What is the correct syntax when we use multiple patterns ?
test3()->
test4(<<"1234567890">>).
test4(A)->
X = binary:split(A,[<<"3">>,<<"8">>]),
X.
[<<"12">>,<<"4567890">>]
I was expected 3 elements!
In order to get 3 elements, you should use the split/3 function and to specify the global option ("Repeats the split until the Subject is exhausted"):
binary:split(<<"1234567890">>,[<<"3">>,<<"8">>],[global]).
and you'll get:
[<<"12">>,<<"4567">>,<<"90">>]
More on this, in the official doc: http://www.erlang.org/doc/man/binary.html#split-3
Hope it helps.
Related
I'm trying to automate some output using printf but I'm struggling to find a way to pass to it the list of arguments expr_1, ..., expr_n in
printf (dest, string, expr_1, ..., expr_n)
I thought of using something like Javascript's spread operator but I'm not even sure I should need it.
For instace, say I have a list of strings to be output
a:["foo","bar","foobar"];
a string of appropriate format descriptors, say
s: "~a ~a ~a ~%";
and an output stream, say os. How can I invoke printf using these things in such a way that the result will be the same as writing
printf(os,s,a[1],a[2],a[3]);
Then I could generalize it to output lists of variable size.
Any suggestions?
Thanks.
EDIT:
I just learned about apply and, using the conditions I posed in my OP, the following seems to work wonderfully:
apply(printf,append([os,s],a));
Maxima printf implements most or maybe all of the formatting operators from Common Lisp FORMAT, which are quite extensive; see: http://www.lispworks.com/documentation/HyperSpec/Body/22_c.htm See also ? printf in Maxima to get an abbreviated list of formatting operators.
In particular for a list you can do something like:
printf (os, "my list: ~{~a~^, ~}~%", a);
to get the elements of a separated by ,. Here "~{...~}" tells printf to expect a list, and ~a is how to format each element, ~^ means omit the inter-element stuff after the last element, and , means put that between elements. Of course , could be anything.
There are many variations on that; if that's not what you're looking for, maybe I can help you find it.
Here is my sample string.
[echo] The SampleProject solution currently has 85% code coverage.
My desired output should be.
The SampleProject solution currently has 85% code coverage.
Btw, I had this out because I'm getting through the logs in my CI using Jenkins.
Any help? Thanks..
You can try substText parameter in BUILD_LOG_REGEX token to substitute the text matching your regex
New optional arg: ${BUILD_LOG_REGEX, regex, linesBefore, linesAfter, maxMatches, showTruncatedLines, substText} which allows substituting text for the matched regex. This is particularly useful when the text contains references to capture groups (i.e. $1, $2, etc.)
Using below will remove prefix [echo] from all of your logs ,
${BUILD_LOG_REGEX, regex="^\[echo] (.*)$", maxMatches=0, showTruncatedLines=false, substText="$1"}
\[[^\]]*\] will match the bit you want to remove. Just use a string replace function to replace that bit with an empty string.
Andrew has the right idea, but with Perl-style regex syntaxes (which includes Java's built-in regex engine), you can do even better:
str.replaceAll("\\[.*?\\]", "");
(i.e., use the matching expression \[.*?\]. The ? specifies minimal match: so it will finish matching upon the first ] found.)
I'm trying to look at a string and reject anything that has seq= or app= in the string. Where it gets tricky is I need elements with q=something or p=something.
The seq= part of the string is always preceded an & and app= is always preceded by a ?
I have absolutely no idea where to start. I've been using http://www.rubular.com/ to try and figure it out but to no avail.
Any help would be hugely appreciated.
Based on your question, I believe you could just reject any strings that match the following expression:
[\?&](?:seq|app)=
This will match any string that contains a ? or & followed by either app= or seq=. The ?: inside the parentheses just tells the regular expression not to bother to capture matching groups as sub-matches. They're not really necessary, but what the heck.
Here's a Rubular link with some samples.
I am relatively new to maxima. I want to know how to write an array into a text file using maxima.
I know it's late in the game for the original post, but I'll leave this here in case someone finds it in a search.
Let A be a Lisp array, Maxima array, matrix, list, or nested list. Then:
write_data (A, "some_file.data");
Let S be an ouput stream (created by openw or opena). Then:
write_data (A, S);
Entering ?? numericalio at the input prompt, or ?? write_ or ?? read_, will show some info about this function and related ones.
I've never used maxima (or even heard of it), but a little Google searching out of curiousity turned up this: http://arachnoid.com/maxima/files_functions.html
From what I can gather, you should be able to do something like this:
stringout("my_new_file.txt",values);
It says the second parameter to the stringout function can be one or more of these:
input: all user entries since the beginning of the session.
values: all user variable and array assignments.
functions: all user-defined functions (including functions defined within any loaded packages).
all: all of the above. Such a list is normally useful only for editing and extraction of useful sections.
So by passing values it should save your array assignments to file.
A bit more necroposting, as google leads here, but I haven't found it useful enough. I've needed to export it as following:
-0.8000,-0.8000,-0.2422,-0.242
-0.7942,-0.7942,-0.2387,-0.239
-0.7776,-0.7776,-0.2285,-0.228
-0.7514,-0.7514,-0.2124,-0.212
-0.7168,-0.7168,-0.1912,-0.191
-0.6750,-0.6750,-0.1655,-0.166
-0.6272,-0.6272,-0.1362,-0.136
-0.5746,-0.5746,-0.1039,-0.104
So I've found how to do this with printf:
with_stdout(filename, for i:1 thru length(z_points) do
printf (true,"~,4f,~,4f,~,4f,~,3f~%",bot_points[i],bot_points[i],top_points[i],top_points[i]));
A bit cleaner variation on the #ProdoElmit's answer:
list : [1,2,3,4,5]$
with_stdout("file.txt", apply(print, list))$
/* 1 2 3 4 5 is then what appears in file.txt */
Here the trick with apply is needed as you probably don't want to have square brackets in your output, as is produced by print(list).
For a matrix to be printed out, I would have done the following:
m : matrix([1,2],[3,4])$
with_stdout("file.txt", for row in args(m) do apply(print, row))$
/* 1 2
3 4
is what you then have in file.txt */
Note that in my solution the values are separated with spaces and the format of your values is fixed to that provided by print. Another caveat is that there is a limit on the number of function parameters: for example, for me (GCL 2.6.12) my method does not work if length(list) > 64.
Ok. Given the example of:
http://example.com/news/3226-some-post-title.html
I'm trying to get the 3226. This regexp: http://interaktywnie.com/newsy/(.*).html
doesn't seem to work. Please help.
Thanks.
You can just use:
/\/(\d+)-(.*)\.html$/
This will grab the digits (\d) after the '/' and put the digits into the first variable once it finds them.
A great place to test regular expression is http://rubular.com/.
You want this:
/http:\/\/example.com\/news\/(\d+)-.+\.html/
\d is any digit. Also, the following site is very useful for regular expressions in ruby:
http://www.rubular.com
"http://example.com/news/3226-some-post-title.html".split("/").last.to_i
Try this pattern:
/http:\/\/example\.com\/news\/(\d+)-.+\.html/
So:
match = /http:\/\/example\.com\/news\/(\d+)-.+\.html/.match("http://example.com/news/3226-some-post-title.html")
puts match[1]