Need conversion technique from Times ten dateTime to Saxon Timestamp - saxon

Trying to retrieve a dateTime Information from Timesten Database and use it in Saxon Xquery .below is the example for that and getting the below error . Do we need to convert timesten dateTime to saxom dataTime if yes how to do that ? pls help me if have idea.
let $DateVar:=fn:data($PERSON/BIRTHDAY)
where as $PERSON/IN_BIRTHDAY is 2010-04-04 03:16:04.000000
if I am trying
let $day-b-DT :=day-from-dateTime($DateVar)
I am getting
Validation error
FORG0001: Invalid dateTime value "2010-04-04 03:16:04.000000" (Day must be two digits)
net.sf.saxon.s9api.SaxonApiUncheckedException: Invalid dateTime value "2010-04-04 03:16:04.000000" (Day must be two digits)

I believe the problem is just your string format, which should be
"2010-04-04T03:16:04.000000". See the documentation for dateTime for more information.
I don't know anything about the Times ten database, or whether you retrieve values in a "rich" format which you happen to be formatting to a string (in which case you should be able to specify a different format) but I believe that's what's wrong.

Related

Different date format for same column in Informatica IICS

I am getting data from rest API in JSON forma and have a scenario where a column can have multiple date format. The current date format could be either 2011-02-12T01:00:00 or 2020-04-15T20:44:57.38or could be null or something else also.
I want to parse it through expression and trying to capture the full date string. The following expression seems to be working fine however it is truncating the millisecond part and returning value upto second only.
iif(isnull(%date_fields%),'\N',
to_char(To_date(to_char(%date_fields%),'MM/DD/YYYY HH24:MI:SS'),'YYYY-MM-DD HH24:MI:SS'))
But when I tried it with millisecond usinf below expression:
iif(isnull(%date_fields%),'\N',
to_char(To_date(to_char(%date_fields%),'MM/DD/YYYY HH24:MI:SS.MS'),'YYYY-MM-DD HH24:MI:SS.MS'))
It is throwing error:
TT_11132 Transformation [Expression3] had an error evaluating output column [JobStartDate_out].
Error message is [<<Expression Error>> [TO_DATE]: invalid string for converting to Date
... t:TO_DATE(u:TO_CHAR(t:<02/12/2011 01:00:00>,u:'MM/DD/YYYY HH24:MI:SS'),u:'MM/DD/YYYY HH24:MI:SS.MS')].
I searched few option using below but getting parsing error.
DECODE (TRUE,
iff(isnull(%date_milli%),
'\N',
is_date(To_date(to_char(%date_milli%),'MM/DD/YYYY HH24:MI:SS'),'YYYY-MM-DD HH24:MI:SS'),
is_date(To_date(to_char(%date_milli%),'MM/DD/YYYY HH24:MI:SS.MS'),'YYYY-MM-DD HH24:MI:SS.MS'),
ERROR('NOT A VALID DATE')))
What could be the possible resolution to handle the multiple date format in Informatica? Here JSON date format is string and I am mapping it to date/time type and using Output Marco Fields to combine multiple similar column together.
Why dont you check both options - with and without milliseconds?
You can use below iif condition. Also i think your expression has some issues.
I assumed date_milli is a character type. If its a date, then you can change below expressions accordingly.
iff(isnull(%date_milli%),null,
iif( is_date(to_char(%date_milli%),'MM/DD/YYYY HH24:MI:SS'), to_date(to_char(%date_milli%),'MM/DD/YYYY HH24:MI:SS'),
iif( is_date(to_char(%date_milli%),'MM/DD/YYYY HH24:MI:SS.MS'), to_date(to_char(%date_milli%),'MM/DD/YYYY HH24:MI:SS.MS')
))
)

Date in free format into db

I have a model with :birth_date of type date.
I've tried to put a string like 3 janvier 1968 (French language) into that field and somehow in database I saw that PostgreSQL or someone else converted it into a date!
I also tried some other dates like 3 février 1968 or like 3 fevrier 1968 which didn't work and turned out to be NULL in db.
I can't find information about this feature anywhere. How does this work?
Rails knows that attribute is a Date from the database definition, so it converts the string you give it to a Date. If you create a new instance of your model in the Rails console and assign to birth_date, you can show that it's already a Date even before you save it to the database:
m = Model.new # Use your model name
m.birth_date = "3 février 1968"
m.birth_date.class
The console should tell you that m.birth_date is a Date.
So the conversion to Date is done before you save the model to the database. Rails defines a String::to_date method that calls the Ruby ::Date.parse method, which converts various human-readable date strings into a Date (https://ruby-doc.org/stdlib-2.3.1/libdoc/date/rdoc/Date.html#method-c-parse). In the Rails source, you'll see that whatever you assign to a Date attribute is converted to a Date with the to_date method. So when you assign a String, it happens via String::to_date which calls Date.parse.
As you mentioned in your comment, Date.parse seems to take a fairly loose approach to the months when they're spelled out. I tried a variety of English, French, and Spanish months in Date.parse, and as long as the first three letters of the non-English month are the same as the English month, Date.parse will convert them. But if the first three letters are different, then Date.parse throws an error.
if you have a column in the database as type 'date', it will only save as a date. Rails does it's best to convert a string into a recognized date if possible. You should always pass the 'birth_date' data as a date (i.e. use a date_field). Otherwise, if you REALLY want to store it as a string, the birth_date column must be of type string in the database

Change datetime format from one to another programmatically

In my program, I need to change the input datetime information from Turkish (d.M.yyyy) language to English (M/dd/yyyy).
When client edits datetime information in Turkish datetime format(For Example: 24.9.2015), i need to convert this information in English datetime format(Like; 9/24/2015).
I'm trying to parse the input, but not convert the correct format that i need, code block as in the following.
DateTime.TryParseExact(InputDate,"d.M.yyyy", CultureInfo.InvariantCulture, DateTimeStyles.None, out result))
I need the output named "result" in English U.S datetime format. I also tried to change the code as CultureInfo(en-US) but it doesn't work.
Any ideas?
In what language are you trying to achieve this?
Assuming it is c#, DateTime does not have a specific format until you try to convert it into a string and you can convert it to US version by specifying the correct format when calling ToString()
string americanFormat = myDate.ToString("MM/dd/yyyy");

conversion error from string, when using params in SQL

using Delphi 2010 (Firebird [testing], MS Sql Server, Oracle [production])
The following is my SQL
SELECT p.script_no, MIN(p.start_Time) as startTime, MAX(p.end_Time) as endTime,
SUM(p.duration) as TotalDuration
FROM phase_times p
WHERE (p.script_no=:scriptNo) AND (Trunc(p.start_time) >= :beginDateRange) AND (Trunc(p.start_time) <= :endDateRange)
GROUP BY p.script_no
ParamByName('beginDateRange').AsDate:= Date - 30;
ParamByName('endDateRange').AsDate:= Date;
I am getting a "conversion error from string - 10-25-2012" and i am not sure why, since my datetime fields are in the "10/25/2012 9:20:49 AM" format in the database.
If i change it to the following : ParamByName('beginDateRange').AsString := formatDateTime('mm/dd/yyyy',Date - 30).....i get the error "conversion error from string - 10/25/2012"
reserching this error has provided me no new avenues, do you have any ideas?
According to the Interbase 6.0 manual, Embedded SQL guide, chapter 7, Firebird supports conversion from YYYY-MM-DD and YYYY-MM-DD HH:MM:SS.qqq. I also believe it supports American style shorthand dates (eg 1-JAN-2012) for conversion.
It may be there are some locale dependent conversion supported, but in general: use an actual date/timestamp type instead of a string.
UPDATE
I initially did not spot the TRUNC in your query: it is the cause of the conversion error as this function only works on numbers, see the manual entry for TRUNC.
Given your comment (and the respons of ain) I assume you are only interested in the date part, and want to ignore the time. If so, rewrite your use of TRUNC to:
CAST(<your-timestamp-field> AS DATE)
And the condition (Trunc(p.start_time) >= :beginDateRange) AND (Trunc(p.start_time) <= :endDateRange) to:
CAST(p.start_time AS DATE) BETWEEN :beginDateRange AND :endDateRange
Firebird doesn't support conversion from string to date and time value if string is in 12 hour format. Use 'dd.mm.yyyy hh:mm:ss' or 'mm/dd/yyyy hh:mm:ss' formats.
String to date/time conversions usually use user's locale.
So if you feed a date/time conversion function with string that does not match your date part of the locale - you will get similar errors.
Also specifying date/time values like "10/25/2012" is Locale dependent. So if you execute your program on a computer with different than US Locale (like Mine) - it's likely to fail if using "10/25/2012".
To be Locale independent I suggest two options:
Use StrToDateTime, specifying TFormatSettings
Use ISO 8601 for specifying date/time strings (but I don't think Delphi supports that...)
BTW programs like MS Sql, Excel etc. accept dates in ISO 8601. But you have to check this for FB.
Regarding this:
...since my datetime fields are in the "10/25/2012 9:20:49 AM" format in the database...
The internal storage of date/time fields varies between different DB Engines. What you see in your DB Management Software ("10/25/2012 9:20:49 AM" in your case) is the string representation of the data field, usually formatted (again) according your user Locale
if you connected with DB from Firebird 1.0 under the server Firebird 2.1 (for example) you need todo backup and restore under Firebird 2.1

ruby/rails - Converting Entire Database Field (from string to date)

I have made a huge mistake.
Initially I created my model with a field called start_date and made it a string to keep track of event dates.
Now I'm realizing it would be nice to have this field as a date type so I could do calculations like find events where start_date is between today and 1 month from now.
This issue is I already have 500 records so starting over would suck....
The format of the start_date field is in a rails compatible type " 2011-02-21 22:00:00 " but its just a string...
Is there anything I can do?
Create a migration to add a start_date_2 column of the type you want
Model.find(:all).each { |i| i.update_attributes(:start_date_2, Date.new(i.start_date)) }
Create a migration to delete start_date and to rename start_date_2 to start_date
This should work, out of the top of my head.
You could try just doing an EXPORT on the table (making sure to only export data, do not include CREATE and/or DROP table commands).
Create a migration to change the datatype
TRUNCATE the table
IMPORT the data
Since the column is now a date field, it should parse the input of a string just fine, considering that's what you provide it anyway
Perhaps, you can do away with the risk of changing column type if there is live data. The parse methods can save you. From Ruby-doc:
parse(str='-4712-01-01', comp=true, sg=ITALY)
Create a new Date object by parsing from a String, without specifying the format.
str is a String holding a date representation. comp specifies whether to interpret 2-digit years as 19XX (>= 69) or 20XX (< 69); the default is not to. The method will attempt to parse a date from the String using various heuristics; see _parse in date/format.rb for more details. If parsing fails, an ArgumentError will be raised.
Here and here are some more examples / explanations. Hope this helps.

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