I am having a bit of a problem with an app I'm developing for BlackBerry.
I have a series of Item objects on the screen, each with a DefaultCommand tied to it. Example
below:
...
cmdBrowse = new Command(temp.id,Command.ITEM,0);
mainList.setDefaultCommand(cmdBrowse);
mainList.setItemCommandListener(icl);
...
Previously just clicking on the item with the confirm button would run the proper command. No problem there.
Then I added the handleKeyReleased method to capture the BlackBerry's back button as follows:
protected boolean handleKeyReleased(int keyCode, int gameAction) {
if(keyCode==1769472) {
/*code to deal with back button*/
return true;
} else {
return false;
}
}
Now when I click on the mainList Item with the confirm button, it brings up the list of commands first and I have to click again to actually run the command. Two clicks where it used to be one.
So, is there a way to either:
A. Keep the single click behaviour while still being able to capture the back button with handleKeyReleased
or
B. Capture the back button in a different way ?
I ended up overlooking one very simple thing. All I had to do was call the superclass's handleKeyReleased method and everything worked perfectly.
Related
JQUERY CODE:
$('#selector button').click(function() {
$(this).addClass('active').siblings().removeClass('active');
$('#gaga').toggle
})
PUG CODE FOR #gaga element:
p#gaga
| This is `${Value}`
PUG CODE FOR #gaga element:
How can I use three buttons to toggle the #gaga element on when button is active and off when you click outside the specific button and pass a different Value for ${Value} depending on the clicked button. Plus have only one instance of #gaga element running at a time. Meaning if I click the first button then click the second button only the ${Value} will change but the p#gaga element remains only one. I know I have left out the buttons pug code, I don't think it is necessary in solving the problem. But if needed will provide it.
I tried doing it using switch statements but I have failed. Hopefully someone can help.
UPDATE & EDIT as requested by https://stackoverflow.com/users/463319/twisty in the comments.
Here is the code: https://jsfiddle.net/YulePale/mdvnf0qt/4/
After doing some research I have made some progress... but I am still stuck.
I am trying to make it in such a way that when I click anywhere outside the gender buttons the input disappears and when I click another button it changes appropriately. Also instead of an input I want to show and hide the template in the html code.
Also, if you don't mind is .data() use to assign or get a value.
PS: Got this code from this answer : Fixing toggle with two buttons
and modified it a bit, but I am still not able to achieve my desired result.
If you review the API for Menu, they have a nice _closeOnDocumentClick(). You can simply use this in your code in a similar way.
Example: https://jsfiddle.net/Twisty/0x43bf8q/
JavaScript
$(function() {
$("input[type='button']").on('click', toggleOptions)
.first()
.trigger('click');
$(document).on("click", function(e) {
if (emptyOnDocumentClick(e)) {
$('[name=gender]').val("");
}
});
function toggleOptions() {
var $this = $(this),
onClass = 'button-toggle-on';
$this.toggleClass(onClass)
.siblings('input[type=button]')
.removeClass(onClass);
var gender = $this.filter('.' + onClass).data('gender');
$('[name=gender]').val(gender);
}
function emptyOnDocumentClick(event) {
return !$(event.target).closest("input[type='button']").length;
}
});
Hope that helps.
I'm trying to fire an event programmatically. My problem is that I have two SVG on two DIVs and I want to be able to change the border of the DIV I have clicked. To do that I thought to pass the DIV inside my classes and then trigger a click on it once I click on anything. (if there is a better way, please tell me)
I have the following code:
div = querySelector(divName);
svgElement = new svg.SvgSvgElement();
div.append(svgElement);
div.onClick.listen(_setBorders(1));
later I pass the svgElement to another class
ell.show(svgElement);
where show is
show(svg.SvgElement element) {
if (element.parent is DivElement){
_parentDiv= element.parent as DivElement;
element.children.add(_group);
}
}
_parentDiv is of course a DivElement, which I use for an internal onClick()
_onClick(MouseEvent e) {
window.console.info("onClick Ell");
_parentDiv.click();
}
I'm expecting to see the _setBorders(1); I defined with the main div, but it doesn't work. The weird thing is that when I check with the debugger set to the _parentDiv.click() I see that _parentDiv has the event correctly set.
I suppose click() doesn't work as I expected. Any Idea?
If you want that _setBorders(1) is called on click events you have to use :
div.onClick.listen((_) => _setBorders(1));
I have several TextField's inside a window along with a Button, e.g. aButton.
The TextField's, Button, and window all have setImmediate(True).
When a TextField loses focus some validation code is executed and if it fails it calls:
aButton.setEnabled(False);
When incorrect data is entered into one TextField and then focus is lost the debugger shows that aButton.setEnabled(False) is called but aButton still looks enabled.
Two possible things can happen from here:
1.) If one modifies data in another TextField and exits that field (loses focus), the validation can be successful or not for that field but the system knows to call aButton.setEnabled(False) as the previous TextField is still invalid. This time though aButton is visually disabled.
2.) If one clicks on aButton which is visually enabled it produces this warning then visually becomes disabled:
Warning: Ignoring variable change for disabled component < class 'ui.button.Button'>, caption=OK
Currently using Vaadin 6.7.3
Are there any known work arounds to force aButton to visually become disabled immediately (force the client to update) after manually setting it to be disabled?
Sadly I have only Vaadin 7 at my disposal right now, but I checked this anyway. It works as you wanted it to work and I have to jump to the conclusion that this should be the same in Vaadin 6.7.3. This part is not really different in Vaadin7... Have you tried this feature in an isolated code (only a textbox and the button)?
VerticalLayout vlTestContent = new VerticalLayout();
final Button butChangeMe = new Button("Enabled");
final TextField tf = new TextField("Blur", "default value");
tf.addBlurListener(new BlurListener() {
private static final long serialVersionUID = 5544993392287938660L;
#Override
public void blur(BlurEvent event) {
butChangeMe.setCaption("Disabled");
butChangeMe.setEnabled(false);
}
});
Button but = new Button("Change button", new ClickListener() {
private static final long serialVersionUID = -2235317499126190105L;
#Override
public void buttonClick(ClickEvent event) {
butChangeMe.setCaption("Enabled");
butChangeMe.setEnabled(true);
}
});
vlTestContent.addComponent(butChangeMe);
vlTestContent.addComponent(tf);
vlTestContent.addComponent(but);
(The second button is just for fun)
button.setVisible(false) will always work. You need to be careful to not fire up a another event on the focus lost event that ends up setting the visibility of the button to true.
You can request a repaint of a component or the whole window, but the whole point of the framework is that you will never need to do that, because visually modified components will automatically repaint on each request.
Just to be curious, do you let your request to finish before trying to see if the browser updates? Or you look at your browser right after you pass the setVisible() line in your debugger ?
I think that your point nr 2 happens because you clicked on the button, and what happens in this order is: 1st your focus lost event runs (which probably disables your button), 2nd button click runs and somehow a repaint is requested for that button because a state change happened in the button but a repaint show the warning that it won't do anything with it because it is disabled (was just disable by the focus lost event)
As a side note. I think this UI won't make for a good user experience, it should be the other way arround, if a validation is ok, then show the button (or better, always show the button, but enable/disable instead) But it depends...
I have one fragment activity include two list fragments.
I use D-pad to moving through lists.
For example, when I click on listview1->tv, in listview2 shows tv channels
. When I click listview1->movie, in listview2 shows movies list and so on.
So this is my problem: when I click listview1->item3 (item3 is highlighted now by a selector) and go to listview2 and use d-pad up/down to surf the items then I come back to listview1, by left arrow key, I expect to going back to listview->item3. But it's not the case and I can't gust witch item in listview1 will focused (highlighted)
I can't handle the focused item, I need to go back to last selected item (getListView().getSelectedItemPosition()) has true item position number but focused/hilighted is not in true/last postion)
Android 2.3.4
I used these methods but none worked
getListView().setOnFocusChangeListener(new OnFocusChangeListener() {
#Override
public void onFocusChange(View v, boolean focused) {
// TODO Auto-generated method stub
if (!focused) allowfocus=true;
if (focused && allowfocus){
getListView().setSelection(PosHolder.MENU_LAST_POS);
OR
getListView().setSelection(getListView().getSelectedItemPosition());
OR
getListView().getSelectedView().setSelected(true);
OR
getListView().getSelectedView().requestFocus();
Toast.makeText(getActivity(), "Menu Got Focused:"+ getListView().getSelectedItemPosition(), Toast.LENGTH_SHORT).show();
}
}
});
What worked for me was to create a customListView which inherits from the original ListView, and then override the OnFocusChange Event to handle your focus in there.
I'm having some trouble finding documentation on CLOSING a blackberry map.
My map opens, albeit with some odd marker behavior, but when you close the map it displays a clear screen.
The invoke code is quite simple, as the map request calls a new controller and within the constructor is this:
String document = "<location-document>... etc";
Invoke.invokeApplication(Invoke.APP_TYPE_MAPS, new MapsArguments( MapsArguments.ARG_LOCATION_DOCUMENT, document));
I tried to add a close line
public boolean onClose() {
UiApplication.getUiApplication().popScreen(this);
return true;
}
but this is not being applied to the map itself, but the page the map opened into. That's logical, I guess.
Maybe I'm going about this all wrong. I don't know of how to open a map another way, or if there is a way to have the close button close the map AND the containing screen.
Any help is appreciated.
I solved this with a simple one line function that fixed this problem.
public void onExposed()
{
UiApplication.getUiApplication().popScreen(this);
}
Adding that to the map controller closes the map application when the user clicks the back button. Simple as that.