So I have two csv files, one is the all member information, one is a poll event result,
which is like:
Member information:
[Member Name],[Member Tier]
Apple, Bronze
Banana, Silver
Cat, Gold
Poll event result:
[Member Name],[OptionA],[OptionB],[OptionC]
Apple,0,0,1
Banana,1,0,0
Cat,0,1,0
I want to do is weight the vote value with member's tier, for example, Cat is gold member so in this poll OptionB will win.
But the poll csv file is lack of member's tier parameter, so, I'm thinking to do a function like:
Create list "tier Bronze","tier Silver","tier Gold"
in member information file, loop for everyone, if tier match, add to that list
and then go to poll file, loop for everyone, if name match the name in tier list, mark them.
I'm not sure is this the right way, and how to do it, any help will be appreciated :^)
What you need is a vlookup function.
Take 2 lists with member name (as ID) in first left column and tier in 2nd and then use vlookup.
Put vlookup on the right part of your poll table and write:
=vlookup(ID location;range with poll results;2;false)
Then copy down vlookup formula
Or you can do it in more elegant way using Arrayformula:
=ArrayFormula(
ifna(
vlookup(E3:E;$B$3:$C;2;false)
)
)
Related
I have a graph database with information about different companies and their subsidiaries. Now my task is to display the structure of the company. This I have achieved with d3 and vertical tree.
But additionally I have to write summary statistics about the company that is currently displayed. Companies can be chosen from a dropdown list which is fetching this data dynamically via AJAX call.
I have to write in the same HTML a short summary like :
Total amount of subsidiaries for CompanyA: 300
Companies in Corporate Havens : 45%
Companies in Tax havens 5%
My database consists of two nodes: Company and Country, and the country has label like CH and TH.
CREATE (:TH:Country{name:'Nauru', capital:'Yaren', lng:166.920867,lat:-0.5477})
WITH 1 as dummy MATCH (a:Company), (b:Country) WHERE a.name=‘CompanyA ' AND b.name='Netherlands' CREATE (a)-[:IS_REGISTERED]->(b)
So how can I find amount of subsidiaries of CompanyA that are registered in corporate and tax havens? And how to pass this info further to html
I found different cypher queries to query all the labels as well as apocalyptic.stats but this does not allow me to filter on mother company. I appreciate help.
The cypher is good because you write a query almost in natural language (the query below may be incorrect - did not check, but the idea is clear):
MATCH (motherCompany:Company {name: 'CompanyA'})-[:HAS_SUBSIDIARY]->(childCompany:Company)
WITH motherCompany,
childCompany
MATCH (childCompany)-[:IS_REGISTERED]->(country:Country)
WITH motherCompany,
collect(labels(country)) AS countriesLabels
WITH motherCompany,
countriesLabels,
size([countryLabels IN countriesLabels WHERE 'TH' IN countryLabels ]) AS inTaxHeaven
RETURN motherCompany,
size(countriesLabels) AS total,
inTaxHeaven,
size(countriesLabels) - inTaxHeaven AS inCorporateHeaven
I have a spreadsheet of tasks, each of which I'd like to assign an ID to (in column A). Each task falls within certain categories (contained in column B), and the ID should relate to this category. For example, if the category is '4', then the first ID should be 04.01, and the second task should be 04.02 etc. Are there any formulas that would work well here and ensure that each ID is unique?
The category is a lookup based on the value in column C, so at the moment my formula is:
=vlookup(C1,Lookups!A:B,2,false) & "." & text(row(C1:C) - row(C1) + 1, "00")
Sample data would have been helpful, but UNTESTED might be worth trying:
=vlookup(C1,Lookups!A:B,2,0)&"."&text(countif(C$1:C1,C1),"00")
I am trying to create a report in SSRS. Below is a small example of what my dataset looks like.
Example Data Set
So, there are three different stores (A,B,C) and each has a landlord (a,b,c). Landlords can pay via three different methods (1,2,3) and the amounts paid per method are shown.
Right now, I have two filters set up. The first is by Store and the second is by Landlord.
What I am having trouble with is:
How can I set up a filter by the Amount that will return information from an entire Store/Landlord?
So for example, if I wanted to filter Amount by 150, I would like to return all the "payment" information for the store(s) that have a payment of 150. Such as the following:
Desired Result
Is it possible to add a filter to return information from the entire group? (Store and Landlord are the group in this case)
I am new to SSRS so any help/insight would be greatly appreciated!
You can use LookUpSet to locate the matching groups, JOIN to put the results in a string and the INSTR function to filter your results.
=IIF(ISNOTHING(Parameters!AMOUNT.Value) OR INSTR(
Join(LOOKUPSET(Fields!Amount.Value, Fields!Amount.Value, Fields!Store.Value, "DataSet1"), ", ") ,
Fields!Store.Value
) > 0, 1, 0)
This translates to:
If the Store value is found (INSTR > 0) in the list (JOIN) of Stores where the Amount is the current Amount (Lookupset).
In your filter, put the above expression in the Expression, change the type to INTEGER and the Value to 1.
[
I found this question about Group By in redis but actually does not solve my issue. I have a complex search of products, once I got the ones I am looking for I want to group them by their shops, because they must be showed in a map.
My actual implementation is as follow:
-A function which search products by a pattern, it return products ids as "product:id"
product_ids = search_products_by_indexing(pattern)
-A hash with name "selling" which contains product:id/shop:id as key/value.
shops = $redis.hmget("selling", *product_ids)
# this returns list of shops as "shop:id" which sell the given prodcuts
-Then I do an intersection of shops with another list to get only shops located in a given city.
result_shops = shops & $redis.smembers("shops:city_name")
# OR by redis
$zinterstore(tem_id, shops, $redis.smembers("shops:city_name"))
result_shops = $redis.zrange(temp_id, 0, -1)
-The only thing I still need is to get the searched products grouped by result_shops. or for example this could be a hash as shop:id/[product:id] as key/value (this is the final result, shop must be in the city and product match the pattern)
Is my solution suitable to this problem or maybe there is a better implementation to solve it? any suggestion will be very appreciated!!
UPDATE: One product belongs to only one shop and one shop can have many products.
-A hash with name "selling" which contains product:id/shop:id as key/value.
This usage of a Hash will only allow you to one shop:id per product:id, meaning only one shop can sell a given product... perhaps the value should be a concatenated list of shop:ids or even better - use a Set selling:product:id and store all your relevant shop:ids in it.
-Then I do an intersection of shops with another list to get only shops located in a given city.
IMO this is redundant as the intersect's results is always shops:city_name
-The only thing I still need is to get the searched products grouped by result_shops.
If you've taken my Set instead of a Hash suggestion, this can be done with:
ZINTERSTORE tem_id 2 shops:city_name selling:product:id
ZRANGE tem_id 0 -1
http://about.digg.com/blog/looking-future-cassandra
I've found this article about Digg's move to Cassandra. But I didn't get the author's idea of Bucket for pair (user,item). Little more details on the idea would be helpful to me to understand the solution better.
Thanks
It sounds like they are using one row in a super column family per user with one super column per item; a subcolumn for an item super column represents a friend who dugg the item. At least in pycassa, this makes an insert as simple as:
column_family.insert(user, {item: {friend: ''}})
They could also have done this a couple of other ways, and I'm not sure which they chose.
One is to use a standard column family, use a (user,item) combination for the row key, and use one column per friend who dugg the item:
column_family.insert(user + item, {friend: ''})
Another is to use a standard column family, use just (user) for the row key, and use an (item, friend) combination for the column name:
column_family.insert(user, {item + friend: ''})
Doesn't sound like this is what they used, but it's an acceptable option as well.