I could't setvalue of selected index with nsmutablearray.There is my code:
[[retArray objectAtIndex:1] setValue:str forKey:#"name"];
this line give error. What is the error?
correct code should be is
[retArray insertObject:str atIndex:1];
or
[retArray addObject:str];
or if you are using a dictionary
[retArray insertObject:[NSDictionary dictionaryWithObject:str forKey:#"name"] atIndex:1];
First of all you should explicitly tell us what exact error it gives you then what you are doing in your code is:
retrieving element at index 1
assuming that the item you got from the array is compliant to NSKeyValueCoding protocol (mostly a NSMutableDictionary)
setting a field of the element retrieved
Code is correct as it is, the only concern could be that the array is not mutable (hence NSArray instead that NSMutableArray)
you are using method of dictionary ...Refer NSMutableArray Reference
Related
I have initialized a mutable array like NSMutableArray *mutableArray = [[NSMutableArray alloc]init];. I have printed the object class in NSLogs like NSLog(#"object class is %#",[mutableArray class]);. I have initialized a mutable array but the class of the object is displayed as __NSArrayM.
I try to add items to mutableArray then application is crashed. I don't know where is the problem. Please tell me why it is considered as a NSArray instead of NSMutableArray.
Thanks In Advace
It is as expected, the M in __NSArrayM means mutable.
NSArray / NSMutableArray is a class cluster and you should never expect to see the class directly printed as NSArray or NSMutableArray.
For Immutable array it returns
__NSArrayI // Here I is for Immutable
And for mutable it returns
__NSArrayM // Here M is for Mutable
May be you are assigning a non mutable array to this mutable array or you are inserting nil objects. Could you post the exception details.
[mutableArray insertObject:object atIndex:0]; (for first)
[mutableArray insertObject:object atIndex:[mutableArray count]]; (for last)
or [mutableArray addObject:object];
How are you adding them?
I'm not to be able to change a NSNumber within a NSMutableDictionary. The 'Before' NSLog prints but then crashes when I change the number.
As you can see the class is of type NSNumber and therefore I should be able to change the number with the class method 'numberWithIn'. However, I get the error "unrecognized selector sent to instance." Which is strange because if the method didn't exist, the if statement would not work? Thoughts? Have I just missed something strange?
Data is an NSMutableArray and within are NSMutableDictionaries from json data. Data has been initialised.
if([[Data[i] objectForKey:#"Pop"] isKindOfClass:[NSNumber class]]){
NSLog(#"Before: %#",[Data[i] objectForKey:#"Pop"]);
[[Data[i] objectForKey:#"Pop"] numberWithInt:5];
NSLog(#"After: %#",[Data[i] objectForKey:#"Pop"]);
}
if([[Data[i] objectForKey:#"Pop"] isKindOfClass:[NSNumber class]]){
NSLog(#"Before: %#",[Data[i] objectForKey:#"Pop"]);
[[Data[i] setObject:[NSNumber numberWithInt:5] forKey:#"Pop"];
NSLog(#"After: %#",[Data[i] objectForKey:#"Pop"]);
}
should work.
You didnt properly set a new NSNumber object.
[Data[i] objectForKey:#"Pop"] just access an element of your dictionary. If you want to change it you need a method that does so: [Data[i] setObject:[NSNumber numberWithInt:5] forKey:#"Pop] or more concisely [Data[i] setObject:#5 forKey:#"Pop"]. Did you know you can also access dictionary elements now like so: Data[i][#"Pop"]...
+(NSNumber *)numberWithInt:(int)value is a class method to create a new NSNumber. You cannot call it on an instance of NSNumber.
You should use one of those function :
[dataArray setObject:yourObject forKey:#"Pop"];
[dataArray replaceObjectAtIndex:theIndextoChange withObject:yourObject];
Specifically:
self.words = (NSMutableArray*)[self.text componentsSeparatedByString:#" "];
works fine so long as there are separators. I see that the method returns the original string wrapped in an NSArray if there isn't, though. This single element NSArray stubbornly refuses to be cast as an NSMutableArray.
But, when I do:
self.words = [NSMutableArray arrayWithArray:self.words];
It works just fine.
Is there something I'm missing here? Is it bad practice to cast from NSArray to NSMutableArray?
You are confused.
This code:
self.words = (NSMutableArray*)[self.text componentsSeparatedByString:#" "];
...is wrong, and is setting you up for a crash later on. Casting just tells the compiler "trust me, I know what I'm doing." It does not change the type of the underlying object. The method componentsSeparatedByString returns an NSArray, not a mutable array. If you then try to mutate the resulting array, you will crash with an unrecognized selector message. With the cast, the compiler trusts you that your object will really be a mutable array at runtime, but it will not be.
This would crash:
self.words = (NSMutableArray*)[self.text componentsSeparatedByString:#" "];
[self.words addObject: #"new"];
However, this code:
self.words = [[self.text componentsSeparatedByString:#" "] mutableCopy];
[self.words addObject: #"new"];
...does the right thing. It doesn't cast a pointer, it is a method call to a method that takes an NSArray as input and returns a mutable array with the same contents. Thus the second line will work because the first line takes the immutable array it gets back from componentsSeparatedByString and uses it to create a mutable array.
It is bad practice to cast from NSArray to NSMutableArray. It may works if you are lucky because the array are constructed using NSMutableArray, but you can't rely on it.
If you want NSMutableArray from NSArray, use mutableCopy
self.words = [[self.text componentsSeparatedByString:#" "] mutableCopy];
Is it bad practice to cast from NSArray to NSMutableArray?
Yes. Bordering on nonsensical, really.
Typecasting does not change the object in any way at all, it just tells the compiler that it should regard the object as if it were an instance of the new type. At run time though, the object stays exactly the same. You may cast an NSArray to an NSMutableArray but it doesn't make the object transform into an NSMutableArray. It's still the same object of the same type.
Your misconception seems to be about the nature of casting. Casting doesn't change the object, it just tells the compiler to pretend that it's an object of that type. If the object really isn't an NSMutableArray, casting is not expected to make it become one.
NSString* string1 = #"this thing";
NSString* string2 = #"this";
NSMutableArray* array1;
NSMutableArray* array2;
array1 = (NSMutableArray*)[string1 componentsSeparatedByString:#" "];
array2 = (NSMutableArray*)[string2 componentsSeparatedByString:#" "];
[array1 addObject:string1]; //(A)
[array2 addObject:string1]; //(B)
This will break at (B) the last line with :
-[__NSArrayI addObject:]: unrecognized selector sent to instance 0x1702257a0
But will not break at (A)1
An object that is publicly declared as immutable may have been privately created as mutable. In this case, if you cast from the immutable public type to the private mutable type, everything will work fine. Where the object was not created as mutable, such a cast will not get you what you want.
In the case of componentsSerparatedByString, this suggests that the method implementation creates a mutable array only if it needs to - i.e. if it has to add more than one object to the array. If it only finds one object, you get an NSArray, if it finds more than one, you get an NSMutableArray. This is an implementation detail that is deliberately hidden from you as the user.
The interface tells you to expect an NSArray in all cases, and in all cases this will work.
You should not rely on such details to get you what you want. Stick to the public API, that's what it is for.
1 rather, as Bryan Chen points out, it may not break now but could well do so in the future
When you do that:
self.words = (NSMutableArray*)[self.text componentsSeparatedByString:#" "];
the array still remains immutable and if you send it a message from NSMutableArray class it will crash. The trick (NSMutableArray*) is only good to make the compiler happy.
In the second case:
self.words = [NSMutableArray arrayWithArray:self.words];
you do not CAST, you CREATE a new array object.
And of course you don't need to cast the arrays this way. NSMutableArray object IS already NSArray just like any object of a derived class is an object of a base class at the same time
Use second variant in all cases because it is right solution and more clearly for users who will support your code:
NSArray *array = [self.text componentsSeparatedByString:#" "];
self.words = [NSMutableArray arrayWithArray:array];
Never do this one:
self.words = [NSMutableArray arrayWithArray:self.words];
It will totally confuse all devs =)
In the first case, the componentsSeparatedByString: method is specifically returning an NSArray, which can't just be cast to the mutable type. If you wanted that to be mutable, you would have to do this:
self.words = [[self.text componentsSeparatedByString:#" "] mutableCopy];
The second one is calling the arrayWithArray: method on the NSMutableArray class, meaning it is making an instance of NSMutableArray. That's why it works. You can cast an NSMutableArray to an NSArray, but not the other way around, because an NSMutableArray is a subclass of NSArray.
Casting does nothing with an object. example:
NSString *mouse = (id)#[#"mouse"];
it will compile, but variable mouse is not NSString. it is NSArray. you can check it simply by writing
po mouse
in console.
The only way to create mutable copy of an object is to call 'mutableCopy' method on it:
NSArray *array = #[#"a"];
NSMutableArray *mutableCopy = [array mutableCopy];
I have declared an NSMutableArray *arrAllRecordsM and am trying to add NSMutableDictionary *dicRecordM to it using addObject. The dicRecordM gets added to arrAllRecordsM but on doing [dicRecordM removeAllObjects] it sets to nil in arrAllRecordsM. Below is the code, please help me fix it.
self.arrAllRecordsM = [NSMutableArray array];
self.dicRecordM = [NSMutableDictionary dictionary];
// Some Method
[self.dicRecordM setObject:#"Test" forKey:#"ADDRESS"];
[self.arrAllRecordsM addObject:self.dicRecordM];
// Value: Test
NSLog(#"Value: %#", [[self.arrAllRecordsM objectAtIndex:0] valueForKey:#"ADDRESS"]);
[self.dicRecordM removeAllObjects];
// Value: null
NSLog(#"Value: %#", [[self.arrAllRecordsM objectAtIndex:0] valueForKey:#"ADDRESS"]);
Adding an object to an NSMutableArray just stores a pointer (or "strong reference")
to the object into the array. Therefore
[self.arrAllRecordsM objectAtIndex:0]
and
self.dicRecordM
are two pointers to the same object. If your remove all key/value pairs from self.dicRecordM then [self.arrAllRecordsM objectAtIndex:0] still points to the same
(now empty) dictionary. That is the reason why
[[self.arrAllRecordsM objectAtIndex:0] valueForKey:#"ADDRESS"]
returns nil.
If you want an independent copy of the dictionary in the array, use
[self.arrAllRecordsM addObject:[self.dicRecordM copy]];
copy can be used on many classes, such as NSDictionary, NSArray and NSString
and their mutable variants, to get a "functionally independent object". Formally, it is available for all classes conforming to the NSCopying protocol.
This is expected behavior.
You removed all the objects from the dictionary by calling removeAllObjects, then tried to retrieve an object from it and rightfully getting nil, since it doesn't exist in the dictionay anymore (you removed it).
What's maybe unclear to you is that NSArray doesn't copy the element you add to it, instead it just holds a strong reference.
So both dicRecordM and arrAllRecordsM are holding a reference to the same object, hence any modification to it (in this case removeAllObjects) will affect the same dictionary.
Incidentally, you shouldn't use valueForKey: for accessing the dictionary's entries. Use objectForKey: or the shorter subscripted syntax. For instance
self.arrAllRecordsM[0][#"ADDRESS"]
You can read this answer Difference between objectForKey and valueForKey? as a reference, but the main problem is that valueForKey: can behave very differently from objectForKey: in case the key contains special KVC characters, such as # or ..
I want to add #"ALL ITEMS" object at the first index of NSARRAY.
Initially the Array has 10 objects. After adding, the array should contains 11 objects.
you can't modify NSArray for inserting and adding. you need to use NSMutableArray. If you want to insert object at specified index
[array1 insertObject:#"ALL ITEMS" atIndex:0];
In Swift 2.0
array1.insertObject("ALL ITEMS", atIndex: 0)
First of all, NSArray need to be populated when it is initializing. So if you want to add some object at an array then you have to use NSMutableArray. Hope the following code will give you some idea and solution.
NSArray *array = [[NSArray alloc] initWithObjects:#"1",#"2",#"3",#"4",#"5",#"6",#"7",#"8",#"9",#"0", nil];
NSMutableArray *mutableArray = [[NSMutableArray alloc] init];
[mutableArray addObject:#"ALL ITEMS"];
[mutableArray addObjectsFromArray:array];
The addObject method will insert the object as the last element of the NSMutableArray.
I know that we have six answers for insertObject, and one for creating a(n) NSMutableArray array and then calling addObject, but there is also this:
myArray = [#[#"ALL ITEMS"] arrayByAddingObjectsFromArray:myArray];
I haven't profiled either though.
Take a look at the insertObject:atIndex: method of the NSMutableArray class.To add an object to the front of the array, use 0 as the index:
[myMutableArray insertObject:myObject atIndex:0];
NSArray is immutable array you can't modify it in run time. Use NSMutableArray
[array insertObject:#"YourObject" atIndex:0];
NSArray is immutable but you can use insertObject: method of NSMutableArray class
[array insertObject:#"all items" atIndex:0];
As you are allready having 10 objects in your array,and you need to add another item at index 11...so,you must try this.... hope this helps..
NSMutableArray *yourArray = [[NSMutableArray alloc] initWithCapacity:11];
[yourArray insertObject:#"All Items" atIndex:0];
NSArray is not dyanamic to solve your purpose you have to use NSMutableArray. Refer the following method
- (void)insertObject:(id)anObject atIndex:(NSUInteger)index;
Apple documents says NSMutableArray Methods
[temp insertObject:#"all" atIndex:0];
Swift 3:
func addObject(){
var arrayName:[String] = ["Name1", "Name2", "Name3"]
arrayName.insert("Name0", at: 0)
print("---> ",arrayName)
}
Output:
---> ["Name0","Name1", "Name2", "Name3"]