I am trying to submit to a controller action method by using Html.ActionLink in my view. I am doing this as non-ajax submit because the return type of my action is FileContentResult (thanks to #Darin for this info). However, my action link is not posting my view to Action Method. Below is my code
View's Code (Partial view)
#Html.ActionLink("Save", "SaveFile", "ui", new { htmlResult="asdf"})
Here, UI is controller name, SaveFile is method name.
Controller method
public FileContentResult SaveFile(string htmlString)
{
...
...
pdfBytes = pdfConverter.GetPdfBytesFromHtmlString(html);
var cd = new ContentDisposition
{
FileName = "MyFile.pdf",
Inline = false
};
Response.AddHeader("Content-Disposition", cd.ToString());
return File(pdfBytes, "application/pdf");
}
When I hit the same URL from browser address bar, then it is hit and also returns the pdf file with no issues. Same this is not happening through action link. I also tried putting the action link inside #using Html.BeginForm().... but no use.
Can you please tell me where I might be doing wrong here?
Thanks!
Html.ActionLink has a lots of overloads and it's very easy to use the wrong one. You are currently using the (String, String, Object, Object) overload which treats your third argument "ui" this route values which leads to a wrongly generated link.
Use this overload instead:
#Html.ActionLink("Save", //Link text
"SaveFile", // Action Name
"ui", // Controller name
new { htmlResult="asdf"}, //Route values
null /* html attributes */)
Related
I have an MVC app where users fill in a 4-step form then go to a "confirm" screen. On the confirm screen, if they select to modify their info I use RedirectToAction to take them back to the first step view, and I pass a URL parameter "modify=true", which tells the controller to use the session object already created as opposed to creating a new object from the DB and displaying an empty form. But once they submit the form for step 1 I want to send them from my controller to the step 2 view along with the "modify=true" parameter. There doesn't seem to be a way to return a viewmodel to a view and also pass a query string parameter. How can I accomplish this?
I have considered adding a bool to the viewmodels to signify "inReview" but i use different viewmodels for each of these views and they're all pretty clean, it seems like this bool would muck things up a bit.
I have also considered adding the bool to viewbag or viewdata, but then i'd be using the submit button to pass that value and the "modify=true" parameter would drop off the URL, possibly confusing the user and definitely confusing the code.
Thanks
If you use the Html.BeginForm() helper (without parameters) it will automatically append existing query string parameters to the generated form action attribute. If you use some of the other overloads such as Html.BeginForm("SomeAction", "SomeController", FormMethod.Post) then you're gonna lose those parameters. This could be easily fixed by writing a custom helper that will take into account those parameters:
public static class HtmlHelpers
{
public static IDisposable BeginRequestForm(this HtmlHelper html, string action, string controller, FormMethod method)
{
var builder = new TagBuilder("form");
var urlHelper = new UrlHelper(html.ViewContext.RequestContext);
var routeValues = new RouteValueDictionary();
var query = html.ViewContext.HttpContext.Request.QueryString;
foreach (string key in query)
{
routeValues[key] = query[key];
}
builder.MergeAttribute("action", urlHelper.Action(action, controller, routeValues));
builder.MergeAttribute("method", HtmlHelper.GetFormMethodString(method), true);
html.ViewContext.Writer.Write(builder.ToString(TagRenderMode.StartTag));
return new MvcForm(html.ViewContext);
}
}
and then use in your view (after bringing it into scope of course):
#using (Html.BeginRequestForm("SomeAction", "SomeController", FormMethod.Post))
{
...
}
You can either use ViewBag or your view model. You just need to pass the value somehow to the view:
ViewBag.modify = true;
return View(model);
Then in your view:
Html.BeginForm("MyAction", "MyController", new { modify = ViewBag.modify })
I've been scouring the web for a way to do this.
I want to generate a hyperlink to an action from my controller and put it in a string. I need to be able to define the label and give it html attributes. I can get Url.Action(...) working but that method doesn't let me define the label on the link.
HtmlHelper.GenerateLink(...) looks promising but I can't find any concrete examples on how to use it.
The link should look something like this:
View
Add this property to your base controller:
protected HtmlHelper Html
{
get
{
var viewContext = new ViewContext( ControllerContext, new WebFormView( Request.CurrentExecutionFilePath ),
new ViewDataDictionary(), new TempDataDictionary(), Response.Output )
{
RouteData = ControllerContext.RouteData
};
return new HtmlHelper( viewContext, new ViewPage() );
}
}
and then call it from anywhere:
var link = Html.ActionLink( "Click Me", "action" );
try this
string str = string.Concat("View"
and then pass this in ViewData and call it in view
<%= str%>
there are a few ways to do this - here are 2:
Link name here
Html.ActionLink(article.Title,
"Login", // <-- Controller Name.
"Item", // <-- ActionMethod
new { id = "<arguments here" }, // <-- Route arguments.
null // <-- htmlArguments .. which are none. You need this value
// otherwise you call the WRONG method ...
// (refer to comments, below).
)
there are other overloads of each available
Perhaps a little more information on why you would want to do this would be a little more helpful. If you return a string that contains HTML it will by default be HTML encoded and rendered useless on the client. If you have a custom view where this will be rendered why not build the link there using #Html.ActionLink?
I guess I am trying to figure out the benefit of doing it in the controller rather than the view...
Is there a way within asp.net MVC 2 whereby I can route a request and have a portion of the URL ignored and passed to the controller as a variable?
My needs state that I must store pages dynamically in a database, and they should be accessible by looking at the URL and reading the URL segments to find the relevant page. Effectively, I need a Site controller, to which the remaining portion of the URL will be passed.
Site-Controller/this/is/a/page
So this in case the site controller would pick up the /this/is/a/page 'string'
Is this possible?
Thanks!
Yes, use a wildcard route, like:
routes.MapRoute(
"SiteController", // Route name
"Site-Controller/{*url}", // URL with parameters
new { controller = "SiteController", action = "Index" }, // Parameter defaults
null // constraints
);
Then your action looks like:
public ActionResult Index(string url)
{
}
Create a wildcard Route in Global.asax which captures everything after the first segment of the url and passes it to your Action method:
routes.MapRoute("Page",
"Site-Controller/{*urlsegments}",
new {
controller = "Site-Controller",
action = "YourAction",
urlsegments = ""
});
Make sure your Action method accepts a 'urlsegments' parameter and you can work with it from there:
public ActionResult YourAction(string urlsegments)
{
// Do something with the segments here
}
I'm trying to create an extension method similar to MVCContrib's RedirectToAction method by creating a method that will take an #anchor argument and add it to the Url. I am familiar with this question but it's not strongly typed. It's also possible to add values to the query-string, but that won't work for an anchor.
public static RedirectToRouteResult RedirectToAction<T>(this Controller controller, Expression<Action<T>> action, string anchor) where T : Controller
{
var result = new RedirectToRouteResult<T>(action);
// how can I add the #anchor to the result's url?
return result;
}
I am creating a modular ASP.NET MVC application using areas. In short, I have created a greedy route that captures all routes beginning with {application}/{*catchAll}.
Here is the action:
// get /application/index
public ActionResult Index(string application, object catchAll)
{
// forward to partial request to return partial view
ViewData["partialRequest"] = new PartialRequest(catchAll);
// this gets called in the view page and uses a partial request class to return a partial view
}
Example:
The Url "/Application/Accounts/LogOn" will then cause the Index action to pass "/Accounts/LogOn" into the PartialRequest, but as a string value.
// partial request constructor
public PartialRequest(object routeValues)
{
RouteValueDictionary = new RouteValueDictionary(routeValues);
}
In this case, the route value dictionary will not return any values for the routeData, whereas if I specify a route in the Index Action:
ViewData["partialRequest"] = new PartialRequest(new { controller = "accounts", action = "logon" });
It works, and the routeData values contains a "controller" key and an "action" key; whereas before, the keys are empty, and therefore the rest of the class wont work.
So my question is, how can I convert the "/Accounts/LogOn" in the catchAll to "new { controller = "accounts", action = "logon" }"??
If this is not clear, I will explain more! :)
Matt
This is the "closest" I have got, but it obviously wont work for complex routes:
// split values into array
var routeParts = catchAll.ToString().Split(new char[] { '/' }, StringSplitOptions.RemoveEmptyEntries);
// feels like a hack
catchAll = new
{
controller = routeParts[0],
action = routeParts[1]
};
You need to know what part is what in the catchAll parameter. Then you need to parse it yourself (like you are doing in your example or use a regexp). There is no way for the framework to know what part is the controller name and what is the action name and so on, as you haven't specified that in your route.
Why do you want to do something like this? There is probably a better way.