How to check iPhone Device Version in iOS? - ios

Question

Hi i would like to check iPhone Device Version in iOS.
I mean , currently running device is iPhone 4 or iPhone 5.
I need to check the device , is that iPhone 5 or not?
Because i have some problem in my app that need to know iPhone 5 or not.
So how can i?

Answer 1

Add this code:
if(UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone){
if ([[UIScreen mainScreen] respondsToSelector: #selector(scale)]) {
CGSize result = [[UIScreen mainScreen] bounds].size;
CGFloat scale = [UIScreen mainScreen].scale;
result = CGSizeMake(result.width * scale, result.height * scale);
if(result.height == 960) {
NSLog(#"iPhone 4 Resolution");
resolution_number = 1;
}
if(result.height == 1136) {
NSLog(#"iPhone 5 Resolution");
}
}
else{
NSLog(#"Standard Resolution");
}
}

Answer 2

Add This Macros to your code:
#define HEIGHT_IPHONE_5 568
#define IS_IPHONE ([[UIDevice currentDevice] userInterfaceIdiom] == UIUserInterfaceIdiomPhone)
#define IS_IPHONE_5 ([[UIScreen mainScreen] bounds ].size.height == HEIGHT_IPHONE_5 )
then just check whenever you needs..
if (IS_IPHONE_5) {
//Code for iPhone5
}else{
//Code for earlier version
}

Answer 3

I actually found a #define that does the trick
#define IS_IPHONE_5 (fabs((double)[[UIScreen mainScreen] bounds].size.height - (double) 568) < DBL_EPSILON)

Answer 4

#define IS_IPAD (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad)
#define IS_IPHONE (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone)
#define IS_IPHONE_4 (IS_IPHONE && [[UIScreen mainScreen] bounds].size.height == 480.0f)
#define IS_IPHONE_5 (IS_IPHONE && [[UIScreen mainScreen] bounds].size.height == 568.0f)
#define IS_IPHONE_6 (IS_IPHONE && [[UIScreen mainScreen] bounds].size.height == 667.0f)
#define IS_IPHONE_6PLUS (IS_IPHONE && [[UIScreen mainScreen] nativeScale] == 3.0f)
#define IS_IPHONE_6_PLUS (IS_IPHONE && [[UIScreen mainScreen] bounds].size.height == 736.0f)
#define IS_RETINA ([[UIScreen mainScreen] scale] == 2.0f)