I have a joined model that has a foreign key for the model event.
The joined model is called Goals. I'm trying to find the proper find condition to figure out which event_id has the most instances in the Goal join model. Essenially which foreign key id has the most entries in the join model.
Is there a way to do this?
Goal.where(:event.id => ??????? ).first
Couldn't come up with a more elegant solution but try this:
results = Goal.connection.select_all('SELECT COUNT(*) as amount, event_id FROM goals GROUP BY event_id ORDER BY amount DESC LIMIT 0, xx')
raise results.inspect
If you just want the one most event_id with most entries you can also use:
event_id = Goal.connection.select_one('SELECT COUNT(*) as amount, event_id FROM goals GROUP BY event_id ORDER BY amount DESC LIMIT 1').first
If you have set up your models correctly you should be able to do this (if this is not the case then: setup your models correctly):
if Event.all.length == 0
return
end
eventMax = Event.first
Event.all.each do |e|
eventMax = e.goals.length>eventMax.goals.length?e:eventMax
end
#output or do whatever with your newly found event
puts eventMax.to_json
The solution from Danny is not really good.
You should never (or at least very rarely) have to write sql by yourself in rails.
Related
I have a Company model that has_many Statement.
class Company < ActiveRecord::Base
has_many :statements
end
I want to get statements that have most latest date field grouped by fiscal_year_end field.
I implemented the function like this:
c = Company.first
c.statements.to_a.group_by{|s| s.fiscal_year_end }.map{|k,v| v.max_by(&:date) }
It works ok, but if possible I want to use ActiveRecord query(SQL), so that I don't need to load unnecessary instance to memory.
How can I write it by using SQL?
select t.username, t.date, t.value
from MyTable t
inner join (
select username, max(date) as MaxDate
from MyTable
group by username
) tm on t.username = tm.username and t.date = tm.MaxDate
For these kinds of things, I find it helpful to get the raw SQL working first, and then translate it into ActiveRecord afterwards. It sounds like a textbook case of GROUP BY:
SELECT fiscal_year_end, MAX(date) AS max_date
FROM statements
WHERE company_id = 1
GROUP BY fiscal_year_end
Now you can express that in ActiveRecord like so:
c = Company.first
c.statements.
group(:fiscal_year_end).
order(nil). # might not be necessary, depending on your association and Rails version
select("fiscal_year_end, MAX(date) AS max_date")
The reason for order(nil) is to prevent ActiveRecord from adding ORDER BY id to the query. Rails 4+ does this automatically. Since you aren't grouping by id, it will cause the error you're seeing. You could also order(:fiscal_year_end) if that is what you want.
That will give you a bunch of Statement objects. They will be read-only, and every attribute will be nil except for fiscal_year_end and the magically-present new field max_date. These instances don't represent specific statements, but statement "groups" from your query. So you can do something like this:
- #statements_by_fiscal_year_end.each do |s|
%tr
%td= s.fiscal_year_end
%td= s.max_date
Note there is no n+1 query problem here, because you fetched everything you need in one query.
If you decide that you need more than just the max date, e.g. you want the whole statement with the latest date, then you should look at your options for the greatest n per group problem. For raw SQL I like LATERAL JOIN, but the easiest approach to use with ActiveRecord is DISTINCT ON.
Oh one more tip: For debugging weird errors, I find it helpful to confirm what SQL ActiveRecord is trying to use. You can use to_sql to get that:
c = Company.first
puts c.statements.
group(:fiscal_year_end).
select("fiscal_year_end, MAX(date) AS max_date").
to_sql
In that example, I'm leaving off order(nil) so you can see that ActiveRecord is adding an ORDER BY clause you don't want.
for example you want to get all statements by start of the months you should use this
#companey = Company.first
#statements = #companey.statements.find(:all, :order => 'due_at, id', :limit => 50)
then group them as you want
#monthly_statements = #statements.group_by { |statement| t.due_at.beginning_of_month }
Building upon Bharat's answer you can do this type of query in Rails using find_by_sql in this way:
Statement.find_by_sql ["Select t.* from statements t INNER JOIN (
SELECT fiscal_year_end, max(date) as MaxDate GROUP BY fiscal_year_end
) tm on t.fiscal_year_end = tm.fiscal_year_end AND
t.created_at = tm.MaxDate WHERE t.company_id = ?", company.id]
Note the last where part to make sure the statements belong to a specific company instance, and that this is called from the class. I haven't tested this with the array form, but I believe you can turn this into a scope and use it like this:
# In Statement model
scope :latest_from_fiscal_year, lambda |enterprise_id| {
find_by_sql[..., enterprise_id] # Query above
}
# Wherever you need these statements for a particular company
company = Company.find(params[:id])
latest_statements = Statement.latest_from_fiscal_year(company.id)
Note that if you somehow need all the latest statements for all companies then this most likely leave you with a N+1 queries problem. But that is a beast for another day.
Note: If anyone else has a way to have this query work on the association without using the last where part (company.statements.latest_from_year and such) let me know and I'll edit this, in my case in rails 3 it just pulled em from the whole table without filtering.
I'm quite new to RoR and creating a student project for a course I'm taking. I'm wanting to construct a type of query we didn't cover in the course and which I know I could do in a snap in .NET and SQL. I'm having a heck of a time though getting it implemented the Ruby way.
What I'd like to do: Display a list on a user's page of all "posts" by that user's friends.
"Posts" are found in both a questions table and in a blurbs table that users contribute to. I'd like to UNION these two into a single recordset to sort by updated_at DESC.
The table column names are not the same however, and this is my sticking point since other successful answers I've seen have hinged on column names being the same between the two.
In SQL I'd write something like (emphasis on like):
SELECT b.Blurb AS 'UserPost', b.updated_at, u.username as 'Author'
FROM Blurbs b
INNER JOIN Users u ON b.User_ID = u.ID
WHERE u.ID IN
(SELECT f.friend_id FROM Friendships f WHERE f.User_ID = [current user])
ORDER BY b.updated_at DESC
UNION
SELECT q.Question, q.updated_at, u.username
FROM Questions q
INNER JOIN Users u ON q.User_ID = u.ID
WHERE u.ID IN
(SELECT f.friend_id FROM Friendships f WHERE f.User_ID = [current user])
ORDER BY b.updated_at DESC
The User model's (applicable) relationships are:
has_many :friendships
has_many :friends, through: :friendships
has_many :questions
has_many :blurbs
And the Question and Blurb models both have belongs_to :user
In the view I'd like to display the contents of the 'UserPost' column and the 'Author'. I'm sure this is possible, I'm just too new still to ActiveRecord and how statements are formed. Happy to have some input or review any relevant links that speak to this specifically!
Final Solution
Hopefully this will assist others in the future with Ruby UNION questions. Thanks to #Plamena's input the final implementation ended up as:
def friend_posts
sql = "...the UNION statement seen above..."
ActiveRecord::Base.connection.select_all(ActiveRecord::Base.send("sanitize_sql_array",[sql, self.id, self.id] ) )
end
Currently Active Record lacks union support. You can use SQL:
sql = <<-SQL
# your sql query goes here
SELECT b.created_at ...
UNION(
SELECT q.created_at
....
)
SQL
posts = ActiveRecord::Base.connection.select_all(sql)
Then you can iterate the result:
posts.each do |post|
# post is a hash
p post['created_at']
end
Your best way to do this is to just use the power of Rails
If you want all of something belonging to a user's friend:
current_user.friends.find(id_of_friend).first.questions
This would get all of the questions from a certain friend.
Now, it seems that you have writings in multiple places (this is hard to visualise without your providing a model of how writings is connected to everywhere else). Can you provide this?
#blurbs = Blurb.includes(:user)
#blurbs.each do |blurb|
p blurb.blurb, blurb.user.username
end
I have a users table, which has a one-to-many relationship with a user_purchases table via the foreign key user_id. That is, each user can make many purchases (or may have none, in which case he will have no entries in the user_purchases table).
user_purchases has only one other field that is of interest here, which is purchase_date.
I am trying to write a Sequel ORM statement that will return a dataset with the following columns:
user_id
date of the users SECOND purchase, if it exists
So users who have not made at least 2 purchases will not appear in this dataset. What is the best way to write this Sequel statement?
Please note I am looking for a dataset with ALL users returned who have >= 2 purchases
Thanks!
EDIT FOR CLARITY
Here is a similar statement I wrote to get users and their first purchase date (as opposed to 2nd purchase date, which I am asking for help with in the current post):
DB[:users].join(:user_purchases, :user_id => :id)
.select{[:user_id, min(:purchase_date)]}
.group(:user_id)
You don't seem to be worried about the dates, just the counts so
DB[:user_purchases].group_and_count(:user_id).having(:count > 1).all
will return a list of user_ids and counts where the count (of purchases) is >= 2. Something like
[{:count=>2, :user_id=>1}, {:count=>7, :user_id=>2}, {:count=>2, :user_id=>3}, ...]
If you want to get the users with that, the easiest way with Sequel is probably to extract just the list of user_ids and feed that back into another query:
DB[:users].where(:id => DB[:user_purchases].group_and_count(:user_id).
having(:count > 1).all.map{|row| row[:user_id]}).all
Edit:
I felt like there should be a more succinct way and then I saw this answer (from Sequel author Jeremy Evans) to another question using select_group and select_more : https://stackoverflow.com/a/10886982/131226
This should do it without the subselect:
DB[:users].
left_join(:user_purchases, :user_id=>:id).
select_group(:id).
select_more{count(:purchase_date).as(:purchase_count)}.
having(:purchase_count > 1)
It generates this SQL
SELECT `id`, count(`purchase_date`) AS 'purchase_count'
FROM `users` LEFT JOIN `user_purchases`
ON (`user_purchases`.`user_id` = `users`.`id`)
GROUP BY `id` HAVING (`purchase_count` > 1)"
Generally, this could be the SQL query that you need:
SELECT u.id, up1.purchase_date FROM users u
LEFT JOIN user_purchases up1 ON u.id = up1.user_id
LEFT JOIN user_purchases up2 ON u.id = up2.user_id AND up2.purchase_date < up1.purchase_date
GROUP BY u.id, up1.purchase_date
HAVING COUNT(up2.purchase_date) = 1;
Try converting that to sequel, if you don't get any better answers.
The date of the user's second purchase would be the second row retrieved if you do an order_by(:purchase_date) as part of your query.
To access that, do a limit(2) to constrain the query to two results then take the [-1] (or last) one. So, if you're not using models and are working with datasets only, and know the user_id you're interested in, your (untested) query would be:
DB[:user_purchases].where(:user_id => user_id).order_by(:user_purchases__purchase_date).limit(2)[-1]
Here's some output from Sequel's console:
DB[:user_purchases].where(:user_id => 1).order_by(:purchase_date).limit(2).sql
=> "SELECT * FROM user_purchases WHERE (user_id = 1) ORDER BY purchase_date LIMIT 2"
Add the appropriate select clause:
.select(:user_id, :purchase_date)
and you should be done:
DB[:user_purchases].select(:user_id, :purchase_date).where(:user_id => 1).order_by(:purchase_date).limit(2).sql
=> "SELECT user_id, purchase_date FROM user_purchases WHERE (user_id = 1) ORDER BY purchase_date LIMIT 2"
I have a many-to-many relationship between a model User and Picture. These are linked by a join table called Picturization.
If I obtain a list of users of a single picture, i.e. picture.users -> how can I ensure that the result obtained is sorted by either creation of the Picturization row (i.e. the order at which a picture was associated to a user). How would this change if I wanted to obtain this in order of modification?
Thanks!
Edit
Maybe something like
picture.users.where(:order => "created_at")
but this created_at refers to the created_at in picturization
Have an additional column something like sequence in picturization table and define sort order as default scope in your Picturization
default_scope :order => 'sequence ASC'
If you want default sort order based on modified_at then use following default scope
default_scope :order => 'modified_at DESC'
You can specify the table name in the order method/clause:
picture.users.order("picturizations.created_at DESC")
Well, in my case, I need to sort many-to-many relation by a column named weight in the middle-table. After hours of trying, I figured out two solutions to sort many-to-many relation.
Solution1: In Rails Way
picture.users.where(:order => "created_at")
cannot return a ActiveRecord::Relation sorted by Picturization's created_at column.
I have tried to rewrite a default_scope method in Picturization, but it does not work:
def self.default_scope
return Picturization.all.order(weight: :desc)
end
Instead, first, you need to get the ids of sorted Picturization:
ids = Picturization.where(user_id:user.id).order(created_at: :desc).ids
Then, you can get the sorted objects by using MySQL field functin
picture.users.order("field(picturizations.id, #{ids.join(",")})")
which generates SQL looks like this:
SELECT `users`.*
FROM `pictures` INNER JOIN `picturizations`
ON `pictures`.`id` = `picturizations`.`picture_id`
WHERE `picturizations`.`user_id = 1#for instance
ORDER BY field(picturizations.id, 9,18,6,8,7)#for instance
Solution2: In raw SQL Way
you can get the answer directly by using an order by function:
SELECT `users`.*
FROM `pictures` INNER JOIN `picturizations`
ON `pictures`.`id` = `picturizations`.`picture_id`
WHERE `picturizations`.`user_id = 1
order by picturizations.created_at desc
I'm using rails and am trying to figure out how to use ActiveRecord within the method to combine the following into one query:
def children_active(segment)
parent_id = Category.select('id').where('segment' => segment)
Category.where('parent_id'=>parent_id, 'active' => true)
end
Basically, I'm trying to get sub categories of a category that is designated by a unique column called segment. Right now, I'm getting the id of the category in the first query, and then using that value for the parent_id in the second query. I've been trying to figure out how to use AR to do a join so that it can be accomplished in just one query.
You can use self join with a alias table name:
Category.joins("LEFT OUTER JOIN categories AS segment_categories on segment_categories.id = categories.parent_id").where("segment_categories.segment = ?", segment).where("categories.active = ?", true)
This may looks not so cool, but it can implement the query in one line, and there will be much less performance loss than your solution when data collection is big, because "INCLUDE IN" is much more slower than "JOIN".