Return number from NSString - ios

Question

I have NSString like this: #"text 932".
How I can return number from this string. Number is always at the end of string, but i can' t use stringWithRange, because number don' t have constant length. So I'm seeking for better method.
I aslo want' know how to return number from string like this #"text 3232 text". I aslo don' t know position of number.
There is any function that find number in string ?

Answer 1

Here is a solution that will work for both strings
NSString *myString = #"text 3232 text";
//Create a scanner with the string
NSScanner *scanner = [NSScanner scannerWithString:myString];
//Create a character set that includes all letters, whitespaces, and newlines
//These will be used as skip tokens
NSMutableCharacterSet *charactersToBeSkipped = [[NSMutableCharacterSet alloc]init];
[charactersToBeSkipped formUnionWithCharacterSet:[NSCharacterSet letterCharacterSet]];
[charactersToBeSkipped formUnionWithCharacterSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]];
[scanner setCharactersToBeSkipped:charactersToBeSkipped];
[charactersToBeSkipped release];
//Create an int to hold the number
int i;
//Do the work
if ([scanner scanInt:&i]) {
NSLog(#"i = %d", i);
}
The output of the NSLog is
i = 3232
EDIT
To handle decimals:
float f;
if ([scanner scanFloat:&f]) {
NSLog(#"f = %f", f);
}

Answer 2

Update:
Updated to test whether there is a match or not, and also to handle negative/decimal numbers
NSString *inputString=#"text text -9876.234 text";
NSString *regExprString=#"-{0,1}\\d*\\.{0,1}\\d+";
NSRegularExpression * regex = [NSRegularExpression regularExpressionWithPattern:regExprString options:NSRegularExpressionCaseInsensitive|NSRegularExpressionDotMatchesLineSeparators error:nil];
NSRange rangeOfFirstMatch=[regex firstMatchInString:inputString options:0 range:NSMakeRange(0, inputString.length)].range;
if(rangeOfFirstMatch.length>0){
NSString *firstMatch=[inputString substringWithRange:rangeOfFirstMatch];
NSLog(#"firstmatch:%#",firstMatch);
}
else{
NSLog(#"No Match");
}
Original:
Here is a solution that uses regular expressions:
NSString *inputString=#"text text 0123456 text";
NSString *regExprString=#"[0-9]+";
NSRegularExpression * regex = [NSRegularExpression regularExpressionWithPattern:regExprString options:NSRegularExpressionCaseInsensitive|NSRegularExpressionDotMatchesLineSeparators error:nil];
NSString *firstMatch=[inputString substringWithRange:[regex firstMatchInString:inputString options:0 range:NSMakeRange(0, inputString.length)].range];
NSLog(#"%#",firstMatch);
output is:
0123456
If you want an actual integer from that, you can add:
NSInteger i=[firstMatch integerValue];
NSLog(#"%d",i);
Output is then: 123456