How do I submit a boolean parameter in Rails? - ruby-on-rails

Question

I'm submitting a parameter show_all with the value true. This value isn't associated with a model.
My controller is assigning this parameter to an instance variable:
#show_all = params[:show_all]
However, #show_all.is_a? String, and if #show_all == true always fails.
What values does Rails parse as booleans? How can I explicitly specify that my parameter is a boolean, and not a string?

Answer 1

UPDATE: Rails 5:
ActiveRecord::Type::Boolean.new.deserialize('0')
UPDATE: Rails 4.2 has public API for this:
ActiveRecord::Type::Boolean.new.type_cast_from_user("0") # false
PREVIOUS ANSWER:
ActiveRecord maintains a list of representations for true/false in https://github.com/rails/rails/blob/master/activerecord/lib/active_record/connection_adapters/column.rb
2.0.0-p247 :005 > ActiveRecord::ConnectionAdapters::Column.value_to_boolean("ON")
2.0.0-p247 :006 > ActiveRecord::ConnectionAdapters::Column.value_to_boolean("F")
This is not part of Rails' public API, so I wrapped it into a helper method:
class ApplicationController < ActionController::Base
private
def parse_boolean(value)
ActiveRecord::ConnectionAdapters::Column.value_to_boolean(value)
end
end
and added a basic test:
class ApplicationControllerTest < ActionController::TestCase
test "parses boolean params" do
refute ApplicationController.new.send(:parse_boolean, "OFF")
assert ApplicationController.new.send(:parse_boolean, "T")
end
end

Answer 2

I wanted to comment on zetetic answer but as I can't do that yet I'll post this as an answer.
If you use
#show_all = params[:show_all] == "1"
then you can drop ? true : false because params[:show_all] == "1" statement itself will evaluate to true or false and thus ternary operator is not needed.

Answer 3

This question is rather old, but since I came across this issue a couple of times, and didn't like any of the solutions proposed, I hacked something myself which allows to use multiple strings for true such as 'yes', 'on', 't' and the opposite for false.
Monkey patch the class String, and add a method to convert them to boolean, and put this file in /config/initializers as suggested here: Monkey Patching in Rails 3
class String
def to_bool
return true if ['true', '1', 'yes', 'on', 't'].include? self
return false if ['false', '0', 'no', 'off', 'f'].include? self
return nil
end
end
Notice that if the value is none of the valid ones either for true or false, then it returns nil. It's not the same to search for ?paid=false (return all records not paid) than ?paid= (I don't specify if it has to be paid or not -- so discard this).
Then, following this example, the logic in your controller would look like this:
Something.where(:paid => params[:paid].to_bool) unless params[:paid].try(:to_bool).nil?
It's pretty neat, and helps to keep controllers/models clean.

Answer 4

#show_all = params[:show_all] == "1" ? true : false
This should work nicely if you're passing the value in from a checkbox -- a missing key in a hash generates nil, which evaluates to false in a conditional.
EDIT
As pointed out here, the ternary operator is not necessary, so this can just be:
#show_all = params[:show_all] == "1"

Answer 5

You could change your equality statement to:
#show_all == "true"
If you want it to be a boolean you could create a method on the string class to convert a string to a boolean.

Answer 6

I think the simplest solution is to test "boolean" parameters against their String representation.
#show_all = params[:show_all]
if #show_all.to_s == "true"
# do stuff
end
Regardless of whether Rails delivers the parameter as the String "true" or "false" or an actual TrueClass or FalseClass, this test will always work.

Answer 7

You could just do
#show_all = params[:show_all].downcase == 'true'

Answer 8

It's worth noting that if you're passing down a value to an ActiveModel in Rails > 5.2, the simpler solution is to use attribute,
class Model
include ActiveModel::Attributes
attribute :show_all, :boolean
end
Model.new(show_all: '0').show_all # => false
As can be seen here.
Before 5.2 I use:
class Model
include ActiveModel::Attributes
attribute_reader :show_all
def show_all=(value)
#show_all = ActiveModel::Type::Boolean.new.cast(value)
end
end
Model.new(show_all: '0').show_all # => false

Answer 9

Another approach is to pass only the key without a value. Although using ActiveRecord::Type::Boolean.new.type_cast_from_user(value) is pretty neat, there might be a situation when assigning a value to the param key is redundant.
Consider the following:
On my products index view by default I want to show only scoped collection of products (e.g. those that are in the stock). That is if I want to return all the products, I may send myapp.com/products?show_all=true and typecast the show_all parameter for a boolean value.
However the opposite option - myapp.com/products?show_all=false just makes no sense since it will return the same product collection as myapp.com/products would have returned.
An alternative:
if I want to return the whole unscoped collection, then I send myapp.com/products?all and in my controller define
private
def show_all?
params.key?(:all)
end
If the key is present in params, then regardless of its value, I will know that I need to return all products, no need to typecast value.

Answer 10

You can add the following to your model:
def show_all= value
#show_all = ActiveRecord::ConnectionAdapters::Column.value_to_boolean(value)
end

Answer 11

You could convert all your boolean params to real booleans like this:
%w(show_all, show_featured).each do |bool_param|
params[bool_param.to_sym] = params[bool_param.to_sym] == "true"
end
In this solution, nil parameters would become false.

Answer 12

While not explicitly what the question is about I feel this is appropriately related; If you're trying to pass true boolean variables in a rails test then you're going to want the following syntax.
post :update, params: { id: user.id }, body: { attribute: true }.to_json, as: :json
I arrived at this thread looking for exactly this syntax, so I hope it helps someone looking for this as well. Credit to Lukom