Getting substring from NSString - ios

I have a NSString which looks like this:
http://fiskltd.com/components/com_jshopping/files/img_products/thumb_09afd9f041af34fb0cffec1e0b1222e8.jpg
And I need extract from that this string:
thumb_09afd9f041af34fb0cffec1e0b1222e8.jpg
I will have lots of such strings, so I won't know the number of characters and how many of them will the name of the picture. Can anyone tell me how to extract the name of picture?

May be the best solution in your case will be [NSString lastPathComponent].

Try this:
NSString *originalString = #"http://fiskltd.com/components/com_jshopping/files/img_products/thumb_09afd9f041af34fb0cffec1e0b1222e8.jpg";
NSString *filename = [originalString lastPathComponent];
Apple docs here.

Related

Replace multiple placeholders in string

What I am looking to do is use placeholders in a string and replace the placeholders with data specific to the user. I can setup the placeholders to be anything so basically I am looking to do the following:
Setup placeholders in a string (up to 4 placeholders)
Replace those placeholders with strings I specify
Here is what I have. I currently have a url that has a set of placeholders like so. http://example.com/resource?placeholder1=placeholder2 or http://placeholder1:placeholder2#example.com/something?placeholder3
How do I properly label the placeholders and replace them?
Thank you in advance for any help.
You can use the stringByReplacingOccurrencesOfString method as below
NSString *strUrl = #"http://example.com/resource?placeholder1=placeholder2";
strUrl = [strUrl stringByReplacingOccurrencesOfString:#"placeholder1" withString:#"value1"];
strUrl = [strUrl stringByReplacingOccurrencesOfString:#"placeholder2" withString:#"key1"];
Quote : "I want to replace placeholder1 with an NSString I have already created called value1 and placeholder2 with an NSString called key1."
NSString *mainUrl = "http://example.com/resource";
NSString *string1 = "value1";
NSString *string2 = "value2";
Now change your URL:
NSString *newURL = [NSString NSStringWithFormat:#"%#?%#=%#",mainUrl,string1,string2];
This will generate newURL : http://example.com/resource?value1=value2
This might help you.
#define placeHolder1 #"<>p1p1p1<>"
#define placeHolder2 #"<>p2p2p2<>"
And place this in a function of yours where you want to replace strings
NSString * string = [NSString stringWithFormat:#"http://example.com/resource?%#=%#",placeHolder1,placeHolder2];
NSLog(#"string %#",string);
NSString * replacerForP1 = #"123";
NSString * replacerForP2 = #"741";
string = [string stringByReplacingOccurrencesOfString:placeHolder1
withString:replacerForP1];
string = [string stringByReplacingOccurrencesOfString:placeHolder2
withString:replacerForP2];
NSLog(#"string %#",string);
It would be best to keep your placeholder strings in the constants defined somewhere. And ofcourse the replacement of those placeholders will be dynamic as you said so cannot make them constants.
Tell me if this helps or if you require further assistance in the matter.

Unusual stringWithFormat: argument

I apologize if this is a noob question.
I have been following this tutorial about mapkit and I stumbled on this line of code
NSString *json = [NSString stringWithFormat:formatString,
centerLocation.latitude,
centerLocation.longitude,
0.5 * METERS_PER_MILE];
The reason this is unusual at least to me is that it is missing the nsstring that has the %# flags in it. The tutorial claims that we are adding the latitude and longitude information into the json.
But when I print out formatString and json, the output is identical.
I have never seen nsstrings used in this way before. Is there a hidden variable that is getting set?
Can someone explain to me how this nsstring object (named json) contains those 4 arguments?
Someplace else in the code, formatString must be defined something like this:
NSString *formatString = #"latitude=%f, longitude=%f, %f = half the number of meters in a mile";
Make sure your test looks like this:
NSLog(#"the format is %# and the json is %#", formatString, json);
They shouldn't look the same. The only way they would look the same is if format string doesn't refer to any format specifiers, like this:
NSString *formatString = #"I'm a silly format with no percent format specifiers";
Here's a good intro on the topic from Apple.
That formatString actually contains the %#'s. It might be like this:
NSString *formatString = #"lat: %f | lon: %f | half-meters-per-mile: %f";
NSString *json = [NSString stringWithFormat:formatString,
centerLocation.latitude,
centerLocation.longitude,
0.5 * METERS_PER_MILE];
(note that the substitutions (%f) might not be correct, I'm guessing)
As for how it contains those four arguments, everything after the first one are values that you want added into the string. The first one is a string that says where to put those values.
If you check the tutorial, following line of code is written above what you have posted-
NSString *jsonFile = [[NSBundle mainBundle] pathForResource:#"command" ofType:#"json"];
NSString *formatString = [NSString stringWithContentsOfFile:jsonFile encoding:NSUTF8StringEncoding error:nil];
From here the format string is created, this file will be available in the resources folder of your tutorial.

Adding a percentage % sign to an NSString [duplicate]

I want to have a percentage sign in my string after a digit. Something like this: 75%.
How can I have this done? I tried:
[NSString stringWithFormat:#"%d\%", someDigit];
But it didn't work for me.
The code for percent sign in NSString format is %%. This is also true for NSLog() and printf() formats.
The escape code for a percent sign is "%%", so your code would look like this
[NSString stringWithFormat:#"%d%%", someDigit];
Also, all the other format specifiers can be found at Conceptual Strings Articles
If that helps in some cases, it is possible to use the unicode character:
NSLog(#"Test percentage \uFF05");
The accepted answer doesn't work for UILocalNotification. For some reason, %%%% (4 percent signs) or the unicode character '\uFF05' only work for this.
So to recap, when formatting your string you may use %%. However, if your string is part of a UILocalNotification, use %%%% or \uFF05.
seems if %% followed with a %#, the NSString will go to some strange codes
try this and this worked for me
NSString *str = [NSString stringWithFormat:#"%#%#%#", #"%%",
[textfield text], #"%%"];
uese following code.
NSString *searchText = #"Bhupi"
NSString *formatedSearchText = [NSString stringWithFormat:#"%%%#%%",searchText];
will output: %Bhupi%
iOS 9.2.1, Xcode 7.2.1, ARC enabled
You can always append the '%' by itself without any other format specifiers in the string you are appending, like so...
int test = 10;
NSString *stringTest = [NSString stringWithFormat:#"%d", test];
stringTest = [stringTest stringByAppendingString:#"%"];
NSLog(#"%#", stringTest);
For iOS7.0+
To expand the answer to other characters that might cause you conflict you may choose to use:
- (NSString *)stringByAddingPercentEncodingWithAllowedCharacters:(NSCharacterSet *)allowedCharacters
Written out step by step it looks like this:
int test = 10;
NSString *stringTest = [NSString stringWithFormat:#"%d", test];
stringTest = [[stringTest stringByAppendingString:#"%"]
stringByAddingPercentEncodingWithAllowedCharacters:
[NSCharacterSet alphanumericCharacterSet]];
stringTest = [stringTest stringByRemovingPercentEncoding];
NSLog(#"percent value of test: %#", stringTest);
Or short hand:
NSLog(#"percent value of test: %#", [[[[NSString stringWithFormat:#"%d", test]
stringByAppendingString:#"%"] stringByAddingPercentEncodingWithAllowedCharacters:
[NSCharacterSet alphanumericCharacterSet]] stringByRemovingPercentEncoding]);
Thanks to all the original contributors. Hope this helps. Cheers!

iOS finding string within a string

Hello everyone I am trying find a string inside a string
lets say I have a string:
word1/word2/word3
I want to find the word from the end of the string to the last "/"
so what I will get from that string is:
Word3
How do I do that?
Thanks!
You are looking for the componentsSeparatedByString: method
NSString *originalString = #"word1/word2/word3";
NSArray *separatedArray = [originalString componentsSeparatedByString:#"/"];
NSString *lastObject = [separatedArray lastObject]; //word3
once check this one By using this one you'l get last pathcomponent values,
NSString* theFileName = #"how /are / you ";
NSString *str1=[theFileName lastPathComponent];
NSLog(#"%#",str1);
By using lastPathComponent you'l get the last path component directly no need to take array for separate the string.
you must use NSScanner class to split substring.
check this.
Objective C: How to extract part of a String (e.g. start with '#')
NSString *string = #"word1/word2/word3"
NSArray *arr = [string componentsSeperatedByString:#"/"];
NSSting *str = [arr lastObject];
You can find it also with this way:
NSMutableString *string=[NSMutableString stringWithString:#"word1/word2/word3"];
NSRange range=[string rangeOfString:#"/" options:NSBackwardsSearch];
NSString *subString=[string substringFromIndex:range.location+1];
NSRegularExpression or NSString rangeOfString:options:range:locale: (with options to search backwards).
The answer really depends on exactly what the input string will contain (how consistent it is).

Get range of part of NSString before and after a certain character

I have a pretty simple question, however I don't know how to approach it off the top of my head. I'd like to get the range of two parts of my NSString.
I've got a time, let's say 9:42, and I want to isolate the NSRange of the hour and minute portion of the string, so the part of the string before the colon, and the part after.
Does anyone have an idea for the best way to approach this? Thanks!
NSArray *subStrings = [myString componentsSeparatedByString:#":"];
NSString *hour = [subStrings objectAtIndex:0];
NSString *minutes = [subStrings objectAtIndex:1];
Hope this helps...

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