I have the following 2 commands working as expected.
grep -B3 'Max_value: 127' proc_*.*
grep -B3 'Max_value: 32767' proc_*.*
But can I write a single grep command? There can be upto 4 Max Values.
grep -B3 'Max_value: \(127\|32767\)' proc_*.*
Give grep a regular expression:
grep -B3 'Max_value: (?:127|32767)' proc_*.*
Related
I'm trying to find lines with words not preceded by double colons (::).
Example
void myClass::doMything() // I don't want this line
myObj->doMyThing() // I want this line
My goal is to get the lines where some methods are used, but not where the methods are defined.
I try with this command :
grep --color=always -rwna "methodName" --include=*.cpp | grep -v "::methodName"
but it doesn't work : it keeps extracting also lines containing
::methodName
I've also tried by writing
grep --color=always -rwna "methodName" --include=*.cpp | grep -v "\:\:methodName"
egrep --color=always -rwna "methodName" --include=*.cpp | egrep -v "\:\:methodName"
but neither works.
What should I do ?
Although grep is probably most common used tool among all linux CLI tools and is used by every1 and everywhere... still doesnt mean its perfect. The thing you are trying to achieve is not achievable with basic grep's regex - you need python/perl regex here.
As a workaround (I assume you are trying to only find line where method is invoked) you can try:
grep -Eno "(::)?methodName" your_input_files | grep -v "::methodName"
-n to prints line number and I believe it will give convenience to you
-o to prints only matched part, but I use it here to split output - to have each match in separate line (if you have 5x methodName in line of code you will have 5 lines in grep's output)
(::)? to find distinguish if its declaration or invokation of methodName, we will need it when 2nd grep comes to play...
grep -v ...and here it comes, to get rid of what you dont want
I guess you want to use maaaaany times so you can even try to make a function into your .bashrc
find_invocations () {
# below example goes through current dir, but you can improve it :)
grep --color=yes -Eno "(::)?$1" * 2>/dev/null | grep -v "::$1"
}
in above function you might go risky and use $1.* instead of $1 but an unpleasant case is if you have both methodname and ::methodName in same line AFAIR my C++ lessons (ages ago - anno 2010) methodName::methodName is a constructor...
...sorry for bad english
I've finally managed to make it work.
I've tried linux_beginner's suggestion:
grep -Eno '(::)?myMethodName' path/to/one/of/the/files.cpp | grep -v '::myMethodName'
with a single file and this works. (I found I prefer not using the o option, because I also want to se how it's used).
In this search I need anyway to use multiple files. So I've also tried to include more files :
grep -Eno '(::)?myMethodName' --include=*.cpp | grep -v '::myMethodName'
but in this case it remains like stuck in the search (maybe it triggers some slow scripting ? perl or python ?).
I've checked RavinderSingh13's command. Taken in a single instance, it can capture the lines with double colon(and only them, correctly), both on single file or in multiple files :
grep -rna '::myMethodName' path/to/one/of/the/file.cpp
grep -rna '::myMethodName' --include=*.cpp
but there must not be the -w switch, so the following:
grep -rna '::myMethodName' path/to/one/of/the/file.cpp
grep -rna '::myMethodName' --include=*.cpp
don't get any result.
RavinderSingh13's suggestion put inside the pipelining doesn't manage to filter out the double colon lines (my original goal), either with single or multiple files :
grep -rwna 'myMethodName' path/to/one/of/the/files.cpp | grep -v '::[[:alpha:]]+'
-> extracts both myMethodName and ::myMethodName from the chosen file
grep -rwna 'myMethodName' --include=*.cpp | grep -v '::[[:alpha:]]+'
-> extracts both myMethodName and ::myMethodName from all the cpp files
Now, how I could solve:
usually, when I concatenate grep commands I also add to the first of them the switch --color=always, which preserves results coloring also across the piping of multiple commands.
But that... was the culprit !
i.e., doing
grep --color=always -rwna 'myMethodName' --include=*.cpp | grep -v '::myMethodName'
preserves the color in results, but sadly fails to exclude lines containing ::myMethodName, while
grep -rwna 'myMethodName' --include=*.cpp | grep -v '::myMethodName'
gives colorless but correct results (manages to filter out double column lines).
The distribution on which I've experimented these codes and behaviours is Ubuntu 20.04.1 LTS.
Grep version : grep (GNU grep) 3.4
Thanks everybody for the interest.
I want to do sth like:
grep -A 10 'myString' && NOT 'anotherString'
If I didn't need -A 10 I know I could pipe greps and use -v, but it would not work like that in this case. So I would do sth like that:
grep "myString" | grep -v "anotherString"
Any ideas?
Try to invert and place the grep with the -A 10 argument in the end. Like this:
grep -v 'anotherString' | grep -A 10 'myString'
The only POSIX supported options for grep are -EFcefilnqsvx so be aware that the -A option may not be present on all implementations of grep. And even on GNU grep there is no option to specify "match OR match" and there is no regex that can emulate this as all it can do is provide additional matches, but can not withhold them. Essentially the only way to accomplish this with grep alone is to use a pipe.
I want to grep "[calleruid]=aab01b055-89e3-49f3-839e-507bb128d07e&smscresponse"
in Below file
2014-10-15 18:38:32,831 plivo-rest[2781]: INFO: Fetching GET http://*******/outbound_callback.aspx with smscresponse[to]=8912722fsf9&smscresponse[ALegUUID]=5bb516fsd64-546c-11e4-879f-551816a551303677&smscresponse[calluid]=aab01b055-89e3-49f3-839e-507bb128d07e&smscresponse[direction]=outbosund&smscresfdsponse[endreason]=UNALLOCATED_NUMBER&smscresponse[from]=83339995896999&smscresponse[starttime]=0&smscresponse[ALegRequestUUID]=5bb4bafc-546c-11e4-891d-000c29ec6e41&smscresponse[RequestUUID]=5bb4bafc-546c-11e4-891d-000c29ec6e41&smscresponse[callstatus]=completed&smscresponse[endtime]=1413378509&smscresponse[ScheduledHangupId]=5bb4c15a-546c-11e4-891d-000c29ec6e41&smscresponse[event]=missed_call_hangup
I used this command
$ grep -oP '(calluid).*$'
this greps upto end of file
I used this command
$ grep -oP '(calluid).{40}'
it fetches 40 characters but i have 1000's of calleruid's so each have different no.s of characters
So please guide me to grep exact callerid data
Use a lookahead to force the regex engine to do the match upto a specific character or a boundary.
$ grep -oP '\[calluid\][^\]\[]*(?=\[|$)' file
[calluid]=aab01b055-89e3-49f3-839e-507bb128d07e&smscresponse
Here is an gnu awk (due to multiple characters in RS) version:
awk -v RS="[[]calluid[]]=" -F[ 'NR==2 {print $1}' file
aab01b055-89e3-49f3-839e-507bb128d07e&smscresponse
You can also set RS like this: RS="\\\[calluid]="
I am trying to parse items out of a file I have. I cant figure out how to do this with grep
here is the syntax
<FQDN>Compname.dom.domain.com</FQDN>
<FQDN>Compname1.dom.domain.com</FQDN>
<FQDN>Compname2.dom.domain.com</FQDN>
I want to spit out just the bits between the > and the <
can anyone assist?
Thanks
grep can do some text extraction. however not sure if this is what you want:
grep -Po "(?<=>)[^<]*"
test
kent$ echo "<FQDN>Compname.dom.domain.com</FQDN>
dquote>
dquote> <FQDN>Compname1.dom.domain.com</FQDN>
dquote>
dquote> <FQDN>Compname2.dom.domain.com</FQDN>"|grep -Po "(?<=>)[^<]*"
Compname.dom.domain.com
Compname1.dom.domain.com
Compname2.dom.domain.com
Grep isn't what you are looking for.
Try sed with a regular expression : http://unixhelp.ed.ac.uk/CGI/man-cgi?sed
You can do it like you want with grep :
grep -oP '<FQDN>\K[^<]+' FILE
Output:
Compname.dom.domain.com
Compname1.dom.domain.com
Compname2.dom.domain.com
As others have said, grep is not the ideal tool for this. However:
$ echo '<FQDN>Compname.dom.domain.com</FQDN>' | egrep -io '[a-z]+\.[^<]+'
Compname.dom.domain.com
Remember that grep's purpose is to MATCH things. The -o option shows you what it matched. In order to make regex conditions that are not part of the expression that is returned, you'd need to use lookahead or lookbehind, which most command-line grep does not support because it's part of PCRE rather than ERE.
$ echo '<FQDN>Compname.dom.domain.com</FQDN>' | grep -Po '(?<=>)[^<]+'
Compname.dom.domain.com
The -P option will work in most Linux environments, but not in *BSD or OSX or Solaris, etc.
I have a file that possibly contains bad formatting (in this case, the occurrence of the pattern \\backslash). I would like to use grep to return only the line numbers where this occurs (as in, the match was here, go to line # x and fix it).
However, there doesn't seem to be a way to print the line number (grep -n) and not the match or line itself.
I can use another regex to extract the line numbers, but I want to make sure grep cannot do it by itself. grep -no comes closest, I think, but still displays the match.
try:
grep -n "text to find" file.ext | cut -f1 -d:
If you're open to using AWK:
awk '/textstring/ {print FNR}' textfile
In this case, FNR is the line number. AWK is a great tool when you're looking at grep|cut, or any time you're looking to take grep output and manipulate it.
All of these answers require grep to generate the entire matching lines, then pipe it to another program. If your lines are very long, it might be more efficient to use just sed to output the line numbers:
sed -n '/pattern/=' filename
Bash version
lineno=$(grep -n "pattern" filename)
lineno=${lineno%%:*}
I recommend the answers with sed and awk for just getting the line number, rather than using grep to get the entire matching line and then removing that from the output with cut or another tool. For completeness, you can also use Perl:
perl -nE 'say $. if /pattern/' filename
or Ruby:
ruby -ne 'puts $. if /pattern/' filename
using only grep:
grep -n "text to find" file.ext | grep -Po '^[^:]+'
You're going to want the second field after the colon, not the first.
grep -n "text to find" file.txt | cut -f2 -d:
To count the number of lines matched the pattern:
grep -n "Pattern" in_file.ext | wc -l
To extract matched pattern
sed -n '/pattern/p' file.est
To display line numbers on which pattern was matched
grep -n "pattern" file.ext | cut -f1 -d: