I try to get text content inside execute script of open table...
My query is like :
var q = y.query('select * from html where url="http://awebpage.html" and xpath="/html/body/div/table/tr/td/table/tr/td/div/div[2]/center/div[3]//text()"');
y.log(q.results);
This work fine and i can see in log of console the text of the content. But i don't know how i can return this!!
if i try
response.object = {'test': q.results } };
don't work.... i try to write :
response.object = {'test': q.results.toXMLString() } };
but it return something like : { 'test' : '<result> bla bla bla bla </result>' }
How can i get only the content of result?!?! I need only "bla bla bla"
As it looks like you know, q.results is an XML object. To get the text content as a string you would first call text() to get an XML text object, then call toString() to turn it into a JavaScript string.
response.object = {'test': q.results.text().toString()};
There is also the option of simply returning an XML object of your own.
response.object = <test>{q.results.text()}</test>;
Related
i want to convert my excel hyperlink's path to open links with PHPExcel.
$links = $objPHPExcel->getActiveSheet()->getHyperlinkCollection();
This method will return an array of hyperlink objects, indexed by cell address; and you could then use array_filter() with an appropriate callback and the ARRAY_FILTER_USE_KEY flag set to extract those within a specific range.
my var_dump($links); output :
But i dont know how to loop the array of objects with array_filter() function..
I try :
$test = str_replace($links, "file", "mnt");
var_dump($test);
and i got the error above.. Any ideas please ?
The collection is an array of objects, indexed by cell address; and the PHPExcel_Cell_Hyperlink object has a set of documented methods for accessing and setting its data:
foreach($links as $cellAddress => $link) {
// get the URL from the PHPExcel_Cell_Hyperlink object
$url = $link->getUrl();
// change the URL however you want here
$url = str_replace($url, "file", "mnt");
// Set the new value for the link
$link->setUrl($url);
}
If you want to modify just those URLs for cells in column N, then you can wrap them in an if test:
foreach($links as $cellAddress => $link) {
// Test for column N
sscanf($cellAddress, '%[A-Z]%d', $column, $row);
if ($column == 'N') {
// get the URL from the PHPExcel_Cell_Hyperlink object
$url = $link->getUrl();
// change the URL however you want here
$url = str_replace($url, "file", "mnt");
// Set the new value for the link
$link->setUrl($url);
}
}
I have a very basic helper method that sets Bookmark's text.
public static Bookmark SetBookmark(this Document doc, string bookmarkName, string value)
{
var bm = doc.Range.Bookmarks[bookmarkName];
if(bm == null)
throw new NullReferenceException(string.Format("Bookmark {0} Not Found!", bookmarkName));
bm.Text = value ?? string.Empty;
return bm;
}
What I need is to remove a bookmark and delete line of text that contains it when a certain condition is met, e.g. when value == null. Any suggestions?
Sample document looks like:
Hello
[Bookmark]
Goodbye
Resulted document after removal:
Hello
Goodbye
Please set the value of Bookmark.Text property to empty string to remove its content and use Bookmark.Remove method to remove the bookmark from the document. Bookmark.Remove method does not remove text inside the bookmark.
I work with Aspose as Developer evangelist.
Please set the value of Bookmark.Text property to empty string to remove its content as shown in following code example. I already shared this in my previous answer.
Document doc = new Document(MyDir + "Bookmark.doc");
// Use the indexer of the Bookmarks collection to obtain the desired bookmark.
Bookmark bookmark = doc.Range.Bookmarks["MyBookmark"];
// Remove the contents of bookmark.
bookmark.Text = "";
doc.Save(MyDir + #"Out.docx");
I work with Aspose as Developer evangelist.
I have a query that bring back a cell in my table the has all xml in it. I have it so I can spit out what is in the cell without any delimiters. Now i need to actually take each individual element and link them with my object. Is there any easy way to do this?
def sql
def dataSource
static transactional = true
def pullLogs(String username, String id) {
if(username != null && id != null) {
sql = new Sql(dataSource)
println "Data source is: " + dataSource.toString()
def schema = dataSource.properties.defaultSchema
sql.query('select USERID, AUDIT_DETAILS from DEV.AUDIT_LOG T WHERE XMLEXISTS(\'\$s/*/user[id=\"' + id + '\" or username=\"'+username+'\"]\' passing T.AUDIT_DETAILS as \"s\") ORDER BY AUDIT_EVENT', []) { ResultSet rs ->
while (rs.next()) {
def auditDetails = new XmlSlurper().parseText(rs.getString('AUDIT_EVENT_DETAILS'))
println auditDetails.toString
}
}
sql.close()
}
}
now this will give me that cell with those audit details in it. Bad thing is that is just puts all the information from the field in on giant string without the element tags. How would I go through and assign the values to a object. I have been trying to work with this example http://gallemore.blogspot.com/2008/04/groovy-xmlslurper.html with no luck since that works with a file.
I have to be missing something. I tried running another parseText(auditDetails) but haven't had any luck on that.
Any suggestions?
EDIT:
The xml int that field looks like
<user><username>scottsmith</username><timestamp>tues 5th 2009</timestamp></user>
^ simular to how it is except mine is ALOT longer. It comes out as "scottsmithtue 5th 2009" so on and so forth. I need to actually take those tags and link them to my object instead of just printing them in one conjoined string.
Just do
auditDetails.username
Or
auditDetails.timestamp
To access the properties you require
I fetched the results of a query in the model. Next i right away added a .to_json and assumed I will get a correct JSON object. But JQuery was not able to parse the json
def self.get_all_specials(year)
data_array=AttributeCalendarAnnual.find(:all, :conditions=>["created_at between ? and ?",Date.civil(Date.today.year), Date.civil(Date.today.next_year.year)], :order=>["created_at asc"])
return data_array.to_json
end
But the result I get is not a valid JSON it seems.
EDIT
The output :
[{"created_at":"2012-01-17T17:38:27Z","id":1,"in_market_end_date":"2012-01-31T23:59:59Z","in_market_start_date":"2012-01-18T00:00:00Z","initiative_id":1,"is_mail_count_selected":true,"is_mailer_selected":true,"is_market_selected":true,"is_offer_selected":true,"mail_count":1,"mailer_start_date":"2012-01-25T00:00:00Z","offer_selection_end_date":"2012-01-12T23:59:59Z","offer_selection_start_date":"2012-01-09T00:00:00Z","updated_at":"2012-01-17T17:38:27Z"},{"created_at":"2012-01-17T20:21:37Z","id":2,"in_market_end_date":"2012-01-28T23:59:59Z","in_market_start_date":"2012-01-24T00:00:00Z","initiative_id":3,"is_mail_count_selected":true,"is_mailer_selected":true,"is_market_selected":true,"is_offer_selected":true,"mail_count":5,"mailer_start_date":"2012-01-30T00:00:00Z","offer_selection_end_date":"2012-01-21T23:59:59Z","offer_selection_start_date":"2012-01-09T00:00:00Z","updated_at":"2012-01-17T20:21:37Z"}]
if you are simply outputting the escaped object to your page and hoping JS will parse it this will not work because it will be interpreted as a string. Instead try feeding the string into a function like this:
function parseJSON(txt, escape) {
if (escape === true) {
txt = unescape(txt);
}
return new Function("return " + txt)();
}
var result = parseJSON(someString);
I am trying to iterate over a list of parameters, in a grails controller. when I have a list, longer than one element, like this:
[D4L2DYJlSw, 8OXQWKDDvX]
the following code works fine:
def recipientId = params.email
recipientId.each { test->
System.print(test + "\n")
}
The output being:
A4L2DYJlSw
8OXQWKDDvX
But, if the list only has one item, the output is not the only item, but each letter in the list. for example, if my params list is :
A4L2DYJlSwD
using the same code as above, the output becomes:
A
4
L
2
D
Y
J
l
S
w
can anyone tell me what's going on and what I am doing wrong?
thanks
jason
I run at the same problem a while ago! My solution for that it was
def gameId = params.gameId
def selectedGameList = gameId.class.isArray() ? Game.getAll(gameId as List) : Game.get(gameId);
because in my case I was getting 1 or more game Ids as parameters!
What you can do is the same:
def recipientId = params.email
if(recipientId.class.isArray()){
// smtg
}else{
// smtg
}
Because what is happening here is, as soon as you call '.each' groovy transform that object in a list! and 'String AS LIST' in groovy means char_array of that string!
My guess would be (from what I've seen with groovy elsewhere) is that it is trying to figure out what the type for recipientId should be since you haven't given it one (and it's thus dynamic).
In your first example, groovy decided what got passed to the .each{} closure was a List<String>. The second example, as there is only one String, groovy decides the type should be String and .each{} knows how to iterate over a String too - it just converts it to a char[].
You could simply make recipientId a List<String> I think in this case.
You can also try like this:
def recipientId = params.email instanceof List ? params.email : [params.email]
recipientId.each { test-> System.print(test + "\n") }
It will handle both the cases ..
Grails provides a built-in way to guarantee that a specific parameter is a list, even when only one was submitted. This is actually the preferred way to get a list of items when the number of items may be 0, 1, or more:
def recipientId = params.list("email")
recipientId.each { test->
System.print(test + "\n")
}
The params object will wrap a single item as a list, or return the list if there is more than one.