breaks (<br>). Unfortunately (and obviously), the <br> gets encoded by Html.Encode so it doesn't cause an actual line break.
How do I process line breaks correctly in Html Encoded strings?
The easiest solution I've seen is:
#MvcHtmlString.Create(Html.Encode(TempData["message"]).Replace(Environment.NewLine, "<br />"))
If you are using a razor view, you should not have to call Html.Encode normally. By default, Razor html encodes all output. From Scott Gu's blog introducing Razor:
By default content emitted using a # block is automatically HTML encoded to better protect against XSS attack scenarios.
I agree with #Roger's comment - there is not really any need to encode anything that you have total control over.
If you still wish to be better safe than sorry (which isn't a bad thing), you could use the Microsoft AntiXss library and use the .GetSafeHtmlFragment(input) method - see HTML Sanitization in Anti-XSS Library
e.g.
<%= AntiXss.GetSafeHtmlFragment(TempData["message"]) %>
FYI, the Microsoft Web Protection Library (A.K.A. Microsoft AntiXSS Library) developers seem to have broken the assembly and pulled all previous versions that were working. It is no longer a viable solution in its current state. I was looking at it as a solution for this problem before reading the comments. All 18 of the current ratings for the latest release are negative and complain about it being broken with no updates from the developers so I didn't even try it.
I went with #ICodeForCoffee's solution since I'm using Razor. It is simple and seems to work quite well. I needed to take potentially lengthy descriptions with line breaks and format them so the line breaks would come through in the page.
Just for completeness, here's the code I used which is #ICodeForCoffee's code modified to use the description field of the view's model:
#MvcHtmlString.Create(Html.Encode(Model.Description).Replace(Environment.NewLine, "<br />"))
"Process" the message in the controller:
HTMLEncode the message
Insert the line break tags
Add message to the TempData collection.
Try this:
StringBuilder sb = new StringBuilder();
foreach(string message in messages)
{
sb.Append(string.Format("{0}<br />", Server.HtmlEncode(message));
}
TempData["message"] = sb.ToString();

How to count the number of occurences of urls and hyperlinks in a Ruby string?

Say a user submits this comment on a blog:
#SO - Great community, but we've also
seen some great communities at Stack
Overflow. At the same time
Google's Gmail (http://gmail.com) is a
great example of a community with
endless bounds. I'm just wondering if
anyone will really go toe-to-toe with
something like http://www.twitter.com.
What do you think?
Note: the 3rd url was actually posted as plain text, but SO converted it to a hyperlink.
Anyways, the total url and hyperlink count should be 3.
So, from a Ruby and/or Ruby on Rails perspective:
How to count the number of occurences of urls and hyperlinks in a Ruby string?
This is pretty easy, albeit relatively naive:
string.count("http://")
Of course, it won't pick up links without a leading "http://", but that might be a reasonable assumption.
The easiest way is to scan for "http" pattern, but really it can be more complicated, because sometimes urls haven't got "http://" at the beggining
string = "#SO - Great community, but we've also seen some great communities at <a href='http://blabla'>Stack Overflow</a>. At the same time Google's Gmail (http://gmail.com) is a great example of a community with endless bounds. I'm just wondering if anyone will really go toe-to-toe with something like http://www.twitter.com. What do you think?"
string.scan(/http/).size #=> 3
Using regular expressions is a good way. Here is an example on how to do that:
yourpost.each do |yourword|
if yourword =~ /^(((ht|f)tps?\:\/\/)|~/|/)?([a-zA-Z]{1}([\w\-]+\.)+([\w]{2,5})(:[\d]{1,5})?)/?(\w+\.[\w]{3,4})?((\?\w+=\w+)?(&\w+=\w+)*)?/
puts %Q!We found #{$&} an URL in #{$1}!
end
end
See this post for further discussion on regular expressions matching URLs.

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