i used a CurrencyFormatter to parse 2 number into its currency representation
currencyFormat.format("10" + "." + "99") ---> $10.99
I'm curious if there is a way to parse a string "$10.99" back to a number / double ?
so it is possible to get the value on the left side of the decimal and right side of the decimal.
thanks,
You could do this a number of ways. Here are 2 off the top of my head:
function currencyToNumbers($currency:String):Object {
var currencyRE:RegExp = /\$([1-9][0-9]+)\.?([0-9]{2})?/;
var val = currencyRE.exec($currency);
return {dollars:val[1], cents:val[2]};
}
function currencyToNumbers2($currency:String):Object {
var dollarSignIndex:int = $currency.indexOf('$');
if (dollarSignIndex != -1) {
$currency = $currency.substr(dollarSignIndex + 1);
}
var currencyParts = parseFloat($currency).toString().split(".");
return {dollars:currencyParts[0], cents:currencyParts[1]};
}
var currency:Object = currencyToNumbers('$199.99');
trace(currency.dollars);
trace(currency.cents);
var currency2:Object = currencyToNumbers2('$199.99');
trace(currency2.dollars);
trace(currency2.cents);
Related
Is there a way to split a string by some symbol but only at first occurrence?
Example: date: '2019:04:01' should be split into date and '2019:04:01'
It could also look like this date:'2019:04:01' or this date : '2019:04:01' and should still be split into date and '2019:04:01'
string.split(':');
I tried using the split() method. But it doesn't have a limit attribute or something like that.
You were never going to be able to do all of that, including trimming whitespace, with the split command. You will have to do it yourself. Here's one way:
String s = "date : '2019:04:01'";
int idx = s.indexOf(":");
List parts = [s.substring(0,idx).trim(), s.substring(idx+1).trim()];
You can split the string, skip the first item of the list created and re-join them to a string.
In your case it would be something like:
var str = "date: '2019:04:01'";
var parts = str.split(':');
var prefix = parts[0].trim(); // prefix: "date"
var date = parts.sublist(1).join(':').trim(); // date: "'2019:04:01'"
The trim methods remove any unneccessary whitespaces around the first colon.
Just use the split method on the string. It accepts a delimiter/separator/pattern to split the text by. It returns a list of values separated by the provided delimiter/separator/pattern.
Usage:
const str = 'date: 2019:04:01';
final values = string.split(': '); // Notice the whitespace after colon
Output:
Inspired by python, I've wrote this utility function to support string split with an optionally maximum number of splits. Usage:
split("a=b=c", "="); // ["a", "b", "c"]
split("a=b=c", "=", max: 1); // ["a", "b=c"]
split("",""); // [""] (edge case where separator is empty)
split("a=", "="); // ["a", ""]
split("=", "="); // ["", ""]
split("date: '2019:04:01'", ":", max: 1) // ["date", " '2019:04:01'"] (as asked in question)
Define this function in your code:
List<String> split(String string, String separator, {int max = 0}) {
var result = List<String>();
if (separator.isEmpty) {
result.add(string);
return result;
}
while (true) {
var index = string.indexOf(separator, 0);
if (index == -1 || (max > 0 && result.length >= max)) {
result.add(string);
break;
}
result.add(string.substring(0, index));
string = string.substring(index + separator.length);
}
return result;
}
Online demo: https://dartpad.dev/e9a5a8a5ff803092c76a26d6721bfaf4
I found that very simple by removing the first item and "join" the rest of the List
String date = "date:'2019:04:01'";
List<String> dateParts = date.split(":");
List<String> wantedParts = [dateParts.removeAt(0),dateParts.join(":")];
Use RegExp
string.split(RegExp(r":\s*(?=')"));
Note the use of a raw string (a string prefixed with r)
\s* matches zero or more whitespace character
(?=') matches ' without including itself
You can use extensions and use this one for separating text for the RichText/TextSpan use cases:
extension StringExtension on String {
List<String> controlledSplit(
String separator, {
int max = 1,
bool includeSeparator = false,
}) {
String string = this;
List<String> result = [];
if (separator.isEmpty) {
result.add(string);
return result;
}
while (true) {
var index = string.indexOf(separator, 0);
print(index);
if (index == -1 || (max > 0 && result.length >= max)) {
result.add(string);
break;
}
result.add(string.substring(0, index));
if (includeSeparator) {
result.add(separator);
}
string = string.substring(index + separator.length);
}
return result;
}
}
Then you can just reference this as a method for any string through that extension:
void main() {
String mainString = 'Here was john and john was here';
print(mainString.controlledSplit('john', max:1, includeSeparator:true));
}
Just convert list to string and search
productModel.tagsList.toString().contains(filterText.toLowerCase())
I'm attempting to get a user input number and find the sum of all the digits. I'm having issues with larger numbers, however, as they won't register under an Int64. Any idea as to what structures I could use to store the value? (I tried UInt64 and that didn't work very well with negatives, however, I'd prefer something larger than UInt64, anyways. I'm having a hard time implementing a UInt128 from Is there a number type with bigger capacity than u_long/UInt64 in Swift?)
import Foundation
func getInteger() -> Int64 {
var value:Int64 = 0
while true {
//we aren't doing anything with input, so we make it a constant
let input = readLine()
//ensure its not nil
if let unwrappedInput = input {
if let unwrappedInt = Int64(unwrappedInput) {
value = unwrappedInt
break
}
}
else { print("You entered a nil. Try again:") }
}
return value
}
print("Please enter an integer")
// Gets user input
var input = getInteger()
var arr = [Int] ()
var sum = 0
var negative = false
// If input is less than 0, makes it positive
if input < 0 {
input = (input * -1)
negative = true
}
if (input < 10) && (input >= 1) && (negative == true) {
var remain = (-1)*(input%10)
arr.append(Int(remain))
input = (input/10)
}
else {
var remain = (input%10)
arr.append(Int(remain))
input = (input/10)
}
}
// Adds numbers in array to find sum of digits
var i:Int = 0
var size:Int = (arr.count - 1)
while i<=size {
sum = sum + arr[i]
i = (i+1)
}
// Prints sum
print("\(sum)")
You can use a string to perform the operation you describe. Loop through each character and convert it to an integer and add to the sum. Be careful to handle errors.
This question already has answers here:
Swift - Resolving a math operation in a string
(4 answers)
Closed 6 years ago.
let randsign = Int(arc4random_uniform(2) + 1)
//This function returns a random operator
func whatSign(par1:Int)-> String {
if (par1 == 1){
return "+"
}
else {
return "-"
}
}
var sigh = whatSign(par1: randsign)
let randnum1:Any = Int (arc4random_uniform(10) + 1)
let randnum2:Int = Int (arc4random_uniform(10) + 1)
//I want the variable "finVal" to perform mathematical operation, but it does not because the variable "sign" is String
let finVal = "\(randnum1)\(sigh)\(randnum2)"
print(finVal)
//When I print I get for example 1-3, 9-4, 8+2 .But I wanted them to do arithmetic
NSExpression is one the good way to evaluate the Math
let finVal = "(randnum1)(sigh)(randnum2)"
let result = NSExpression(format: finVal).expressionValue(with: nil, context: nil) as! Int
let randsign = Int(arc4random_uniform(2) + 1)
let randnum1:Any = Int (arc4random_uniform(10) + 1)
let randnum2:Int = Int (arc4random_uniform(10) + 1)
var finVal:Int
//This function returns a random operator
func whatSign(par1:Int)-> String {
//I want to compute the variables and get final result from adding or subtracting them
if (par1 == 1){
finVal = randnum1 + randnum2
return "+"
}
else {
finVal = randnum1 - randnum2
return "-"
}
}
whatSign(par1: randsign)
print(finVal)
//When I print I get for example 1-3, 9-4, 8+2 .But I wanted them to do arithmetic
Maybe it will helps you
Like: 0123, 0913, 7612
Not like: 0000, 1333, 3499
Can it be done with arcRandom() in swift? Without array or loop?
Or If that impossible, how it be done with arcRandom() in any way ?
You just want to shuffle the digits and pick the number you want.
Start with Nate Cook's Fischer-Yates shuffle code.
// Start with the digits
let digits = 0...9
// Shuffle them
let shuffledDigits = digits.shuffle()
// Take the number of digits you would like
let fourDigits = shuffledDigits.prefix(4)
// Add them up with place values
let value = fourDigits.reduce(0) {
$0*10 + $1
}
var fourUniqueDigits: String {
var result = ""
repeat {
// create a string with up to 4 leading zeros with a random number 0...9999
result = String(format:"%04d", arc4random_uniform(10000) )
// generate another random number if the set of characters count is less than four
} while Set<Character>(result.characters).count < 4
return result // ran 5 times
}
fourUniqueDigits // "3501"
fourUniqueDigits // "8095"
fourUniqueDigits // "9054"
fourUniqueDigits // "4728"
fourUniqueDigits // "0856"
Swift Code - For Generation of 4 digit
It gives number between 1000 and 9999.
func random() -> String {
var result = ""
repeat {
result = String(format:"%04d", arc4random_uniform(10000) )
} while result.count < 4 || Int(result)! < 1000
print(result)
return result
}
Please Note - You can remove this Int(result)! < 1000 if you want numbers like this - 0123, 0913
An issue here to me that if i use parse string for the result of calculator program for instance,
4.5 * 5.0 = 22.5
how can I use splitting here to depart decimal part from result?
Assuming you're working with strings only :
var str = "4.5 * 5.0 = 22.5 "
// Trim your string in order to remove whitespaces at start and end if there is any.
var trimmedStr = str.stringByTrimmingCharactersInSet(NSCharacterSet.whitespaceCharacterSet())
// Split the string by " " (whitespace)
var splitStr = trimmedStr.componentsSeparatedByString(" ")
// If the split was successful, retrieve the last past (your number result)
var lastPart = ""
if let result = splitStr.last {
lastPart = result
}
// Since it's a XX.X number, split it again by "." (point)
var splitLastPart = lastPart.componentsSeparatedByString(".")
// If the split was successful, retrieve the last past (your number decimal part)
var decimal = ""
if let result = splitLastPart.last {
decimal = result
}
Use modf to extract decimal part from result.
Objective-C :
double integral = 22.5;
double fractional = modf(integral, &integral);
NSLog(#"%f",fractional);
Swift :
var integral:Double = 22.5;
let fractional:Double = modf(integral,&integral);
println(fractional);
Want only interger part from double of float
Want only integer value from double then
let integerValue:Int = Int(integral)
println(integerValue)
Want only integer value from float then
let integerValue:Float = Float(integral)
println(integerValue)