local code = [[
print("this is a trap")
asd("XDasdsadasdasd")
print("this is a trap")
]]
print("\n\n\n\n\n")
print(string.match(code, 'asd(.*)'))
I made this but the problem is it also returns the print under it. It'll return anything under the asd("XDasdsadasdasd"), but i only want whats inside asd("XDasdsadasdasd") to return that will be "XDasdsadasdasd"
Parentheses are magic chars in Lua patterns. You need to escape them. Also, you need to stop at the first closing parenthesis. See the code below:
print(string.match(code, 'asd%(.-%)'))
If you only want what's inside asd(...), then use
print(string.match(code, 'asd%((.-)%)'))
Related
I'm trying to modify an existing lua script that cleans up subtitle data in Aegisub.
I want to add the ability to delete lines that contain the symbol "♪"
Here is the code I want to modify:
-- delete commented or empty lines
function noemptycom(subs,sel)
progress("Deleting commented/empty lines")
noecom_sel={}
for s=#sel,1,-1 do
line=subs[sel[s]]
if line.comment or line.text=="" then
for z,i in ipairs(noecom_sel) do noecom_sel[z]=i-1 end
subs.delete(sel[s])
else
table.insert(noecom_sel,sel[s])
end
end
return noecom_sel
end
I really have no idea what I'm doing here, but I know a little SQL and LUA apparently uses the IN keyword as well, so I tried modifying the IF line to this
if line.text in (♪) then
Needless to say, it didn't work. Is there a simple way to do this in LUA? I've seen some threads about the string.match() & string.find() functions, but I wouldn't know where to start trying to put that code together. What's the easiest way for someone with zero knowledge of Lua?
in is only used in the generic for loop. Your if line.text in (♪) then is no valid Lua syntax.
Something like
if line.comment or line.text == "" or line.text:find("\u{266A}") then
Should work.
In Lua every string have the string functions as methods attached.
So use gsub() on your string variable in loop like...
('Text with ♪ sign in text'):gsub('(♪)','note')
...thats replace the sign and output is...
Text with note sign in text
...instead of replacing it with 'note' an empty '' deletes it.
gsub() is returning 2 values.
First: The string with or without changes
Second: A number that tells how often the pattern matches
So second return value can be used for conditions or success.
( 0 stands for "pattern not found" )
So lets check above with...
local str,rc=('Text with strange ♪ sign in text'):gsub('(♪)','notation')
if rc~=0 then
print('Replaced ',rc,'times, changed to: ',str)
end
-- output
-- Replaced 1 times, changed to: Text with strange notation sign in text
And finally only detect, no change made...
local str,rc=('Text with strange ♪ sign in text'):gsub('(♪)','%1')
if rc~=0 then
print('Found ',rc,'times, Text is: ',str)
end
-- output is...
-- Found 1 times, Text is: Text with strange ♪ sign in text
The %1 holds what '(♪)' found.
So ♪ is replaced with ♪.
And only rc is used as a condition for further handling.
Can someone help me solve the problem I'm having with a regular expression? I have a file containing the following code:
I'm using a visit to find matches and replace them so that I can remove the empty lines. The result is, however, not what I'm expecting. The code is as follows:
str content = readFile(location);
// Remove empty lines
content = visit (content) {
case /^[ \t\f\v]*?$(?:\r?\n)*/sm => ""
}
This regular expression also removes non empty lines resulting in an output equal to:
Can someone explain what I'm doing wrong with the regular expression as well as the one shown below? I can't seem to figure out why it's not working.
str content = readFile(location);
// Remove empty lines
content = visit (content) {
case /^\s+^/m => ""
}
Kind regards,
Bob
I think the big issue here is that in the context of visit, the ^ anchor does not mean what you think it does. See this example:
rascal>visit ("aaa") { case /^a/ : println("yes!"); }
yes!
yes!
yes!
visit matches the regex at every postfix of the string, so the ^ is relative for every postfix.
first it starts at "aaa", then at "aa" and then at "a".
In your example visit, what will happen is that empty postfixes of lines will also match your regex, and substitute those by empty strings. I think an additional effect is that the carriage return is not eaten up eagerly.
To fix this, simply not use a visit but a for loop or while, with a := match as the condition.
I am trying to replace some characters in a text block. All of the replacements are working except the one at the beginning of the string variable.
The text block contains:
[FIRST_NAME] [LAST_NAME], This message is to inform you that...
The variables are defined as:
$fname = "John";
$lname = "Doe";
$messagebody = str_replace('[FIRST_NAME]',$fname,$messagebody);
$messagebody = str_replace('[LAST_NAME]',$lname,$messagebody);
The result I get is:
[FIRST_NAME] Doe, This message is to inform you that...
Regardless of which tag I put first or how the syntax is {TAG} $$TAG or [TAG], the first one never gets replaced.
Can anyone tell me why and how to fix this?
Thanks
Until someone can provide me with an explanation for why this is happening, the workaround is to put a string in front and then remove it afterward:
$messagebody = 'START:'.$messagebody;
do what you need to do
$messagebody = substr($messagebody,6);
I believe it must have something to do with the fact that a string starts at position 0 and that maybe the str_replace function starts to look at position 1.
I'm following a tutorial(http://youtube.com/watch?v=xvvsG9Cl4HA 19 min 20sec) and to make his code look neat he puts some on a ew line like this
if let myPlacement = myPlacements?.first
{
let myAddress = "\(myPlacement.locality) \
(myPlacement.country) \
(myPlacement.postalCode)"
}
. But when I try I get an error
unterminated string literal
and
consecutive statements on a line must be seperated by a ';'
but the guy in the tutorial has done it the exact same way. What's going on?
I'm using the latest swift and and latest xcode 7.2 any help would be apreciated
if I write everything on the same line like this
if let myPlacement = myPlacements?.first
{
let myAddress = "\(myPlacement.locality) \(myPlacement.country) \(myPlacement.postalCode)"
}
it works fine though
if I write everything on the same line like this
Well, there's your answer. You are not permitted to break up a string literal into multiple lines as you are doing in your first example. There are languages that permit this, but Swift is not one of them. This is not legal:
let s = "hello
there"
There is no magic line-continuation character which, placed at the end of the first line, would make that legal.
If the window is narrower than the line, the editor may wrap the line, for display purposes; but you cannot put actual line breaks inside a string literal.
You can work around this by combining (concatenating) multiple string literals, if you think that makes for greater legibility. This, for example, is legal:
let myAddress = "\(myPlacement.locality) " +
"\(myPlacement.country) " +
"\(myPlacement.postalCode)"
I look your video tutorial carefully. You have a misunderstanding here.
You must pay attention to the video, the code in this picture is not break lines because he add a return here, it is because his screen is too narrow.
So, the real code is
let myAddress = "\(myPlacement.locality) \(myPlacement.country) \(myPlacement.postalCode)"
Please watch it carefully.
And you may need know first, \ in \(myPlacement.locality) is a escape character, it means to get the value of myPlacement.locality and put in the string.
For example, say I wanted to determine whether this form was storing newlines as carriage returns or newlines or whatever characters. I'm often in situations where I'm writing code and am not sure what type of new-line character a file/form/whatever I'm parsing is using.
How could I determine this? Is there a way to determine this without actually doing a check inside of code? (It seems like I should be able to right-click and "show all characters" or something like that).
Note: I realize I could write code saying
(if == '\r') cout << "Carriage";
etc
but I have a feeling there's a simpler solution.
Maybe is list what you are looking for (from vim help):
:[range]l[ist] [count] [flags]
Same as :print, but display unprintable characters
with '^' and put $ after the line. This can be
changed with the 'listchars' option.
See ex-flags for [flags].
You can switch modes with:
:set list
and
:set nolist
Additionally you can use "listchars" as shown in this example:
You could for example check your document for occourences of "Carriage Return" or "New Line"/"Line Feed".
e.g. (php):
if( strstr( $yourstring , "\r" ) != false ){ // You have Carriage return
// Do something
}
elseif( strstr( $yourstring , "\n" ) != false ){ // You have New Line/Line feed
// Do something
}
else{
// You cannot determine which on is used, because the string is single-lined
}
I hope this is the thing you're looking for
Note: In windows "\r\n" is used to specify ne lines